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Chemistry
NECO SSCE 2009
Metals, Transition Elements & Extraction
During the extraction of iron in the blast furnance, slag is produced using
A
carbon
B
crylite
C
limestone
D
oxygen
E
sulphur
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #43738)
Chemistry
NECO SSCE 2009
Atomic Structure, Orbitals & Nuclear Chemistry
Brain tumors can be located by using an isotope of
A
carbon - 14
B
iodine 131
C
technetium 99
D
uranium235
E
uranium 238
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #43739)
Chemistry
NECO SSCE 2009
Stoichiometry, Mole Concept & Volumetric Analysis
What volume of carbon (IV) oxide in dm 3 is produced at s.t.p. when 2.50g of CaCO3 reacts with excess acid according to the following equation? CaCO3(s) + 2HCI(aq) → CaCl2(aq) + H2O(1) + CO2(g)
[CaCO2 100; molar volume of a gas at s.t.p. = 22.4dm 3]
A
0.28
B
0.56
C
2.24
D
5.6
E
11.2
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #43740)
Chemistry
NECO SSCE 2009
Oxidation, Reduction & Redox Reactions
The following equations represent redox reactions EXCEPT
A
Ba2+(aq) + SO2-4 (aq) → BaSO4(s)
B
Cl2(g) + 2Br- (aq) → 2CI - (aq) + Br2(g)
C
Fe2+(aq) + ½ C I2(aq) → Fe3+ (aq) + CI-(aq)
D
2Fe3+(aq) + Sn2+(aq) → 2Fe2+(aq) Sn4+ (aq)
E
Zn(s) + CU2+(aq) → Zn2+(aq) + CU(s)
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #43750)
Chemistry
UTME / JAMB 2009
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
If the relative atomic mass of an element is not a whole number, it can be deduced that the element is?
A
Naturally radioactive
B
abundant in nature
C
a transition metal
D
an isotopic mixture
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
This happens because the relative atomic mass is the average of all an element’s isotopes, weighted by how common each isotope is. If the isotopes have different masses, the average won’t be a whole number.
Source: Myschool Past Questions Archive (Record #44097)
Chemistry
WAEC / WASSCE 2009
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
Burette readings (initial and final reading) must be given to two decimal places. Volume of pipette used must also be recorded but no account of experimental procedure is required. All calculations must be done in your answer book.
A is 0.0950 mol dm\(^{-3}\) HCI. B is a solution 13.50g dm\(^{-3}\) of X\(_2\)CO\(_3\).10H\(_2\)O.
(a) Put A into the burette and titrate it against 20.0 cm\(^3\) or 25.0 cm\(^3\) portions öf B using methyl orange as an indicator. Tabulate your readings and calculate the average volume of A used.
(b) From your results and the information provided above, calculate the;
(i) concentration of B in mol dm\(^{-3}\);
(ii) molar mass of X\(_2\)CO\(_3\).10H\(_2\)O in g mol\(^{-1}\);
(iii) percentage by mass X in X\(_2\)C)\(_3\).10H\(_2\)O. [H = 1, C = 12, O = 16]. The equation for the reaction involved in the titration is 2HCl\(_{(aq)}\) + X\(_2\)CO\(_3\).10H\(_2\)O\(_{(aq)}\) \(\to\) 2XCl\(_{(aq)}\) + 11H\(_2\)O\(_{(l)}\) + CO\(_{2(g)}\)
A
2He
B
10Ne
C
18Ar
D
36Kr
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Volume of pipette = 25.00 cm\(^{3}\)
indicator used = methyl orange
colour change at end point yellow to orange/purple
Burette Reading
Rough
(1) First
(2nd) Second
(3rd) Third
