In the diagram above, AB represents a uniform rod of length 1.50m which is in equilibrium on a pivot at P, If AP = 40cm, calculate the mass of the rod. [g = 10ms-2]
Attached Figure / Diagram
A
0.280kg
B
0.400kg
C
0.613kg
D
0.800kg
Verified Correct Answer: D.
Physical Principles & Numerical Solution
m = \(\frac{0.7 \times 40}{35} = 0.8kg\)
Source: Myschool Past Questions Archive (Record #34008)