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Chemistry
UTME / JAMB 2018
Stoichiometry, Mole Concept & Volumetric Analysis
An aqueous solution of a metal salt, M. gives a white precipitate with NaOH which dissolves in excess NaOH. With aqueous ammonia, the solution of M also gives a white precipitate which dissolves in excess ammonia Therefore the cation in M is
A
Zn
B
Ca
C
Al
D
Pb
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #47333)
Chemistry
UTME / JAMB 2018
Stoichiometry, Mole Concept & Volumetric Analysis
What is the concentration of a solution containing 2g of NaOH in 100cm3 of solution? [Na = 23, O =16, H = 1]
A
0.40 moldm\(^{-3}\)
B
0.50 moldm\(^{-3}\)
C
0.05 moldm\(^{-3}\)
D
0.30 moldm\(^{-3}\)
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #47335)
Chemistry
UTME / JAMB 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
How many atoms are present in 6.0g of magnesium? [Mg = 24, N.A = 6.02 x 10 \(^{23}\)mol]
A
1.20 x 10\(^{22}\)
B
2.4 x 10\(^{22}\)
C
1.51 x 10\(^{23}\)
D
3.02 x 10\(^{22}\)
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Using the formula, Number of moles = \(\frac{Number of atoms or molecules}{Avogadro number}\)
Given: Mass of Magnessium = 6g
Mass number of Mg = 24g/mol
Number of moles = \(\frac{mass}{Molar mass}\)
= \(\frac{6}{24}\) = \(\frac{1}{4}\) = 0.25 mole
Thus, Number of moles = \(\frac{Number of atoms or molecules}{Avogadro number}\)
n = \(\frac{N}{L}\)
0.25 = \(\frac{N}{(6.02\times 10\(^{23}}\)
N = \(0.25 \times 6.02\times 10\(^{23}\))
N = 1.505 X 10\(^{23}\)
N = 1.51 X 10\(^{23}\)
Source: Myschool Past Questions Archive (Record #47336)
Chemistry
UTME / JAMB 2018
Atomic Structure, Orbitals & Nuclear Chemistry
The radio isotope used in industrial radiography for the rapid checking of faults in welds and casting is?
A
carbon-14
B
phosphorus-32
C
cobalt-60
D
iodine-131
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #47337)
Chemistry
UTME / JAMB 2018
Periodic Table & Periodicity
Solution
Beryllium and Aluminium have similar properties because they
A
are both metals
B
belong to the same group
C
belong to the same period
D
are positioned diagonally to each other
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Beryllium and Aluminium exhibit similar properties because of their diagonal relationship on the periodic table, meaning they are positioned diagonally to each other, resulting in comparable atomic sizes, electronegativity, and a tendency to form covalent compounds, despite being in different periods and groups.
Source: Myschool Past Questions Archive (Record #47338)
Chemistry
UTME / JAMB 2018
Non-Metals & Their Compounds
Suitable reagents for the laboratory preparation of nitrogen are
A
sodium dioxonitrate(III) and ammonium chloride
B
sodium trioxonitrate(V) and ammonium chloride
C
sodium chloride and ammonium trioxonitrate(V)
D
sodium chloride and ammonium di-ozonitrate(III)
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #47328)
Chemistry
UTME / JAMB 2018
Atomic Structure, Orbitals & Nuclear Chemistry
The number of electrons in the valence shell of an element of atomic number 14 is?
A
1
B
2
C
3
D
4
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #47329)
Chemistry
UTME / JAMB 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
What volume of oxygen will remain after reacting 8cm\(^3\) of hydrogen gas with 20cm\(^3\) of oxygen gas?
A
10cm\(^3\)
B
12cm\(^3\)
C
14cm\(^3\)
D
16cm\(^3\)
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
First we need to write the balanced chemical equation:
2H\(_2\) + O\(_2\) → 2H\(_2\)O
Reacting moles: 2 moles : 1 moles 2 moles
Expected reacting Volume: 8 cm\(^3\): 20 cm\(^3\)
Actual reacted Volume: 8 cm\(^3\): 4cm\(^3\) (Based on the balanced equation)
Residual Volume(Expected - Actual): 0cm\(^3\) : 16cm\(^3\)
Therefore, 16cm\(^3\) of Oxygen will remain after reacting 8cm\(^3\) of hydrogen gas with 20cm\(^3\) of oxygen gas.