Final (cm\(^3\))
25.20
24.90
24.80
24.82
Initial (cm\(^3\))
0.00
0.00
0.00
0.00
Volume of acid used
25.20
24.00
24.80
24.85
Average volume of A used = \(\frac{24.90 + 24.80 + 24.85}{3}\) = 24.85 cm\(^3\)
The equation for the reaction
X\(_2\)CO\(_3\).10H\(_2\)O\(_{(aq)}\) + 2HNO\(_{3(aq)}\) \(\to\) 2 x 2NO\(_{3(aq)}\) + CO\(_{2(g)}\) + 11HNO\(_{(l)}\)
(b)(i) Mole ratio of Acid to Base is 2:1
concentration of B in mol. dm\(^{-3}\)
\(\frac{C_AV_A}{C_BV_B} = \frac{2}{1}\)
C\(_B\) = \(\frac{C_AV_A}{2V_B}\)
C\(_B\) = \(\frac{0.0950 \times 24.85}{2 \times 25}\)
= \(\frac{2.36075}{50}\)
= 0.0472 mol. dm\(^{-3}\)
(ii) Molar mass B in g mol\(^{-1}\)
Molar mass X\(_2\)CO\(3\).10H\(_2\)O = \(\frac{\text{mass concentration gdm}^{-3}}{\text{molar concentration of B in moldm}^{-3}}\)
= \(\frac{13.5 gdm^{-3}}{0.0472 moldm^{-3}}\)
= 286 g mol\(^{-1}\)
(iii) Percentage by mass of X
X\(_2\)CO\(_3\).10H\(_2\)O = 286g
i.e. relative molar mass of X\(_2\)CO\(_3\)
= 2x + 12 + (16 x 3) + 10(2 x 1) + 16 = 286
= 2x + 12 + 48 + 180 = 286
= 2x + 240 = 286
2x = 286 - 240 = 46
x = \(\frac{46}{2}\)
= 23 gmol\(^{-1}\)
Percentage by mass of X = \(\frac{2 \times 23}{286} \times \frac{100}{1}\)
= 16.08%
Source: Official Exam / Past Question Archive
Chemistry
WAEC / WASSCE 2009
Oxidation, Reduction & Redox Reactions
Solution
(a)(i) Outline a suitable procedure for the preparation of ZnCl\(_2\) crystals stating from zinc granules.
(ii) Write a balanced equation for the reaction in (a)(i).
(b) Considei' the following solutions: Na\(_2\)SO\(_{4(aq)}\), CH3COOK\(_{(aq)}\), Pb(NO\(_3\))\(_{2(aq)}\) and MgCl\(_2\). Which of them has/have a pH
(i) greater than 7;
(ii) equal to 7;
(iii) less than 7?
(c)(i) Determine the oxidation number of Mn in I. MnO\(_2\); II. KMnO\(_4\).
(ii) State one laboratory use of each of the .compounds in (c)(i).
(d) Explain why oxidation and reduction processes are complementary.
(e) Consider the reaction represented by the equation: Fe\(_{(s)}\) + 2Ag\(^+_{(aq)}\) \(\to\) Fe\(^{2+}_{(aq)}\) + 2Ag\(_{(s)}\)
(i) Write a balanced ionic half equations for the reaction.
(ii) Which of the species is I. oxidized; II. reduced?
(iii) State the change in the oxidation number of silver during the reaction.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) (i) to some dil. HCI in a beaker, add Zn granules and shake.
(ii) continue to add Zn granules un effervescence stops and the Zn is in excess.
(iii) filter off undissolved Zn granules
(iv) put the filtra in an evaporating dish and heat to concentrate.
(v) cool to obtain crystals (vi) filter and dry the crysta between filter papers.
(ii) Zn\(_{(s)}\) + 2HCI\(_{(aq)}\) \(to\) ZnCl\(_{2(aq)}\) + H\(_{2(g)}\)
(b)(i) CH\(_3\)COOK\(_{(aq)}\)
(ii) Na\(_2\)SO\(_{4(aq)}\)
(iii) Pb(NO\(_3\))\(_{2(aq)}\) and MgCl\(_{2(aq)}\)
(c)(i) I. MnO\(_2\)
Mn + (-2 x 2) = O
Mn — 4 = 0
Mn = + 4
(ii) KMnO\(_4\)
1 + Mn + (– 2 x 4) = 0
1 + Mn – 8 = 0
Mn = + 7
(ii) MnO\(_2\) – as a catalyst
– as an oxidizing agent
KMnO\(_4\) – as an oxidizing agent
(d) Oxidation is a process of electron loss, while reduction is a process of electron gain. A species can only be oxidized if there is another species that would readily accept the donated electron(s)/ Hence every oxidation must be accompanied by a reduction.
