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Chemistry
WAEC / WASSCE 2018
Non-Metals & Their Compounds
Solution
(a)(i) Describe briefly the laboratory preparation of hydrogen gas from the action of steam on iron.
(ii) Write the equation for the reaction in (a)(i).
(iii) List three methods for the industrial preparation of hydrogen gas.
(b)Consider the following reaction equation:
CO(g) + 2H\(_{2(g)}\) CH\(_3\)OH\(_{(g)}\) + 201 kJmol-J
Predict the effect of each of the following factors on the position of equilibrium:
(i) decrease in temperature;
(ii) increase in pressure;
(iii) increase in concentration of CO\(_{(g)}\).
(c) (i) Define condensation polymerization.
(ii) Name two condensation polymers.
(iii) Write the formula of ethylethanoate.
(d) (i) Define the term allotropy.
(ii) Name two crystalline allotropes of carbon.
(iii) State one use of each of the allotropes named in (d)(ii).
(e) State two differences between nitrogen (I) oxide and oxygen.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) Heat the iron strongly in a combustion tube until it is red hot. Generate steam
by boiling water in a flask. Pass the steam over the red-hot iron. Hydrogen gas would be given off. Collect the hydrogen gas formed over water.
(ii) 3Fe(s) + 4H\(_2\)O\(_{(g)}\) Fe\(_3\)O\(_{4(s)}\) + 4H\(_{2(g)}\)
(iii) - from water gas / Bosch process
- from methane
- by electrolytic method
- from catalytic cracking of petroleum products
(b) (i) It favours the backward reaction / Equilibrium position shifts to the left
(ii) Equilibrium position shifts to the right / favours the forward reaction
(iii) Equilibrium position shifts to the right / favours the forward reaction.
(c)(i) Condensation polymerization is defined as the linking together of monomers (with two different functional groups) to form a polymer with the elimination of a small molecule.
(ii) - Nylon/polyamide
- Terylene
- Silk
- Wool
- Cellulose
- Proteins
- Starch
- Dacron/polyester
- Phenol methanal
- Urea methanal
- Melamine methanal
(iii) - CH\(_3\)COOC\(_2\)H\(_5\)
(d) (i) Allotropy is defined as the existence of two or more forms of an element in the same physical state.
(ii)- diamond
- graphite
(iii)
Diamond
Graphite
- jewellery
- lubricant
- drilling
- black pigment in paints
- cutting
- electrical conductor for electrodes
- abrasive
- lead pencil
- making of bearings
- alloying
- pivot support
- neutron moderators
- dies for drawing wires
-lining of crucibles
(e)
N\(_2\)O
O\(_2\)
- pleasant smell
- odourless
- no reaction with NO
- reacts with NO
- produces N\(_2\)/gas with heated
copper
- produces no N\(_2\)/gas with heated copper
Source: Myschool Past Questions Archive (Record #56495)
Chemistry
WAEC / WASSCE 2018
Electrolysis & Electrochemical Cells
Solution
(a) (i) Name the ore mostly used in the extraction of aluminium.
(ii) Name two major impurities in the ore named in (a)(i).
(iii) Name the material used in making the electrodes in the extraction of aluminium.
(iv) Give two reasons why aluminium is commonly recycled.
(v) Explain briefly why the anode has to be replaced at regular intervals during the extraction of aluminium.
(b) A current of 0.75 amperes was passed through an electrolysis containing chromium ions for one hour and four minutes. If the mass of chromium deposited was 0.52 g, calculate the:
(i) quantity of electricity passed;
(ii) moles of chromium deposited;
(iii) quantity of electricity required to deposit one mole of chromium;
(iv) charge on the chromium ion.
[Cr = 52.0, 1 F = 96500 C]
(c) In the contact process for the manufacture of tetraoxosulphate(VI) acid, the following reaction occurs:
2SO\(_2\)\(_{(g)}\) + O\(_2\)\(_{(g)}\) 2SO\(_3\)\(_{(g)}\) H = - 197 kJ mol\(^{-1}\)
(i) Name the catalyst used in the reaction;
(ii) State the optimum temperature for this reaction;
(iii) What would be the effect on the yield of SO\(_3\) if a temperature higher than the optimum is used?
(d)(i) State two chemical methods by which temporary hardness of water can be removed.
