Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 526–540 of 29811 verified questions
Sort by:
Chemistry
UTME / JAMB 2025
Matter & Separation Techniques
Solution
Bronze is used in making
A
musical instruments and ornaments
B
coins and medals
C
electromagnets and cutlery
D
aircrafts and ship
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Bronze is widely used for making musical instruments, particularly percussion instruments like cymbals, bells, and gongs, due to its excellent acoustic properties and durability. It is also used for the windings of strings on pianos and guitars.
B. coins and medals: Bronze is indeed used for coins and medals, but it is also widely used for musical instruments and ornaments/sculptures, making option A and B both viable. However, some sources group musical instruments and ornaments together as a primary use case.
C. electromagnets and cutlery: Electromagnets typically use copper wire, not bronze. Cutlery is generally made from stainless steel or silver, not bronze.
D. aircrafts and ship: Aluminum and its alloys are the primary materials for aircraft construction due to their lightweight properties. While bronze is used in certain marine applications like ship propellers and fittings due to its corrosion resistance, it is not the main material for the entire ship structure, and it is not a primary material for aircrafts.
Source: Myschool Past Questions Archive (Record #74393)
Chemistry
UTME / JAMB 2025
Stoichiometry & Mole Concept
Solution
Find the hydrogen ion, H\(^+\) concentration and hydroxide ion, OH\(^-\) concentration in 0.06 moldm\(^{-3}\) solution of H\(_2\)SO\(_4\).
A
1.2 x 10\(^{-2}\) ; 8.3 x 10\(^{-13}\)
B
1.2 x 10\(^{-1}\) ; 8.3 x 10\(^{-13}\)
C
1.2 x 10\(^{-1}\) ; 8.3 x 10\(^{-14}\)
D
1.2 x 10\(^{-2}\) ; 8.3 x 10\(^{-14}\)
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Sulphuric acid (H\(_2\)SO\(_4\)) is a strong acid that fully dissociates in water, yielding two moles of hydrogen ions (H\(^+\)) for every one mole of acid, especially in dilute solutions.
[ H\(^+\) ] = 2 X [H\(_2\)SO\(_4\)]
= 2 X 0.06
[ H\(^+\) ] = 0.12 = 1.2 X 10\(^{-1}\) moldm\(^{-3}\)
To get the [OH\(^-\)], recall that the product of the hydrogen ion concentration, [H+] and the hydroxide ion concentration ([OH−]) in an aqueous solution at standard temperature is a constant, known as the ion product of water (Kw), which is approximately1.0 x10\(^{-14}\)mol\(^2\)/dm\(^6\).
K\(_w\) = [ H\(^+\) ] [OH\(^-\)]
[OH\(^-\)] = \(\frac{K_w}{[H^+]}\)
= \(\frac{1.0 x10^{-14}}{0.12}\)
[OH\(^-\)] = 8.33 x 10\(^{-14}\)
Source: Myschool Past Questions Archive (Record #74394)
Chemistry
UTME / JAMB 2025
Acids, Bases, and Salts
Solution
After breathing in a test tube that contains acidified K\(_2\)Cr\(_2\)O\(_7\), a man noticed a change in the colour of the acidified K\(_2\)Cr\(_2\)O\(_7\) from orange to green. This suggests the presence of
A
alkanoic acid
B
alkanal
C
alkanol
D
alkanone
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The test is commonly used in breathalyzers to detect alcohol consumption, where the orange-to-green change confirms the presence of alcohol.
The colour change of acidified K\(_2\)Cr\(_2\)O\(_7\)from orange to green upon breathing into a test tube indicates the presence of an alkanol (specifically ethanol). The ethanol is oxidized to ethanal/acetic acid while the dichromate ions (Cr\(_2\)O\(_7\)\(^{2−}\)) are reduced to green chromium(III) ions (Cr\(^{3+}\)).
Source: Myschool Past Questions Archive (Record #74395)
Chemistry
UTME / JAMB 2025
Atomic Structure and Periodic Table
Solution
The 5\(^{th}\) member of an alkyne series is
A
C\(_5\)H\(_8\)
B
C\(_5\)H\(_{10}\)
C
C\(_6\)H\(_{12}\)
D
C\(_6\)H\(_{10}\)
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
The general formula for the alkyne homologous series is C\(_n\)H\(_{2n−2}\), where n is the number of carbon atoms. The first member of the series has n=2 (ethyne), as a minimum of two carbon atoms is required for a triple bond.