(e) (i) I. Fe\(_{(s)}\) \(\to\) F\(^{2+}_{(aq)}\) + 2e\(^-\)
II. Ag\(^+_{(aq)}\) + e\(^-\) \(\to\) Ag\(_{(s)}\)
(ii) I. Fe is oxidized II. Ag\(^+\) is reduced
(iii) +1 to 0.
Source: Myschool Past Questions Archive (Record #52088)
Chemistry
WAEC / WASSCE 2009
Kinetic Theory of Matter & Gas Laws
Solution
(a) (i) State Boyle's law.
(ii) Give the mathematical expression of Boyle's law.
(iii) Sketch the graphical representation of Boyle's law.
(b) A given mass of gas occupied 500 cm3 at 30^\circC and 6.5 x 104 Nm\(^{-2}\). Calculate the volume of the gas at s.t.p. [ Standard pressure = 1.01 x 105 Nm\(^{-2}\)]
(c) Explain why an inflated balloon expands in warm water.
(d)(i) What is meant by the term vapour density? (ii) Determine the vapour density of S\(O_2\). [ S = 32, O = 16 ]
(e)(i) Which of the following gases, S\(O_2\) and N\(H_3\) can be collected by I. upward delivery; II. downward delivery?
(ii) What would be the nature of the solution formed by dissolving each of the following substances in water separately. I. S\(O_2\) II. N\(H_3\)
(iii) State the property exhibited by S\(O_2\) and N\(H_3\) in the following equations:
I. 2\(H_2\)S\(_{(aq)}\) + SO\(_{2(g)}\) \(\to\) 3S\(_{(s)}\) + 2\(H_2\)O\(_{(/)}\)
II. 3CuO\(_{(s)}\) + 2NH\(_{3(g)}\) \(\to\) 3Cu\(_{(s)}\) + 3\(H_2\)O\(_{(/)}\) + N\(_{2(s)}\).
(f) State two alloys of tin.
(ii) Give one use of each of the alloys in (f)(i).
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(i) Boyle's law states that the volume of a given mass of gas is inversely proportional to its pressure if the temperature remains constant.
(ii) P \(\propto\) 1 or PV = K or V \(\propto\) \(\frac{1}{P}\)
(iii)
\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\)
\(V_2 = \frac{P_1V_1T_2}{P_2T_1}\)
\(V_2 = \frac{6.5 \times 10^4 \times 500 \times 273}{(273 + 30) \times 1.01 \times 10^5}\)
\(V_2 = 290 cm^3\)
(c) An inflated balloon expands in warm water because in air, particles in the balloon acquire more kinetic energy. There is an increase in the pressure inside the balloon. In order to keep the pressure constant the balloon expands.
(d) (i) Vapour density is the number of times a given volume of a gas or vapour is as heavy as an equal volume of hydrogen gas at the same temperature and pressure.
(ii) molar mass of SO\(_2\) = 32 + 16 x 2 = 64g mol\(^{-1}\).
Vapour density x 2 = relative molar mass
Vapour density = \(\frac{64}{32}\)
= 32
(e) (i) I. upward delivery = NH\(_3\)
II. downward delivery = SO\(_2\)
(ii) I. acidic II. basic/alkaline
(iii) SO\(_2\) – oxidizing agent NH\(_3\) - reducing agent.
(f) (i) – bronze – typemetal – soft solder
(ii) bronze – for making coins, - metals/other ornaments
typemetal – for printing
soft solder – for plumbing/welding.
Source: Myschool Past Questions Archive (Record #52090)
Chemistry
WAEC / WASSCE 2009
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
(a)(i) Define polymerization.
(ii) Mention two types of polymerization.
(iii) Give one example of I. naturally occurring polymer, II. synthetic polymer.
(b)(i) Describe how ethyne could be prepared in the laboratory.
(ii) Write an equation for the I. polymerization of ethyne II. complete reaction of ethyne with hydrogen bromide.
(iii) Name each of the products formed in (b)(ii) II.
(c)(i) Define each of the following terms: I. pollution; Il. pollutant.
(ii) Mention three types of pollution.
(iii) Give two ways by which pollution can be prevented.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) (i) Polymerization is a process whereby many small molecules (monomers) link together to form a giant molecule (polymer)
(ii) - addition polymerization -condensation polymerization.
