A wire of resistivity 4.40 x 10-5\(\Omega\) cm has a cross sectional area of 7.50 x 10-4 cm2. Calculate the length of the wire that will be required to make a 4.0\(\Omega\) resistor
A
82.50 cm
B
68.18cm
C
15.90cm
D
11.95cm
Verified Correct Answer: B.
Physical Principles & Numerical Solution
L = \(\frac{R.A}{e} = \frac{4 \times 7.50 \times 106{-4}}{4.40 \times 10^{-5}} = 68.18cm\)
Source: Myschool Past Questions Archive (Record #35209)