An electric bulb is rated 60W, 220V. Calculate the resistance of its filament when it is operating normally
A
296.7\(\Omega\)
B
400.0\(\Omega\)
C
512.2\(\Omega\)
D
806.7\(\Omega\)
Verified Correct Answer: D.
Physical Principles & Numerical Solution
R = \(\frac{v^2}{P} = \frac{220^2}{100} = 806.7\Omega\)
Source: Myschool Past Questions Archive (Record #33938)