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Biology
WAEC / WASSCE 2009
Basic Ecological Concepts, Ecosystems & Biomes
Solution
Study carefully specimens H, Jand K and use them to answer questions 4(a) to 4(d).
(a) State the habitat of specimen J.
(b) State (i) five observable features of specimen J;
(ii) how the features in 4(b)(i) adapt specimen J to its habitat.
(c)(i) List two differences between specimens H and J.
(ii) State three similarities between specimen H and the skin of specimen J.
(iii) State how the similar features named in 4(C)(i) above adapt specimen H for its functions.
(d)(i) Classify specimen K into its phylum and class. (ii) Give three reasons for placing specimen in its class.
(iii) List three observable features of specimen K and state how these features adapt it to its mode of life.
medium Difficulty
Verified Correct Answer: Option
Biological Concept & Syllabus Guide
4(a) Habitat of J/Toad/Frog: Frogs Pond/Stream/Fresh water swamps/Swamps/River banks.
Toads- Wet damp places/under leaves/small holes.
(b)(i) Adaptive Features: Webbed digits Streamlined body - bulging eyes above the head
- Nostril above the head - Nictitating membrane - Body odour - Short/stout fore limb
- Long (strong) hind limb - Moist/warty skin - poisonous gland - Long tongue attached to front lip.
(b)(ii) Adaptive features of JI Toad: Webbed digits for swimming/paddling in water Streamlined body for easy movement in water
- bulging eyes to see above water when body is submerged
-Position of nostril above the head enables animal ans get atmosphere air while swimming.
-Nictitating membranes protect eyes from foreign bodies while in water/cleans eye surface.
-Body color blends with surrounding for camouflage.
-Short/stout act as shock absorber/ for landing.
- Long strong hind limbs for hopping on land.
- warty skin prevents evaporation from body/moist skin provides surface for gaseous exchange.
- Poisonous gland for protection against predators.
- Long tongue attached to front lip for easy catching of prey.
(c) Advice to farmer: cytokinin should not be applied beyond some concentration for optimum shoot development.
- For maximum shoot development, the farmer should use cytokinin at a concentration of 4.5mg/l.
(d)(i) Similar substances in plants: Gibberellins -Auxin/IAA -Ethylene/Ethene.
(ii) in Animals - Pituitary growth hormone/Somatotro-pin/Follicle stimulating - Hormone (FSH) - Thyroxine - Adrenocorticotropic hormone (ACTH).
(i) Differences:
H/Lung
J/Toad
Bright red/pink
Dark grey/brown
Organ
Organism
(ii) Similarities:
-Thin surface membranes
-Moist surface Large surface area
- richly supplied with blood vessels/highly vascularized.
(ii) Adaptation of H/Lung:
- Thin membranes allow easy diffusion of oxygen and carbon dioxide/exchange of gases.
-Moist surface for dissolving of gases/carbon dioxide and oxygen
- Abundant blood vessels for transport of respiratory gases
-Large surface area for diffusion/exchange gases.
(d)(i) Classification of K/Maize leaf: Phylum/ Angiospermophyta.
Class- Monocotylenonae
(ii) Reasons: - Long narrow blade - Parallel venation - Presence of leaf sheath
(iii) Adaptations -thin/fat blade; to facilitate diffusion or gases. - Green color chlorophyll; to absorb sunlight for photosynthesis.
-Large surface area; to absorb maximum sunlight
-Presence of veins; for transport of water/manufactured food.
