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Most metals do not liberate hydrogen gas when reacting with nitric acid (HNO₃) because nitric acid is a strong oxidizing agent and oxidizes the produced hydrogen gas to water. However, highly reactive metals like Magnesium (Mg) and manganese (Mn) are exceptions. They react with very dilute and cold nitric acid to produce hydrogen gas. The reaction with magnesium is: Mg\(_{(s)}\) + 2HNO\(_3\)(aq, very dilute) → Mg(NO\(_3\))\(_2\)\(_{(aq)}\) + H\(_2\)\(_{(g)}\) A. Cu (Copper) is below hydrogen in the metal reactivity series and cannot displace hydrogen from any dilute acid, including dilute HNO₃. C. Ca (Calcium) is a reactive metal and would likely behave similarly to magnesium with very dilute nitric acid, potentially liberating hydrogen. However, Mg is the most widely cited and confirmed answer for this specific question in the provided sources, often alongside Manganese. D. Zn (Zinc) reacts with dilute nitric acid, but typically produces oxides of nitrogen (like N\(_2\)O or NO), not hydrogen gas (except possibly under extremely specific, very dilute and cold conditions which are less commonly referenced than Mg).

The compound CH\(_3\)CH\(_2\)COOCH\(_2\)CH\(_3\) is an ester. The IUPAC naming for esters follows the format alkyl alkanoate. The alkyl portion comes from the alcohol-derived part (the carbon chain attached to the single-bonded oxygen, −O−CH\(_2\)CH\(_3\)), which has two carbon atoms, making it an ethyl group. The alkanoate portion comes from the carboxylic acid-derived part (the carbon chain including the carbonyl group,CH\(_3\)CH\(_2\)COO−), which has three carbon atoms (eth- plus a methyl group), making it a propanoate group (from propanoic acid). Combining these parts gives the name ethyl propanoate. - option C

Given : Mass of Iron reacted, m = 5g time taken, t = 10 mins However, we must convert the time from mins to hour because of the examiner's demand. Thus, t = \(\frac{10}{60}\) hr = 0.167 Rate of reaction = \(\frac{mass of reacted iron}{time taken}\) = \(\frac{5}{0.167}\) = 29.94 = 30 g/hr The correct answer is option B.

Evaluating petrol from crude oil prevents issues like engine knocking, which is also known as pinking, ensures proper volatility for starting, controls harmful sulphur content, and maintains desired octane ratings, all crucial for engine performance, efficiency, and environmental compliance, ensuring it meets specific standards before sale. Pinking (Pre-ignition) is the process whereby straight-chain alkanes (like heptane) in raw petrol ignite too early under compression, causing engine knocking (pinking). Reforming: This process improves quality by rearranging molecules into branched alkanes and aromatics (like iso-octane), raising the octane rating and preventing pinking. Cracking: Breaks large, heavy hydrocarbons (from heavier fractions) into smaller, more valuable gasoline-range molecules, increasing the quantity of petrol, but the resulting mix might still need reforming. Pyrolysis: An extreme thermal cracking (high heat) that produces basic petrochemical building blocks (like ethylene, propylene) for plastics, not finished petrol, and is energy-intensive.

Aluminum (Al) is widely used as a packaging material, especially in the form of foil, cans (for beverages and food), and as a layer in laminated packaging, due to its low cost, malleability, and excellent barrier properties against light, moisture, and oxygen. It also forms a protective oxide layer that prevents corrosion. Cu (Copper): Copper is not typically used for food packaging due to its reactivity and potential to leach into food, which can be harmful. Fe (Iron): Iron is the primary component of steel used in cans (often as tinplate or tin-free steel), but it is usually coated to prevent rust and interactions with food. Aluminum (Al) is more commonly and widely used for flexible packaging like foils and for many beverage cans without needing extensive internal coatings. Na (Sodium): Sodium is a highly reactive alkali metal that reacts violently with water and is unsuitable and dangerous for use as a packaging material.

