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Heterotrophic nutrition is a type of nutrition in which an organism obtains its food by consuming organic matter from other organisms. In the case of pitcher plants, they capture and digest insects as a source of nutrients to supplement their diet, especially in nutrient-poor environments. This carnivorous adaptation is a specialized form of heterotrophic nutrition, as the pitcher plant relies on consuming other living organisms (insects) to meet its nutritional needs. The pitcher plant is a carnivorous plant that has modified leaves forming pitcher-like structures.

Paternity testing, also known as DNA testing for paternity, is a reliable and accurate method used to determine the biological father of a child. It is based on the analysis of DNA (deoxyribonucleic acid), which is the genetic material found in cells. Every individual inherits their DNA from their biological parents, half from the mother and half from the father.

Mutation is the process by which there is a permanent alteration in the DNA sequence of an organism's genome. These changes can occur due to various factors such as exposure to radiation, chemicals, or errors during DNA replication. Mutations can happen in somatic cells, which affect only the individual, or in germ cells (egg or sperm cells), which can be passed on to offspring.

a.Classification of living things is the grouping/arrangement of organisms; with similar characteristics based on structural/genetic/cellular/evolutionary trends; for easy identification. bi. -cause various plant/animal diseases; -act as decomposers; -recycle nutrients; -bring about fermentation in breweries; -used in baking industries; -serve as source of food; -are used in pharmaceutical industries/production of antibiotics/vitamins; -destroy various substances/cloth/paper/wood/food bii. -are involved in nutrient recycling; -purify the environment/reduce greenhouse effects; -provide shade/shelter; -provide food; -provide oxygen; -prevent erosion; -are sources of timber for building/construction; -provide materials for pharmaceuticals/production of drugs. c. phyla of Kingdom Animalia Examples Porifera Sponges,venus flower basket Cnidaria/coelenterata Hydra,obelia,sea anemone,jelly fish,aurelia,coral Platyhelminthes Liverfluke,tapeworm,schistosoma,planaria Nematoda Whipworm,ascaris,guinea worm,hookworm,wucheria Annelida Marine worm, leech,earthworm,lugworm,seaworm,bobbit worm, fireworm. Mollusca Snail, bivalve,slug,octopus,clam,oyster,squid Arthropoda Scorpion,spider,butterfly,housefly,cockroach,crab,crayfish,grasshopper,centipede,millipede,ant. Echinodermata Starfish,sea lily, sea urchin,sea cucumber,brittle star,sea star. Chordata Fish,frog,bird,man,cat,tiger,lion,dog,salamander,alligator,snake,giraffe

a. Element Function in plants Effect of deficiency in plants Iron necessary for the synthesis of chlorophyl/protein Chlorosis/yellowing of leaves,poor growth Molybdenum Converts nitrogen to amino acids Stunted growth,pale leaves potassium Protein synthesis,formation of cell membrane,crop maturation/activates respiration,photosynthesis Premature death of plant/leaf margin turns yellow/brown; copper Activates enzymes for respiration,carbohydrate metabolism/photosynthesis Pale/wilted/spotted leaves Nitrogen Necessary for the formation of chlorophyll/amino acids/protein Poor/stunted growth,yellowing of leaves,poor flower formation b. -Carbohydrate; -Protein; -Lipids/fats and oil -Vitamin. c(i)-Takes in/receives food; -Contains the teeth that chew/masticate the food;to increase the surface area of food particles; -Contains salivary gland that secretes saliva that moistens the food; -it also secretes the enzyme ptyalin which breaks down starch to maltose; -Contains the tongue which tastes/rolls the food into bolus for swallowing. c(ii). -Receives the food as chyme from the stomach; -Receives pancreatic juice from pancreas -Receives bile from the liver which reduces surface tension/emulsifies fats and oil; -Contains amylase in pancreatic juice which hydrolyses starch to maltose; -Contains trypsin which breaks down proteins to polypeptides; -Contains lipase which breaks down fats and oil to carboxyl acid and glycerol; -Provides large surface area for absorption of some digested food/vitamins and nutrients. c(iii). -Temporarily stores food; -Secretes dilute HCI/hydrochloric acid which destroys bacteria; -Churns food; -Contains enzymes which start the digestion of protein d. Glucose and fructose are produced.