(iii) I. starch/cellulose/ proteins/natural rubber/latex. II. polythene(polythene)/PVC/polystyrene/nylon/perplex.
(b) (i) Ethyne is prepared in the laboratory by the action of water on cc!cium dicarbide. The gas evolved is passed through a solution of copper II tetraoxosulphate (VI) to remove impurities and the ethyne is collected over water by upward delivery.
(ii) I. 3C\(_2\)H\(_{2(g)}\) \(\to\) C\(_6\)H\(_{6(g)}\)
II. C\(_2\)H\(_2\) + 2HBr \(\to\) C\(_2\)H\(_4\)Br\(_2\)/ H - C\(\equiv\)C – H + 2HBr \(\to\) CH\(_3\)CHBr\(_2\).
(iii) I. Benzene
II. 1,1 – dibromoethane
(c) I. Pollution is the presence of harmful substances in the environment in concentrations that cause injury to life and property.
(II) Poil spillage prevention - enlightenment programme - tree planting -proper sewage disposal.
(ii) - Air pollutions - water pollutgion - land/soil pollution
(iii) - Use of anti-pollutants in automobiles - promulgation of laws with effective monitoring - oil spoilage prevention - elightenment programme - tree planting
- proper sewage disposal
Source: Myschool Past Questions Archive (Record #52091)
Chemistry
WAEC / WASSCE 2009
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
(a) Atoms of four non-metallic elements in the same group of the periodic table are arranged in order of increasing atomic radius as R < T < W < X. Which of the elements
(i) would readily lose electron(s) from the outermost shell;
(ii) is most electronegative;
(iii) would T displace from aqueous solution;
(iv) is at the top of the group?
(b) The following table shows the electronic configuration of two elements Y and Z.
Element
Electronic Configuration
Y
1s\(^2\) 2s\(^2\) 2p\(^5\)
Z
1s\(^2\) 2s\(^2\) 2p\(^5\) 3s\(^1\)
(i) Name the I. group to which Y belongs II. period to which Z belongs.
(ii) What is the number of protons present in an atom of Z?
(iii) How many unpaired electrons are in an atom of Y?
(iv) Write the formula of the compound formed between Y and Z
(c) Name the type of bond(s) that exist(s) in each of the following compounds.
(i) CaCl\(_2\); (ii) NH\(_4\)Cl; CCl\(_4\)
(d) Describe how the conductance of a molar solution of ammonia compares to that of sodium hydroxide solution.
(e) State the type of reaction illustrated by each of the following equations:
(i) CH\(_3\)CH\(_2\)OH\(_{(/)}\) + CH\(_3\)COOH\(_{(aq)}\) \(\rightleftharpoons\) CH\(_3\)COOC\(_2\)H\(_5\)\(_{(/)}\) + H\(_2\)O\(_{(/)}\)
(ii) H+\(_{Y^+_{(aq)}\) + OH\(^+_{(aq)}\) \(\to\) H\(_2\)O
(f) Determine the volume of the residual gas when 20.0cm\(^3\) of hydrogen was sparked with 15.0cm\(^3\) of oxygen and the resulting mixture cooled to room temperature.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) X (ii) R (iii) VV and X (iv) R
(b) (i) I. group VII II. period III
(ii) eleven
(iii) one
(iv) ZY.
(c) (i) ionic/electrovalent bond
(ii) covalent co-ordinate covalent and ionic
(iii) covalent.
(d) - pour some quantity of each solution into a separate beaker.
- insert electrodes into the solutions and close the circuit. take the readings on the ammeter.
- rinse the electrodes properly with distilled water and dip them into the second solution. Close the circuit and take the reading on the ammeter again.
- the solution with the higher reading is NaOH\(_{(aq)}\) while the one with lower reading is ammonia.
OR
NaOH solution is a strong electrolyte and completely ionizes to produce a lot of ions. NH\(_3\) solution is a weak electrolyte and produces very few ions. The ions produced by NaOH far out-number those produced by NH\(_3\) solution. Hence NaOH solution conducts more than NH\(_3\) solution.
(e) (i) Esterification (ii) Neutralization.
