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Physics
WAEC / WASSCE 2013
Current Electricity & Electric Circuits
The magnitude of the expansion or contraction of a substance depends on the i. temperature change ii. nature of the substance iii. size of the substance. Which of the statements above are correct?
A
i and ii only
B
ii and iii only
C
i and iii only
D
i, ii and iii
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #35666)
Physics
WAEC / WASSCE 2013
Gas Laws & Heat Transfer
Highly polished silvery surfaces are
A
poor absorbers and poor emitters of radiation
B
poor absorbers and good emitters of radiation
C
good absorbers and poor emitters of radiation
D
good absorbers and good emitters of radiation
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35667)
Physics
WAEC / WASSCE 2013
Current Electricity & Electric Circuits
Solution
The volume of a given mass of gas at 27oC and 800 mmHg is 76cm2. Calculate its volume at s.t.p
A
100.0 cm3
B
72.8 cm3
C
60.0 cm3
D
36.4 cm3
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(V_2 = \frac{P_1V_1T_2}{P_2T_1} = \frac{800 \times 76 \times 273}{760 \times 300}\)
= 72.8cm3
Source: Myschool Past Questions Archive (Record #35668)
Physics
WAEC / WASSCE 2013
Calorimetry, Latent Heat & Change of State
Solution
Ice of mass 10g at 5^\circC was completely converted to water at 0^\circC, calculate the quantity of heat used. [specific heat capacity of ice = 2.1 Jg\(^{-1}\)K\(^{-1}\), specific latent heat of fusion of ice = 336 Jg\(^{-1}\)]
A
105J
B
3255J
C
3465J
D
16821J
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Q = ML + MC\(\theta\)
= 10 x 335 + 10 x 2.1 x 5
= 3465J
Source: Myschool Past Questions Archive (Record #35669)
Physics
WAEC / WASSCE 2013
Current Electricity & Electric Circuits
Solution
An electric heater has a resistance of 50\(\Omega\). When it is immersed in water and connected to mains source, it draws a current of 4.0A. Calculate the heat gained by the water if the heater is switched on for 2 minutes, assuming no heat losses to the surroundings
A
4200J
B
1600J
C
24000J
D
96000J
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Q = \(I^2RT\)
= \(4^2\) x 50 x 2 x 60
= 96000J
Source: Myschool Past Questions Archive (Record #35670)
Physics
WAEC / WASSCE 2013
Current Electricity & Electric Circuits
Solution
When salt is dissolved in water, the freezing point of the water
A
increases
B
decreases
C
remains the same
D
increases and later decrease
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The salt in the water (same for any other impurities) lowers the freezing point of the solution so that water freezes at a lower temperature.
Source: Myschool Past Questions Archive (Record #35671)
Physics
WAEC / WASSCE 2013
Waves, Sound & Vibrations
Solution
The equation of a certain progressive transverse wave is y = 2 sin 2 \(\pi ( \frac{t}{0.01} - \frac{x}{30})\), where x and y are in cm and t in seconds. Calculate the period of the wave.
A
0.001s
B
0.010s
C
10.000s
D
100.000s
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Compare: Y = 2 sin 2 \(\pi (\frac{t}{0.01} - \frac{x}{30})\)
with the wave equation,
y = A sin 2 \(\pi (\frac{t}{T} - \frac{x}{\lambda}\))
⇒ \(\frac{t}{T} = \frac{t}{0.01}\)
T = 0.010s
Source: Myschool Past Questions Archive (Record #35672)
Physics
WAEC / WASSCE 2013
Reflection, Refraction & Dispersion of Light
At which position should an object be placed in front of a concave mirror in order to obtain an image which is of the same size as the object?
A
at the centre of curvature
B
at the principal focus
C
between the pole and principal focus
D
between the centre of curvature and principal focus
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #35673)
Physics
WAEC / WASSCE 2013
Reflection, Refraction & Dispersion of Light
Solution
Images formed by a convex mirror are always
A
magnified
B
behind the mirror
C
real
D
inverted
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Convex mirrors always form virtual images, which appear behind the mirror.
Source: Myschool Past Questions Archive (Record #35674)
Physics
WAEC / WASSCE 2013
Reflection, Refraction & Dispersion of Light
Solution
The refractive index of a material is 1.5. Calculate the critical angle at the glass-air interface
A
19o
B
21o
C
39o
D
42o
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Sin C = \(\frac{1}{\eta} = \frac{1}{1.5} = 0.6667\)
C = sin\(^{-1}\) 0.6667
= 42^\circ
Source: Myschool Past Questions Archive (Record #35675)
Physics
WAEC / WASSCE 2013
Atomic, Quantum, Nuclear Physics & Electronics
Solution
Which of the following radiations has it's frequency lower than that of infrared radiation?
A
Utra-violet rays
B
gamma rays
C
x-rays
D
radio waves
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Radio waves have lower frequencies compared to infrared radiation, while ultraviolet rays, gamma rays, and x-rays have higher frequencies.
Source: Myschool Past Questions Archive (Record #35680)
Physics
WAEC / WASSCE 2013
Waves, Sound & Vibrations
Solution
A string under tension produces a note of frequency 14Hz. Determine the frequency when the tension is quadrupled.
A
14Hz
B
18Hz
C
28Hz
D
56Hz
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
The formula for the frequency in a stringed instrument : \(f = \frac{1}{2} \sqrt{\frac{T}{m}}\)
f = frequency; T = tension in the string; m = mass per unit lenth of the string.
f\(_1\) = 14 = \(\frac{1}{2} \sqrt{\frac{T}{m}}\).
When T is quadrupled, we have
f\(_2\) = new frequency = \(\frac{1}{2} \sqrt{\frac{4T}{m}}\)
= 2(\(\frac{1}{2} \sqrt{\frac{T}{m}}\))
= 2 f\(_1\)
= 2 x 14
= 28 Hz
Source: Myschool Past Questions Archive (Record #35682)
Physics
WAEC / WASSCE 2013
Waves, Sound & Vibrations
Which of the following statements about waves in pipes is correct?
A
for open pipes, there is only one end correction to be accounted for
B
for closed pipes, there are two end corrections to be accounted for
C
only odd harmonics are possible in closed pipes
D
all harmonics are possible in closed pipes
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #35685)
Physics
WAEC / WASSCE 2013
Current Electricity & Electric Circuits
When a person holds a negatively charges metal rod and stands bare-footed on the ground, how will the charges leak?
A
negative charges flows to the ground through the person's body
B
positive charges flow from the ground through his body to neutralize the negative charges
C
positive charges in the air neutralizes the negative charges the person is holding
D
negative charges will leak through the air
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #35686)
Physics
WAEC / WASSCE 2013
Electrostatics & Capacitors
Solution
A charge of 2.0 x 10\(^{-5}\) C experiences a force of 80N in a uniform electric field. Calculate the magnitude of the electric field intensity
A
8.0 x 106 NC-1
B
4.0 x 106 NC-1
C
4.0 x 104 NC-1
D
2.0 x 104 NC-1
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
E = \(\frac{F}{Q} = \frac{80}{2 \times 10^{-5}}\)
= 4 x 10\(^6\) NC\(^{-1}\)
Source: Myschool Past Questions Archive (Record #35691)