(ii) Write a balanced chemical equation for each of the methods stated in (d)(i).
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) (i) - Bauxite
(ii) - Iron (III) oxide
- Silica / silicon (IV) oxide
- Calcium trioxosilicate (IV)
(iii)- Graphite / Carbon
(iv) - uses less energy / power / electricity
- conserves resources of ores / bauxite
- less expensive/reduces cost
(v)- Carbon anode reacts with oxygen
- Gas / CO\(_2\) given off
(b)(i) Q = It
Q = 0.75 x 64 x 60
= 2880C
(iv) Number of Faradays = 288,000
96,500
= 2.984
charge = + 3
(c) (i) Vanadium (V) oxide
(ii) 400 – 500\(^o\)C / 673 – 773 K
(iii) the yield decreases
(d)(i) - by boiling
- by addition of(calculated amount of) Ca(OH)\(_2\) – Calcium hydroxide/slaked lime
- by addition of washing soda/Na\(_2\)CO\(_3\)
- by addition of NaOH\(^-\) Sodium hydroxide/Caustic Soda
- by ion exchange/ permutit
(ii)- Ca(HCO\(_3\))\(_2\)\(_{(aq)}\) boil CaCO\(_{3(s)}\) + H\(_2\)O\(_{(l)}\) + CO\(_{2(g)}\)
- Ca(HCO\(_3\))\(_{2(aq)}\) + Ca(OH)\(_{2(aq)}\) → 2CaCO\(_{3(s)}\) + 2H2O\(_{(l)}\)
- Ca(HCO\(_3\))\(_2\)\(_{(aq)}\) + Na\(_2\)CO\(_{3(s)}\) → CaCO\(_{3(s)}\) + 2NaHCO\(_{3(aq)}\)
- Ca(HCO\(_3\))\(_{2(aq)}\) + 2NaOH\(_{(aq)}\) → 2NaHCO\(_{3(aq)}\) + Ca(OH)\(_{2(aq)}\)
- Ca(HCO\(_3\))\(_{2(aq)}\) + 2NaR → CaR\(_2\) + 2NaHCO\(_{3(aq)}\)
Source: Myschool Past Questions Archive (Record #56497)
Chemistry
WAEC / WASSCE 2018
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
(a) (i) State the collision theory of reaction rates.
(ii) Using the collision theory, explain briefly how temperature can affect the rate of a chemical reaction.
(b) (i) Sketch a graphical representation of Charles’ law.
(ii) Calculate the volume of oxygen that would be required for the complete combustion of 2.5 moles of ethanol at s.t.p.
[molar volume at s.t.p = 22.4 dm\(^3\)]
(c) (i) Define esterification.
(ii) Give two uses of alkanoates.
(iii) Give the products of the alkaline hydrolysis of ethyl ethanoate.
(d) A tin coated plate and a galvanized plate were exposed for the same length of time.
(i) Which of the two plates corrodes faster?
(ii) Explain briefly your answer in 2 (d) (i).
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) States that atoms, molecules/ions / particles / reactants involved in a chemical
reaction must collide before reaction can take place.
(ii) When temperature is increased/decreased the reacting molecules gain / lose kinetic energy and move faster / slower.
Frequency of collision and effective collision increases/decreases therefore rate of reaction increases/decreases.
(The explanation must correspond to score)
(ii) C\(_6\)H\(_5\)OH\(_{(aq)}\) + 3O\(_{2(g)}\) → 3H\(_2\)O\(_{(l)}\) + 2CO\(_{2(g)}\)
From the equation 1 mole of ethanol requires 3 x 22.4 dm\(^3\) of oxygen
2.5 mols = \(\frac{2.5 \times 3 \times 22.4}{1}\)
= 168.0 dm\(^3\)
(c) (i) Esterification is the reaction between an alkanol and alkanoic acid to produce an alkanoate / ester (and water in the presence of a mineral acid.)
(ii) - used as solvents (e.g. for paints, nail, varnishes, lacquer, adhesives and
cellulose nitrates)
- used in perfumes/cosmetics
- used in (artificial) flavouring for foods
- production of soap
- plasticizers
(iii) ethanol / C\(_2\)H\(_5\)OH and sodium ethanoate (CH\(_3\)COONa) / potassium ethanoate(CH\(_3\)COOK)
(d)(i) Tin – coated plate
(ii) Zinc is more reactive than tin / higher in the electrochemical series than tin. When the tin coated plate is exposed, the plate goes into solution / corrodes. In zinc coated (galvanized) plate, it is the zinc that dissolves / corrodes hence protecting the plate better and zinc coated plate does not corrode.
