If the frequency of the tuning fork at resonance is 256Hz, calculate the frequency of vibration of the wire when the tension in he wire is increased to 196N
A
130.6Hz
B
182.9Hz
C
358.4Hz
D
501.8Hz
Verified Correct Answer: C.
Physical Principles & Numerical Solution
\(\frac{f}{256} = \sqrt{\frac{196}{100}}\)
f = \(\sqrt{\frac{256^2 \times 196}{100}}\)
= 356.4Hz
Source: Myschool Past Questions Archive (Record #33932)