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Physics
WAEC / WASSCE 2009
Reflection, Refraction & Dispersion of Light
Solution
(a) State two differences between a sound wave and a radio wave.
(b) Explain why a vibrating tuning fork sounds louder when its stem is pressed against a table top than when held in air.
(c)State two conditions necessary for the:
production of stationary wave in a medium;
formation of interference wave patterns;
occurrence of total internal reflection of a wave.
(d) A ray of light is incident on one face of an equilateral glass prism.
Draw a ray diagram to show the path of the ray through the prism.
Calculate the refractive index of the glass if the angle of minimum deviation is 41\(^o\).
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Differences between a sound wave and a radiowave
Sound wave
Radio wave
is a mechanical wave
is an electromagnetic wave
is longitudinal
is transverse
has speed less than speed of light.
has speed equal to that of light
requires a material medium for propagation/cannot travel through vacuum.
does not require a material medium for propagation/can travel through vacuum.
(b) The vibrating tuning fork forces the table top to vibrate. The table top has a much larger area and is therefore in contact with a larger volume of air undergoing vibration. Hence, sound heard is amplified.
(c) Conditions necessary for:
(i) production of stationary wave
- Two waves must be traveling in opposite directions.
- Incident and reflected waves must have the same frequency/wavelength.
- Incident and reflected waves must have equal amplitude.
- There must be superimposition.
- There must be a barrier
(ii) formation of interference wave pattern
- Two sources must be involved.
- The two sources must be coherent/have a constant phase difference as well as the same frequency and amplitude.
- The waves that are interfering must have the same amplitude
- The distance between the sources must be of the order of the wavelengths of the waves.
(iii) total internal reflection
- The wave must be traveling from a denser medium to a less dense medium
- The angle of incidence of the wave in the denser medium must be greater than the critical angle for the medium.
(d)(i) Diagram
Correct diagram
(ii) \(\frac{ Sin (A + dm)}{2}\)
n =
Sin (A/2)
Sin (60 + 41)/2
Sin (60/2)
= 1.54
Source: Myschool Past Questions Archive (Record #53504)
Physics
WAEC / WASSCE 2009
Magnetism, Electromagnetism & AC Circuits
Solution
(a) State two essential differences between a moving coil galvanometer and a d.c. generator.
(b) Explain the term eddy currents and state two devices in which the currents are applied.
(c) State the principle on which the potentiometer is based when it is functioning.
(d) A source of e.m.f. 110 V and frequency 60Hz is connected to a resistor, an inductor and a capacitor in series. When the current in the capacitor is 2A, the potential differences across the resistor is 80 V and that across the inductor is 40 V. Draw the vector diagram of the potential differences across the inductor, the capacitor and the resistor.
Calculate the:
(i) potential difference across the capacitor;
(ii) capacitance of the capacitor;
(iii) inductance of the inductor. [\pi = 3.14]
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
a) Differences between a d. c. generator and a moving coil galvanometer.
D. C. generator
moving coil galvanometer
converts mechanical energy to electrical energy
converts electrical energy to mechanical energy.
uses split rings or commutator
uses hair springs.
rotation of coil is continuous
rotation of coil is incomplete
uses carbon brushes (as terminals)
uses jeweled bearings (as terminals)
(b) Eddy currents are currents induced in a conductor when subjected to varying magnetic field.
Any valid additional information e.g.
eddy current flows in a circular path or closed loops;
eddy current generates heat;
eddy current cannot flow through gaps or slots;
The currents move in such a direction as to oppose the change producing them.
Devices in which eddy currents are applied
pointers of sensitive electric meters
sensitive mass balances
brakes in large electric motors
speedometers in automobiles
detection of cracks in railway tracks
detection of metals
(c) Principle on which a potentiometer is based
When a steady current is allowed to pass through a uniform wire, equal lengths of the wire will have equal potential differences.
OR
The p.d across a length of a wire is (directly) proportional to the length provided the wire has a uniform cross section.
(d)
Vector diagram showing
V\(_L\) with arrow
V\(_C\) with arrow
V\(_R\) with arrow
(i) V\(^2\) = V\(_R^2\) + (V\(_L\) - V\(_C\))\(^2\)
110\(^2\) = 80\(^2\) + (40 – V\(_C\))\(^2\)
(40 – V\(_C\)) = \(\sqrt{(110 + 80) (110 – 80)}\)
40 – V\(_C\) = + 75.5
V\(_C\) = 40 + 75.5
V\(_C\) = 115.5V
(ii) X\(_c\) \(\frac{V_c}{I} = \frac{1}{2 \pi f c}\)
C = \(\frac{1}{2 \pi fV_c}\)
C \(\frac{2}{2 \times 3.14 \times 60 \times 115.5} = 45.9\muF\)
(iii) \(V_L = IX_L = I \times 2 \pi fL}\)
L = \(\frac{V_l}{I \times 1 \times 2 \pifVc}\)
C = \(\frac{2}{2 \times 3.142 \times 60 \times 2}\)
= 0.053H
Source: Myschool Past Questions Archive (Record #53505)
Physics
WAEC / WASSCE 2009
Atomic, Quantum, Nuclear Physics & Electronics
Solution
(a) Briefly explain the following terms:
(i) emission line spectra;
(ii) line absorption spectra.