Source: Myschool Past Questions Archive (Record #56499)
Chemistry
WAEC / WASSCE 2018
Oxidation, Reduction & Redox Reactions
Solution
(a) Arrange the three states of matter in order of decreasing:
(i) kinetic energy;
(ii) force of cohesion.
(b) Consider the redox reaction equation:
(i) State the change in oxidation number of:
I. magnesium;
II. hydrogen.
(ii) Which of the species is being:
I. oxidized;
II. reduced?
(iii) Identify the oxidizing agent.
(c) (i) State two differences between boiling and evaporation.
(ii) What will be the effect of reduction of atmospheric pressure on the boiling point of water?
(d) For a given chemical equilibrium system, what is the significance of the equilibrium constant K?
(e) Consider the following organic compounds:
C\(_3\)H\(_7\)COOH; (CH\(_3\))\(_3\)COH.
Give the IUPAC name of each compound.
(f) Why are organic compounds classified on the basis of functional groups?
(g) State three differences between the solubility of solids in liquids and gases in liquids.
(h) Write a balanced chemical equation for the reaction between fluorine and water.
(i) Define the term basicity of an acid.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)
(i) gas > liquid > solid / gas, liquid, solid
(ii) solid > liquid > gas / solid, liquid, gas
(c) (i)
(I) 0 to +2
(II) +1 to 0
(ii)(I) Magnesium / Mg
(II) Hydrogen / H\(^+\) / HCl
(iii) Hydrochloric acid / HCl
(d) (i)
Evaporation
Boiling
- occurs on the surface of
Liquid
- occurs at the entire length of
Liquid
- occurs slowly
- occurs rapidly
- occurs at any temperature
- occurs at specific temperature
- produces cooling
- does not produce cooling
- occurs using internal energy/is
Spontaneous
- requires an external source of
Heat / not spontaneous
- bubbles are not seen
- bubbles are seen
(ii) The temperature required to boil the water decreases / boils at temperature lower than 1000 C
(e) The equilibrium constant k, indicates the extent to which a reaction will proceed / it gives an idea of where the equilibrium lies / when k is large, more of the products are formed / when k is small, less of the products are formed.
(f) C\(_3\)H\(_7\)COOH: butanoic acid
(CH\(_3\))3COH: 2 – methyl propan-2-ol
(g) Functional groups are atoms or groups of atoms that are responsible for particular chemical properties and reactions of organic compounds.
(h)
Solids in liquids
Gases in liquid
- solubility increases with
temperature
- solubility decreases as
temperature increases
- it is not affected by change in
pressure / does not have any
significant effect
- is greatly affected by pressure,
increases with increase in pressure
- increasing and decreasing of pH
affects the solubility
- pH does not affect them
- depends on the nature of solute
and solvent
- depends on nature of gas and
solvent
(i) 2F\(_{2 (g)}\) + 2H\(_2\)O\(_{(l)}\) → 4HF\(_{ (aq)}\) + O\(_{2 (g)}\)
(j) is the number of replaceable hydrogen ions in a molecule of an acid / number of ionisable hydrogen atoms in one molecule of acid.
Source: Myschool Past Questions Archive (Record #56503)
Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
(a) A compound of carbon, hydrogen and chlorine contains 0.48 g of carbon, 0.08 g of hydrogen and 1.42 g of chlorine.
(i) Determine the empirical formula of the compound.
(ii) If the molar mass of the compound is 99, calculate the molecular formula of the compound.
[H = 1.0, C = 12.0, Cl = 35.5]
(b) State three properties of NaCl (s) which shows that it is ionic.
(c) Consider the following reaction equation:
(i) On the same diagram, sketch and label a reaction profile for a catalysed and uncatalysed reaction between H\(_2\) and O\(_2\).
(ii) Indicate the possible positions of the activated complexes for the reaction profiles in (c)(i).
(d) The petrochemical industry produces addition polymers using one of the fractions obtained from crude oil.
(i) Name the fraction used as a raw material for the process.
