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Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
The valence electrons of \(_{12}Mg\) are in the
A
3s orbital
B
2\(p_x\)
C
2s orbital
D
1s orbital
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
\(_{12}Mg = 2, 8, 2\)
\(= 1s^{2} 2s^{2} 2p^{6} 3s^{2}\)
Source: Myschool Past Questions Archive (Record #49049)
Chemistry
WAEC / WASSCE 2018
Metals, Transition Elements & Extraction
Solution
Stainless steel is an alloy comprising of
A
Fe and C
B
Fe and Ni
C
Fe, C and Ni
D
Fe, C and Al
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Stainless steel comprises iron (Fe), chromium (Cr), manganese (Mn), silicon (Si), carbon (C) and, in many cases, significant amounts of nickel (Ni) and molybdenum (Mo).
Source: Myschool Past Questions Archive (Record #49051)
Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
The number of Hydrogen ions in 1.0\(dm^{3}\) of 0.02\(moldm^{-3}\) tetraoxosulphate(VI) acid is \([N_{A} = 6.02 \times 10^{23}]\)
A
\(1.2 \times 10^{22}\)
B
\(1.2 \times 10^{23}\)
C
\(2.4 \times 10^{22}\)
D
\(2.4 \times 10^{23}\)
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
\(1mole = 6.02 \times 10^{23} ions\)
\(0.02moldm^{-3} = 0.02 \times 6.02 \times 10^{23}\)
=\(0.1204 \times 10^{23} = 1.204 \times 10^{22}\)
\(\approxeq 1.2 \times 10^{22}\)
Source: Myschool Past Questions Archive (Record #49054)
Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
The most suitable substance for putting out petrol fire is
A
water
B
carbon(IV) oxide
C
fire blanket
D
sand
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
In order to extinguish a petrol fire, you have to cut off the oxygen. This can be done by using carbon dioxide gas to dilute the oxygen available and stop the burning.
Source: Myschool Past Questions Archive (Record #49057)
Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
What is the mass of solute in 500\(cm^{3}\) of 0.005\(moldm^{-3}\) \(H_{2}SO_{4}\)? ( H = 1, S = 32.0, O=16.0)
A
0.490g
B
0.049g
C
0.245g
D
0.0245g
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Using
n = cv where n = no of mole, c = molar concentration(mol/dm3) and v = volume( dm3)
volume = 500\(cm^{3}\) = 0.5dm3, c = 0.005\(moldm^{-3}\)
number of mole(n) = c x v = 0.5 X 0.005 = 0.0025mol.
but n = \(\frac{mass}{ molar mass}\) = 0.0025 = \(\frac{mass}{ 98}\) (where 98g/mol is the molar mass of H2SO4)
mass of H2SO4 = 0.0025 x 98 = 0.245g.
Source: Myschool Past Questions Archive (Record #49014)
Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
Pure water can be made to boil at a temperature lower than 100^\circC by
A
reducing its quantity
B
decreasing the external pressure
C
distilling it
D
increasing the external pressure
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
The easiest and most drastic way to change the boiling point is by tampering with the pressure above your water. To lower the boiling point, you need simply to decrease its external pressure.
Source: Myschool Past Questions Archive (Record #49018)
Chemistry
WAEC / WASSCE 2018
Water, Solutions & Solubility
Diagram
Solution
At what temperature does the solubility of \(KNO_{3}\) equal that of \(NaNO_{3}\)?
Attached Figure / Diagram
A
0°C
B
20°C
C
30°C
D
40°C
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
From the graph, check for their point of intersection and trace it down to the temperature axis.
Source: Myschool Past Questions Archive (Record #49023)
Chemistry
WAEC / WASSCE 2018
Water, Solutions & Solubility
Solution
When a salt is added to its saturated solution, the salt
A
dissolves and the solution becomes super saturated
B
dissolves and the solution becomes unsaturated
C
precipitates and the solution remains unchanged
D
dissolves and crystals are formed
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The point of saturation is the point it gets to and from thence, the solution can no longer take in the salt anymore. From this point, it begins to form precipitate while the solution remains unchanged.