Source: Myschool Past Questions Archive (Record #61316)
Mathematics
UTME / JAMB 2008
Plane Geometry, Polygons & Circle Theorems
Solution
Add 1101\(_2\),10111\(_2\) and 111\(_2\)
A
1110112
B
1101102
C
1010112
D
1010102
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
1101\(_2\) + 10111\(_2\) + 111\(_2\) = 101011\(_2\)
Source: Myschool Past Questions Archive (Record #9257)
Mathematics
UTME / JAMB 2008
Linear, Simultaneous & Quadratic Equations
Solution
If 125\(_x\) = 20\(_{10}\) find x
A
2
B
3
C
4
D
5
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
125\(_x\) = 20\(_{10}\)
1 x X\(^2\) + 2 x X\(^1\) + 5x X \(^0\) = 20
X2 + 2X + 5 = 20
X\(^2\) + 2X - 15 = 0
(X + 5)( X - 3) = 0
X + 5 implies X = -5
X - 3 implies X = 3
But X cannot be negative
∴X = 3
Source: Myschool Past Questions Archive (Record #9258)
Mathematics
UTME / JAMB 2008
Plane Geometry, Polygons & Circle Theorems
Evaluate \(\frac{\left(\frac{3}{8}\div\frac{1}{2}+\frac{1}{2}\right)}{\left(\frac{1}{8}\times\frac{2}{3}+\frac{1}{3}\right)}\)
A
1/4
B
1/3
C
1/2
D
3
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #9259)
Mathematics
UTME / JAMB 2008
Fractions, Decimals, Percentages & Approximations
Solution
Express 123456 to 3 significant figures
A
123000
B
124000
C
125000
D
126000
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
NB: This is a correction to the solution in the video lesson.
123456 \(\approxeq\) 123000.
Source: Myschool Past Questions Archive (Record #9260)
Mathematics
UTME / JAMB 2008
Fractions, Decimals, Percentages & Approximations
Solution
calculate the simple interest on N7,500 for 8 years at 5% per annum.
A
N3,000
B
N600
C
N300
D
N150
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(I = \frac{P \times T \times R}{100}\)
= \(\frac{7500 \times 8 \times 5}{100}\)
= N3000
Source: Myschool Past Questions Archive (Record #9261)
Mathematics
UTME / JAMB 2008
Fractions, Decimals, Percentages & Approximations
Solution
The cost of kerosene per liter increased from N60 to N85. What is the percentage rate of increase?
A
42%
B
41%
C
40%
D
25%
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
N85 - N60 = N25 increase
∴percentage increase = \(\frac{25}{60}\times \frac{100}{1}\) = \(\frac{125}{3}\) = 41.67%
= 42%
Source: Myschool Past Questions Archive (Record #9262)
Mathematics
UTME / JAMB 2008
Indices, Logarithms & Surds
Solution
simplify \(16^{\frac{-1}{2}}\times 4^{\frac{-1}{2}} \times 27^{\frac{1}{3}}\)
A
3/8
B
2/3
C
3/4
D
3/2
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(16^{\frac{-1}{2}}\times 4^{\frac{-1}{2}} \times 27^{\frac{1}{3}}\)
=\(\frac{1}{16^{\frac{1}{2}}}\times \frac{1}{4^{\frac{1}{2}}}\times 27^{\frac{1}{3}}\)
=\(\frac{1}{\sqrt{16}} \times \frac{1}{\sqrt{4}} \times \sqrt[3]{27}\)
=\(\frac{1}{4} \times \frac{1}{2} \times \frac{3}{1}\)
= \(\frac{3}{8}\)
Source: Myschool Past Questions Archive (Record #9263)
Mathematics
UTME / JAMB 2008
Indices, Logarithms & Surds
Solution
If log\(_{x^{\frac{1}{2}}}\)64 = 3, find the value of x
A
4
B
16
C
32
D
64
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
If log\(_{x^{\frac{1}{2}}}\)64 = 3
(X\(^{\frac{1}{2}})^3\) = 64
(X\(^{\frac{1}{2}})^3\) = 4\(^3\)
X\(^{\frac{1}{2}}\) = 4
X = 4\(^2\)
X = 16
Source: Myschool Past Questions Archive (Record #9264)
Mathematics
UTME / JAMB 2008
Indices, Logarithms & Surds
Solution
If \(\frac{1+\sqrt{2}}{1-\sqrt{2}}\) is expressed in the form of x+y\sqrt2 find the values of x and y
A
(-3, -2)
B
(-2, 3)
C
(3,2)
D
(2,-3)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(\frac{1+\sqrt{2}}{1-\sqrt{2}} \times \frac{1+\sqrt{2}}{1+\sqrt{2}}\)
= \(\frac{1+(1+\sqrt{2})+\sqrt{2}(1+\sqrt{2})}{1^2 - (\sqrt{2})^2}\)
= \(\frac{(1+\sqrt{2}+\sqrt{2}+2)}{1-2}\)
= \(\frac{3+2\sqrt{2}}{-1}\)
= - 3 - 2\(\sqrt{2}\)
∴ X and Y = -3 and -2
Source: Myschool Past Questions Archive (Record #9265)
Mathematics
UTME / JAMB 2008
Sets, Logic & Venn Diagrams
Solution
If X = {n\(^2\) + 1:n = 0,2,3} and Y = {n+1:n=2,3,5}, find X∩Y.