(ii) What process is used to obtain the fraction from crude oil?
(iii) Name two gaseous hydrocarbons that can be used in making polymers.
(iv) Describe briefly how these hydrocarbons can be obtained.
(v) Name the polymer produced from one of the hydrocarbons named in (d)(iii).
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) ratio of atoms
C = \(\frac{0.48}{12}\) = 0.04, H= \(\frac{0.08}{1}\) = 0.08, Cl = \(\frac{1.42}{35.5}\) = 0.04
Divide by the smallest number
\(\frac{0.04}{0.04}\): \(\frac{0.08}{0.04}\) : \(\frac{0.04}{0.04}\)
1 : 2 : 1
Empirical formula = CH\(_2\)Cl
(ii) Molecular formula = (Empirical formula)n
99 = (CH\(_2\)Cl)n
99 = (12 + (2 x 1) + 35.5)n
99 = 49.5n
n = \(\frac{99}{49.5}\)
= 2
molecular formular = C\(_2\)H\(_4\)Cl\(_2\) / (CH\(_2\)Cl)\(_2\)
(b)
- in its molten form / solution conducts electricity
- has strong electrostatic forces
- has high melting / boiling points
- is highly soluble in water
(c) (i) & (ii)
Reaction co-ordinate
(d) (i) Naphtha Accept kerosene / Diesel
(ii) Fractional distillation
(iii) - Ethene
- Propene
(iv) Catalytic cracking whereby long-chain hydrocarbons (in the naphtha fraction) are broken down into small organic molecules
Conditions are 600\(^o\) C and Al\(_2\)O\(_2\)\(_{(s)}\) / SiO\(_2\)\(_{(s)}\) as catalyst
(v)
- Polyethene
- Polypropane
Source: Myschool Past Questions Archive (Record #56506)
Chemistry
WAEC / WASSCE 2018
Chemical Energetics & Thermochemistry
Solution
a) (i) Describe, using the kinetic theory of matter, what happens when potassium chloride dissolves in water.
(ii) Give a reason why the process in (a) (i) is endothermic.
(b) (i) An underground iron pipe is less likely to corrode if it is bonded at intervals with magnesium rods. Give reasons for this observation.
(ii) State the stages involved in the rusting of iron.
(iii) State the condition for the rusting of iron in water.
(c) (i) What is a spontaneous reaction?
(ii) State two conditions that could make a reaction spontaneous.
(iii) Explain briefly why one gramme of sodium reacts more rapidly with water at 250C than one gramme of calcium at the same temperature.
(iv) Write equations for the reactions in (c)(iii).
(d) What mass of lead (II) trioxocarbonate (IV) would contain 35.0 g of lead?
[C=12.0, O = 16.0, Pb = 207.0]
(e) Name the type of intermolecular force present in:
(i) fluorine;
(ii) hydrogen fluoride.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) (i) The cations and anions attract the polar water molecules the energy released as the ion-dipole forces are formed provides the energy to break the electrostatic forces of attraction between the oppositely charged ions in the potassium chloride.
OR
The water molecules split KCl into free ions with a release of energy known as lattice energy. The free ions are hydrated/surrounded by water molecules. This is known as the hydration energy.
(ii) More energy is needed to overcome the ion-ion attraction hence the
dissolution process is endothermic /
OR
lattice energy is greater than hydration energy.
(b) (i) Magnesium is more reactive than iron therefore magnesium reacts
preferentially / acts as a sacrificial anode.
(ii) Iron oxidizes to Fe\(^{2+}\) by oxygen and water to give Iron (II) hydroxide / Fe\(^{2+}\) and
OH\(^-\) formed. Further oxidation gives hydrated Iron (III) oxide / Fe2O\(_3\).xH\(_2\)O
(iii) Presence of (dissolved) oxygen / air
(c) (i) It is a reaction that occurs without being driven by some outside / external force.
(ii)
- G must be negative
- the products are more random, more disorganized than the reactants /
entropy of products is greater than entropy of reactants / entropy must increase
(iii) Sodium is in Group I and is more reactive metal than calcium that is in
Group II. / sodium is more electropositive than calcium / higher in the reactivity series
(iv)
(d) Mr (PbCO\(_3\)) = 207 + 12 + 16(3)
= 267g mol\(^{-1}\)
(e)
(i) van der Waal’s forces
(ii) hydrogen bonding
Source: Myschool Past Questions Archive (Record #56514)
Chemistry
WAEC / WASSCE 2018
Metals, Transition Elements & Extraction
Solution
(a) Outline the procedures for the treatment of water for town supply.
