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Physics
WAEC / WASSCE 2015
Electrostatics & Capacitors
Which of the following statements is correct? When capacitors of different values are connected in series
A
the same charge flows through them
B
the same voltage appears across each capacitor
C
different quantities of charges flow through them in different voltages across them
D
different quantities of charges flows through them with the same voltage across them
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #45547)
Physics
WAEC / WASSCE 2015
Current Electricity & Electric Circuits
Which of the following statements about a three-pin plug is/are correct. i. The brown wire is the live wire. ii. The fuse is connected to the live wire. iii. The earth wire is coloured blue
A
i only
B
ii only
C
i and ii only
D
i, ii and iii
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #45548)
Physics
WAEC / WASSCE 2015
Current Electricity & Electric Circuits
Solution
A wire of cross-sectional area 0.60mm2 has a restivity of 7.2 x 10-7 \(\Omega\). Calculate the length of wire that will have a resistance of 3\(\Omega\).
A
0.25m
B
2.50m
C
3.60m
D
36.00
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
R = \(\frac{PL}{A}\)
C = \(\frac{RA}{P}\)
C = \(\frac{0.60 \times 10^{-6} \times 3}{7.2 \times 10^{-7}}\)
C = 2.50m
Source: Myschool Past Questions Archive (Record #45553)
Physics
WAEC / WASSCE 2015
Atomic, Quantum, Nuclear Physics & Electronics
Solution
in a nuclear fission process, the mass defect was 1.2 x 10-5kg. Calculate the energy released. [speed of the light in vacuum = c = 3.0 x 108ms-1]
A
1.08 x 1011J
B
5.20 x 1011J
C
1.08 x 1012J
D
2.50 x 1013J
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
E - Mec2
E = 1.2 x 10-5 x (3 x 108)2
E = 1.08 x 1012J
Source: Myschool Past Questions Archive (Record #45567)
Physics
WAEC / WASSCE 2015
Atomic, Quantum, Nuclear Physics & Electronics
Which of the following statements about diode is correct?
A
reverse bias diodes have low resistance
B
forward bias diodes have high resistance
C
forward bias diodes produce high current
D
forward bias diodes function as a result of heat
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #45569)
Physics
WAEC / WASSCE 2015
Atomic, Quantum, Nuclear Physics & Electronics
Which of the following radiations constitutes a stream of electrons?
A
Ramma rays
B
X-rays
C
Cathode rays
D
Radio waves
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #45570)
Physics
WAEC / WASSCE 2015
Atomic, Quantum, Nuclear Physics & Electronics
\(^{226}_{88}Ra\) emits two alpha particles to produce polonium(po) nuclide. The correct formula for the nuclide?
A
\(^{224}_{86}po\)
B
\(^{222}_{86}po\)
C
\(^{222}_{84}po\)
D
\(^{218}_{84}po\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #45572)
Physics
WAEC / WASSCE 2015
Current Electricity & Electric Circuits
Diagram
Solution
A battery of emf 24V is connected to three resistor P, Q and R as illustrated in the given diagram. Determine the voltage across the resistor Q.
Attached Figure / Diagram
A
5V
B
10V
C
14V
D
24V
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
E - V1 + V2
24V = 14V + VQP
VQP = 24 + 14V
VQP = 10V
Source: Myschool Past Questions Archive (Record #45557)
Physics
WAEC / WASSCE 2015
Current Electricity & Electric Circuits
Solution
The mass of the earth is 6.0 x 1024kg and that of the moon is 7.0 x 1022kg. If the distance between them is 4.0 x 108m, calculate the force of attraction between them. [G = 6.7 x 10-11Nm2kg-2]
A
1.8 x 105N
B
1.8 x 1010N
C
1.8 x 1015N
D
1.8 x 1020N
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
F = \(\frac{GM_1M_2}{12^2}\)
F = 6.7 x 10-11x
F = \(\frac{M_1M_2}{R^2}\)
F = \(\frac{6.7 \times 10^{-11} \times 6.0 \times 10^{24} \times 7.0 \times 10^{22}}{(4 \times 10^8)^2}\)
= 1.8 x 1020N
Source: Myschool Past Questions Archive (Record #45558)
Physics
WAEC / WASSCE 2015
Magnetism, Electromagnetism & AC Circuits
The angle which the direction of the earth magnetic field makes with the horizontal at a palace is know as.
A
angle of contact
B
angle of dip
C
angle of declination
D
magnetic meridian
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #45560)
Physics
WAEC / WASSCE 2015
Current Electricity & Electric Circuits
Diagram
What must be connected between the points P and Q to establish a steady current through the incomplete circuit diagram given?
Attached Figure / Diagram
A
Fuse
B
ammeter
C
Cell
D
voltmeter
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #45563)
Physics
WAEC / WASSCE 2015
Magnetism, Electromagnetism & AC Circuits
When current flows through a moving-coil galvanometer, the force exerted on the pointer depends on the: i. strength of the current. ii. magnetic field strength. iii. length of the coil. Which of the statement(s) above is/are correct?
A
i only
B
ii only
C
i and iii only
D
i, ii and iii
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #45565)
Physics
WAEC / WASSCE 2015
Current Electricity & Electric Circuits
Solution
Two angles of a pentagon are in the ratio 2:3. The others are 60o each. Calculate the smaller of the two angles
A
72o
B
100o
C
120o
D
144o
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The diagram given simple illustrates that a pentagon contains three \(\Delta\)s.
Two angles which are in the ratio 2:3 will have actual values 2xo, 3xo respectively. Thus 2xo + 3xo + 3 x 60 = 3x sum of angles of \(\Delta\)a
i.e. 5xo + 180o = 3 x 180o
5xo + 180o = 540o
5xo = 540o - 180o
5xo = 360o
xo = \(\frac{360^o}{5}\)
= 72o
Hence, the smaller of the two angles is
2 x 72o = 144o
Source: Myschool Past Questions Archive (Record #45995)
Physics
WAEC / WASSCE 2015
Linear Motion, Projectiles & Kinematics
Solution
(a) What is a projectile?
(b) Give the reason why the horizontal component of the velocity of a projectile remains the same at every point of its flight.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Projectile is an object thrown into the air, and left to move under the influence of gravity.
(b) the acceleration of free fall due to gravity does not act in the horizontal direction.
Source: Myschool Past Questions Archive (Record #52979)
Physics
WAEC / WASSCE 2015
Elasticity, Density, Pressure & Fluids
Solution
A wire of length 2.00 m and radius 1.0 mm is stretched by 25.0 mm on the application of a force of \(10^3\) N. Calculate Young's modulus for the wire.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Given:
L = 2m r = 1mm = 1 x \(10^{-3}\)m. e = 25mm = 25 x \(10^{-3}\)m
F = 1000N
Young modulus, E = \(\frac{F \times l}{A \times e}\)
Area, A = \pir^2 = \(3.142 x (10^{-3})^2\) = \(3.142x10^{-6}\)
E = \(\frac{1000 \times 2}{3.142 \times 10^{-6} \times 25 \times 10^{-3}}\)
E = \(2.55 x 10^{10} NM^{-2}\)
Source: Myschool Past Questions Archive (Record #52981)