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Chemistry
UTME / JAMB 2017
Kinetic Theory of Matter & Gas Laws
Solution
The densities of two gases, X and Y are 0.5gdm-3 and 2.0gdm-3 respectively. What is the rate of diffusion of X relative to Y?
A
0.1
B
0.5
C
2.0
D
4.0
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The rate of dimension of a gas inversely proportional to the square root of its molecular mass or its density, which is Graham's Law of diffusion of gas.
R ∝ \(\frac{1}{\sqrt{Mm}}\) or R ∝ \(\frac{1}{\sqrt{D}}\)
Dx = 0.5gdm-3, Dy = 2gdm-3
R= \(\frac{K}{\sqrt{D}}\)
R\(\sqrt{D}\) = k
R1\(\sqrt{D_1}\) = R1\(\sqrt{D_2}\)
Rx\(\sqrt{D_x}\) = Ry\(\sqrt{D_y}\)
\(\frac{R_x}{R_y}\) = \(\frac{\sqrt{D_y}}{\sqrt{D_x}}\)
= \(\frac{\sqrt{2}}{\sqrt{0.5}}\)
= 2.0
Source: Myschool Past Questions Archive (Record #46547)
Chemistry
UTME / JAMB 2017
Chemical Bonding & Intermolecular Forces
Solution
The carbon atoms on ethane are
A
sp2 hybridized
B
sp3 hybridized
C
sp4 hybridized
D
sp hybridized
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Alkane's family are sp3 hybridized
Source: Myschool Past Questions Archive (Record #46551)
Chemistry
UTME / JAMB 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
According to Charle's law, the volume of a gas becomes zero at
A
−100°c
B
−273°c
C
−373°c
D
0°c
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Where −273°c = OK
i.e −273°c + 273 = OK
At zero kelvin, the volume of a gas becomes zero.
Source: Myschool Past Questions Archive (Record #46556)
Chemistry
UTME / JAMB 2017
Particulate Nature of Matter, Laws & Formulae
Solution
An oxide XO2 has a vapour density of 32. What is the atomic mass of X?
A
20
B
32
C
14
D
12
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Molecular mass = vapour density X2
Mm of XO2 = x + 16(2) = x + 32
vapour density = 32
∴ x + 32 = 32 × 2
x + 32 = 64
x = 64 - 32
x = 32
∴ the relative molecular mass of X is 32
Relative molecular mass = vapour density × 2
Source: Myschool Past Questions Archive (Record #46558)
Chemistry
UTME / JAMB 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
The gas that can be collected by downward displacement of air is
A
chlorine
B
sulphur (IV) oxide
C
carbon (IV) oxide
D
ammonia
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Upward delivery works well for hydrogen and ammonia, which are both less densed than air. Sometimes, they are collected over water.
Source: Myschool Past Questions Archive (Record #46562)
Chemistry
UTME / JAMB 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
In the laboratory preparation of trioxonitrate (V) acid the nitrogen(iv) oxide formed as a by-product is removed by
A
further heating
B
adding concentrated H2SO4
C
cooling the acid solution with cold water
D
bubbling air through the acid solution
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Bubbling of air through the acid solution removes deposited oxides of nitrogen.
Nitric acid is prepared in the laboratory by heating a nitrate salt with the concentrated acid.
NaNO3 + H2SO4 → NaHSO4 + HNO3
Vapours of nitric acid are condensed to a brown liquid in a receiver cooled under cold water. "Dissolved oxides of nitrogen" e.g NO2 are removed by redistillation or blowing a current of carbondioxide or dry air through the warm acid
Source: Myschool Past Questions Archive (Record #46565)
Chemistry
UTME / JAMB 2017
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
A particle that contains 9 protons, 10 neutrons and 10 electrons is
A
positive ion
B
neutral atom of a metal
C
neutral atom of a non-metal
D
negative ion
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
protons = 9
neutrons = 10
electrons = 10
Electronic configuration = 2, 8
Ground state Electronic configuration=2, 7
It means that the atom has gained an electron thereby making it have a negative ion.
When an atom donates an electron, it becomes positively charged.
When an atom accepts an electron, it becomes negatively charged
Source: Myschool Past Questions Archive (Record #46571)
Chemistry
UTME / JAMB 2017
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
Ethene is prepared industrially by
A
Reforming
B
Polymerization
C
Distillation
D
Cracking
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Ethene is produced from cracking which involves breaking up large hydrocarbon molecules into smaller and more useful bits. This is achieved by using high temperatures and pressures without a catalyst.