The general gas law equation, often called the Ideal Gas Law, is PV = nRT, describing the relationship between a gas's Pressure (P), Volume (V), amount in mole(n), Ideal gas constant(R), and Temperature (T), relating all four key properties in one formula. A related form, the combined law, for a fixed mass of gas is (P₁V₁)/T₁ = (P₂V₂)/T₂, used to find changes in one variable when others change. However, the equation given in the question will give PV = nRT, on rearrangement.

An alkanoic acid is a type of saturated carboxylic acid with the general molecular formula C\(_n\)H\(_{2n}\)O\(_2\). Given: empirical formula is CH\(_2\)O. Recall, (Empirical formula) x = Relative molecular mass, since the molecular formula is a whole-number multiple of the empirical formula, (CH\(_2\)O)?, which expands to C\(_x\)H\(_{2x}\)O\(_x\). Equating the general formula for an alkanoic acid to the derived empirical formula general form, we find x = 2 for the oxygen atoms. Thus, the molecular formula is C\(_2\)H\(_4\)O\(_2\). i.e C\(_n\)H\(_{2n}\)O\(_2\) = C\(_x\)H\(_{2x}\)O\(_x\) The relative molecular mass with the empirical formula CH\(_2\)O can be calculated using the following expression: Relative Molecular Mass = (2\timesC) + (4\timesH) + (2\timesO) Substituting the values: Relative Molecular Mass = (2 x12) + (4 x 1) + (2 x16) = 60 Relative Molecular Mass=24+4+32Relative Molecular Mass equals 24 plus 4 plus 32 Relative Molecular Mass=24+4+32

Al\(^{3+}\) + 3e\(^-\) → Al 3e\(^-\) = 3F 3 F produced 27g of Al 3 x 96,500C produced 27g Al (18 x t) C will produce 9g Al (Recall that Q = I x t) By simple proportion, \(\frac{3 x 96500}{18t}\) = \(\frac{27}{9}\) t = \(\frac{9 x 3 x 96500}{18 x 27}\) t = 5,361.11 seconds Since the option is in minutes, we have to convert 5,361 seconds to minutes by dividing by 60 (60 sec = 1 min) t = \(\frac{5361}{60}\) t = 89.35 minutes The correct answer is option B.

Concentrated sulfuric acid (H\(_2\)SO\(_4\)) has a very strong affinity for water and readily absorbs water molecules from other substances or chemical reactions, thus acting as a powerful dehydrating agent. This property is notably demonstrated in the "charring of sugar" experiment, where it removes the water from sucrose (C\(_{12}\)H\(_{22}\)O\(_{11}\)), leaving behind a column of black carbon. In many organic synthesis reactions, it is used to remove water. A. It reacts with metals to give a salt and hydro gas: While dilute sulphuric acid reacts with reactive metals (like zinc or iron) to produce hydrogen gas, concentrated sulphuric acid is a strong oxidizing agent and reacts differently, often producing sulphur dioxide gas instead of hydrogen. C. It neutralizes alkali: Concentrated sulphuric acid is a very strong acid and, like all acids, it reacts with alkalis (soluble bases) in a neutralization reaction to form a salt and water. However, its primary function is not limited to this and its prominent characteristic function, as listed in the options, is its dehydrating property. D. It produces a cryolite precipitate with basic solution: This statement is incorrect. Sulphuric acid does not produce a cryolite precipitate (cryolite is a mineral, sodium hexafluoroaluminate, Na\(_3\)AlF\(_6\)) with basic solutions.

