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Physics
UTME / JAMB 2014
Current Electricity & Electric Circuits
The small droplets of water that form on the grass in the early hours of the morning is
A
Fog
B
Haul
C
Mist
D
Dew
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #26968)
Physics
UTME / JAMB 2014
Temperature, Thermometry & Thermal Expansion
Solution
What is the equivalent of 20K in Celsius scale?
A
-253oC
B
-293oC
C
68oC
D
36oC
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
= (20 - 273)^\circC
= -253^\circC
Source: Myschool Past Questions Archive (Record #26969)
Physics
UTME / JAMB 2014
Gas Laws & Heat Transfer
Solution
The equation PaVbTc= constant reduces to Charles Law if
A
a=1, b=1and c=0
B
a=1, b=0 and c=-1
C
a=0, b=1 and c=1
D
a=0, b=1 and c=-1
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
if a=0, b=1 and c=-1 then
P0V1T-1 = V/T (Charles Law)
Source: Myschool Past Questions Archive (Record #26970)
Physics
UTME / JAMB 2014
Calorimetry, Latent Heat & Change of State
The quantity of heat needed to raise the temperature of a body by 1K is the body's
A
Heat capacity
B
Internal energy
C
Specific heat capacity
D
Latent heat of fusion
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #26971)
Physics
UTME / JAMB 2014
Calorimetry, Latent Heat & Change of State
The melting point of a substance is equivalent to its
A
Vapour Pressure
B
Solidification Temperature
C
Liquidification Temperature
D
Solidification Pressures
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #26972)
Physics
UTME / JAMB 2014
Calorimetry, Latent Heat & Change of State
Solution
The temperature at which the water vapour present in the air is just sufficient to saturate air is
A
Boiling point
B
Ice point
C
Saturation point
D
Dew point
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The dew point is defined as the temperature to which air must be cooled (at constant pressure and without adding or removing moisture) for the water vapor present in it to become just sufficient to saturate the air, meaning the relative humidity reaches 100%, and condensation (like dew) begins if cooled further
Source: Myschool Past Questions Archive (Record #26973)
Physics
UTME / JAMB 2014
Gas Laws & Heat Transfer
Solution
Heat transfer by convection in a liquid is due to the
A
Latent heat of vaporization of the liquid
B
Increased vibration of the molecules of the liquid about theit mean position
C
Variation of density of the liquid
D
Expansion of the liquid as it is heated
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Liquids and gases expand when they are heated. The liquid or gas in hot areas is less dense than the liquid or gas in cold areas, so it rises into the cold areas.
Source: Myschool Past Questions Archive (Record #26974)
Physics
UTME / JAMB 2014
Waves, Sound & Vibrations
Solution
The distance between two successive crests of a wave is 15cm and the velocity 300ms-1. Calculate the frequency.
A
2.0x102Hz
B
4.5x103Hz
C
2.0x103Hz
D
4.5x102Hz
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Wavelength = 15cm = 0.15m
Velocity = 300m/s
V = fx
F = V/Wavelength
F = 300/0.15 Hertz
F = 2 x 103Hz
Source: Myschool Past Questions Archive (Record #26975)
Physics
UTME / JAMB 2014
Waves, Sound & Vibrations
Solution
A boy receives the echo of his clap reflected by a nearby hill 0.8s later. How far is he from the hill? [ speed of sound in air = \(340ms^{-1}\)
A
528m
B
66m
C
136m
D
264m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Time for echo both ways = 0.8
Therefore time for echo in 1 way = 0.8/2 = 0.4
Distance = Speed x time
Distance = 340 x 0.4
Distance = 136m
Source: Myschool Past Questions Archive (Record #26976)
Physics
UTME / JAMB 2014
Lenses & Optical Instruments
Solution
An object is placed 10m from a pinhole camera of length 25cm. Calculate the linear magnification.
A
2.5x102
B
2.5x10-2
C
2.5x10-1
D
2.5x101
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(\text{Linear Magnification} = \frac{\text{Length of Camera}}{\text{Distance of the Object}}\)
\(\text{Linear Magnification} = \frac{25}{1000}\)
\(\text{Linear Magnification} = 2.5 \times 10^{-2}\)
Source: Myschool Past Questions Archive (Record #26977)
Physics
UTME / JAMB 2014
Reflection, Refraction & Dispersion of Light
Solution
The focal length of a concave mirror is 2.0cm. If an object is placed 8.0cm from it, the image is at
A
2.7m
B
2.0m
C
2.3m
D
2.5m
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
\(\frac{1}{U} + \frac{1}{V} = \frac{1}{f}\)
\(\frac{1}{8} + \frac{1}{V} = \frac{1}{2}\)
\(V = \frac{8}{3}\)
\(V = 2.7cm\)
Source: Myschool Past Questions Archive (Record #26978)
Physics
UTME / JAMB 2014
Lenses & Optical Instruments
In a compound microscope, the objective and the eye piece focal lengths are
A
At infinity
B
Long
C
Short
D
The same
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #26979)
Physics
UTME / JAMB 2014
Reflection, Refraction & Dispersion of Light
When a telescope is in normal use, the final image is at
A
Infinity
B
The focus
C
The radius of curvature
D
The near point
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #26980)
Physics
UTME / JAMB 2014
Electrostatics & Capacitors
Solution
When a negatively charged rod is brought near the cap of a charged gold leaf electroscope which has positive charges, the leaf
A
Remains the same
B
Collapses
C
Collapses and diverges again
D
Diverges
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
When a negatively charged rod is brought near the cap of a charged gold leaf electroscope which has positive charges, the leaf collapses.
Source: Myschool Past Questions Archive (Record #26981)
Physics
UTME / JAMB 2014
Electrostatics & Capacitors
Solution
What charge is stored in a 0.1F capacitor when a 10V supply is connected across it?
A
1C
B
5C
C
4C
D
2C
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Q = CV = 0.1 x 10 = 1C
Source: Myschool Past Questions Archive (Record #26982)