(3a) I: Saprophytism II: Commensalism III: Mutualism IV: Predation V: Parasitism (b). B- Prey, G- Predator (c). B: Antelope/goat/sheep/cow/rabbit/guinea pig/rat/ C: Remora fish D: Shark E: Hermit crab F: Sea anemone G: Lion/tiger/leopard/cat/dog/snake/hawk/eagle/ H: Tapeworm/tick/louse/Plasmodium I: Ascaris J: Human/pig/cattle/cow/sheep/dog/cat (di). Saprophytism (ii). It is involved in nutrient recycling/replenishment of nutrients in the ecosystem. (ei). -Mushroom/Mucor/Rhizopus/Yeast; -Pseudomonas/Bacillus/Clotridium/Enterobacter|Escherichia spp./E.coli/Salmonella spp (ii). Fungi/Bacteria/mold/mould

a. X Bt Bt Bt Bt bT BbtT BbtT BbtT BbtT bT BtbT BbtT BbtT BbtT bT BbtT BbtT BbtT BbtT bT BbtT BbtT BbtT BbtT (b) i.black fur and short tail-0 ii. brown fur and long tail-0 iii. black fur and long tail-16 iv. brown fur and short tail-0 (c) i.Pollen grain: 10 ii. Guard cell: 20 iii. Ovule: 10 iv. Root cell: 20

ai. Organs with sensory receptors; that detect changes from the environment;and relay the impulses to the nervous system;for interpretation and appropriate response sent to the effector organ. ii. -Tongue; -Nose; -Skin; bi. -Agama lizard/lizard; -Leopard/tiger; -Jaguar; -Lion; -Monkey; -Chimpanzee/baboon; -Dog; -Cat; -Male Tilapia. ii. -Termite; -Human; -Gibbon; -Domestic fowl/duck/pigeon; -Fish; -Spider;- monkey,- toad; ci. Both have -yolk; -embryo; -vitelline membrane cii. Eggs of toads Eggs of birds Surrounded by jelly coat surrounded by calcareous shell; Relatively smaller Relatively larger Shell membrane absent Shell membrane absent Presence of black part No black part Eggs are laid in chains Eggs are laid in single piece Many/numerous eggs One egg at a time Transparent Opaque Airspace absent Airspace present Yolk not suspended in chalaza Yolk suspended in chalaza d. Organisms involved in the nitrogen cycle One role of organism Animal Excrete nitrogenous compounds,Eat proteins in plant,Die,decay to form ammonium compound; Plant Absorbs nitrate from soil/Die/decay to form ammonium compound; Putrefying bacteria break down dead plants and animals Azotobacter Converts atmospheric nitrogen to nitrate Rhizobium Converts atmospheric nitrogen to nitrates Nitrobacter Converts nitrites to nitrate. Nitrosomonas Converts ammonium compounds to nitrites. Pseudomonas converts amino compounds to ammonium compounds e. Two modes of heterotrophic nutrition Two examples of organisms that can carry out mode of nutrition Holozoic Human,domestic fowl,dog,cat,goat,sheep,cow,snake,lion,rabbit,amoeba Parasitic lice, tick,tapeworm,liverfluke,guinea worm,hookworm. Saprophytic fungi,mushroom,soil bacteria,yeast,rhizopus,mucor.

Check: (2a-3b) (2a+3b) 4a\(^2\) + 6ab - 6ab - 9b\(^2\) 4a\(^2\) - 9b\(^2\)

5x + 3y=4 5x-3y= 2 Using elimination method 5x + 3y=4 → 5x + 3y=4 -[5x-3y= 2] → -5x +3y= -2 6y = 2 y → 1/3 and x = 3/5 solving (25x\(^2\) -9y\(^2\)) 25 * [3/5]\(^2\) -9 * [1/3]\(^2\) 25 * \(\frac{9}{25}\) - 9 \(\frac{1}{9}\) 9 - 1 = 8

\(\frac{2-18m^2}{1+3m}\) = \(\frac{2[1-9m^2]}{1+3m}\) \(\frac{2[1-3m][1+3m]}{1+3m}\) 2[1-3m]

Since the mean of the two numbers x and y is: \(\frac{x+y}{2}\) = 4 x+y =2 * 4 x+y = 8 then we get: \(\frac{x+2x+y+2y}{4}\) =(\(\frac{3x+3y}{4}\)) = 3(\(\frac{x+y}{4}\)) → 3(\(\frac{8}{4}\)) = 3 * 2 = 6

Where sin \theta = \(\frac{opp}{hyp}\) → \(\frac{-3}{5}\) opp = -3, hyp = 5 using pythagoras formula hyp\(^2\) = adj\(^2\) + opp\(^2\) adj\(^2\) = hyp\(^2\) - opp\(^2\) adj\(^2\) = 5\(^2\) - 3\(^2\) → 25 - 9 adj\(^2\) = 16 adj = 4 cos \theta = \(\frac{adj}{hyp}\) → \(\frac{4}{5}\) In third quadrant: cos \theta is negative → - \(\frac{4}{5}\)

Using line LZ with angles sum = 180º : ∠MNY = 180º - (g + h)º or 180º - gº - hº

Given that sec\(^2\)\theta + tan\(^2\)\theta = 3 Where sec\(^2\)\theta = 1 + tan\(^2\)\theta : 1 + tan\(^2\)\theta + tan\(^2\)\theta = 3 2tan\(^2\)\theta = 3 - 1 2tan\(^2\)\theta = 2 divide both sides by 2 tan\(^2\)\theta = 1 tan\theta = \sqrt1 tan\theta = 1 \theta = tan\(^{-1}\) (1) \theta = 45º