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Chemistry
UTME / JAMB 2017
Oxidation, Reduction & Redox Reactions
Solution
Cu\(_2\)S(g) + O\(_2\)(g) → 2Cu + SO\(_2\)(g)
What is the change in the oxidation number of copper in the reaction?
A
0 to + 2
B
0 to + 1
C
+ 1 to 0
D
+ 2 to + 1
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
In the reactant;
Cu\(_2\)S
2 Cu - 2(1) = 0
2 Cu = 2
Cu = \(\frac{2}{2}\)
Cu = +1
In the product, Cu
Cu = O (Oxidation state of an element in its free state is 0)
The oxidation number of Cu in Cu\(_2\)S and Cu respectively is +1 and 0 respectively
Source: Myschool Past Questions Archive (Record #46541)
Chemistry
UTME / JAMB 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Diagram
Solution
In the diagram above. X is
Attached Figure / Diagram
A
SO3
B
SO2
C
S
D
H2S
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
The setup represents the production of sulfur dioxide. And the cylinder marked X is SO2
Source: Myschool Past Questions Archive (Record #46542)
Chemistry
UTME / JAMB 2017
Non-Metals & Their Compounds
Diagram
Solution
The diagram above. Y is
Attached Figure / Diagram
A
fused CaO
B
H2O
C
NaOH
D
Concentrated H2SO4
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
In the preparation of sulphur dioxide by the action of dilute acids on sulphates and bisulphites. conc H2SO4 helps to release SO2 from the mixture.
The setup represents the production of sulphur dioxide
Source: Myschool Past Questions Archive (Record #46543)
Chemistry
UTME / JAMB 2017
Electrolysis & Electrochemical Cells
Solution
Calculate the mass of copper deposited when a current of 0.5 ampere was passed through a solution of copper(II) chloride for 45 minutes in an electrolytic cell. [Cu = 64, F = 96500Cmol-1]
A
0.300g
B
0.250g
C
0.2242g
D
0.448g
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
M = \(\frac{\text{Molar mass × Quantity of Electricity}}{\text{96500 × no of charge}}\)
= \(\frac{MmIT}{96500n}\)
Copper II Chloride = CuCl2
CuCl2 → Cu2+ + 2Cl2
Mass of compound deposited = \(\frac{\text{Molar mass × Quantity of Electricity}}{\text{96500 × no of charge}}\)
Q = IT
I = 0.5A
T = 45 × 60
T = 2700s
Q = 0.5 × 2700
= 1350c
Molarmass = 64gmol-1
no of charge = + 2
Mass = \(\frac{64 \times 1350}{96500 \times 2}\)
Mass = 0.448g
Source: Myschool Past Questions Archive (Record #46544)
Chemistry
UTME / JAMB 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Diagram
Solution
The IUPAC nomenclature of the structure above is
Attached Figure / Diagram
A
3-methybut-3-ene
B
2-methylbut-1-ene
C
2-ethylprop-1-ene
D
2-methylbut-2-ene
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
CH2CH2 - CCH3CH2
Start the numbering from the terminal carbon.
Source: Myschool Past Questions Archive (Record #46545)
Chemistry
WAEC / WASSCE 2017
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
Which of the following species determines the chemical properties of an atom?
A
Electron
B
Neutron
C
Nucleus
D
Proton
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
An element's chemical properties depend on its valence electrons.The chemical properties of elements depend on an element's electron configuration.
Source: Myschool Past Questions Archive (Record #49180)
Chemistry
WAEC / WASSCE 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
The following glasswares are used to measure the volume of liquids EXCEPT
A
graduated beaker
B
pipette
C
test tube
D
burette
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Test tubes are convenient containers for heating small amounts of liquids or solids with a Bunsen burner or alcohol burner.
Source: Myschool Past Questions Archive (Record #49181)
Chemistry
WAEC / WASSCE 2017
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
Pauli exclusion principle is related to
A
quantity of electrons in the valence shell
B
filling the orbitals with lower energy first
C
the filling of degenerated orbitals
D
quantum numbers of electrons
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Pauli Exclusion Principle states that, in an atom or molecule, no two electrons can have the same four electronic quantum numbers.
Source: Myschool Past Questions Archive (Record #49183)
Chemistry
WAEC / WASSCE 2017
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
The species with no electron in the 3d-orbital is
A
\(Zn^{2+}\)
B
\(Sc^{3+}\)
C
Cu
D
\(Mn\)
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Scandium has electronic configuration \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{1}4s^{2}\) hence, \(Sc^{3+}\) has configuration \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\). Hence, no electron in the 3d-orbital.
Source: Myschool Past Questions Archive (Record #49188)
Chemistry
WAEC / WASSCE 2017
Nature of Matter & Separation Techniques
Solution
The seperation of Nitrogen from oxygen using fractional distillation of air is possible because
A
nitrogen is less dense than oxygen
B
oxygen is more reactive than nitrogen
C
of the difference in their boiling points
D
they belong to the same period
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The various gases vaporize as their boiling points are reached, then they are pumped away and separately re-liquefied for convenient storage.
Source: Myschool Past Questions Archive (Record #49192)
Chemistry
WAEC / WASSCE 2017
Water, Solutions & Solubility
Solution
The purity of a solid sample can best be determined by its
A
boiling point
B
melting point
C
conductivity
D
solubility
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
The purity of a solid can be determined by measuring the melting point. A pure solid will have a single, sharp melting point.
Source: Myschool Past Questions Archive (Record #49194)
Chemistry
WAEC / WASSCE 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
The mass of one mole of \((NH_{4})_{2}CO_{3}\) is [O=16.0, N=14.0, C=12.0, H=1.0]
A
66.0g
B
76.0g
C
80.0g
D
96.0g
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
This is same as asking for the molar mass of the compound
= \((2\times 14.0)+ (8\times 1.0) + 12.0+(16.0\times 3)\)
= 28.0+8.0+12.0+48.0 = 96.0g
Source: Myschool Past Questions Archive (Record #49199)
Chemistry
WAEC / WASSCE 2017
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
Atomic orbital is
A
the circular path through which electrons revolve round the nucleus
B
a region around the nucleus where electrons are most likely to be found
C
the path around the nucleus through which electrons move
D
the path around the nucleus through which protons move
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
The orbital is a path or region around the nucleus. The electrons move in the orbitals and not through it.
Source: Myschool Past Questions Archive (Record #49201)
Chemistry
WAEC / WASSCE 2017
Periodic Table & Periodicity
Solution
The property of elements which increases down a group of the periodic table is
A
electronegativity
B
electron affinity
C
ionic radius
D
ionization energy
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The ionic radius decreases across a period but increases along a group.
Source: Myschool Past Questions Archive (Record #49203)
Chemistry
WAEC / WASSCE 2017
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
The reason for the decrease in the atomic size of elements across a period is that
A
nuclear charge increases while the outermost electrons are drawn closer to the nucleus
B
nuclear charge decreases while the outermost electrons are drawn closer to the nucleus
C
valence electrons increase across the period while the valence shell remains constant
D
nuclear charge decreases while the distance of the valence shell from the nucleus is increasing
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
This is caused by the increase in the number of protons and electrons across a period.
Source: Myschool Past Questions Archive (Record #49209)