Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 9901–9915 of 29821 verified questions
Sort by:
Biology
WAEC / WASSCE 2013
Basic Ecological Concepts, Ecosystems & Biomes
Solution
(a)(i) What is ecological succession?
(ii) Describe the process of ecological succession on a bare plot of land.
(b) Explain the following terms:
(i) biosphere
(ii)population
(iii)community
(iv)ecosystem.
(c) Name one instrument each used for measuring:
(i) relative humidity
(ii) wind speed
medium Difficulty
Verified Correct Answer: Option
Biological Concept & Syllabus Guide
(a)(i) Ecological succession: A gradual and orderly change/replacement; of different species of plant and animal communities, in a given area; over a period of time, until the conditions Of the area became gradually modified by their activities, so that a climax/equilibrium/balanced community is reached/established.
(ii) Process of ecological succession on a bare piece of land: -
The first living organisms on a bare plot of land are the pioneers/algae/mosses
as the pioneers live and die they add nutrients to the soil
this creates conditions that are more suitable/favourable to other plants/ferns/herbs/lower animals/insects/ worms which could not live there before
as they also live and die, their remains improve the soil conditions farther
and so perennial herbs/grasses and other animals/lizards, snakes, toads, rats are able to live there
subsequently a point is reached at which the soil can support the growth of taller / species/shrubs/ trees and higher animals
and higher animals/birds/various mammals may be found at this stage
a climax community is established which is in equilibrium with the environment.
(b)(i) Biosphere: - Parts of the earth/air, water, soil; in which life exists.
(ii) Population: - Total number of organisms; of the same species; which live in a given area; at a given time.
(iii) Community: -A group of different living organisms/ population; living together in a habitat; and interacting with each other.
(iv) Ecosystem: - A natural unit; made up of living organisms and their non-living components; interacting together; to produce a stable system.
(c)(i) Instrument or measuring relative humidity: Hygrometer/wet-dry bulb/paper hygrometer.
(ii) Instrument for measuring wind speed: Anemometer.
Source: Myschool Past Questions Archive (Record #52731)
Biology
WAEC / WASSCE 2013
Population Ecology, Habitats & Conservation
Solution
(a)(i) What is conservation?
(ii) State six factors responsible for the decline of the abundance and variety of wildlife.
(b) Outline six ways in which the government can improve the situation in (a)(ii) above.
(c)(i) What is Eutrophication?
(ii) State two causes of eutrophication.
medium Difficulty
Verified Correct Answer: Option
Biological Concept & Syllabus Guide
(a)(i) Conservation: Planned/wise/judicious use/management of the earth's natural resources; in order to ensure sustenance/availability/continuity; and preservation of the quality of the natural/original nature of the environment.
(ii) Factors responsible for decline of abundance and variety of wildlife:
Commercial hunting which kills off animals indiscriminately
industrialization which involves clearing of forests
for various purposes/construction/farming/urbanization
destruction of habitats of wildlife by human activities
bush burning/noise pollution leads to wildlife migration
environmental pollution which releases dangerous materials that degrades environment making it unbearable for the wildlife
massive/excessive tree felling to make charcoal/domestic uses
lack of awareness/inadequate education of populace on the need for conservation
lack of adequate funding to enforce conservation policy.
(b) Ways by which the Government can improve the situation:
establishment of forestry departments
establishment of Environment Protection Agency to improve the situation
creation of Parks and Games Reserves/any correctly named example; to preserve/maintain plants and animals in their natural environment
conservation education carried out through tree planting! campaigns against bush burning/ tree felling /poaching
conservation laws to regulate tree felling; poaching/hunting of wild animals and bush burning
establishment of zoological gardens preserving endangered species.
(c)(i) Eutrophication: Excessive growth of plant life/algae/algal bloom; in water courses/bodies, caused by an increase in organic nutrients and minerals; leading to the death of aquatic organisms.
(ii) Causes of eutrophication: Overuse of fertilisers/plant nutrients which drain off into water bodies; sewage discharge; was from fish farming.
Source: Myschool Past Questions Archive (Record #52732)
Biology
WAEC / WASSCE 2013
Basic Ecological Concepts, Ecosystems & Biomes
Solution
(a) Describe the carbon cycle.