(b) (i) State two main impurities present in bauxite.
(ii) Give one reason why bauxite is usually preferred as the ore for the extraction of aluminium.
(iii) Outline the manufacture of aluminium form purified bauxite.
(c) (i) Explain briefly the term fine chemical industry.
(ii) State two differences between a fine chemical and a heavy chemical.
(d) (i) Write a balanced chemical equation for the combustion of coal.
(ii) If 5.4 g of coal is burnt completely, calculate the amount of oxygen measured at s.t.p. that would be required for the combustion.
[C = 12.0, O = 16.0, Molar volume of a gas at s.t.p. = 22.4 dm\(^3\)]
(e) Name two substances which can be used as electrodes during the electrolysis of acidified water.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)
- addition of alum / addition of coagulating agent
- sedimentation
- filtration
- disinfection / chlorination / addition of chlorine
(b) (i) - iron (III) oxide
- silicon (IV) oxide / sand
- trioxosilicates (IV)
(ii) because aluminium oxide has too high a melting point to eletrolyse on its own / bauxite has low silica content
(iii) - Alumina and molten cryolite
Melted and electrolysed
Cell with carbon electrodes
Molten aluminium produced at the base of cell.
siphoned off / removed at the base
(c) (i) A fine chemical industry is the one that manufactures chemicals in smaller
quantities / amounts for specific use with high level of purity
(ii)
Fine chemical
Heavy chemical
- they are produced in
smaller quantities
- they are produced in larger
quantities
- they are highly pure
- they are not pure
- they are final products
- they are intermediate products
- they are more costly /
expensive
- less costly / less expensive
(d) (i) C\(_{(s)}\) + O\(_{2(g)}\)
(ii) Amount of coal burnt = \(\frac{5.4}{12}\) mol\(^{-1}\)
= 0.45mol
From the equation of the reaction moles of O\(_2\) used = moles of C burnt = 0.45
1 moles of O\(_2\) = 22.4 dm\(^3\)
0.45 mol O\(_2\) = 22.4 x 0.45
= 10.1dm\(^3\)
(e) - platinum
- carbon
Source: Myschool Past Questions Archive (Record #56515)
Chemistry
WAEC / WASSCE 2018
Non-Metals & Their Compounds
Solution
(a) (i) List two gaseous pollutants that can be generated by burning coal.
(ii) Explain briefly why coal burns more easily when it is broken into pieces than when it is in lumps.
(iii What gas is responsible for most of the explosions in coal mines?
(iv) Name the non-volatile residue left behind after the destructive distillation of coal.
(b) State one oxide in each case which:
(i) is used in bleaching;
(ii) oxidizes hot concentrated HCl to chlorine;
(iii) dissolves in water to give a solution with pH greater than 7;
(iv) reacts with NaOH and also with HCl;
(v) is a reddish-brown gas.
(c) (i) Write a balanced chemical equation for the reaction between chlorine gas and iron(II) chloride solution.
(ii) State the type of reaction in (c)(i).
(iii) Give a reason for your answer in (c)(ii).
(d) Consider the following set-up:
(i) Identify A and B.
(ii) Write a balanced chemical equation for the reaction.
(iii) Name the gas produced.
(iv) Why was the flask tilted downwards?
(v) What is the:
(I) function of B in the experiment;
(II) method of collection of the gas?
(e) Give one product obtained from refining petroleum that is solid.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) (i) - sulphur (IV) oxide /SO\(_2\)
- nitrogen (IV) oxide / NO\(_2\)
- nitrogen (II) oxide / NO
- carbon (II) oxide / (CO)
- methane / CH\(_4\)
(ii) Large lumps have smaller surface area to volume ratio than the broken pieces which has a greater surface area / increased exposed surface area. This makes the broken pieces to collide more frequently.
OR
The greater the rate of frequency of successful collisions, the greater the rate of reaction hence for the pieces of coal more reactant particles are exposed at the surface thereby increasing the frequency of successful collisions between reactant particles.
