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Physics
UTME / JAMB 2013
Current Electricity & Electric Circuits
The bond between silicon and germanium is
A
dative
B
covalent bond
C
trivalent
D
ionic
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Official Exam / Past Question Archive
Physics
WAEC / WASSCE 2013
Work, Energy, Power & Simple Machines
Solution
A body of mass 2kg is released from rest on a plane inclined at an angle of 60^\circ to the horizontal. Calculate the acceleration of the body down the plane.[g = 10ms\(^{-2}\)]
A
3.1ms-2
B
5.2ms-2
C
6.0ms-2
D
8.7ms-2
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
a = g sin \(\theta\)
= 10 sin 60
= 8.7 ms\(^{-2}\)
Source: Myschool Past Questions Archive (Record #35654)
Physics
WAEC / WASSCE 2013
Current Electricity & Electric Circuits
Solution
The total area under a force-velocity graph represents
A
energy
B
momentum
C
power
D
pressure
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Power = Force x Velocity.
Therefore, the area under the force- velocity graph gives Power.
Source: Myschool Past Questions Archive (Record #35656)
Physics
WAEC / WASSCE 2013
Linear Motion, Projectiles & Kinematics
Solution
A body of mass 20g projected vertically upwards in vacuum returns to the point of projection after 1.2s. [g = 10ms\(^{-2}\)]. Calculate the speed of projection
A
1.2ms-1
B
6.0ms-1
C
12.0ms-1
D
0.6ms-1
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
To find the speed of projection, we can use the formula for the time of flight of an object projected vertically upwards:
\(t = \frac{2u}{g}\)
where:
- \( t \) is the total time of flight (1.2 s),
- \( u \) is the initial speed of projection,
- \( g \) is the acceleration due to gravity (10 m/s²).
Rearranging the formula to solve for \( u \):
\(u = \frac{gt}{2}\)
Substituting the values:
\(u = \frac{10 \, \text{m/s}^2 \times 1.2 \, \text{s}}{2} = \frac{12}{2} = 6 \, \text{m/s}\)
Thus, the speed of projection is \( 6 \, \text{m/s} \).
Source: Myschool Past Questions Archive (Record #35658)
Physics
WAEC / WASSCE 2013
Linear Motion, Projectiles & Kinematics
Solution
A body of mass 20g projected vertically upwards in vacuum returns to the point of projection after 1.2s. [g = 10ms-2]. Determine the potential energy of the body at the maximum height of its motion
A
0.36J
B
0.72J
C
360.00J
D
720.00J
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
P.E at max = K.E on projection
= \(\frac{1}{2}\)mv2 = \(\frac{1}{2} \times 0.02 \times 6^2 = 0.36J\)
Source: Myschool Past Questions Archive (Record #35660)
Physics
WAEC / WASSCE 2013
Waves, Sound & Vibrations
The maximum displacement on either side of the equilibrium position of an object in simple harmonic motion represents
A
period
B
amplitude
C
wavelength
D
frequency
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35661)
Physics
WAEC / WASSCE 2013
Elasticity, Density, Pressure & Fluids
Solution
The rising of a liquid in an open and ended glass tube of narrow bore is
A
osmosis
B
adhesion
C
capillarity
D
surface tension
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Capillarity, or capillary action, occurs when a liquid rises in a narrow space due to the adhesive forces between the liquid and the surface of the tube and the cohesive forces within the liquid itself.
Source: Myschool Past Questions Archive (Record #35648)
Physics
WAEC / WASSCE 2013
Work, Energy, Power & Simple Machines
Solution
Which of the following units is equivalent to the watt?
A
kgms-2
B
kgm2s-3
C
kgm2s-2
D
kgm2s-1
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(Power = \frac{\text{Work done}}{time}\)
= \(\frac{Force \times distance}{time}\)
= \(\frac{mass \times acceleration \times distance}{time}\)
= \(\frac{kg \times m \times m}{s^{2} \times s}\)
= \(kgm^{2} s^{-3}\)
Source: Myschool Past Questions Archive (Record #35649)
Physics
WAEC / WASSCE 2013
Current Electricity & Electric Circuits
Solution
Which of the following statements about pressure in a liquid is correct?
A
the pressure in a liquid increases with depth
B
the higher the density of a liquid, the lower the pressure it exerts
C
pressure in liquid act only in a direction perpendicular to the sides of the containing vessel
D
pressure is independent of the acceleration due to gravity
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
At different depths, the pressure of a liquid differs.
Source: Myschool Past Questions Archive (Record #35650)
Physics
WAEC / WASSCE 2013
Elasticity, Density, Pressure & Fluids
Solution
Solid friction, like viscosity is
A
independent of the surface area in contact
B
independent of the relative motion between layers
C
dependent on normal reaction
D
in opposition to motion
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The force acting on a body due to the viscous resistance of the surrounding fluid is called the drag force and it acts in the direction opposite to the direction of motion. So also does friction.
Source: Myschool Past Questions Archive (Record #35651)
Physics
WAEC / WASSCE 2013
Current Electricity & Electric Circuits
The slope of a linear distance-times graph represents
A
acceleration
B
displacement
C
speed
D
velocity
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #35652)
Physics
WAEC / WASSCE 2013
Newton's Laws, Momentum & Collisions
Solution
From Newton's first law of motion,
A
a body can only undergo translational motion
B
once a body remains at rest no force acts on it
C
the net force acting in uniform linear motion is zero
D
a body's inertia is its weight
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
The key point of this law is that if there is no net force resulting from unbalanced forces acting on an object. If all the external forces cancel each other out, then the object will maintain a constant velocity.
Source: Myschool Past Questions Archive (Record #35662)
Physics
WAEC / WASSCE 2013
Elasticity, Density, Pressure & Fluids
Solution
A body of mass 11kg is suspended from a ceiling fan by an aluminum wire of length 2m and diameter 2mm. Calculate the elastic energy stored in the wire [Young's modulus of aluminum is 7.0 x \(10^10Nm^{-2}\), g = 10m\(s^{-2}\), \(\pi\) = 3.142]`
A
1.1 x 10-1J
B
5.5 x 10-2J
C
1.1 x 10-4J
D
5.5 x 10-8J
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
e = \(\frac{4FI}{Y \pi d^2} = \frac{4 \times 11 \times 10 \times 2}{7 \times 10^{10} \times 3.14(2 \times 10^{-3})^2}\)
= 0.001m
E = \(\frac{1}{2} Fe = \frac{1}{2} \times 110 \times 0.001\)
= 5.5 x \(10^{-2}\)J
Source: Myschool Past Questions Archive (Record #35663)
Physics
WAEC / WASSCE 2013
Work, Energy, Power & Simple Machines
Solution
The velocity ratio of an inclined plane
A
increases with increase in the angle of inclination
B
increases with decrease in the angle of inclination
C
decreases with decrease in the angle of inclination
D
is independent of the angle of inclination
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
In general, the V.R and hence the M. A increases when the inclination angle decreases.
Source: Myschool Past Questions Archive (Record #35664)
Physics
WAEC / WASSCE 2013
Temperature, Thermometry & Thermal Expansion
Which of the following types of thermometer is used for the calibration of other thermometers?
A
liqud-in-glass thermometer
B
constant volume gas thermometer
C
optical pyrometer
D
thermocouple
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35665)