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(a) (i) ar\(^2\) = \(\frac{1}{4}\) ........(i) ar\(^5\) = \(\frac{1}{32}\) ........(ii) \(\frac{ar^5}{ar^2} = \frac{1}{32} \div \frac{1}{4}\) r\(^3 = \frac{1}{32} \times \frac{4}{1}\) r\(^3 = \frac{1}{32} \times \frac{4}{1}\) r\(^3 = 2^{-3} = (\frac{1}{2})^3\) r = \(\frac{1}{2}\) Since ar\(^2\) = \(\frac{1}{4}\) a(\(\frac{1}{2}\))\(^2\) = \(\frac{1}{4}\) a = 1 The first term is 1 ad the common ratio is \(\frac{1}{2}\) (ii) T\(_7\) = ar\(^6\) = 1 x (\(\frac{1}{2}\))\(^6\) The seventh term = \(\frac{1}{64}\) (b) x = 2 and x = -3 a(2)\(^2\) + b(2) + c = 0 4a + 2b + c = 0 4a + 2b + c = 0.....(i) a(-3)\(^2\) + b(-3) + c = 0 9a - 3b + c = 0.......(ii) Solving eq.(i) and (ii) 4a + 2b + c = 0 -(9a - 3b + c) = 0 -5a + 5b = 0 (x - 2)(x + 3) = 0 x\(^2\) + 3x - 2x - 6 = 0 x\(^2\) + x - 6 = 0 a = 1, b = 1, c = -6

x\(^2\) = 172\(^2\) - 8\(^2\) x\(^2\) = 289 - 64 x\(^2\) = 225 x = \(\sqrt{225}\) x = 15 tan y \(\frac{8}{15}\) 1 + 2 tan y = 1 + 2(\(\frac{8}{15}\)) = \(\frac{1}{1} + \frac{6}{15}\) = \(\frac{15 + 16}{15} = \frac{31}{15}\) \(\frac{\tan y}{1 + 2 \tan y}\) = \(\frac{8}{15} \div \frac{31}{15}\) = \(\frac{8}{15} \times \frac{15}{31} = \frac{8}{31}\) (b) Otobo shares = N60,000 Remainder = N300,000 - N60,000 = N240,000 Ada's share = \(\frac{5}{12}\) x N240,0000 = N100,000 Adeola's share =; = 300,000 - N160,000 = N140,000 Ratio of the money is Otobo : Ada : Adeola 60,000 : 100,000 : 140,000 60 : 100 : 140 6 : 10 : 14 3 : 5 : 7

T\(O\)S = 68\(^o\) x 2 = 136\(^o\) (Angle at centre is twice angle at circumference) T\(R\) = 180\(^o\) - (90 + 68\(^o\)) = 180\(^o\) - 158\(^o\) = 22\(^o\) x = 2 x T\(R\)O = 2 x 22\(^o\) = 44\(^o\) (b) Let the capacity of Tank B = x litres Capacity of Tank A = x + 600 litres If 100 litres is pumoed out of each tank then, (x + 600) - 100 = 3(x - 100) x + 500 = 3x - 300 500 + 300 = 3x - x \(\frac{800}{2} = \frac{2x}{x}\) x = 400 litres Capacity of Tank A = 400 + 600 = 1,000 litres Capacity of Tank B = 400 litres

Flowering plants having both the male and female flowers on the same flower are called Monoecious plants

SECTION C (a(i) Sex of specimen P (cockroach): Male. (ii) Reason: Presence of anal style (b)(i) Habitat of Specimen P (Cockroach) and Specimen Q (Grasshopper): Specimen P (Cockroach): Pit toilet/dark boxes/soak away/wardrobe/kitchen/dark cupboard/book shelves/crevices cracks. Specimen Q (Grasshopper): Garden/farmland/vegetation/grassland. (b(i) Adaptations of Specimens P and Q to their Habitats:, Specimen P (Cockroach): - flat/dorsoventral flattened body; to move between small cracks/spaces/crevices. Jointed legs; for fast movement (to escape from predators); -tiny legs to crawl (membraneous) wings for flight, dark brown colour of body; serves as camouflage (from predators); ;- well developed mandibles/mouth parts; - for feeding; - compound eyes; for vision/sight/wide view hardened forewings/chitinous exoskeleton; for protection; spiracles for gaseous exchange; -antenna for detection Specimen Q (Grasshopper):-(Green) colour of body/for camouflage (from predators), (A pair of) antenna to detect vibrations and smell/sensitivity;-(numerous abdominal) spiracles; for gaseous exchange/breathing ;- well developed mandibles/mouth parts; - for chewing / feeding / tearing Jointed legs for fast movement (to escape from predators); -(membraneous) wings; for flight (from predators); eyes; for vision/sight. ci) Differences between specimens P and Q: Specimen P (Cockroach) Specimen Q (Grasshopper) y -It has brown coloured body Green coloured bod Dorsoventral flattened body Cylindrical body - Short hind leg/limb -Elongated hind leg/limb -Has two pairs of wings One pair of wings - Slender hind leg (s) Large/muscular/stout hind legs - Long antennae Short antennae Spines on every side of hind leg Row of spines on the inner Side of the hind leg (ii) Similarities between Specimens P and Q both have: - membraneous Wings; segmented body; - three body division/head, thorax and abdomen - three pairs of walking legs: have jointed appendages; presence of antennae: -biting chewing mouthparts/mandible;- exoskeleton of chitin: -compound eyes.. (d) (i) Feeding mechanism of Specimen Q (Grasshopper): Biting and chewing (mouthparts). (ii) Food items Specimen Q (Grasshopper):, Feeds on foliage leaves, young/tender stem/green stem/ grass.

Secreting irritating fluid is a behavioral adaptation because it involves an action or response performed by an organism—such as a toad or certain insects—specifically to deter or repel a predator once it is threatened. This behavior serves as a direct defense mechanism to increase the chances of survival during an encounter with a predator.

Aestivation is a period of no activity seen in some animals during period of heat or drought.

When an insect traps movement of leaves, it is a behavioural adaptation for obtaining food.

Gregarious animals are the same species of animal moving together in group.

Spirogyra undergoes holophytic nutrition

One of the raw materials needed by plants to manufacture their food is inorganic substances

Euglena and chlamydomonas are photosynthetic because the possess features of plants which enables them to produce their food.

Symbiotic nutrition involves two organisms of different species living together and deriving nutrients from each other

One of the similarities in plant and animal transport is that materials and hormones are transported in fluid form in both.

Lymph serves as body defence.