C15H32 → 2C2H4 + C3H6 + C8H14
......Δheat...ethene........propene.........octane
Source: Myschool Past Questions Archive (Record #46575)
Chemistry
UTME / JAMB 2017
Kinetic Theory of Matter & Gas Laws
Solution
Calculate the amount in moles of a gas which occupies 10.5 dm3 at 6 atm and 30oC [R = 0.082 atm dm3 K-1 mol-1]
A
2.536
B
1.623
C
4.736
D
0.394
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
For an ideal gas PV = nRT
Amount in moles = n
Volume v = 10.5dm3
Pressure P = 6atm
Temperature T = 30^\circC + 273 = 303k
R, Gas constant = 0.082 atmdm3k-1 mol
Recall from ideal gas equation
pv = nRT
n = \(\frac{RV}{RT}\)
n = \(\frac{6 \times 10.5}{0.082 \times 303}\)
n= 2.536mol
Source: Myschool Past Questions Archive (Record #46587)
Chemistry
UTME / JAMB 2017
Kinetic Theory of Matter & Gas Laws
Solution
If 100cm3 of oxygen pass through a porous plug is 50 seconds, the time taken for the same volume of hydrogen to pass through the same porous plug is? [O = 16, H = 1]
A
10.0s
B
12.5s
C
17.7s
D
32.0s
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Rate of diffusion \(\frac{\alpha_1}{Density}\) or \(\frac{1}{\sqrt{Mm}}\)
Rate = \(\frac{1}{time}\)
\(\frac{1}{time}\) \(\frac{\alpha_1}{Density}\) or \(\frac{1}{\sqrt{Molarmass}}\)
Time \(\alpha \sqrt{Density}\) or \(\sqrt{Molarmass}\)
At constant volume of 100cm3
\(\frac{t_{o2}}{\sqrt{Mn_{o2}}}\) = \(\frac{t_{n2}}{\sqrt{1 \times 2}}\)
\(\frac{50}{4 \sqrt{2}}\) = \(\frac{t_{n2}}{\sqrt{2}}\)
tn2= 12.5s
Source: Myschool Past Questions Archive (Record #46593)
Chemistry
UTME / JAMB 2017
Metals, Transition Elements & Extraction
Solution
Due to the high reactivity of sodium, it is usually stored under
A
water
B
mercury
C
paraffin
D
phenol
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Na is kept under kerosene (paraffin) to avoid reactivity with air.
Paraffin is also known as Kerosene.
Na(sodium) is kept in kerosene to prevent it from coming in contact with oxygen and moisture. If this happens, it will react with the moisture present in air and form sodium hydroxide.
Source: Myschool Past Questions Archive (Record #46602)
Chemistry
UTME / JAMB 2017
Water, Solutions & Solubility
Solution
The furring of kettles is caused by the presence in water of
A
calcium hydrogentrioxocarbonate (IV)
B
calcium trioxocarbonate (IV)
C
calcium tetraoxosulphate (VI)
D
calcium hydroxide
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Furring of kettles is caused by the temporary hardness in water. Temporary hardness in water is caused by calcium and magnesium trioxocarbonate (IV)
CaCO3 causes the furring of kettles
Source: Myschool Past Questions Archive (Record #46604)
Chemistry
UTME / JAMB 2017
Water, Solutions & Solubility
Solution
Water for town supply is chlorinate to make it free from
A
bad colour
B
bacteria
C
temporary hardness
D
permanent hardness
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Chlorine helps to keep water from germs and bacteria.
Source: Myschool Past Questions Archive (Record #46605)
Chemistry
UTME / JAMB 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
Ca(OH)2(s) + 2NH4Cl(s) → CaCl2(s) + 2H2O(l) + X. In the reaction above X is
A
NO2
B
NH3
C
N2O
D
NO2
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Balancing the chemical equation.
Ca[OH]2 + 2NH4Cl → CaCl2 + 2H2O + 2NH3
X = NH3
Source: Myschool Past Questions Archive (Record #46607)
Chemistry
UTME / JAMB 2017
Chemical Energetics & Thermochemistry
Solution
X(g) + 3Y(g) ---- 2z(g) H = +ve. if the reaction above takes place at room temperature, the G will be
A
negative
B
zero
C
positive
D
indeterminate
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
\DeltaG= \DeltaH − T\DeltaS.
To determine whether \DeltaG will be positive or negative, the value of \DeltaH(change in enthalpy) and \DeltaS (change in entropy) must be given. Likewise the temperature.
Entropy represents the degree of disorder in a system. In a gaseous reaction, this is determined by the change in the number of moles of gas.
Reactants: 1 mole of X + 3 moles of Y = 4 moles of gas
Products: 2 moles of Z = 2 moles of gas.
The spontaneity of a reaction is determined by the equation: \DeltaG= \DeltaH − T\DeltaS.
\DeltaH is positive , T = is always positive, \DeltaS = is negative. Substituting the signs into the equation: \DeltaG= \DeltaH − T\DeltaS = (+) - (T x (-)) = +
Since both terms are positive, \DeltaG must be positive regardless of the specific value of T as long as T is expressed in Kelvin (which is always > 0). A positive \DeltaG indicates the reaction is non-spontaneous at room temperature.
Source: Myschool Past Questions Archive (Record #46608)