A
{1,3}
B
{5,10}
C
∅
D
{4,6}
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
X = {1,5,10}
Y = {3,4,6}
X∩Y = ∅
Source: Myschool Past Questions Archive (Record #9266)
Mathematics
UTME / JAMB 2008
Algebraic Expressions, Polynomials & Factorisation
Solution
Factorize completely; (4x+3y)\(^2\) - (3x-2y)\(^2\)
A
(x+5y)(7x+y)
B
(x+5y)(7x-y)
C
(x-5y)(7x+y)
D
(x-5y)(7x-y)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
(4x+3y)\(^2\) - (3x-2y)\(^2\)
Using the differences of two squares:
(4x+3y+3x-2y)(4x+3y-(3x-2y))
(4x+3y+3x-2y)(4x+3y-3x+2y)
(x+5y)(7x+y)
Source: WAEC / JAMB / NECO Classroom Archive (Record #9270)
Mathematics
UTME / JAMB 2008
Sets, Logic & Venn Diagrams
Solution
A book seller sells Mathematics and English books. If 30 customers buy Mathematics books, 20 customers buy English books and 10 customers buy the two books. How many customers has he altogether?
A
30
B
40
C
50
D
60
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
n(M) only = 30-10 = 20
n(E) only = 20-10 = 10
n(M∩E) = 10
∴M∪E = 20+10+10
= 40
Source: Myschool Past Questions Archive (Record #9267)
Mathematics
UTME / JAMB 2008
Plane Geometry, Polygons & Circle Theorems
Solution
Make Q the subject of formula when \(L=\frac{4}{3}M\sqrt{PQ}\)
A
\(\frac{9L^2}{16M^2P}\)
B
\(\frac{3L}{4M\sqrt{P}}\)
C
\(\frac{\sqrt{3L}}{4MP}\)
D
\(\frac{3L^2}{16M^2}P\)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(L=\frac{4}{3}M\sqrt{PQ}\\
=\frac{3}{4M} \times L = \sqrt{PQ}\\
=\left(\frac{3L}{4M}\right)^2=(\sqrt{PQ})^2\\
=\frac{9L^2}{16M^2}=PQ\\
=Q=\frac{9L^2}{16M^2 P}\)
Source: Myschool Past Questions Archive (Record #9268)
Mathematics
UTME / JAMB 2008
Algebraic Expressions, Polynomials & Factorisation
Solution
If 2x\(^2\) - kx - 12 is divisible by x-4, Find the value of k.
A
4
B
5
C
6
D
7
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
2x2 - kx - 12 is divisible by x-4
implies x is a factor ∴ x = 4
f(4) implies 2(4)2 - k(4) - 12 = 0
32 - 4k - 12 = 0
-4k + 20 = 0
-4k = -20
k = 5
Source: Myschool Past Questions Archive (Record #9269)