(iii) methane gas / CH\(_4\)
(iv) coke / carbon
(b) (i) - chlorine dioxide / (ClO\(_2\))
- sulphur (IV) oxide SO\(_2\)
- hydrogen peroxide / H\(_2\)O\(_2\)
- sodium peroxide Na\(_2\)O\(_2\)
(ii) - Manganese (IV) oxide / MnO\(_2\)
- Lead (IV) oxide / PbO2\(_2\)
(iii) - CaO
- MgO
- Na\(_2\)O
- K\(_2\)O
(iv) Aluminium oxide (Al\(_2\)O\(_3\)), ZnO, PbO, SnO\(_2\), SnO, PbO\(_2\)
(v) - nitrogen (IV) oxide / NO2\(_2\)
(c) (i)
(ii) Redox reaction
(iii) Because Iron (II) ions is oxidized to iron (III) ions / chlorine is reduced to chloride ions / chlorine gas oxidizes iron (II) ions to iron (III) ions and in the process chlorine is reduced to chloride ions / oxidation number of iron increases from +2 to +3 while that of chlorine decreases from 0 to -1.
(d) (i)
A - delivery tube
B - Calcium oxide / CaO / quicklime
(ii)
(iii) Ammonia
(iv) To prevent the (round bottom) flask from cracking / to prevent the water / steam formed from condensing into the hot glass flask.
(v) (I) Drying agent / To dry the gas
(II) Upward delivery / downward displacement of air
(e) - Paraffin wax
- Asphalt / bitumen
Source: Myschool Past Questions Archive (Record #56517)
Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
All your burette readings (initials and final) as well as the size of your pipette must he recorded but no account of experimental procedure is required. All calculations must be done in your booklet.
A solution of potassium tetraoxomanganate( VII). B is a solution of iron(II)chloride containing 4.80g of the salt in 250 cm\(^{3}\) of solution.
(a) Put A into the burette. Pipette 20.0cm\(^3\) or 2.50.0 of B into a conical flask, add 20.0 cm\(^3\) of H\(_2\)SO4\(_{(aq)}\) and titrate with A. Repeat the titration to obtain concordant titre values. Tabulate your results and calculate the average volume of A used. The equation of the reaction is: MnO\(_{4(aq)}\) + 5Fe\(^{3+}_{ (aq)}\) + H\(_2\))
(b) From your results and the information provided, calculate the;
(i) concentration of B moldm\(^{-3}\):
(ii) concentration of A in moldm\(^{-3}\)
(iii) number of moles of Fe\(^{2+}\) in the volume of B pipetted. [FeCl\(_2\) = 127 gmol\(^{-1}\)] Credit will be given for strict adherence to the instruction, for observations precisely recorded and for accurate inferences. AlI tests, Observations and inferences must be clearly entered in the booklet in ink at the time they are made.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
Rough Tree
1st Titre
2rd Titre
3rd Titre
Final reading cm\(^3\)
15.60
31.10
45.50
15.60
Initial reading cm\(^3\)
0.00
15.60
31.10
0.00
Volume of the acid cm\(^3\)
15.50
15.50
15.40
15.60
(a) Average Titre = \(\frac{15.50 + 15.40 + 15.60}{3}\) cm\(^3\)
= \(\frac{46.50}{3}\)cm\(^3\)
= 15.50 cm\(^3\)
(b)(i) Concentration of B in moldm\(^{-3}\)
250cm\(^3\) of B contains 480g of FeCl\(_2\)
100 cm\(^{-3}\) of B will contain \(\frac{4.80}{250}\) x 1000g
= 19.2 gdm\(^{-3}\)
Concentration of B in moldm\(^{-3}\) ?
= \(\frac{\text{conc. in gdm}^{-3}}{\text{molar mass}} = \frac{19.2 gdm^{-3}}{127 gmol^{-1}}\)
= 0.151 mol dm\(^3\)
Concentration of A in mol dm\(^{-3}\) = ?
\(\frac{C_AV_A}{C_BV_B} = \frac{n_A}{n_B}\)
C\(_A\) = Molar concentration in moldm\(^{-3}\) of KMnO\(_4\) = ?