(b) Draw a labeled diagram showing the structure of a simple type of photocell and explain its mode of operation.
(c) State two
(i) reasons to show that x-rays are waves;
(ii) uses of x-rays other than in medicine.
(d) An electron jumps from an energy level of -1.6eV to one of -1.4 eV in an atom. Calculate the energy and wavelength of the emitted radiation. [ h = 6.6 x 10\(^{-34}\) Js; c = 3.00 x 10\(^8\) ms\(^{-1}\); eV = 1.6 x 10\(^{-19}\) J ]
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)(i) Emission line spectra consist of distinct and separate bright lines of definite wavelengths on a dark background.
Any valid additional information e.g
- They are obtained when light from a luminous source undergoes dispersion and is observed directly.
- When an electron moves from one energy level to another energy level, line spectra are observed
- The colour of the spectra is a characteristic of the source.
(ii) Line absorption spectra are obtained when light passes through a cool gas and certain wavelengths of the light are absorbed. This gives series of dark lines, each corresponding to one of the wavelengths absorbed.
(b) Diagram
When radiation of appropriate frequency falls on the cathode (with photosensitive surface) electrons are emitted. Because the anode is positive with respect to the cathode, the electrons are attracted to the anode. The electrons flow completes the circuit and current flows.
(c)(i) Wave properties of X-rays
- diffraction
- interference
- reflection
- refraction
- polarization
(ii) Uses of X-rays other than in medicine
to study crystal structures
to detect presence of cracks in welded parts
in artistic works for determining the authenticity of such works
at security check points to scan
X-ray spectroscopy for identifying isotopes of elements.
(d)
\DeltaE = E\(_i\) - E\(_f\)
= - 1.6 – (- 10.4)
= 8.8 e V or 1.41 x 10\(^{-18}\) J
E = hf = hc/\lambda
or
\lambda = hc/E
= 6. 6 x 10\(^{-34}\) x 3 x10\(^{8}\)
8.8 x 1.6 x 10\(^{-19}\)
\lambda = 1.4 x 10\(^{-7}\) m
Source: Myschool Past Questions Archive (Record #53508)
Physics
WAEC / WASSCE 2009
Waves, Sound & Vibrations
Solution
Give three observations in support of de Broglie's assumption that moving particles behave like waves
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
- Moving electrons exhibits wavelength/frequency
- electrons show refraction
- electrons show reflection
- electrons show interference
- electrons show diffraction patterns
Source: Myschool Past Questions Archive (Record #53511)
Physics
WAEC / WASSCE 2009
Reflection, Refraction & Dispersion of Light
Solution
State three methods of polirizing an unpolarized light
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Method of polarizing an unpolarized light;
- by reflexion
- by double refraction
- selective absorption by crystals
- polarizing by pile of plates
- passing unpolarised light through a polariod
Source: Myschool Past Questions Archive (Record #53513)
Physics
WAEC / WASSCE 2009
Equilibrium of Forces, Moments & Flotation
Solution
You are provided with two meter rules and other necessary apparatus.
Place one of the rules on a knife edge and determine its centre of gravity C. Mark this pos with a piece of chalk.
Read and record the mass \(M_R\) of the metre rule written on the reverse side of it.
Attach the mass M= 100g firmly to the rule AB at C using sellotape.
Suspend the metre rule by two parallel threads of length h = 40 cm each at the 10 cm marks. Ensure that the graduated face to the metre rule is facing upwards.
Set the rule AB into a small angular oscillation about the vertical axis through its centre of gravity.
Determine the time, t for 20 complete oscillations. Evaluate the period T and T\(^{2}\)
Read and record the value of d in meters.
Keeping d constant throughout the experiment, repeat the procedure for other values of h = 50, 60, 70, and 80 cm. In each case determine the corresponding values of f T and T. Tabulate your reading. (x) Plot a graph of T on the vertical axis and h on the horizontal axis.
Determine the slope S, of the graph. Evaluate k =s, where Q =2 S, Q 250P
State two precautions taken to ensure accurate results.
