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Physics
WAEC / WASSCE 2015
Calorimetry, Latent Heat & Change of State
Diagram
In an experiment in which a molten substance is allowed to cool, the cooling curve above was obtained. The temperature 60oC is known as the
Attached Figure / Diagram
A
vaporization point
B
cooling temperature
C
boiling point
D
melting point
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #45456)
Physics
WAEC / WASSCE 2015
Calorimetry, Latent Heat & Change of State
Which of the following concepts is a method of heat transfer that does not require a material medium?
A
conduction
B
radiation
C
diffusion
D
convection
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #45457)
Physics
WAEC / WASSCE 2015
Calorimetry, Latent Heat & Change of State
Solution
Which of the following units is the S.I. unit of heat capacity?
A
Jkg-1
B
Jkg-1 K-1
C
JK-1
D
Jg-1K-1
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Heat capacity = \(\frac{\text{Heat energy supplied}}{\text{Rise in temperature}}\)
= JK\(^{-1}\)
Source: Myschool Past Questions Archive (Record #45458)
Physics
WAEC / WASSCE 2015
Elasticity, Density, Pressure & Fluids
The pressure applied to an enclosed fluid to one end id transmitted equally throughout the fluid and to the container walls. This statement is
A
Archimede's principle
B
Bernoulli's principle
C
Pascal's principle Heisenberg's
D
Heisenberg's uncertainty principle
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #45461)
Physics
WAEC / WASSCE 2015
Waves, Sound & Vibrations
Diagram
Solution
The diagram given illustrates a wave form. Determine the speed of the wave
Attached Figure / Diagram
A
5.4 ms-1
B
8.4 ms-1
C
9.6 ms-1
D
10.0 ms-1
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The diagram illustrates three complete cycles over a distance of 9 m. Therefore, the wavelength \lambda is 9 m / 3 = 3 m.
The time t = 0.6 s corresponds to two periods (based on the labeling in the diagram spanning two cycles). Therefore, the period T is \(\frac{0.6 s }{2}\) = 0.3 s.
The speed of the wave v is given by v = \(\frac{\lambda }{\text{T}}\) = \(\frac{3 m }{0.3 s}\) = 10 m/s.
Source: Myschool Past Questions Archive (Record #45466)
Physics
WAEC / WASSCE 2015
Elasticity, Density, Pressure & Fluids
Solution
Water is unsuitable for use as a thermometric liquid because it
A
expands unevenly between 0oC and 40oC
B
has narrow temperature range
C
has a concave meniscus
D
maintains a fixed density
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Water's freezing point is 0^\circC and its boiling point is 100^\circC at standard atmospheric pressure, which provides a limited temperature range for measurement compared to other liquids used in thermometers. Other liquids like mercury can measure a wider range of temperatures.
Source: Myschool Past Questions Archive (Record #45446)
Physics
WAEC / WASSCE 2015
Work, Energy, Power & Simple Machines
Diagram
Solution
The diagram above illustrates a block ans tackle pulley system in which an effort E supports a load of 100.0N. If the efficiency of the machine is 75%, calculate the value of E
Attached Figure / Diagram
A
22.2N
B
38.0N
C
67.0N
D
75.0N
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Given; VR = 6, e = 75%, MA = ?
e = \(\frac{\text{MA}}{\text{VR}} \times \frac{100}{1}\)
MA =\(\frac{75 \times 6}{10}\)
MA = \(\frac{9}{2}\)
MA = \(\frac{L}{E} = \frac{100}{E}\)
\(\frac{9}{2} = \frac{100}{E}\)
9E = 100
E = \(\frac{200}{9}\)
= 22.2N
Source: Myschool Past Questions Archive (Record #45449)
Physics
WAEC / WASSCE 2015
Calorimetry, Latent Heat & Change of State
Solution
A quantity of hot water at 100oC is added to 400g of water at 10oC until the temperature of the mixture is 60oC.
Calculate the mass of the hot water added. [Specific heat capacity of water =4200JKg-1 K-1]
A
200g
B
320g
C
400g
D
500g
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Heat lost by hot water = Heat gained by cold water
M x 4200 x (100 - 60 = 0.4 x 4200 x (60 - 10)
4200m x 40 = 0.4 x 4200 x 50
40m = 0.4 x 50
m = \(\frac{0.4 \times 50}{40}\) = 0.5kg
= 500g
Source: Myschool Past Questions Archive (Record #45450)
Physics
WAEC / WASSCE 2015
Current Electricity & Electric Circuits
Diagram
Solution
A battery of emf 24V is connected to three resistor P, Q and R as illustrated in the diagram. Determine the voltage across the resistor Q
Attached Figure / Diagram
A
5v
B
10v
C
14v
D
24v
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
E - V1 + V2
24V = 14V + VQP
VQP = 4 + 14V
VQP =10V
Source: Myschool Past Questions Archive (Record #45452)
Physics
WAEC / WASSCE 2015
Reflection, Refraction & Dispersion of Light
Red light travels faster than blue light when both of them pass through a glass prism because the
A
refractive index of red light is grester than that of blue light
B
refractive index of blue light is greater than that of red light
C
red light is more intense than the blue light
D
blue light is more intense than the red light
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #45516)
Physics
WAEC / WASSCE 2015
Lenses & Optical Instruments
Solution
An object is placed 20cm from a concave mirror of focal length 15cm. Calculate the linear magnification of the image formed
A
0.5
B
1.5
C
2.0
D
3.0
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
\(\frac{1}{U} + \frac{1}{V} = \frac{1}{F}\)
\(\frac{1}{V} = \frac{1}{F} - \frac{1}{U}\)
\(\frac{1}{V} = \frac{1}{15} - \frac{1}{20}\)
\(\frac{1}{V} = \frac{\text{4 - 3}}{60}\)
\(\frac{1}{V} = \frac{1}{60}\)
V = 60cm
M = \(\frac{V}{U} = \frac{60}{20}\)
M = 3.0cm
Source: Myschool Past Questions Archive (Record #45523)
Physics
WAEC / WASSCE 2015
Waves, Sound & Vibrations
All electromagnetic waves in a vacuum have the same
A
wavelength
B
frequency
C
speed
D
amplitude
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #45526)
Physics
WAEC / WASSCE 2015
Electrostatics & Capacitors
Diagram
The diagram given illustrates two charged particles W and X. The charges on W and x are respectively
Attached Figure / Diagram
A
negative; negative
B
negative; positive
C
positive; positive
D
positive; negative
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #45531)
Physics
WAEC / WASSCE 2015
Current Electricity & Electric Circuits
Solution
An alternating current supply is connected to an electric lamp which lights with the same brightness as it does with direct current source emf 6v. The peak potential difference of the a.c supply is
A
4.6v
B
6.0v
C
8.5v
D
12.0v
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Vo = V\(\_{rms}\) x \(\sqrt{2}\)
Vo = 6 x 1.414
Vo = 8.484
= 8.5v
Source: Myschool Past Questions Archive (Record #45536)
Physics
WAEC / WASSCE 2015
Magnetism, Electromagnetism & AC Circuits
Solution
An electric generator rated 12 kW, 2 kV distribute power through a cable of resistance 20\(\Omega\). Calculate the power loss in the cable.
A
120 w
B
360 w
C
720 w
D
2400 w
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Power - IV
I = \(\frac{P}{V}\)
= \(\frac{12000}{2000}\)
I = 6A
Power loss = I\(^2\)R = 6\(^2\) x 20
= 720 W
Source: Myschool Past Questions Archive (Record #45546)