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Physics
WAEC / WASSCE 2008
Current Electricity & Electric Circuits
Solution
a) On what principle does lighting in a fluorescent tube operate?
(b) State two factors which determine the colour of light produced in a fluorescent tube.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) The princle on which lighting in a fluorescent operation is electrical discharge through a gas at low pressure and at high voltage.
(b) The colour of light produced in a fluorescent tube depends on factors;
(i) coating inside the tube; and (ii) the nature ype of gas in the tube.
Source: Myschool Past Questions Archive (Record #53551)
Physics
WAEC / WASSCE 2008
Current Electricity & Electric Circuits
Solution
(a) Define electrolysis.
(b) Classify each of the following substances as an electrolyte or a non-electrolyte
(i) sugar solution;
(ii) kerosene;
(iii) alkaline solution
(iv) lemon fruit juice.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Electrolysis is the process through which solutions or molten substance is broken down into their component parts by the passage of electric current.
(b)
Electrolytes
Non-electrolytes
- alkaline
- lemon fruit juice
- sugar solution
- kerosene
Source: Myschool Past Questions Archive (Record #53552)
Physics
WAEC / WASSCE 2008
Waves, Sound & Vibrations
Solution
(a) State Heisenberg's Uncertainty Principle.
(b) State one phenomenon that can only be explained in terms of the wave nature of light.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Heiscnberg's uncertainty principle states that it ipossible to determine with accuracy both the ion and the momentum of a particle simultaneously i.e; \(\Delta p.\Delta x \geq \frac{h}{2} \pi\) .
(b) The phenomenon that can only explained in terms of the wave nature of light are ference and diffraction.
Source: Myschool Past Questions Archive (Record #53553)
Physics
WAEC / WASSCE 2008
Linear Motion, Projectiles & Kinematics
Solution
(a) A particle moves on a straight path with an initial speed u and final speed v in time t. Show that the total distance X covered by the particle is given by
\(x = ut + \frac{1}{2}at^2\)
where a is the magnitude of acceleration
(b) State;
(i) Newton's second law of motion
(ii) the principle of conservation of energy
(iii) the law of floatation.
(c) Consider a balloon of mass 0.030 kg being inflated with a gas of density 0.54 kg m\(^{-3}\). What will be the volume of the balloon when it just begins to rise in air of density 1.29 kg m\(^{-3}\)? [ g = 10 ms\(^{-2}\)]
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
a) Average velocity = \(\frac{u + u}{2}\)
From equation V = u + at
Aeverage velocity = \(\frac{u + u + at}{2}\) = \(u + \frac{1}{2} at\)
Distance covered = Ave. vel. x time
x = (u + \(\frac{1}{2}\)at)t
x = ut +s
(b)i) Newton's second law of motion states that the of change of momentum is proportional to the lied force and takes place in tho direction of the force.
(ii) The principle of conservation of energy es that energy is neither created nor destroyed can be changed from one form to another. The law of floatation states that an object wil t in a fluid when the upthrust exerted upon it by fluid in which it floats equals the weight of the
(c) Mass of air displaced = mass of ballon on and contents V x density of A air
= V x density of gas + content
V x 1.29 = v x 0.54 + 0.030
V = \(\frac{0.03}{0.75}\) = 0.04m\(^3}\)
Source: Myschool Past Questions Archive (Record #53554)
Physics
WAEC / WASSCE 2008
Calorimetry, Latent Heat & Change of State
Solution
(a) State two differences between boiling and evaporation.
(b) A closed inexpansibie vessel contains air saturated with water vapour at 77^\circC. The total pressure in the vessel is 1007 mmHg. Calculate the new pressure in the vessel if the temperature is reduced 1.2 27^\circC. [ The s.v.p. of water at 77^\circC and 27^\circC respectively are 314 mmHg and 27 mmHg. Treat the air in the vessel as an ideal gas]
(c) The lengtn of a zinc rod at 23^\circC is 200 m. Calculate the increase in length of the rod when its temperature rises to 33^\circC. [ expansivity of zinc = 2.6 x 10\(^{-5}\) K\(^{-1}\)]
(d) Explain with there is no temperature change when a solid being heated changes into liquid at its melting point.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
a)
Boiling
Evaporation
Takes place at a particular temperature
Takes place through-out the whole volume of the liquid.