V\(_A\) = Volume of KMnO\(_4\) used = 15.50cm\(^3\)
n\(_A\) = 1
C\(_B\) = Molar concentration of FeCl\(_{2(aq)}\) = 0.151 moldm\(^{-3}\)
V\(_B\) = Volume of FeCl\(_{2(aq)}\) = 25.00 cm\(^3\)
= \(\frac{C_A \times 15.50 cm^3}{0.151 mold dm^{-3} \times 25.00 cm^3}\) = \(\frac{1}{5}\)
C\(_A = \frac{0.151 \times 1 \times 25.00}{5 times 15.50} = \frac{3.775}{77.50}\)
= 0.0487 (3sf)
C\(_A\) = 0.0487 moldm\(^{-3}\)
(ii) Number of moles of Fe\(^{2+}\) in the volume of B pipetted? 1000 cm\(^3\) of B contains 0.151 moles of Fe\(^{2+}\) 25cm of B will contain \(\frac{0.151}{1000} \times 25\) moles = 0.0003775 mole of Fe\(^{2+}\)
Source: Myschool Past Questions Archive (Record #59968)
Chemistry
WAEC / WASSCE 2018
Acids, Bases, pH & Salts
Solution
All your burette readings (initials and final) as well as the size of your pipette must be recorded but no account of experimental procedure is required. All calculations must be done in your booklet.
C and D are inorganic salts. Carry out the following exercises on them. Record your observations and identify any gas(es) evolved. State the conclusions you draw from the result of each test.
(a) Put all of C in a test tube and add about 5 cm of distilled water. Shake thoroughly and test the resulting solution with Litmus paper. Divide the solution into three portions.
(i) To the first portion, add NaOH\(_{(aq)}\) in drops, then in excess.
(ii) To the second portion. add NH\(_{3(aq)}\) in drops. then in excess.
(iii) To the third portion. add AgNO\(_{3 (aq)}\) followed by HCl\(_{(aq)}\)
(b)(i) Put all of D in a test tube and add about 5 cm\(^3\) of distilled water. Shakę thoroughly and feel the test tube.
(ii) To about 2 cm\(^3\) of the solution, add HCl\(_{(aq)}\)
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
TEST
OBSERVATION
INTERFERENCE
(a) Sample C + distilled water + shaking
Resulting solution + litmus paper
Sample C dissolved to form a blue/greenish solution
Solution turns blue litmus paper red
Solution is acidic
(I) 1st portion + NaOH\(_{(aq)}\) in drops
Then in excess
Blue precipitate formed
Precipitate insoluble in excess
Cu\(^{2+}\) is present
(ii) 2nd portion NH\(_4\)OH\(_{(aq)}\) in drops
Then in excess
Light blue precipitate formed
Precipitate dissolve in excess to form a deep blue solution
Cu\(^{2+}\) is confirmed
(iii) 3rd portion + AgNO\(_{3(aq)}\)+ NCl\(_{(aq)}\)
White precipitate formed
Precipitate insoluble
Cl\(^{-1}\) or CO\(_{3^{2-}}\) or S\(^{2-}\) or SO\(_3^2\)
Cl\(^{2-}\) is present
(b)(i) Sample D + distilled water touching or feeling the test tubes
Sample D dissolved to form a colourless solution
Test tube feels cold on touching
Dissolution is endothermic
(ii) D\(_{(aq)}\) = HCl\(_{(aq)}\)
Effervescence (bubbling) occurs, a colourless, odourless gad evolved
Gas turned lime water milky
CO\(_{2(g)}\) from CO\(_{3^{2-}}\) or HCO\(_3^-\)
Source: Myschool Past Questions Archive (Record #59969)
Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
All your burette readings (initials and final) as well as the size of your pipette must he recorded but no account of experimental procedure is required. All calculations must be done in your booklet.
State the observation that would be made when each of the following reactions is carried out in the laboratory:
(a) Addition of 2 cm\(^3\) of bench H\(_2\)SO\(_{4(aq)}\) to 2 cm\(^{3}\) of barium chloride solution;
(b) Addition of 2 cm\(^3\) of dilute hydrochloric acid to 1g of powered iron(II) sulphide (FeS):
(C) Addition of 2 cm\(^3\) of dilute hydrochloric acid to 1g of iron filings and allowed to stand for sometime.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) Observation made when 2cm\(^3\) of bench H\(_2\)SO\(_4\) was added to 2cm\(^3\) of barium chloride solution.