(b)i. Define the term couple as it relates to rotational or oscillatory systems.
ii. Give two practical application of a couple in everyday life.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Center of gravity C = 49.5cm
Mass of metre rule (MR) = 135g, d = 80cm = 0.8m
h(cm)
d(m)
t(sec)
T=\(\frac{\text{t(sec)}}{20}\)
T\(^{2}\)(Sec\(^{2}\))
40
0.8
28.0
\(\frac{28.0}{20}\)=1.40
1.9600
50
0.8
29.0
\(\frac{29.0}{20}\)=1.45
2.1025
60
0.8
31.0
\(\frac{31.0}{20}\)=1.55
2.4025
70
0.8
34.0
\(\frac{34.0}{20}\)=1.70
2.8900
80
0.8
37.0
\(\frac{37.0}{20}\)=1.85
3.4225
Slope (s) = \(\frac{\bigtriangleup {T}^{2}}{\bigtriangleup {h(cm)}}\) = \(\frac{(3.42-0.40)sec^{2}}{(80-21)cm}\)
= \(\frac{3.02sec^{2}}{59cm}\)
= 0.0512sec\(^{2}\)cm\(^{-1}\)
K = \(\frac{S}{Q}\), Q = \(\frac{2}{25d^{2}}\)
K = \(\frac {\frac{S}{2}}{25d^{2}}\)
S = 0.0512sec\(^{2}\)cm\(^{-1}\), d = 50cm = 0.8cm
K = \(\frac{0.0512sec^{2}cm^{-1} \times 25 \times (0.80)^{2}}{2}\)
K = \(\frac{0.0512 \times 25 \times 0.6400sec^{2}cm^{-1}}{2}\) = 0.4096sec\(^{2}\)cm\(^{-1}\)m\(^{2}\)
Precautions: i
- ensured smooth and regular oscillations in a horizontal plane.
- ensured there was no error due to parallax when reading my stopwatch.
(b)i. Couple -This can be defined as two forces of the same magnitude acting in opposite directions but not on the same line.
ii. Practical application of couple include:
- Opening or closing taps.
- Turning a spanner.
- Setting a flywheel in motion about an axis through its center
- Motion of a spinning spindle.
- Riding/pedaling of bicycle
Source: Myschool Past Questions Archive (Record #60022)
Physics
WAEC / WASSCE 2009
Gas Laws & Heat Transfer
Solution
You are provided with a measuring cylinder, two different tins labeled C and D, a thermometer, and other necessary materials.
Use the measuring cylinder provided to measure 100 cm of water and pour it into the tin label.
Heat the water in the tin almost to boiling (90^\circC).
Remove the tin and place it on a cork or wooden stand.
Insert the thermometer into the tin and record the temperature of the water every minute starting from 85^\circC until the temperature falls to 60^\circC.
Repeat the experiment with the tin labeled D using exactly the same volume of water and temperature range. Tabulate your readings.
On the same graph sheet and using the same axis and scales, plot two graphs of temperature on the vertical axis and time on the horizontal axis from the readings obtained using tins C and D.
Label the graphs appropriately as C and D to correspond with the tins used.
From each graph, read off the time taken to cool from 85^\circC to 65^\circC.
State two precautions taken to ensure accurate results.
(b)i. Explain how heat losses by radiation and convection are minimized in a vacuum flask.
ii. State four factors that affect the rate of evaporation of a liquid in an open container.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Table of value (observation)
S/N
t(min)
Tc(^\circC)
To(^\circC)
1
0.00
85.00
85.00
2
1.00
83.00
84.00
3
2.00
81.00
83.00
4
3.00
79.00
81.00
5
4.00
78.00
79.00
6
5.00
75.00
78.00
7
6.00
73.00
76.00
8
7.00
71.00
75.00
9
8.00
70.00
73.00
10
9.00
68.00
71.00
11
10.00
66.00
69.50
12
11.00
65.00
68.00
13
12.00
63.00
66.00
14
13.00
62.00
64.00
15
14.00
60.00
62.00
16
15.00
-
61.00
17
16.00
-
60.00
Time taken to cool from 85^\circC to 65^\circC
Tin C = 11 minutes
Tin D = 12.40 minutes
Precautions: i
- ensured there was no error due to parallax when reading my thermometer.
- ensured that the liquid in the tins was gently stirred.
(b)i. Silvered wall minimized radiation.
Insulating cork minimized convection.
(i) Factors affecting the rate of evaporation.
- Temperature
- Nature of liquid.
- Humidity
- Area of liquid surface exposed
- Draught
Source: Myschool Past Questions Archive (Record #60026)
Physics
WAEC / WASSCE 2009
Current Electricity & Electric Circuits
Diagram
Solution
1. Connect the circuit as shown in the diagram above. PQ is a potentiometer wire 100 cm long and R is a standard resistor of 5\(\Omega\).