Takes place at a steady temperature
Takes place at all temperatures
Takes place only on the surface of the liquid.
Can take place at reduced temperature.
(b) \(P_1 = 1007 - 314 = 693 mmH_g\)
\(\frac{P_1}{T_1} - \frac{P_2}{T_2} = \frac{693}{350} = \frac{P_2}{300}\)
\(p_2 = \frac{963}{350} \times \frac{300}{1}\) = 594 mmH\(_g\)
Pressure in vessel at 27^\circC = pressure of air + S.V.P of water at 27^\circC
= 594 + 27 = 621mm Hg
(c) \(\alpha = \frac{L_2 - L_1}{L_1(\theta_1 - \theta_2)}\)
= 2.6 x 10-5 x 200 (33-23) = 0.052m
(d) At the solid state the molecules are tightly bounded, therefore at the melting point the heat supplied is absorbed and used to break the bonds holding the molecules together.
Source: Myschool Past Questions Archive (Record #53555)
Physics
WAEC / WASSCE 2008
Waves, Sound & Vibrations
Solution
(a) The equation y = \(\alpha\) sin (wt - kx) represents a plane wave travelling in a medium along the x-direction, being the displacement at the point x at time t.
(i) Given that x is in metres and t is in seconds, state the units of k and w
(ii) What physical quantity does \(\frac{W}{k}\) represent? Justify your answer
(iii) State whether the wave is travelling in the positive or negative x-direction.
(b)(i) What are beats?
(ii) A sonometer wire has a frequency of 259 Hz. It is sounded alongside a tuning fork of frequency 256 Hz. Calculate the beat frequency
(iii) The sonometer wire in (b)(ii) above is under a tension of 1200 N. If a metre of the wire has a mass of 0.03 kg, calculate the length l of the wire when it is vibrating in the fundamental mode.
(c) List two similarities between the human eye and the photographic camera.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)(i) K is measured in m\(^{-1}\) and w rad s\(^{-1}\)
(ii) \(\frac{w}{k}\) represents speed of wave
w = 2\(\pi\)f; and
k = \(\frac{2 \pi}{\pi}\)
\(\frac{w}{k} \frac{2 \pi f}{2 \pi/\lambda} = f\lambda\)
But V = f\(\lambda\)
(iii) The direction of travel of the wave :s in the positive x - direction.
(b)(i) Beats are periodic rise and fall in amplitude of the sound produced when two notes of nearly equal frequencies are sounded together.
(ii) Beat frequency = \(f_1 - f_2\)
= 259 - 256 = 3Hz
(iii) f = \(\frac{1}{2L} \sqrt{T}{m}\)
259 = \(\frac{1}{2L} \sqrt{\frac{1200}{0.03}}\)
L = 0.386m
(c) 1. Both have converging or convex lenses.
2. Their interiors are black.
3. Both form real, inverted, and diminished image.
4. Images of objects are formed on the retina of the eye and the film of the camera.
Source: Myschool Past Questions Archive (Record #53560)
Physics
WAEC / WASSCE 2008
Magnetism, Electromagnetism & AC Circuits
Solution
(a) What is a magnetic field?
(b) With the aid of a labelled diagram describe an experiment to show that a magnetic field exists around a straight wire carrying current.
(c) A 40 \(\mu\)F capacitor in series with a 40 Q resistor is connected to a 100 V, 50 Hz a.c. supply.
(i) Draw a circuit diagram of the arrangement
(ii) Calculate the: I. impedance in the circuit; II. current in the circuit III. potential difference across the capacitor.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) A magnetic field is a region or space where a magnetic force is experienced.
(b)
Connect a straight wire to the circuit as shown above, sprinkle iron fillings on the cardboard paper round the straight wire; and tap gently. Then close the key and gently tap again, the iron fillings form a concentric circles round the wire. This shows that there is magnetic field round a current carrying conductor.