(b) State the functions of:
(i) nitrogen fixing bacteria
(ii) nitrifying bacteria
(iii) denitrifying bacteria; in nature.
medium Difficulty
Verified Correct Answer: Option
Biological Concept & Syllabus Guide
(a) Description of the carbon cycle: Carbon occurs in the air/atmosphere/as carbon dioxide/dissolved in the oceans/seas/water bodies; and is circulated continuously; through the activity of microorganisms/ decay bacteria/saprophytic organisms/fungi; which decompose the dead organisms; plants/animals release carbon dioxide and water; the carbon dioxide released increases the concentration of carbon in the atmosphere/ocean/sea/water bodies; this is further increased by respiration in plants and animals; combustion of wood/coal/peat/oil/fuel; some of the excess carbon dioxide is absorbed by the sea/water bodies and also used by plants in photosynthesis; organisms in seas/oceans/wafer bodies release carbon dioxide into the atmosphere/water.
(b) Functions of;
(i) Nitrogen-Fixing Bacteria; Nitrogen fixing bacteria in the nodules of legumes; those living freely in soil; convert atmospheric nitrogen; into ammonia/ammonium compounds.
(ii) Nitrifying Bacteria: They live freely in the soil; oxidize/breakdown the ammonium compounds; to nitrites; which are then oxidized by others/Nitrobacter/named bacteria; to nitrates.
(iii) Denitrifying Bacteria: They live freely in the soil; these break down/oxidise ammonium compounds; into nitrogen; and oxygen; which is released into the atmosphere.
Source: Myschool Past Questions Archive (Record #52733)
Biology
WAEC / WASSCE 2013
Excretion & Homeostasis
Solution
(a)(i) What is excretion?
(ii) List the excretory organs in humans and name one waste product excreted by each organ
(B) Name the excretory organs in:
(i) insects
(ii) earthworms.
medium Difficulty
Verified Correct Answer: Option
Biological Concept & Syllabus Guide
(a)(i) Excretion: The elimination of waste products; of metabolism; from the body of an organism.
(ii) Excretory organs in Humans with their waste products.
Excretory Organs in humans Waste Products
Kidney - Nitrogenous wastes/urea/water/salts/urine
Skin - Urea/SaltsNVater/Sweat
Liver - Bile/excess cholesterol
Lungs - CO2/water vapour.
(b) Functioning of kidney as excretory: Blood from the renal artery enters the bowman's capsule; through the afferent arteriole; ultra filtration occurs in the Bowman's capsule; high pressure in the glomerulus causes the filtration of small molecules/amino acids/ glucose/ minerals salts/ water/ urea; out of the blood plasma into the cavity of the capsule; the filtrate/glomerular filtrate passes through the nephron; where selective reabsorption of useful metabolites/glucose/amino acids take place; in the descending/first proximal convoluted/coiled tubule; the reabsorption of salts and water is regulated in the loop of Henle; and the ascending/second/distal convoluted tubule/large waste molecules like creatine secreted at loop of Henle; depending on blood concentration; the filtrate continues into the main collecting duct/tube; where further reabsorption of water and salt takes place; the remaining fluid in the duct becomes urine.
(c) Excretory organs in;
(i) Insects → Malpighian tubules
(ii) Earthworm →Nephridia/Nephridium
Source: Myschool Past Questions Archive (Record #52735)
Biology
WAEC / WASSCE 2013
Variety of Organisms & Classification of Living Things
Solution
Study specimens A, B C and D carefully and use them to answer questions 1(a) to 1(d).
(a)(i) Name tne phylum to which each of specimens A and D belong.
(ii) Name the habitat or each Specimens A and D.
(b)(i) Name the type of reproduction common to specimens A, B, C and D.
(ii) List the method of reproduction of each of specimens A, B,C and D giving one reason each for the method of reproduction listed.
(c) In a tabular form, state three observable differences between specimens B and C.
(d) Make a drawing 8-10 cm long of specimens A to show the essential parts and label fully.
medium Difficulty
Verified Correct Answer: Option
Biological Concept & Syllabus Guide
a)(i) Phylum of specimens A and D
A- cassava/Sugar/Sweet Potato. Tracheophvta/Angiospermatophyta/Angiospemophyta/Spermatophyta
D-Spirogyra-Thallophyta/Chlorophyta.
(ii) Habitat of specimen A and D:Habitat of A=Land/Grassland/Garden. Habitat of D=Stream/ponds/puddles/ditches.
(b)(i) Type common to all specimens: A sexual/vegetative Reproduction
(ii)
Method of Reproduction
Reason
Cassava-Cutting/stem cutting
Presence of buds
Plantain-Sucker
Presence of axillary buds/buds
Runner of grass-runners
Presence of terminal buds on stem/rhizome
Spirogyra-Fragmentation
Cells joined end to end on the filaments
( C) observable differences between specimen B and C (Banana Sucker and Runner of grass)
Specimen B (Banana Sucker)
Specimen C (Runner of Grass)
Erect/vertical stem
Horizontal/creeping stem
Thick/Swollen stem
Slender/thin/narrow stem
Internode not conspicuous
Internode is conspicuous
Source: Myschool Past Questions Archive (Record #60305)
Biology
WAEC / WASSCE 2013
Basic Ecological Concepts, Ecosystems & Biomes
Solution
Study specimens E, F, G1 and G2 carefully and use them to answer questions 2(a) to 2(d).
