A spiral spring of natural length 30.0cm and force constant of 20Nm-1 is compressed to 20.0cm. Calculate the energy stored in the spring
A
0.1J
B
1.0J
C
10.0J
D
100.0J
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Energy = \(\frac{1}{2} ke^2 = \frac{1}{2} \times 20 \times 0.1^2\)
= 0.1J
Source: Myschool Past Questions Archive (Record #34007)