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Gravity is always directed in a vertical fashion at X (i.e. 90 degrees which is where tension will be minimum). The more horizontally aligned the cable is, the more it will pull horizontally. This increased horizontal pull will increase the tension in the cable.

Split ring is used for reversing the direction of current in the coil. For the continuous rotation of the coil in the same direction, the current in the coil must be reversed.

law of multiple proportions, statement that when two elements combine with each other to form more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers.

Alkanoate: Any salt or ester formed from the reaction of an alkanoic acid and alkanol.

No expanded working has been attached for this question yet. The verified answer is Option E.

Length of arc = θ/360 * 2πr => r = 90/360 * 14/4 = 3.5 slant height t = 14cm curved surface area of cone = πrl => 3.142 x 3.5 x 14 = 153.95

Circumference = 2\pir 2 x 22/7 x 3.5 ≅ 22m 22m = 360o 11m = 360/22 x 11 = 180o

\(\Delta RPS\) = Isosceles triangle \(\therefore < RPS = \frac{180^\circ - 90^\circ}{2}\) = 45^\circ In \(\Delta QPR\),\(\sin < QPR = \frac{1}{2}\) = 30^\circ \(\therefore < QPS = 30^\circ + 45^\circ = 75^\circ\)

θ/360 * 2πR = 7/360 * 2 * 22/7 * 6400 = 782km

Q = {1, 4, 9, 16, 25} P = { 1, 3, 5, 7, 9} Q ∩ P = { 1, 9}

Those who scored at most 30% = ( 5 + 10 + 20)thousand = 35000

No. of possible outcome = 40 No. of expected outcome = 16 + 9 = 25 Probability = 25/40 = 5/8

14 of the letters of the alphabet do not appear as the first letter of surname ∴ the no. of letters that appeared = 26-14 = 12 alphabets 15 surnames begin with 10 letters beside O and A ∴ 6 surnames begin with a letter

\(1 x 4^3 + P x 4^2 + 0 x 4 + 3 = 115_{10}\) 16p + 67 = 115 p = \(\frac{48}{16}\) = 3

\(\frac{1}{p} = \frac{a^{2} + 2ab + b^{2}}{a - b}\) \(\frac{1}{q} = \frac{a + b}{a^{2} - 2ab + b^{2}}\) \(\frac{1}{p} = \frac{(a + b)^{2}}{a - b}\) \(\frac{1}{q} = \frac{a + b}{(a - b)^{2}}\) \(\therefore p = \frac{a - b}{(a + b)^{2}}\) \(\frac{p}{q} = p \times \frac{1}{q} = \frac{a - b}{(a + b)^{2}} \times \frac{a + b}{(a - b)^{2}}\) = \(\frac{1}{(a + b)(a - b)}\) = \(\frac{1}{a^{2} - b^{2}}\)