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Physics
WAEC / WASSCE 2015
Scalars, Vectors & Relative Motion
The resultant force in a couple is
A
zero
B
infinite
C
the sum of the forces
D
thr product of the forces
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #45420)
Physics
WAEC / WASSCE 2015
Linear Motion, Projectiles & Kinematics
The slope of a straight-line velocity-time graph represents
A
uniform acceleration
B
uniform speed
C
total distance travelled
D
workdone
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #45421)
Physics
WAEC / WASSCE 2015
Linear Motion, Projectiles & Kinematics
A body is projected with an initial velocity U at an angle O to the horizontal. The time taken by it to reach its maximum height is given by the expression
A
\(\frac{2u \text{sin}\theta}{g}\)
B
\(\frac{u^2 \text{sin}^2\theta}{2g}\)
C
\(\frac{u \text{sin}\theta}{g}\)
D
\(\frac{u \text{sin}\theta}{2g}\)
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #45422)
Physics
WAEC / WASSCE 2015
Equilibrium of Forces, Moments & Flotation
Which of the following statements describes a body in a stable equilibrium correctly?
A
a person walking on a tight-rope
B
ball on a smooth horizontal table
C
ball resting on an inverted hemisphere bowl
D
ball in the middle of a nemispherical bowl
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #45425)
Physics
WAEC / WASSCE 2015
Current Electricity & Electric Circuits
Solution
In a school compound a girl walks 40m due east from the laboratory to the staff room to submit her report. Then she returns and walks 30m due north to her classroom. Determine the magnitude of her displacement from the10m laboratory
A
10m
B
35m
C
50m
D
70m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
East (\(x\)): 40 m, North (\(y\)): 30 m
displacement: \(\sqrt{40^{2}+30^{2}}\)
= \(\sqrt{1600 + 900} = \sqrt{2500} = 50\)m.
Source: Myschool Past Questions Archive (Record #45427)
Physics
WAEC / WASSCE 2015
Current Electricity & Electric Circuits
Two strings each inclined at an angle 30o to the horizontal are used to hold a bucket of water weighing 20N. Calculate the tension i n each string.
A
20 (\sqrt{3}\)N
B
20N
C
10 (\sqrt{3}\)N
D
10N
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #45438)
Physics
WAEC / WASSCE 2015
Current Electricity & Electric Circuits
Solution
A bullet fired vertically upwards reaches a height of 500m. Neglecting air resistance, calculate the magnitude of the initial velocity of the bullet. [g = 10ms-2]
A
500.0ms-1
B
100.0ms-1
C
70.0ms-1
D
50.0ms-1
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
V2 = U2 + 2gs
V2 = 0
V2 = 2gs
h = 500m
g = 10ms-2
V2 2 x 10 x 500
V2 = 10,000
V = \(\sqrt{10000}\)
V = 100ms-1
Source: Myschool Past Questions Archive (Record #45442)
Physics
WAEC / WASSCE 2015
Equilibrium of Forces, Moments & Flotation
Solution
A uniform bar AB is balanced on a knife-edge which is 60cm from B by a mass of 22g which hangs at C 10cm from A. Calculate the mass of the bar.
A
133.2g
B
66.0g
C
60.0g
D
22.0g
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
clockwise movement = anticlockwise movement
w x 10 = 22 x 30
w = \(\frac{22 \times 30}{10}\)
w = 66.0g
Source: Myschool Past Questions Archive (Record #45443)
Physics
WAEC / WASSCE 2015
Work, Energy, Power & Simple Machines
Solution
A body of mass 1000kg is released from a height of 10m above the ground. Determine its kinetic energy just before it strikes the ground .[g = 10ms-2]
A
10J
B
103J
C
104J
D
105J
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Ke = mgh
Ke = Pe
\(\frac{1}{2}\)MV2 = mgh
Ke = 1000 x 10 x 10
Ke = 100000J
Ke = 105J
Source: Myschool Past Questions Archive (Record #45444)
Physics
WAEC / WASSCE 2015
Gas Laws & Heat Transfer
The crackling noise produced by aluminum roofing sheets on a house during a hot sunny day is a result of
A
thermal equilibrium of the sheets
B
conduction of heat by the sheets
C
contraction of the sheets
D
expansion of the sheets
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #45445)
Physics
WAEC / WASSCE 2015
Atomic, Quantum, Nuclear Physics & Electronics
What type of wave is emitted by a loud speaker?
A
Transverse
B
Longitudinal
C
Gamma
D
Radio
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #45467)
Physics
WAEC / WASSCE 2015
Lenses & Optical Instruments
Solution
An object is placed 15cm from a diverging lens of focal length 12cm. The image of the object formed by the lens in
A
real and 6.67cm from the lens
B
virtual and 6.67cm from the lens
C
real and 60.00cm from the lens
D
virtual and 60.00cm from the lens
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The focal length of a diverging lens is negative.
f = -12 cm; u = 15 cm.
\(f = \frac{uv}{u + v}\)
\(-12 = \frac{15v}{15 + v}\)
\(-12 (15 + v) = 15v \implies -180 - 12v = 15v\)
\(-180 = 15v + 12v \implies -180 = 27v\)
\(v = \frac{-180}{27} = -6.67 cm\)
The image is virtual and 6.67 cm from the lens.
Source: Myschool Past Questions Archive (Record #45468)
Physics
WAEC / WASSCE 2015
Reflection, Refraction & Dispersion of Light
Solution
A swimming pool is 2.1m deep. If it contains water of refractive index 1.3, calculate the apparent depth of pool
A
3.4m
B
2.7m
C
1.6m
D
0.8m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
n = \(\frac{\text{real depth}}{\text{apparent depth}}\)
1.3 = \(\frac{2.1}{\text{apparent}}\)
A.D = \(\frac{2.1}{1.3} = 1.6\)
Source: Myschool Past Questions Archive (Record #45472)
Physics
WAEC / WASSCE 2015
Waves, Sound & Vibrations
When an air column is set into vibrations, the distance between two consecutive nodes of the resultant wave is
A
one quarter of the wavelength
B
half of the wavelength
C
the wavelength
D
twice the wavelength
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #45489)
Physics
WAEC / WASSCE 2015
Waves, Sound & Vibrations
Solution
A girl standing some distance from the cliff claps her hands and hears the echo 0.8s later. calculate her distance from the cliff. [speed of sound in air = 320 ms-1]
A
23m
B
128m
C
288m
D
298m
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
V = \(\frac{2nx}{E}\)
= \(\frac{2 \times 1 \times X}{0.8} = 320\)
2x = 0.8 x 320
x = \(\frac{0.8 \times 320}{2}\)
= 128m
Source: Myschool Past Questions Archive (Record #45503)