A battery of e.m.f. 12.0V and internal resistance0.5\(\Omega\) is connected to 1.5\(\Omega\) and 4.0\(\Omega\) series resistor. Calculate the terminal voltage of the battery.
A
13.0V
B
11.0V
C
3.0V
D
1.0V
Verified Correct Answer: B.
Physical Principles & Numerical Solution
\(\frac{V}{R} = \frac{E}{R + r} = \frac{V}{5.5} = \frac{12}{6}\)
v = 11.0V
Source: Myschool Past Questions Archive (Record #35210)