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Physics
UTME / JAMB 2011
Magnetism, Electromagnetism & AC Circuits
Solution
In an A.C circuit, the ratio of r.m.s value to peak value of current is
A
2
B
\( \frac{1}{2} \)
C
\( \frac{1}{\sqrt{2}} \)
D
\( \sqrt{2} \)
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Irms = \( \frac{I_0}{\sqrt{2}} \)
\( \text{Therefore } \sqrt{2Irms} = I_0 \\
\frac{Irms}{I_0} = \frac{1}{\sqrt{2}} \)
Source: Myschool Past Questions Archive (Record #41407)
Physics
UTME / JAMB 2011
Current Electricity & Electric Circuits
Solution
Two resistors 5\Omega and 10\Omega are arranged first in series and later in parallel to a 24V source, the ratio of total power dissipated in the series and parallel arrangements respectively is
A
5:3
B
1:50
C
50:1
D
3:5
E
No Correct Option
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
Power in Series Arrangement
Total Resistance (R_series): R\(_{series}\) = R\(_1\) + R\(_2\) = 5\Omega + 10\Omega = 15\Omega
Total Power (P_series): P = \(\frac{V^2}{\text{R}}\) = \(\frac{24^2}{15}\) = 38.4W
Power in parallel Arrangement
Total Resistance(R\(_{parallel}\)): R\(_{parallel}\) = \(\frac{R_1 \times R_2}{R_1 + R_2}\) = \(\frac{5 \times 10}{5 + 10}\) = 3.33
Total Power(P_{parallel}\): P = \(\frac{V^2}{\text{R}}\) = \(\frac{24^2}{3.33}\) = 172.8W
Ratio of Powers
Power ratio = \(\frac{\text{Pseries}}{\text{Pparallel}}\) = \(\frac{38.4}{172.8}\) = \(\frac{1}{4.5}\) = \(\frac{2}{9}\)
Therefore, there is no correct answer.
Source: Myschool Past Questions Archive (Record #41409)
Physics
WAEC / WASSCE 2011
Reflection, Refraction & Dispersion of Light
Solution
Use the diagram above as a guide to carry out the following experiment.
Trace the outline ABCD of the rectangular glass prism on the drawing paper provided.
Remove the prism. Select a point N on AB such that AN is about one-quarter of AB.
Draw the normal LNM. Also, draw a line RN to make an angle \(\theta\) = 75^\circ with AB at N.
Fix two pins at \(P_1\) and \(P_2\) on line RN. Replace the prism on its outline.
Fix two other pins at \(P_3\) and \(P_4\) such that they appear to be in a straight line with the images of the pins at \(P_1\) and \(P_2\) when viewed through the prism from DC.
(vi) Remove the prism and the pins at \(P_3\) and \(P_4\). Draw a line to join \(P_3\) and \(P_4\)
Produce line \(P_4\) \(P_3\) to meet the line DC at O. Draw a line to join NO.
Measure and record the values of MO and NO.
Evaluate \(\theta\) = \(\frac{MO}{NO}\) and cos \(\theta\).
Repeat the procedure for four other values of \(\theta\) = 65^\circ 55^\circ, 45^\circ, and 35^\circ. In each case, evaluate \(\theta\) and cos \(\theta\).
Tabulate your readings.
Plot a graph with cos \(\theta\) on the vertical axis and \(\theta\) on the horizontal axis.
Determine the slope, s, of the graph.
State two precautions taken to ensure accurate results
(b)i. State Snell's law of refraction.
ii. Calculate the critical angle for the glass prism used in the experiment above if its refractive index is 1.5.
A
10.0V
B
8.0V
C
6.7V
D
2.0V
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Observation/table of values
S/N
\(\theta\)(0)
Mo(cm)
No(cm)
\(\theta\)=\(\frac{MO}{NO}\)
Cos \(\theta\)
1
75.0
1.60
6.60
0.100
0.260
2
65.0
3.00
7.00
0.290
0.420
3
55.0
3.10
7.30
0.390
0.570
4
45.0
3.10
7.60
0.480
0.700
5
35.0
4.50
8.00
0.520
0.820
Slope (s) = \(\frac{\bigtriangleup \text {cos} \theta}{\bigtriangleup \theta} = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)
\(\frac{MO}{NO} = \frac{0.77-0.20}{0.50-0.17}\)
\(\frac{0.57}{0.33}\)
Slope (s) = 1.72
Graph cos \(\theta\) against = \(\phi\) = \(\frac{MO}{NO}\)
see the graph above.