The 5th member of the alkyne series is hexyne (C\(_6\)H\(_{10}\)).
Source: Myschool Past Questions Archive (Record #74882)
Chemistry
WAEC / WASSCE 2025
Stoichiometry & Mole Concept
Solution
Which of the following pairs of gases cannot be collected by downward delivery?
A
SO\(_2\) and NH\(_3\)
B
CO and N\(_2\)
C
Cl\(_2\) and N\(_2\)
D
SO\(_2\) and N\(_2\)
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Downward delivery (also known as upward displacement of air) is a method used to collect gases that are denser than air. Air has an average relative molecular mass of approximately 29.
CO (Carbon Monoxide) has a molecular mass of 28, making it slightly lighter than air. N\(_2\) (Nitrogen) has a molecular mass of 28, making it slightly lighter than air.
Because both gases in this pair are lighter than air, they will rise rather than settle at the bottom of a gas jar, meaning they cannot be collected by downward delivery.
Source: Myschool Past Questions Archive (Record #76996)
Chemistry
WAEC / WASSCE 2025
Atomic Structure and Periodic Table
Solution
Nickel is used in the hydrogenation of alkenes because it
A
Increases the yield of the product
B
lowers the activation energy of the reaction
C
makes the reaction more exothermic
D
prevents a reverse reaction from occuring
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Nickel acts as a catalyst in the hydrogenation of alkenes. Catalysts function by providing an alternative reaction pathway with a lower activation energy. By lowering the energy barrier, a larger fraction of reactant molecules have sufficient energy to react at a given temperature, which significantly increases the reaction rate. In this specific reaction, nickel adsorbs hydrogen onto its surface, weakening the H-H bonds and facilitating their addition to the alkene.
Source: Myschool Past Questions Archive (Record #76997)
Chemistry
WAEC / WASSCE 2025
Electrochemistry and Redox
Solution
Aluminum is extracted by
A
electrolysis of the purified ore
B
froth floatation of the smelted ore
C
reduction of the ore with coke in a furnace
D
roasting the ore in excess supply of air
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Aluminum is a highly reactive metal, placing it high on the reactivity series. Because it forms very stable oxides, it cannot be extracted from its ore (bauxite) using standard chemical reducing agents like carbon or coke. Instead, the industrial extraction process is by electrolysis of the purified ore.
Source: Myschool Past Questions Archive (Record #76998)
Chemistry
WAEC / WASSCE 2025
Matter & Separation Techniques
Solution
Which of the following gases is used in fire extinguishers?
A
Carbon(IV)oxide
B
Nitrogen(IV)oxide
C
Carbon(II)oxide
D
Sulphur(IV)oxide
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Carbon(IV)oxide, commonly known as carbon dioxide (CO\(_2\)), is the primary gas used in fire extinguishers because it is non-combustible and denser than air. When released, it displaces the oxygen surrounding the fire, effectively "suffocating" the flames by removing one of the three essential components (fuel, heat, and oxygen) needed for combustion.
Source: Myschool Past Questions Archive (Record #77016)
Chemistry
WAEC / WASSCE 2025
Atomic Structure and Periodic Table
Solution
Both Na\(^+\) and K\(^+\) have
A
tendency to give electrons
B
positive reduction potential
C
tendency to accept electrons
D
negative oxidation potential
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Sodium (Na\(^+\)) and potassium (K\(^+\)) are cations, meaning they have already lost an electron to achieve a stable noble gas configuration. Because they are positively charged, they have a tendency to accept electrons to return to their neutral elemental state (Na or K), a process called reduction.
Conversely, option A, which is the tendency to give electrons describes the neutral atoms (Na and K) which are strong reducing agents that readily lose their single valence electron. Once they become Na\(^+\) and K\(^+\) ions, they have a stable octet and do not tend to lose further electrons.
The correct answer is option C.
Source: Myschool Past Questions Archive (Record #77017)
Chemistry
WAEC / WASSCE 2025
Matter & Separation Techniques
Solution
If a gas occupies a volume of 400cm\(^3\) at a temperature of 400K and a pressure of 1 atm, at what temperature and pressure would its volume be 200cm\(^3\)?