Source: Myschool Past Questions Archive (Record #49024)
Chemistry
WAEC / WASSCE 2018
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
When substance X was added to a solution of bromine water, the solution became colourless. X is likely to be
A
propane
B
propanoic acid
C
propyne
D
propanol
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Thus bromine water will be decolorized by alkynes due to the presence of two pi bonds available for reaction!
Source: Myschool Past Questions Archive (Record #49025)
Chemistry
WAEC / WASSCE 2018
Air & Environmental Chemistry
Solution
The following factors would contribute to environmental pollution except
A
production of ammonia
B
manufacture of cement
C
photosynthesis
D
combustion
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Photosynthesis is the process of food-making in plants, it doesn't have any by-products that pose a threat to the environment. Infact, the plants use our waste product of respiration (Carbon dioxide) and uses it for the photosynthetic process and gives off oxygen as by-product.
Source: Myschool Past Questions Archive (Record #49059)
Chemistry
WAEC / WASSCE 2018
Reaction Rates & Chemical Equilibrium
Solution
The position of equilibrium in a reversible reaction is affected by
A
particle size of the reactants
B
vigorous stirring of the reaction mixture
C
presence of a catalyst
D
change in concentration of the reactants
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
The position of equilibrium will shift under the effects of changes in temperature, pressure and concentration.
Source: Myschool Past Questions Archive (Record #49061)
Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Diagram
Solution
The diagram above illustrates a conical flask containing water and ice. Which of the following is correct about the diagram?
Attached Figure / Diagram
A
The water is at lower temperature than the ice
B
Energy is absorbed when the ice changes to water
C
Energy is released when the ice changes to water
D
The water molecules vibrate about a fixed point
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Heat energy near the ice gets absorbed into the ice. The energy breaks the bonds of the ice, causing it to melt into liquid water. On other words, when ice melts, the energy gets absorbed into the water.
Source: Myschool Past Questions Archive (Record #49068)
Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
Which of the following statements best explains the difference between a gas and a vapour?
A
Unlike gases, vapours are liquids at room temperature
B
Unlike gases, vapour can easily be condensed into liquids
C
Unlike gases, vapour is readily converted into solids
D
Vapours are generally denser than gases
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Vapour is the equilibrium state between the gases and liquid, and it can bounce back to its original form, liquid with constant temperature and pressure exerted on it.
Source: Myschool Past Questions Archive (Record #49071)
Chemistry
WAEC / WASSCE 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
Consider the following reaction equation: \(2HCl + Ca(OH)_{2} \to CaCl_{2} + H_{2}O\). What is the volume of 0.1\(moldm^{-3}\) HCl that would completely neutralize 25\(cm^{3}\) of 0.3\(moldm^{-3}\) Ca(OH)\(_{2}\)?
A
150\(cm^{3}\)
B
75\(cm^{3}\)
C
30\(cm^{3}\)
D
25\(cm^{3}\)
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Using the formula, \(\frac{C_{A}V_{A}}{C_{B}V_{B}} = \frac{N_{A}}{N_{B}}\), we have
\(\frac{0.1 \times V_{A}}{0.3 \times 25} = \frac{2}{1}\)
\(V_{A} = \frac{0.3 \times 25 \times 2}{0.1 \times 1}\)
\(V_{A} = 150cm^{3}\)
Source: Myschool Past Questions Archive (Record #49073)
Chemistry
WAEC / WASSCE 2018
Periodic Table & Periodicity
Solution
\(Cu\) and \(HNO_{3}\) are not suitable for preparing hydrogen gas because of their
A
reactivity and oxidation respectively
B
conductivity and corrosiveness respectively
C
melting point and reduction respectively
D
electronegativity and solubility respectively
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Copper is not active enough to replace hydrogen in an acid. Also, nitric acid is a strong oxidizing agent which quickly oxidises hygrogen to water.
Source: Myschool Past Questions Archive (Record #49076)