Source: Myschool Past Questions Archive (Record #47330)
Chemistry
UTME / JAMB 2018
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
If one of the following oxides is heated with hydrogen or carbon using a bunsen burner. it is not reduced to the metal, Which one is it?
A
lead oxide
B
Magnesium oxide
C
Copper oxide
D
Tin oxide
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
The oxides of Potassium, Sodium, Calcium, and Magnesium are not reduced when they react with carbon and hydrogen.
Source: Myschool Past Questions Archive (Record #47331)
Chemistry
UTME / JAMB 2018
Organic Chemistry I: Hydrocarbons & Crude Oil
Diagram
Solution
The lUPAC name for
Attached Figure / Diagram
A
1-methyl pentane
B
3-methylbutane
C
2-methylbutane
D
1-dimethyl propane
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The longest carbon chain is butane, with one substituent attached at carbon number 2
therefore the compound is named 2-methyl butane
Source: Myschool Past Questions Archive (Record #47332)
Chemistry
UTME / JAMB 2018
Reaction Rates & Chemical Equilibrium
mE + nF -----> pG + qH
In the equation shown, the equilibrium constant is given by?
A
\(\frac{[E]^m[F]}{[G]^p[H]^q}\)
B
\(\frac{[E][F]}{[G][H]}\)
C
\(\frac{[G]^p[H]^q}{[E]^m[F]^n}\)
D
\(\frac{[G][H]}{[E][F]}\)
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #47339)
Chemistry
UTME / JAMB 2018
Oxidation, Reduction & Redox Reactions
(I). 3CuO(s) + 2NH3(g) -----> 3Cu(s) + 3H2O(l) + N2(g)
(II). 2NH3(g) + 3Cl2(g) -----> 6HCl(g) + N2(g)
(III). 4NH3(g) + 3O2(g) -----> 6H2O(l) + N2(g)
The reactions represented by the equations above demonstrate the
A
basic properties of ammonia
B
acidic properties of ammonia
C
reducing properties of ammonia
D
oxidizing properties of ammonia
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #47340)
Chemistry
UTME / JAMB 2018
Oxidation, Reduction & Redox Reactions
Solution
The salt that reacts with dilute hydrochloric acid to produce a pungent smelling gas which decolourizes acidified purple potassium tetraoxomanganate (VII) solution is
A
Na\(_2\)SO\(_4\)
B
Na\(_2\)SO\(_3\)
C
Na\(_2\)S
D
Na\(_2\)CO\(_3\)
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
When sodium sulphite (Na₂SO₃) reacts with hydrochloric acid (HCl), it produces sulphur dioxide gas (SO₂), which readily decolourises acidified potassium permanganate (KMnO₄) solution.
Reaction: Na₂SO₃(aq) + 2HCl(aq) → 2NaCl(aq) + H₂O(l) + SO₂(g)
The reaction produces sodium chloride (NaCl), water (H₂O), and sulphur dioxide gas (SO₂). Sulphur dioxide gas (SO₂) is a reducing agent, and when it reacts with acidified potassium permanganate (KMnO₄), it decolourises the purple solution.
Source: Myschool Past Questions Archive (Record #47341)
Chemistry
UTME / JAMB 2018
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
The refreshing and characteristic taste of soda water and other soft drinks is as a result of the presence of
A
carbon(IV)oxide
B
carbon(ll)oxide
C
soda
D
glucose
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #47342)
Chemistry
UTME / JAMB 2018
Organic Chemistry I: Hydrocarbons & Crude Oil
Which of the following are mixtures?
I. Petroleum
II. Rubber latex
III. Vulcanizer's solution
IV. Carbon sulphide
A
I, II and III
B
I, II and IV
C
I and II only
D
I and IV
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #47343)