PRECAUTIONS; i
- Ensured pins are vertical/ erect.
- Ensured neat traces/sharp pencil (shown on trace)
- Ensured reasonable spacing of pins (about 4cm apart)
- Avoided parallax error in reading protractor/metre rule.
(b)i. Snell's law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant for a given pair of media.
Or \(\frac {\text {Sin i}}{\text {Sin r}}\) = a constant for a given pair of media
Where i = angle of incidence;
r = angle of refraction
ii. n = \(\frac{i}{\text{Sin c}}\)
Sin c = \(\frac{1}{1.5}\) = 0.6667
C = sin\(^{-1}\) 0.6667
C = 41.80^\circ
Source: Official Exam / Past Question Archive
Physics
WAEC / WASSCE 2011
Linear Motion, Projectiles & Kinematics
Solution
A stone projected horizontally from the top of a tower with a speed of 4 ms\(^{-1}\) lands on the level ground at a horizontal distance of 25 m from the foot of the tower. Calculate the height of the tower. = 10 ms\(^{-2}\)]
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
R = U\(\sqrt{\frac{2h}{g}}\)
h = \(\frac{R^2g}{2u^2}\)
= \(\frac{25^2 \times 10}{2 \times 4^2}\)
= 195.3m
Source: Myschool Past Questions Archive (Record #53322)
Physics
WAEC / WASSCE 2011
Current Electricity & Electric Circuits
Solution
(a) Explain diffusion.
(b) Give one reason why the rate of diffusion is higher in gases than in liquids at the same temperature.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Diffusion is a process whereby fluids mix intimately with one another due to random molecular motion.
(b) Diffusion rate in gases is higher than that in liquids at the same temperature because molecular motion in gases are faster, the intermolecular forces is less and the density is also less than those in liquids.
Source: Myschool Past Questions Archive (Record #53323)
Physics
WAEC / WASSCE 2011
Current Electricity & Electric Circuits
Solution
State: (a) the difference between plane polarized light and ordinary light;
(b) two uses of polaroids.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) In plane polarized light the vibrations of light waves are perpendicular in one plane only while in ordinary light the vibrations of the particles are in all planes.
(b) Two uses of polaroids are:
- in sunglass to reduce sunlight intensity
- to eliminate reflected light or glare
- in the measurement of sugar solution concentration or saccharimetry; and
- in photo elasticity or stress analysis.
Source: Myschool Past Questions Archive (Record #53324)
Physics
WAEC / WASSCE 2011
Current Electricity & Electric Circuits
Solution
(a). State: (a) two applications of electrolysis in an industry
(b) one application of electrolysis in a school laboratory.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
a) Industrial application of electrolysis are
- purification of some metals
- electroplating
- production of gases, e.g. Hydrogen from water
- extraction of some metals from their ores, e.g. Aluminium from bauxite.
(b) Applications of electrolysis in school laboratory
- electrolysis of acidified water
- calibration of ammeter.
Source: Myschool Past Questions Archive (Record #53325)
Physics
WAEC / WASSCE 2011
Work, Energy, Power & Simple Machines
Solution
In fig. la and fig.1 b above, Ida and Wb represent the respective loads on a spring placedtiear a 30 cm rule, when in air and when in water:
(a) Identify the force causing a shrink in the spring in fig.(b).
(b) Given that the force constant of the spring is 2.0 x 10\(^{11}\) Nm\(^{-1}\), calculate the work done by the force in causing the shrink.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) The force causing a shrink is the upthrust of the water.