(f) 2H\(_2(g)\) + O\(_{2(g)}\) —> 2H\(_2\)O
(I) from the equation 2 vols of H\(_2\) reacts with 1 vol. of O\(_2\)/ 20cm\(^3\) of H\(_{2(s)}\) reacts with 10cm\(^3\) of O\(_{2(g)}\) residual gas = (15 — 10)cm\(^3\) = 5cm\(^3\) .
Source: Myschool Past Questions Archive (Record #52099)
Chemistry
WAEC / WASSCE 2009
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
(a)(1) Define each of the following terms: I. deliquescence; II. efflorescence.
(ii) Give one example I substance that undergoes each of the processes in (a)(i).
(b) Outline how three colourless gases suspected to be ethane, ethene and ethyne could be distinguished in the laboratory.
(c)(i) What is water crystallization?
(ii) Hydrated calcium chloride (CaCl\(_2\) = 111, xH\(_2\)O) contains 49.32% water of cystallization. Calm the value of x. [ (CaCl\(_2\) = 111, H\(_2\)O = 18 ]
(d) Name one calcium compound used (i) in the manufactur cement; (ii) as a dessicant; (iii) in the production of plaster of Paris (POP);
(iv) to neutralise acidic soils
(e) A concentrated solution of sodium chloride was electrolysed using graphite electrodes.
(i) State the ions present in the solution
(ii) Name the products at the I. anode, II. cathode.
(iii) Give the by-product of the electrolysis.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) (i) I. Deliquescence is a process by which a compound absorbs moisture/water from the atmosphere and dissolves in it to form a solution. II. Efflorescence is a process whereby a hydrated salt loses all or part of its water of crystallization when exposed to the air.
(ii) Deliquescence: NaOH/FeCl\(_3\)/CaCl\(_3\)/CaCl\(_2\)/POl\(_5\) etc.
Efflorescence: Na\(_2\)CO\(_3\).10H\(_2\)O/Na\(_2\)SO\(_4\).10H\(_2\)O/MgSO\(_4\).7H\(_2\)O etc.
(b) — To a sample of each of the gases, add acidified KMnO\(_4\)/Br, water (vapour).
— No visible reaction shows ethane OR decolourization of KMnO\(_4\)/Br\(_2\) water (vapour) shows ethene and ethyne.
—To each of the two remaining samples, add ammoniacal copper (I) chloride/ammoniacal AgNO\(_3\)/Ag\(_2\)O
— No visible reaction shows ethene/formation of reddish-brown precipitate/white precipitate indicate the presence of ethyne.
(c) (i) Water of crystallization is the definite amount of water some substances chemically combine with when they form salt from their aqueous solution.
(ii) % of anhydrous CaCl\(_2\) is 100 — 49.32 = 50.68%.
Number of moles of CaCl\(_2\) H\(_2\)O
\(\frac{50.68}{111}\) \(\frac{49.32}{18}\)
0.457 2.74
0.457 0.457
1 : 6
x = 6
(d) (i) Calcium trioxocarbonate (IV)
(ii) Calcium chloride
(iii) Calcium tetraoxosulphate (VI)
(iv) Calcium oxide/calcium hydroxide.
(e) (i) Na\(^+\) and CI\(^-\) H\(^+\) and OH\(^-\)
(ii) I. chlorine II. hydrogen (iii) Sodium hydroxide solution/NaOH
Source: Myschool Past Questions Archive (Record #52118)
Chemistry
WAEC / WASSCE 2009
Kinetic Theory of Matter & Gas Laws
Solution
(a) State Gay Lussac's Law.
(b) Carbon (II) oxide reacted with oxygen to form carbon (IV) oxide in a see tube.
(i) Write a balanced equation for the reaction.
(ii) If 40 cm\(^3\) of the carbon (II) oxide were mixed with cm\(^3\) of oxygen,
I. calculate the volume of carbon (IV) oxide produced
II. which reactant is in excess and how much?
III. what was the total volume of the gaseous mixture at the end of the reaction?
(c) Consider the following oxides: CaO, SiO\(_2\), CO, NO\(_2\) and ZnO. Which of the oxide(s)
(i) is an acidic oxide that is insoluble in water?
(ii) reacts with water to give alkaline solution?