2. With the jockey J not making contact with PQ, close the switch. Read and record the ammeter reading I. Open the switch.
3. Use the jockey to make contact with PQ at the 20cm mark such that PJ = I = 20 cm. Close the switch, read and record the value \(I_i\) of the ammeter. Evaluate I\(^{-1}\).
4. Repeat the procedure for other values of I = 35, 50, 65, and 80 cm. In each case, determine the corresponding values of \(I_i\), and I\(^{-1}\). Tabulate your readings.
Plot a graph of I\(^{i}\) on the vertical axis and \(I_i\), on the horizontal axis, starting both axes from the origin (0, 0).
From your graph deduce the value, of \(I_o\) of \(I_i\), when I\(^{-1}\)= 0.
Evaluate \(I_o\)e
State two precautions taken to ensure accurate results.
(b)) Define the e. m.f. of a battery
ii. A cell X e.m.f. 1.00 V is balanced by a length of 40.0 cm on a potentiometer wire. Another cell Y is balanced by a length of 60.0 cm on the same wire. Calculate the e.m.f. of Y.
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
S/N
L(cm)
Ii(A)
L\(^{-1}\)(cm\(^{-1}\))
1
20
1.00
0.050
2
35
0.90
0.029
3
50
0.85
0.020
4
65
0.80
0.015
5
80
0.75
0.013
When L\(^{-1}\) = 0, Ii = 0.75A
\(I_o\) = 75A
\(\frac{I_{o}}{I}= \frac{0.75A}{0.20A}\) = 37.5
SEE THE GRAPH ABOVE...
Precautions: i
- ensured there was no error due to parallax when reading my ammeter.
- ensured that I removed the key after each reading.
(b)i. E.m.f is the total work done in pushing one coulomb of electricity round an external resistor and the internal resistor of the source, or the total energy obtained per coulomb from a cell or battery
ii. \(\frac{Ey}{Ex} = \frac{Iy}{Ix}\)
Iy = 60cm
Ex = 1.00v
Ix = 40.cm
Ey = ?
\(\frac{Ey}{1.00}=\frac{60}{40}\)
Ey = \(\frac{60 \times 1.00}{40}\) = 1.50.v
Source: Myschool Past Questions Archive (Record #60030)
Chemistry
UTME / JAMB 2009
Electrolysis & Electrochemical Cells
Solution
Cathode rays causes an object placed behind a perforated anode to cast a shadow on the screen. This observation shows that the rays?
A
are positively charged
B
are negatively charged
C
have mass
D
travel in straight lines
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Cathode rays travel in a straight line and can cast sharp shadows.
Cathode rays are negatively charged.
Electric field and magnetic field deflect cathode rays.
Source: Myschool Past Questions Archive (Record #4297)
Chemistry
UTME / JAMB 2009
Stoichiometry, Mole Concept & Volumetric Analysis
If 10.5g of lead (II) trioxonitrate (V) is dissolved in 20cm3 of distilled water at 18oC, the solubility of the solute in mol dm-3 is
[Pb = 207, N = 14, O = 16]
A
1.60
B
5.25
C
16.00
D
525.00
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #4307)
Chemistry
UTME / JAMB 2009
Water, Solutions & Solubility
For a given solute, the concentration of its saturated solution in different solvents are
A
the same at the same temperature
B
different at the same temperature
C
the same at different temperature
D
constant
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #4308)
Chemistry
UTME / JAMB 2009
Non-Metals & Their Compounds
Solution
The major source of oxides of nitrogen is from the burning of
A
coal
B
wood
C
fuel
D
chlrofluorocarbons
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Nitrogen oxides form when fuel is burned at high temperatures
Source: Myschool Past Questions Archive (Record #4309)
Chemistry
UTME / JAMB 2009
Stoichiometry, Mole Concept & Volumetric Analysis
What volume of 1.5M solution of KOH would contain 0.045 moles
A
67.50 cm3
B
30.00 cm3
C
6.75 cm3
D
3.00 cm3
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #4312)
Chemistry
UTME / JAMB 2009
Chemical Energetics & Thermochemistry
The equilibrium of an endothermic reaction which proceeds with an increase in volume can be shifted in the reverse direction by
A
increasing the temperature and decreasing the pressure
B
increasing the pressure and increasing the temperature
C
decreasing the temperature and increasing the pressure
D
decreasing the pressure and decreasing the temperature
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #4326)
Chemistry
UTME / JAMB 2009
Electrolysis & Electrochemical Cells
What current will deposit 3.25g of zinc in 2hrs?
[Zn = 65, F = 96500 mol-]
A
3.25A
B
2.00A
C
1.34A
D
0.67A
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #4320)