(b) Work done = \(\frac{1}{2}ke^2\)
= \(\frac{1}{2}(2 \times 10^{11}) \times (2 \times 10^{-2})^2\) = 4.0 x 10\(^7\)
Source: Myschool Past Questions Archive (Record #53328)
Physics
WAEC / WASSCE 2011
Elasticity, Density, Pressure & Fluids
Solution
Explain why water in a narrow glass tube has a concave meniscus while mercury, in the same tube, has a convex meniscus.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
In the case of water in axarrow glass tube, the force of adhesion between the water and glass molecules is greater than the cohesive force among water molecule, hence, water clings to the glass tube forming a concave meniscus. In the case of mercury, the cohesive force among its molecules is greater than the adhesive force, between mercury molecules and water molecules hence mercury molecules cling to each other forming a convex meniscus in the capillary glass tube.
Source: Myschool Past Questions Archive (Record #53329)
Physics
WAEC / WASSCE 2011
Reflection, Refraction & Dispersion of Light
Solution
State three methods of polarizing an unpolarized light
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
The methods of polarizing an unpolarized light are:
- reflection from plane, smooth surfaces.
- double refraction through crystals.
- selective absorption
- polaroid.
- Scattering by small particles, etc.
Source: Myschool Past Questions Archive (Record #53330)
Physics
WAEC / WASSCE 2011
Current Electricity & Electric Circuits
Solution
An electron of charge 1.60 x 10\(^{-19}\) C is accelerated under a potential difference of 1.0 x 10\(^5\) V. Calculate the energy of the electron in joules.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
E = eV= 1.6 x 10\(^{-19}\) x 1.0 x 10\(^5\)
=1.6 x 10\(^{-14}\)J
Source: Myschool Past Questions Archive (Record #53331)
Physics
WAEC / WASSCE 2011
Atomic, Quantum, Nuclear Physics & Electronics
Solution
The uncertainty in determining the duration during which an electron remains in a particular energy level before returning to the ground state is 2.0 x 10\(^{-9}\)s. Calculate the uncertainty in determining its energy at that level. (\(\frac{h}{2 \pi}\) = h = 1.054 x 10\(^{-34}\)Js)
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
\(\Delta E \geq \frac{h}{2 \pi} \times \frac{1}{\Delta t}\)
\(\geq 1.054 \times 10^{-37} \times \frac{1}{2 \times 10^{-9}}\)
\(\geq 5.27 \times 10^{-28}\)J
Source: Myschool Past Questions Archive (Record #53333)
Physics
WAEC / WASSCE 2011
Elasticity, Density, Pressure & Fluids
Solution
(a) What is a vector quantity?
(b) Three vectors 3 ms\(^{-1}\) N 45^\circ W, 12 ms\(^{-1}\)W and 5 ms\(^{-1}\)S act at a point.
(i) Sketch a vector diagram to illustrate the given information.
(ii) Calculate the resultant of the vectors.
(c) In a laboratory experiment to determine the force constant of a spiral spring, the mass or, the spring was varied and the corresponding extensions were measured and recorded as shown in the table below.
Mass M/g
Weight W/N
Extension e/cm
50
100
150
200
250
6.5
11.0
15.0
20.0
25.0
(i) Copy and complete the table. (Take g = 10 ms\(^{-2}\))
(ii) Plot a graph with weight, W, on the vertical axis and extension, e, on the horizontal axis.
(iii) Using the graph, determine the force constant of the spring.
(iv) Determine the natural length of the spring if its length was 38.0 cm when loaded with 250 g mass.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Vector quantity is any quantity that has both magnitude and direction, e.g. velocity.
(b)(i)
(ii)
x
y
-3 cos 45 = -2.121
-12.000
0.000
V_x = -14.121
+ 3 sin 45 = 2.121
0000
-5000
V_y = -2.879
R = \(\sqrt{V_x^2 + Vy^2}\)
= \(\sqrt{-14.121^2} + -2.879^2\) = 14.4m/s
Ta n \(\theta = \frac{2.879}{14.121} = 0.2039\)
\(\theta = tan^{-1} 0.2039 = 11.5^o\)
R = 14.4m/s S78.5\(^o\)W
(c)(i)
Mass/g
Weight W/N
Ext.e/cm
50
100
150
200
250
0.5
1.0
1.5
2.0
2.5
6,5
11.0
15.0
20.0
25.0
(iii) Force constant = slope
\(\frac{\Delta W}{\Delta e} = \frac{3.1 - 1.0}{30 - 11} = \frac{2.1}{9} = 0.1105\)
(iv) Nature length = 38.0 - 25 = 13cm
Source: Myschool Past Questions Archive (Record #53338)
Physics
WAEC / WASSCE 2011
Calorimetry, Latent Heat & Change of State
Solution
(a)(i) State two advantages of alcohol over mercury as a thermometric liquid.