(a)(i) Name the life process in mammals that is associated with specimens E.
(ii) State two structural similarities between the surface of specimen E and the skin of specimen F.
(b)(i) Name the habitat in which specimen F will function efficiently.
(ii) Explain how two observable features of specimens F adapt the organism to its habitats.
(C)(i) Using the blade provided cut a thin transverse section of the stem of specimens G add two drops of freshly prepared iodine solution to the cut section.
Record your observation and inferences :
(ii) In which part of the stem is food stored.
(iii) Name two tissues used for transportation of materials in specimens G,
(iv) List two supporting tissues present in specimen G,
(d) Make a drawing 10-12 cm long of a cut transverse section of the stem of specimen G, and label fully.
medium Difficulty
Verified Correct Answer: Option
Biological Concept & Syllabus Guide
(a)(i) Life process in mammals associated with specimen F:
-External Respiration/Respiration/ Gaseous exchange/Breathing.
(ii)Similarities between Specimens E and F: - both richly supplied with blood capillaries/vascularised,
-both have thin surface;
both are moist,
both have large surface area.
(b)i)Habitat of specimen F: Land/ terrestrial/Moist place Pond
(ii) Observable features that adapt specimen F to its habitat:
-Streamlined body for ease movement in water,
- Webbed digits of hind limb(s) for swimming
-Presence of poisonous gland for protection against predators
-Muscular long hind limbs for hopping/jumping:
-Stout short forelimbs for absorbing shock on landing.
-large bulging eyes for wide vision.
-Moist skin for gaseous for exchange/breathing/respiration
(c)(i)Observation: cortex stained blue-black, starch present in the cortex.
(ii)Part of stem where food is stored: cortex/parenchyma
(iii) Tissues for transportation in G: Xylem; phloem
(iv) Supporting Tissues in Gi; Collenechyme, scelerenechyme, xylem, parenchyma.
Source: Myschool Past Questions Archive (Record #60306)
Mathematics
WAEC / WASSCE 2012
Indices, Logarithms & Surds
Solution
Simplify; \(\frac{3\sqrt{5} \times 4\sqrt{6}}{2 \sqrt{3} \times 3\sqrt{2}}\)
A
\(\sqrt{2}\)
B
\(\sqrt{5}\)
C
2\(\sqrt{2}\)
D
2\(\sqrt{5}\)
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\(\frac{3\sqrt{5} \times 4\sqrt{6}}{2 \sqrt{3} \times 3\sqrt{2}}\)
= \(\frac{\sqrt{5} \times 2\sqrt{6}}{\sqrt{2} \times \sqrt{3}}\)
= \(\frac{\sqrt{5} \times 2 \sqrt{6}}{\sqrt{6}}\)
= 2\(\sqrt{5}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #36731)
Mathematics
WAEC / WASSCE 2012
Linear, Simultaneous & Quadratic Equations
Solution
(a) (i) Using a scale of 2 cm to 1 unit on both axes, on the same graph sheet, draw the graphs of \(y - \frac{3x}{4} = 3\) and \(y + 2x = 6\).
(ii) From your graph, find the coordinates of the point of intersection of the two graphs.
(iii) Show, on the graph sheet, the region satisfied by the inequality \(y - \frac{3}{4}x \geq 3\).
(b) Given that \(x^{2} + bx + 18\) is factorized as \((x + 2)(x + c)\). Find the values of c and b.
medium Difficulty
Verified Correct Answer: Option
Step-by-Step Mathematical Solution
(a)(i) R is the required region.
(iii) Coordinates of the point of intersection of the two graphs = (1.1, 3.8)
(b) Assuming \(y - \frac{3x}{4} = 3\)
If x = 0, \(y - \frac{3}{4}(0) = 3 \implies y = 3\)
If y = 0, \(0 - \frac{3}{4}x = 3 \implies -3x = 12 ; x = - 4\)
x
0
-4
y
3
0
Assuming \(y + 2x = 6\)
If x = 0, \(y + 2(0) = 6 \implies y = 6\)
If y = 0, \(0 + 2x = 6 \implies 2x = 6 ; x = 3\)
x
0
3
y
6
0
(b) \((x + 2)(x + c) = x^{2} + 2x + cx + 2c\)
\(x^{2} + (2 + c)x + 2c = x^{2} + bx + 18\)
\( 2c = 18 ; c = 9\)
\(b = 2 + c = 2 + 9 = 11\)
(b, c) = (11, 9).