Oxidation is defined as the loss or removal of electrons from a substance. A common mnemonic device used to remember this is "OIL RIG", which stands for "Oxidation Is Loss", "Reduction Is Gain" (of electrons). When a substance is oxidized, its oxidation number increases, indicating a loss of negatively charged electrons. A. hydrolysed and D. hydrated: Hydrolysis is a chemical process involving the splitting of a molecule by the addition of water, while hydration is the addition of water molecules to a substance. These processes are not the general definition of what happens to electrons during oxidation reactions. C. added: The addition or gain of electrons is the definition of a reduction reaction, which occurs simultaneously with oxidation in a redox reaction. The correct answer is option B - removed

To determine the IUPAC name for the compound (CH\(_3\))\(_2\)CHCH(OH)CH\(_2\)C(CH\(_3\))\(_3\), follow these steps: Identify the longest carbon chain including the hydroxyl (-OH) group: The longest continuous chain containing the hydroxyl group has 6 carbon atoms, so the parent alkane name is hexane, and the compound is a hexanol. Number the carbon chain: Start numbering from the end closest to the hydroxyl group to give the -OH group the lowest possible number. Numbering from left to right puts the -OH on carbon. The chain is: C1-C2-C3(OH)-C4-C5-C6. The groups are attached as: two methyls on C2, two methyls on C5. Identify and name the substituents: There are three methyl groups in total. One is on carbon 2, and two are on carbon 5. Combine the information: The substituents are listed with their positions. There are three methyl groups, so we use the prefix "tri-". The full name is 2,5,5-trimethylhexan-3-ol.

The primary active ingredient in most modern automotive antifreeze is ethylene glycol (also known as ethanediol or glycol), or the less toxic propylene glycol. However, historically and in some specific formulations, propanetriol, more commonly known as glycerol (or glycerine), has also been used as an antifreeze agent. Propanetriol is effective, non-toxic, and can withstand high temperatures. Given the options provided, propanetriol is the correct answer - option A. B. propanol (also known as 1-propanol) is an alcohol and can be used as an antifreeze in specific applications (like windscreen washer fluid de-icers), but it is generally not used as the primary, long-term antifreeze in a vehicle's radiator due to its volatility (it evaporates easily). C. propanone (also known as acetone) is a solvent and not used as an antifreeze in vehicle radiators. D. propanal (also known as propionaldehyde) is an aldehyde primarily used in chemical synthesis and is not an antifreeze agent for vehicle cooling systems.

Magnesium tetraoxosulphate(VI) salt, commonly known as magnesium sulphate or Epsom salt, is a saline laxative used for short-term relief of constipation. When taken orally, magnesium sulphate acts as an osmotic purgative or saline laxative. It draws water into the intestines, softening the stool and increasing bowel movements. A. disinfectant: Disinfectants are chemical substances used to destroy microorganisms on inert surfaces. Magnesium sulfate is not primarily used as a disinfectant. B. plasticizer: Plasticizers are additives used to increase the plasticity or fluidity of a material. This is not a use of magnesium sulphate. C. fertilizer: While magnesium sulfate is used in agriculture as a fertilizer to add magnesium and sulphur to the soil, its use as a laxative is a more common and direct application in a general/medical context, as implied by the multiple-choice question format asking for the most common use among the given options. In the context of the typical educational question, the medical use is often the intended answer, which is option D - Laxative

Permalloy is primarily an iron-nickel magnetic alloy, typically consisting of about 80% nickel and 20% iron. This specific composition gives permalloy its characteristic high magnetic permeability and low coercivity, making it useful in applications like magnetic shielding and electrical transformers. The correct option is A. Nickel. B. Tin: Tin is a primary component in bronze (a copper-tin alloy) and in some types of solder, but not the main secondary constituent of permalloy. C. Chromium: Chromium is a key element in stainless steel (an alloy of iron, chromium, and sometimes nickel) to provide corrosion resistance, not the primary alloying element with iron in permalloy. D. Copper: Copper is the primary component in brass and bronze. While some specific permalloy variations may contain small amounts of copper, it is not the main constituent with iron in the general definition of permalloy.

When an inflated balloon is placed in a freezer, the temperature of the gas inside decreases. According to the kinetic molecular theory and Charles's Law: Gas molecules lose kinetic energy and move more slowly. This reduced motion results in less frequent and less forceful collisions with the inner walls of the balloon. The overall effect is a decrease in the internal pressure of the gas. Since the external atmospheric pressure remains constant, the balloon is compressed and shrinks in volume until the internal and external pressures equalize, resulting in a smaller balloon.