H\(_2\)SO\(_{4(q)}\) + BaCl\(_{2(aq)}\) \(\to\) BaSO\(_{4(s)}\)(white) + 2HCl\(_{(aq)}\)
White precipitate of BaSO\(_4\) Barium tetraoxosulphate(VI) is formed
(b) Observation made by the addition of dilute hydrochloric acid to 1g of powered iron (III) sulphide (FeS)
2HCl\(_{(aq)}\) + FeS\(_{(s)}\) \(\to\) FeCl\(_{(aq)}\) + H\(_2\)S\(_{(g)}\)
Effervescence (bubbling) occurs or evolution of a gas with a smell of rotten eggs and a green solution is formed.
(c) Observation made by the addition of 2cm\(^3\) of dillute hydrochloric acid to 1g of iron filings and allowed to stand for sometime
Effervescence or evolution of colourless, odourless gas noticed with the formation of light green solution that will turn brown after sometime.
Source: Myschool Past Questions Archive (Record #59970)
Chemistry
UTME / JAMB 2018
Air & Environmental Chemistry
Solution
In the upper atmosphere, the ultra-violet light breaks off a free chlorine atom from chlorofluorocarbon molecule. The effect of this is that the free chlorine atom will
A
be very reactive and will attack ozone
B
be non-reactive and will not attack ozone
C
not change the level of ozone in the atmosphere
D
increase the level of ozone in the atmosphere
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
CFCs (Chlorofluorocarbons) have a lifetime in the atmosphere of about 20 to 100 years, and consequently one free chlorine atom from a CFC molecule can do a lot of damage, destroying ozone molecules for a long time
Source: Official Exam / Past Question Archive
Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
All your burette readings (initials and final) as well as the size of your pipette must he recorded but no account of experimental procedure is required. All calculations must be done in your booklet.
State the observation that would be made when each of the following reactions is carried out in the laboratory:
(a) Addition of 2 cm\(^3\) of bench H\(_2\)SO\(_{4(aq)}\) to 2 cm\(^{3}\) of barium chloride solution;
(b) Addition of 2 cm\(^3\) of dilute hydrochloric acid to 1g of powered iron(II) sulphide (FeS):
(C) Addition of 2 cm\(^3\) of dilute hydrochloric acid to 1g of iron filings and allowed to stand for sometime.
A
vibrational motion
B
vibrational and translational motion
C
vibrational and random motion
D
random and translational motion
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
(a) Observation made when 2cm\(^3\) of bench H\(_2\)SO\(_4\) was added to 2cm\(^3\) of barium chloride solution.
H\(_2\)SO\(_{4(q)}\) + BaCl\(_{2(aq)}\) \(\to\) BaSO\(_{4(s)}\)(white) + 2HCl\(_{(aq)}\)
White precipitate of BaSO\(_4\) Barium tetraoxosulphate(VI) is formed
(b) Observation made by the addition of dilute hydrochloric acid to 1g of powered iron (III) sulphide (FeS)
2HCl\(_{(aq)}\) + FeS\(_{(s)}\) \(\to\) FeCl\(_{(aq)}\) + H\(_2\)S\(_{(g)}\)
Effervescence (bubbling) occurs or evolution of a gas with a smell of rotten eggs and a green solution is formed.
(c) Observation made by the addition of 2cm\(^3\) of dillute hydrochloric acid to 1g of iron filings and allowed to stand for sometime
Effervescence or evolution of colourless, odourless gas noticed with the formation of light green solution that will turn brown after sometime.
Source: Official Exam / Past Question Archive
English Language
UTME / JAMB 2018
Reading Comprehension, Summary & Composition
Solution
According to this passage, it gives the child great pleasure
A
for Daddy to see the tower he has built
B
to destroy the tower himself
C
to see his tower accidentally destroyed
D
to be helped to destroy the tower
medium Difficulty
Verified Correct Answer: Option B
Grammar & Contextual Explanation
According to the passage, the child ''enjoys causing the same tower to waver and collapse''. He enjoys destroying the tower himself.
Source: Myschool Past Questions Archive (Record #47014)
English Language
UTME / JAMB 2018
Lexis, Structure & Register (Cloze & Vocabulary)
What other feeling does the child derive from the fall of his tower apart from pleasure?
A
Strength
B
Anxiety
C
Pity
D
Depression
medium Difficulty
Verified Correct Answer: Option A
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #47015)