(c)(i)
\(x_c = \frac{1}{2 \pi fc} = \frac{1}{2 \pi \times 50(40 \times 10^{-6})}\)
= 79.567\(\Omega\)
z = \(\sqrt{R^2 + X^2_c} = \sqrt{40^2 + 79,580^2}\)
(ii) I = \(\frac{v}{2} = \frac{100}{89.1} = 1.12A\)
(iii) V = IX\(_c\) = 1.12 x 79.567
= 89.1V
Source: Myschool Past Questions Archive (Record #53561)
Physics
WAEC / WASSCE 2008
Atomic, Quantum, Nuclear Physics & Electronics
Solution
(a)(i) State Einstein's equation of photoelectric effect
(ii) What conservation principle does the equation represent?
(b) List three applications of photocells
(c) A photo emissive surface has a threshold frequency of 4.02 x 10\(^{14}\)Hz. If the surface is illuminated by light of frequency 5.0 x 10\(^{15}\)Hz, calculate the:
(i) threshold wavelength;
(ii) work function;
(iii) kinetic energy of the emitted photoelectrons. [ c = 3.0 x 10\(^{8}\) ms\(^{-1}\), h = 6.63 x 10\(^{-34}\) Js]
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)(i) E = W + K.E, where
E = energy of incident radiation
W = work function of metal
K.E. = Kinetic energy of ejected electrons
(ii) The equation represents the principle of conservation of energy.
(b) Applications of photocells:
1. for burglar alarm
2. for television cameras
3. automatic doors
4. automatic street lighting
5. automatic digital counters.
(c)(i) V = \(f_o\lambda_o\)
\(\lambda_o = \frac{v}{f_o} = \frac{3 \times10^8}{4.02 \times 10^{14}}\)
= 7.46 x 10\(^{-7}\)m
(ii) W = \(hf_o = 6.63 \times 10^{-34} \times 4.02 \times 10^{14}\)
= 2.67 x 10\(^{-19}\)J
(iii) K.E. = \(h (f - f_o) = 6.63 \times10^{-34} (5.0 \times 10^{15} - 4.02 \times 10^{14})\)
= 3.05 x 10\(^{-15}\)J
Source: Myschool Past Questions Archive (Record #53603)
Physics
WAEC / WASSCE 2008
Equilibrium of Forces, Moments & Flotation
Solution
You are provided with a uniform meter rule, a knife edge, masses and other necessary apparatus.
Suspend the metre rule horizontally on the knife edge. Read and record the point of balance G of the métre rule. Keep the knife edge at this point throughout the experiment.
Using the thread provided, suspend the object labelled W at the 15cm mark of the metre rule.
Suspend a mass M= 20g on the other side of G. Adjust the position of the mass until the metre rule balances horizontally again.
Read and record the position Y of the mass M on the metre rule.
Determine and record the distance L between the mass and G. Also determine and record the distance D between W and G.
Repeat the procedure for four other values of M = 30, 40, 50 and 60 g. In each casse ensure that W is kept Constant at the 15 cm mark and the knife edge at G.
Evaluate L\(^{-1}\) in each case. Tabulate your readings.
Plot a graph of M on the vertical axis against L\(^{-1}\) on the horizontal axis.
Determine the slope S, of the graph.
Evaluate \(\frac{4}{D}\)
State two precautions taken to obtain accurate results.
(b)i. State the principle of moments.
ii. Define centre of gravity
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Table of values (observation)
G = 48cm
D = 48 - 15 = 33cm
S/N
MCg
YCcm
LCcm
DCcm
L\(^{-1}\)Ccm
1
20
-
-
33.00
-
2
30
81.00
33.00
33.00
0.03
3
40
72.75
24.75
33.00
0.04
4
50
67.80
19.80
33.00
0.05
5
60
64.58
16.50
33.00
0.06
Slope = dm = \(m_2\) - \(m_1\) = 60 - 10 = 50g
d(1\(^{-1}\))\(_{2}\) - (1\(^{-1}\))\(_{1}\) = 0.06 - 0.01 = 0.05cm\(^{-1}\)
= 1000gcm
\(\frac{S}{D} = \frac{1000}{33}\) 30.3g
Precautions: i
Draught was avoided.
