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(a) Type of Fruits of Specimens E/Pawpaw fruit, F/Tomato fruit and H/Pod of Pride of Barbados: (b) Placentation of Fruits of Specimens E/Pawpaw fruit and F E: Berry F: Berry H: Legume. (b) Placentation of Fruits of Specimens E/Pawpaw fruit and F Tomato fruit. E: Parietal F: Axile. (c) Agents of Dispersal of Specimens E/Pawpaw fruit, F/ Tomato fruit and H/Pod of Pride of Barbados: E: Man/Human/animal/any correctly named animal F: Man/Human /animal/any correctly named animal H: Explosive mechanism (d)i) Explanation of how Specimen E is dispersed:-The epicarp is brightly colored;-Which attracts man/humans/ animal/correctly named animal; -To eat its succulent parts (mesocarp and endocarp);-then eventually -Which attracted man/humans/ throws away its seed/plants it. (ii) Nutrient present in Specimen E: -Vitamins; -Carbohydrate -Protein/amino acid/calcium/magnesium/potassium/zinc/phosphorus/iron/ Carbohydrate: fructose/sucrose/sugars copper/manganese; -Mineral salts; -Water; -Riboflavin (e) Color of Specimen H: Green. (ii) Significance of the Color of Specimen : It indicates that the fruit contains chlorophyll / is photosynthetic. (f(i)) Type of Placentation of Specimen H: Marginal.

x = 180\(^o\) - (52\(^o\) + 70\(^o\)) = 180\(o\) - 122\(^o\) = 58\(^o\)

E\(G\)R = 50\(^o\) (Alternative angles) n + 55\(^o\) + 50\(^o\) = 180\(^o\) (Sum of angles on a straight line) n = 180\(^o\) - 105\(^o\) n = 75\(^o\)

\(\frac{0.42 \div 2.5}{0.5 \times 2.05} = \frac{0.168}{1.025}\) = 1.639 x 10\(^{-1}\)

T = {2, 3, 5, 7} M = {1, 3, 5, 7, 9} \(\mu\) = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} T\(^{\prime}\) = = {1, 4, 6, 8, 9, 10} M\(^{\prime}\) = {2, 4, 6, 8, 10} (T\(^{\prime}\) \(\cap\) M\(^{\prime}\)) = {4, 6, 8, 10}

Tan 52\(^o\) = \(\frac{32}{\text{|XZ|}}\) |XZ| = \(\frac{32}{Tan 52^o}\) = 25cm

Number of students that scored above 40 = 55 + 45 + 30 + 15 + 5 = 150 students.

Mean = \(\frac{8 + 18 + 10 + 14 + 18 + 11 + 13 + 14 + 13 + 17 + 15 + 8 + 16 + 13}{14}\) Mean = \(\frac{188}{14}\) Mean = 13.4 Number above the mean is 7

(\(\frac{2}{5} \times \frac {3}{5}) + (\frac{3}{5} \times \frac{2}{5})\) \(\frac{6}{25} + \frac{6}{25} = \frac{12}{25}\)

L\(_1\) = 100cm, T\(_1\) = 200^\circC L\(_2\) = 99.4cm, T\(_2\) = ? \alpha 2 \times 10\(^{-5}\) C\(^{-1}\) \alpha = L\(_2\) - L\(_1\) L\(_1\)(T\(_2\) - T\(_1\)) 2 \times 10\(^{-5}\) = 110 - 99.4 100(200 - T\(_2\)) = 0.6 100(200 - T\(_2\)) 2 \times 10\(^{-5} \times 100(200 - T_2\)) = 0.6 200 - T\(_2\) = 0.6 0.002 = 300^\circC T\(_2\) = 200 - 300 = -100^\circC

The range of usefulness of the thermometer is set by the boiling point of the liquid used. In the case of the ethanol-filled thermometer, the upper limit for measurement is 78 ^\circC (172.4 ^\circF), which makes it useful for measuring daytime, nighttime and body temperatures, although not for anything much hotter than these.

Angular speed of the electron (W) w = \(\frac{Velocity}{Radius} = \frac{V}{R}\) = \(\frac{2.0 \times 10^6}{6.1 \times 10^{11}}\) = 3.28 x 10\(^{16}\) rads\(^{-1}\)

M\(_r\)(90 - 50) = 0.2(100 - 90) 40M\(_r\) = 0.2 \times 10 M\(_r\) = \(\frac{2}{40}\) = 0.05kg

An elastic collision is an encounter (collision) between two bodies in which the total kinetic energy of the two bodies remains the same.

n = 200, S = 132 rev/min, v = 350m/s\(^2\) f = ns = 200 \times 132 rev min \times 1min 60s = 440Hz \lambda = v f = 350 440 = 0.795m