(iii) is amphoteric?
(iv) is neutral?
(v) is/are gaseous at room temperature?
(d) Explain why
(i) colourless concentrated trioxonitrate (V) acid turns yellow,
(ii) dilute trioxonitrate (V) acid does not liberate hydrogen when it reacts with magnesium.
(e) Write a chemical equation for the thermal decomposition of (i) Cu(NO\(_3\))\(_{2(g)}\)
(ii) NH\(_4\)NO\(_{3(g)}\)
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
a) Gay Lussac's law states that when gases react, they do so in volumes which simple ratios to one another and to the volumes of the products, if gaseous, provided that the temperature and pressure remain constant.
(b) (i) 2CO\(_{(g)}\) + O\(_{2(g)}\) \(\to\) 2CO\(_{2(g)}\)
(ii) I. from the equation: 2 volumes of CO\(_{(g)}\) and 1 volume of O\(_{2(g)}\) —> 2 volumes of CO\(_2\). ratio of reacting volumes
40cm\(^3\) + 20cm\(^3\) —> 40cm\(^3\)
40cm\(^3\) of CO requires 20cm\(^3\) of oxygen to form 40cm\(^3\) of CO\(_2\).
40cm\(^3\) of CO\(^2\) is produced
II. excess reactant is oxygen Volume is 30cm\(^3\)— 20cm\(^3\) = 10cm\(^3\).
III. total volume of gaseous mixture 10cm\(^3\) of O\(^2\) + 40cm\(^3\) CO\(_2\) = 50cm\(^3\).
(c) (i) SiO\(_2\). (ii) CaO (iii) ZnO (iv) CO (v) CO and NO\(_2\).
(d) (i) Conc. HNO\(_3\). slowly decomposes releasing brown NO, which dissolves in the acid to give the yellow colour.
(ii) HNO\(_3\). is an oxidizing acid. Any hydrogen produced is oxidized to water.
(e) (i) 2Cu(NO\(_3\))\(_2\) \(\to\) 2CuO\(_{(s)}\) + 4NO\(_{2(g)}\) + O\(_{2(g)}\)
(ii) NH\(_4\)NO\(_3{(s)}\) \(\to\) N\(_2\)O(_{(g)}\) + 2H\(_2\)O\(_{(g)}\)
Source: Myschool Past Questions Archive (Record #52127)
English Language
WAEC / WASSCE 2009
Antonyms (Opposite in Meaning)
In each of the following sentences, there is one word underlined and one gap. From the list of words lettered A - D, choose the word that is most nearly opposite in meaning to the underlined word and that will, at the same time, correctly fill the gap in the sentences.
It was a very harmonious meeting, without one.............note
A
divergent
B
adverse
C
discordant
D
strident
medium Difficulty
Verified Correct Answer: Option C
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25836)
English Language
WAEC / WASSCE 2009
Antonyms (Opposite in Meaning)
In each of the following sentences, there is one word underlined and one gap. From the list of words lettered A - D, choose the word that is most nearly opposite in meaning to the underlined word and that will, at the same time, correctly fill the gap in the sentences.
The man was accused of premeditated murder but he pleaded that it was...............
A
determined
B
accidental
C
planned
D
contrived
medium Difficulty
Verified Correct Answer: Option B
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #25837)
English Language
WAEC / WASSCE 2009
Antonyms (Opposite in Meaning)
Solution
In each of the following sentences, there is one word underlined and one gap. From the list of words lettered A - D, choose the word that is most nearly opposite in meaning to the underlined word and that will, at the same time, correctly fill the gap in the sentences.
We nearly lost the trend of his argument because of its complexity but the..............of his language was our saving grace
A
simplicity
B
correctness
C
openness
D
naivety
medium Difficulty
Verified Correct Answer: Option A
Grammar & Contextual Explanation
The underlined word in the sentence is "complexity," which refers to the state of being intricate, complicated, or difficult to understand. The sentence indicates that the complexity of the argument made it challenging to follow. The opposite of complexity is "simplicity." Option A, "simplicity," because it suggests that the straightforward and easy-to-understand nature of the language used in the argument was what made it easier for the audience to comprehend.
Source: Myschool Past Questions Archive (Record #25838)