Parallax error on reading metre rule/was avoided.
Repeated readings (must be shown on table).
Ensured suspended masses did not touch the table.
(b) The principle of moments states that for a body in equilibrium, the sum of the clockwise moments about a point is equal to the sum of the anticlockwise moments about the same point.
ii. The centre of gravity of a body is the point through which its resultant weight acts.
Source: Myschool Past Questions Archive (Record #60034)
Physics
WAEC / WASSCE 2008
Lenses & Optical Instruments
Solution
Using the above diagram as a guide, carry out the following instructions.
Fix a metre rule on the bench with its graduated side facing up.
Place the illuminated object at the 0cm end and the screen at the 100cm end of the rule such that the distance d between the illuminated object and screen is 100cm.
Record the distance d. Also, evaluate and record d\(^{2}\).
Place and move the Converging lens between the illuminated object and the Screen until a sharp diminished image of the object is formed on the screen.
Read and record the position Ih of the lens.
Now move the lens towards the object until another sharp image of the object is formed on the Screen.
Read and record the new position \(l_2\) of the lens.
Evaluate and record L= (\(l_1\) - \(I_2\)), also evaluate L\(^{2}\) and D = d\(^{2}\) - L\(^{2}\).
Repeat the procedure for four values of d= 85, 75, 65 and 55cm. Tabulate your readings.
Plot a graph or Don the vertical axis against d on the horizontal axis.
Determine the slope, s, of the graph.
Evaluate k = \(\frac{s}{4}\).
State two precautions taken to obtain accurate results.
(b)i. Explain the statement the focal length of a converging lens is 15cm.
ii. Distinguish between a real image and a virtual image.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
d(cm)
d\(^{2}\)(cm)
\(l_1\)
\(l_1\)
L=(\(l_1\)-\(l_2\))
L\(^{2}\)
D=(d\(^{2}\)-L\(^{2}\))
100
10,000
79.8
59.5
20.3
412.09
9587.90
85
7225
63.6
20.3
43.3
1874.89
5350.11
75
5626
51.6
23.6
28.0
784.00
4841.00
65
4225
38.3
21.6
16.7
278.89
3946.11
55
3025
33.5
26.5
07.0
049.0
2976.00
k = \(\frac{s}{4} = \frac{146.9}{4}\) = 36.733
Precautions:
Parallax error on reading metre rule was avoided.
The optical components are correctly aligned.
The vertical placement of the lens ensured.
Repeated readings (shown on the table)
(b)i. This means that the distance between the optical centre (or middle of lens) of the lens and its principal focus is 15cm.
Real image
Virtual image
(i) Can be received/formed on a screen
(ii) Formed by the intersection of actual rays
(i) Cannot be received/formed on a screen.
(ii) Formed by the intersection of imaginary rays.
Source: Myschool Past Questions Archive (Record #60035)
Physics
WAEC / WASSCE 2008
Current Electricity & Electric Circuits
Diagram
Solution
You are provided with two resistance wires labeled A and B, a1\(\Omega\) standard resistor Rx, and other necessary apparatus.
Connect \(R_x\) in the left-hand gap of the metre bridge, a length L= 100cm of wire A in the right-hand gap, and the other apparatus as shown in the diagram above.
Determine and record the balance point P on the bridge wire NQ.
Measure and record \(l_x\) = NP and \(l_y\) = PQ.
Evaluate \(R_1\) = \(\frac{I_{y}}{L_{x}}\) = \(R_x\)
Repeat the procedure for four other values of L= 95, 85, 75 and 65cm. In each case, determine and record the balance point P and the length \(l_x\) and \(l_y\). Also, evaluate \(R_1\).
Repeat the experiment with the second wire B. Obtain the balance points P and the values of and \(l_x\) and \(l_y\).
Evaluate \(R_1\) = \(\frac{I_{y}}{L_{x}}\) = \(R_x\) in each case. Tabulate your readings.