Source: WAEC / JAMB / NECO Classroom Archive (Record #52695)
Physics
WAEC / WASSCE 2012
Current Electricity & Electric Circuits
Solution
A 12\(\Omega\) resistor dissipates 8kJ of heat in 20s. Calculate the current through the resistor
A
5.8A
B
6.9A
C
30.0A
D
33.3A
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Q = I2Rt
I = \(\sqrt{\frac{Q}{Rt}}\)
= \(\sqrt{\frac{8000}{12 \times 20}}\)
= 5.8
Source: WAEC / JAMB / NECO Classroom Archive (Record #35622)
Physics
WAEC / WASSCE 2012
Reflection, Refraction & Dispersion of Light
Solution
An object is placed 10cm from a converging lens of foal length 15cm. Calculate the magnification of the image formed
A
3.0
B
1.5
C
0.6
D
0.3
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Concave/converging mirror:
* produces a virtual image when object distance(u) exceeds its focal length(f).
\(\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\)
\(\frac{1}{v} = \frac{1}{f} - \frac{1}{u}\)
\(\frac{1}{15} - \frac{1}{10} = \frac{2 - 3}{30}\)
\(\frac{1}{v} = \frac{-1}{30}\)
v = -30cm( virtual image)
but m = \(\frac{v}{u} = \frac{30}{10} = 3\)
Note that the negative sign only shows the placement of the image. It does not affect the magnification.
Source: WAEC / JAMB / NECO Classroom Archive (Record #35598)
Chemistry
WAEC / WASSCE 2012
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
Which of the following electron configurations represents that of an atom in its ground state?
A
1s 22s12p1
B
1s22s22p63s13p1
C
1s22s12p3
D
1s22s22p63s0
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
The ground state of an electron, the energy level it normally occupies, is the state of lowest energy for that electron.
Source: WAEC / JAMB / NECO Classroom Archive (Record #37732)
Chemistry
UTME / JAMB 2012
Kinetic Theory of Matter & Gas Laws
Solution
50 cm\(_3\) of gas was collected over water at 10ºC and 765 mm Hg. Calculate the volume of the gas at s.t.p. if the saturated vapour pressure of water at 10ºC is 5mm Hg
A
49.19 cm 3
B
48.87 cm 3
C
48.55 cm 3
D
48.23 cm 3
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
General Gas Equation:
\(\frac{P_1 V_1}{T_1}\) = \(\frac{P_2 V_2}{T_2}\)
where P\(_1\) = 765 - 5 = 760mmhg
\(V_2 = \frac{P_1 V_1 T_2}{P_2 T_1}\)
\(V_2 = \frac{760 * 50 * 273}{ 760 * 283}\) → 48.23cm\(^3\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #27466)
Chemistry
WAEC / WASSCE 2012
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
A spot of oil paint on a shirt can best be removed using?
A
brine
B
detergent
C
kerosine
D
warm water
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
: To remove oil paints, the use of chemicals is usually required, including turpentine, acetone, kerosene, and various paint thinners.
Source: WAEC / JAMB / NECO Classroom Archive (Record #37792)
Mathematics
UTME / JAMB 2012
Number Bases & Modular Arithmetic
Solution
Convert 112\(_6\) to a number in base three
A
2211
B
2121
C
1212
D
1122
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
First, convert to base 10
112\(_6\) = (1 x 6\(^2\)) + (1 x 6\(^1\)) + (2 x 6\(^0\))
= 36 + 6 + 2
= 44\(_{10}\)
\(\begin{array}{c|c} 3 & 44 \\ \hline 3 & 14 & r 2 \\ \hline 3 & 4 & r 2 \\ \hline 3 & 1 & r 1 \\ \hline 3 & 0 & r 1 \end{array}\)
Ans = 1122 = D
Source: Myschool Past Questions Archive (Record #27186)
Mathematics
UTME / JAMB 2012
Plane Geometry, Polygons & Circle Theorems
Solution
Simply \(\frac{2\frac{2}{3} \times 1\frac{1}{2}}{4\frac{4}{5}}\)
A
\(1\frac{1}{4}\)
B
\(1\frac{1}{6}\)
C
\(\frac{5}{6}\)
D
\(\frac{4}{5}\)
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
\(\frac{2\frac{2}{3} \times 1\frac{1}{2}}{4\frac{4}{5}}\)
\(\frac{8}{3} \times \frac{3}{2} \div \frac{24}{5}\)
\(\frac{8}{3} \times \frac{3}{2} \times \frac{5}{24}\)
\(\frac{5}{6}\)
Source: Myschool Past Questions Archive (Record #27189)