A
800 K and 1 atm
B
800 k and 0.5 atm
C
200 k and 1 atm
D
200 k and 0.5 atm
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
To determine the correct conditions, we use the Combined Gas Law, which relates the pressure, volume, and temperature of a fixed amount of gas:
\(\frac{P\(_1\)V\(_1\)}{T\(_1\)}\) = \(\frac{P\(_2\)V\(_2\)}{T\(_2\)}\)
Given:
V\(_1\) = 400 cm\(^3\) , T\(_1\) = 400 K , P\(_1\) = 1 atm
V\(_2\) = 200 cm\(^3\) , T\(_2\) = ? , P\(_2\) = ?
We need to find which pair of pressure and temperature satisfies the equality
P\(_1\)V\(_1\)/T\(_1\) = P\(_2\)V\(_2\)/T\(_2\)
First, calculate the initial constant:
\(\frac{1 atm . 400cm{^3}}{400K}\) = 1
Now, test Option C:
P\(_2\) = 1 atm
V\(_2\) = 200cm\(^3\)
T\(_2\) = 200 K
\(\frac{1 atm . 200cm{^3}}{200K}\) = 1
Options A, B and D will not give you 1.
Source: Myschool Past Questions Archive (Record #77018)
Chemistry
WAEC / WASSCE 2025
Atomic Structure and Periodic Table
Solution
The nucleus of a hydrogen atom consists of
A
one proton only
B
one proton and one neutron
C
one neutron only
D
one electron only
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The nucleus of an ordinary hydrogen atom (specifically the most abundant isotope, protium) consists of a single proton.
Atomic Number: Hydrogen has an atomic number of 1, meaning it contains exactly one proton.
Source: Myschool Past Questions Archive (Record #77020)
Chemistry
WAEC / WASSCE 2025
Atomic Structure and Periodic Table
Solution
If acidified K\(_2\)Cr\(_2\)O\(_7\) acts as an oxidizing agent, the colour changes from
A
orange to red
B
yellow to green
C
orange to green
D
yellow to red
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Acidified potassium dichromate (K\(_2\)Cr\(_2\)O\(_7\)) is a strong oxidizing agent that undergoes a distinct colour change during redox reactions. In an acidic medium, the chromium is present in the dichromate ion (Cr\(_2\)O\(_7\)\(^{2-}\)), where it has an oxidation state of +6. This ion gives the solution its characteristic orange colour.
When it acts as an oxidizing agent, it accepts electrons and is reduced to chromium(III) ions (Cr\(^{3+}\)), where the oxidation state is +3. The formation of Cr\(^{3+}\) ions (often as chromium(III) sulfate in sulphuric acid solutions) turns the solution green.
Source: Myschool Past Questions Archive (Record #77021)
Chemistry
WAEC / WASSCE 2025
Matter & Separation Techniques
Solution
Which of the following elements is a metalloid?
A
Aluminium
B
Selenium
C
Phosphorus
D
Sodium
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
While standard chemical definitions usually limit metalloids to a list of six elements (Boron, Silicon, Germanium, Arsenic, Antimony, and Tellurium), Selenium is frequently classified as a metalloid in various educational contexts and standardized tests because it exhibits intermediate properties between metals and nonmetals. Though more strictly defined as a nonmetal in some academic circles, it is the only viable answer among the choices provided that displays "metalloid-like" or semiconducting behavior.
Source: Myschool Past Questions Archive (Record #77022)
Chemistry
WAEC / WASSCE 2025
Matter & Separation Techniques
Solution
Iodine could be separated from the mixture of iodine and Calcium chloride by
A
Evaporation
B
Sublimation
C
fractional distillation
D
fractional crystallization
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Iodine can be separated from calcium chloride using sublimation because of the distinct physical properties of the two substances:
1. Iodine is a sublimable solid, meaning it transitions directly from a solid state to a gaseous state upon heating without passing through a liquid phase.
2. Calcium chloride is a non-sublimable ionic salt with a very high melting point, so it remains in the solid state while the iodine vapourizes.
Source: Myschool Past Questions Archive (Record #77024)
Chemistry
WAEC / WASSCE 2025
Matter & Separation Techniques
Solution
Sodium chloride is used in the following processes except
A
treatment of water
B
manufacturing of chloride
C
preservation of food
D
separation of soap glycerol
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Sodium chloride (common salt) is a versatile chemical used in various industrial and domestic processes. While it has many applications, it is not typically used for the primary treatment of water (such as purification or filtration of polluted water).
Source: Myschool Past Questions Archive (Record #77025)