Plot a graph of \(R_2\) on the vertical axis against \(R_1\) on the horizontal axis.
Determine the slope, s, of the graph.
Evaluate k = \(\sqrt s \).
State two precautions taken to obtain accurate results.
(b)i. State two advantages of using a potentiometer over a voltmeter for measuring the potential difference.
ii. Define the internal resistance of a cell.
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
L(cm)
Lx(cm)
Ly(cm)
\(R_1\)=Ly. L x R
L\(x_1\)
L\(y_1\)
\(R_2\),(Ly/Lx)Rx
100
5.2
95.0
18.3
21.5
78.3
3.64
95
6.0
94.0
15.7
22.6
77.8
3.44
85
6.5
94.0
14.5
22.8
76.4
3.35
75
7.8
93.1
12.0
23.4
75.6
3.23
65
8.5
95.5
11.2
24.3
75.2
3.10
k = s
s = 0.0903
k = 0.0903 = 0.3005
Precautions: I
ensured keys were removed when not taking readings.
ensured tight connections/clean terminals.
avoided parallax errors in reading meter rule.
ensured jockey did not scratch the resistance wire.
avoided zero error of meter rule noted and corrected.
(b)i. Advantages of the potentiometer over the voltmeter
- High accuracy
- Null deflection (does not draw current at balance point).
- Range can be increased as required.
- No friction in moving parts.
ii. The internal resistance of a cell is the opposition to the current flow through (the electrolyte of) the cell.
Source: Myschool Past Questions Archive (Record #60036)
Chemistry
UTME / JAMB 2008
Nature of Matter & Separation Techniques
Solution
Chlorophyll obtained from green leaves of plant can be shown to be composed of more than one coloured component by the technique of
A
crystallization
B
hydrolysis
C
chromatography
D
sublimation
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The chlorophyll from the green leaves of plant being a mixture can be separated by Chromatography into its different components. Chromatography has to do with the separation of coloured components. chromatography is used in industrial processes to purify materials, test trace amounts of contaminants, isolate chiral compounds, and quality control test products
Source: Myschool Past Questions Archive (Record #4006)
Chemistry
UTME / JAMB 2008
Nature of Matter & Separation Techniques
Solution
In countries where the temperature falls below 273K, salt is always sprinkled on the icy road in order to
A
lower the melting point of the ice
B
increase the density of the ice
C
make the ice impure
D
raise the melting point of the ice
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The presence of impurities in a substance lowers the melting point. Salt is added on icy roads to cause the ice to melt on time.
Source: Myschool Past Questions Archive (Record #4007)
Chemistry
UTME / JAMB 2008
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)
From the equation above, calculate the mass of sodium hydroxide produced by 2.3g of sodium.
[H = 1, O = 16, Na = 23]
A
0.40g
B
0.80g
C
4.00g
D
8.00g
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)
Relative molecular mass of NaOH = 23 + 16 + 1 = 40smol-1
2 * 23g of sodium react with water to produce
2 * 40g of NaOH
∴ 2.3g of sodium will react with water to produce
(2.3 * 40 * 2)/(23 * 2) = 4.00g
Source: Myschool Past Questions Archive (Record #4011)
Chemistry
UTME / JAMB 2008
Kinetic Theory of Matter & Gas Laws
Solution
16.8 g of sodium hydrogen trioxocarbonate (IV) is completely decomposed by heat. Calculate the volume of carbon(IV) oxide given off at s.t.p
[Na 23, C = 12, O = 16, H = 1, Molar volume of a gas at s.t.p = 22.4 dm3]
A
22.40 dm3
B
11.20 dm3
C
2.24 dm3
D
1.12 dm3
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
2NaHCO3(s) → Na2CO3(s) + H2O(l) + CO2
Relative molecular mass of NaHCO3 = 23 +1 + 12 + 16 * 3 = 84gmol-1
2 * 84g of NaHCO3 will be liberated 22.4dm3 or CO2 at s.t.p
16.8g of NaHCO3 will liberate (16.8 * 22.4)/(2 * 84) = 2.24 dm3
Source: Myschool Past Questions Archive (Record #4019)