(ii) When the bulb of a thermometer is placed in a beaker of hot water, the level of the mercury first falls and then rises gradually. Explain this observation.
(b) List two factors, other than temperature, that affect the rate of evaporation of a liquid.
(b) A block of lead of mass 100 kg in a crucible and at a temperature of 40 ^\circC was placed in an electric furnace rated 10 kW. If the melting point of lead is 320 ^\circC, calculate the:
(i) quantity of heat required to heat the lead to its melting point;
(ii) additional heat energy required to melt the lead;
(iii) time taken to supply this additional energy. (Specific heat capacity of lead = 120 Jkg\(^{-1}\) K\(^{-1}\) (Specific Idtent heat of fusion lead = 2.5 x 10\(^{4} JK^{-1}\))
(d) State two precautions necessary in an experiment to determine the specific latent heat of vaporization of water.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
a)(i) Advantages of alcohol over mercury as a thermometric liquid are:
- Alcohol is cheaper
-Alcohol is easily available
-Alcohol has higher expansivity
- Alcohol has lower freezing point.
(ii) The glass bulb of the thermometer first got heated and expands, therefore the mercury level in it falls. Then the mercury expands and increases more than that of the glass and then rises.
(b) Factors that affect the rate of evaporation of a liquid, temperature exclusively are:
- Pressure, area of liquid surface exposed, humidity, nature of the liquid, wind and dryness of air, etc.
(c)(i) Q = mc
\(\Delta \theta = 100 \times 120 \times (320 - 40)\)
ii) Q = Ml = 100 x 0.25 x 10\(^5)\) = 2500000J
= 2.5MJ
ii) Pt = ml
t = \(\frac{ml}{p} = \frac{2500000}{10000} = 250s\)
(d) Precautions to be considered are:
- Calorimeter should be well lagged.
- Use only dry steam.
- Stir the mixture gently and continually.
- Shield the calorimeter from heat sources.
Source: Myschool Past Questions Archive (Record #53340)
Physics
WAEC / WASSCE 2011
Lenses & Optical Instruments
Solution
(a)(i) What is an eclipse?
(ii) List the three types of eclipse.
(b) A student in a lecture theatre can read from the board clearly but requires a pair of spectacles to read from a book.
(i) What eye defect has this student?
(ii) What type of lens is needed to correct the eye defect?
(iii) The focal length of the lens used to correct this defect is 10cm. Calculate the power of the lens.
(c) A car B moves towards a stationary car A. If B produces an ultrasonic sound at a point and it takes 5.6 x 10\(^{-3}\)s for a beep to be heard in B, calculate the distance between the two cars at that instant. (Speed. sound in air = 340 ms\(^-\))
(d) The image of an object is located 9 cm behind a convex mirror. If magnification produced is 0.6, calculate the focal length of the mirror.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(i) An eclipse is a shadow that results from the obstruction of light from the sun by the moon or the earth.
(ii) Types of eclipse:
-Eclipse of the sun or solar eclipse.
-Annular eclipse
- Eclipse of the moon or lunar eclipse.
(b i) The eye defect is long sight or hypermetropia.
(ii) The type of lens to correct the defect is convex or converging lens.
(iii) Power of lens = \(\frac{1}{f} = \frac{1}{0.1} = dioptre(D)\)
(c) Velocity of an echo = \(\frac{2d}{t}\)
d = \(\frac{vt}{2} = \frac{340 \times 5 \times 10^{-3}}{2} = 0.952 m\)
(d) M = \(\frac{v}{u}\)
U = \(\frac{V}{M} = \frac{9}{0.6} = 15cm\)
\(\frac{1}{f} = \frac{1}{u} + \frac{1}{v} = \frac{1}{15} + \frac{1}{-9}\)
f = -22.5cm
Source: Myschool Past Questions Archive (Record #53343)