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Physics
WAEC / WASSCE 1988
Waves, Sound & Vibrations
A sounding tuning fork is brought near the end of a pipe containing an air column and the loudness of the sound increases. This effect is due to
A
diffraction
B
an echo
C
resonance
D
interference
E
reverberation
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #21250)
Physics
WAEC / WASSCE 1988
Electrostatics & Capacitors
If the leaves a positively charged electroscope collapse completely as an object is brought near the cap of the electroscope, the objects possesses
A
an equal amount of positive charge
B
less amount of negative charge
C
no charge
D
a positive charge
E
an equal amount of negative charge
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option E.
Source: Myschool Past Questions Archive (Record #21251)
Physics
WAEC / WASSCE 1988
Magnetism, Electromagnetism & AC Circuits
Solution
A transformer with 5500 turns in its primary is used between a 240V a. c supply and a 120V kettle. Calculate the number of turns in the secondary
A
11000
B
2750
C
460
D
232
E
10
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(\frac{E_p}{E_s}\) = \(\frac{n_p}{n_s}\)
\(\frac{240}{120}\) = \(\frac{5500}{n_s}\)
=> n\(_s\) = 2750
Source: Myschool Past Questions Archive (Record #21252)
Physics
WAEC / WASSCE 1988
Current Electricity & Electric Circuits
Local action is normally prevented from taking place in a simple electric cell by
A
introducing an oxidising agent into the acid
B
not drawing current continuously for long periods
C
amalgamating the surface of the zinc plate
D
using a porous pot to isolate the zinc plate from the acid
E
using dilute sulphuric acid
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #21253)
Physics
WAEC / WASSCE 1988
Current Electricity & Electric Circuits
Solution
A cell can supply current of 0.8A and 0.4A through a 2\Omega and a 3\Omega resistors respectively. Calculate the internal resistance of the cell.
A
0.2Ω
B
0.4Ω
C
1.0Ω
D
3.0Ω
E
9.0Ω
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Assume the internal resistor = R
Current with 2 Ohm Resistor = 0.80A
Voltage = (R + 2) x 0.80 = V ; That is 0.8R + 1.6 = V ———————[[1]
Current with 3 Ohm Resistor = 0.40 A
Voltage = (R+3) x 0.40 = V ; That is 0.4R + 1.2 = V ————————[[2]
Subtracting 1 from 2 gives
--> (0.8 - 0.4) R
( 1.6 - 1.2 )
( V - V )
Therefore
0.4R + 0.4 = 0
R = 0.4 /0.4 = 1 Ohms
Source: Myschool Past Questions Archive (Record #21254)
Physics
WAEC / WASSCE 1988
Current Electricity & Electric Circuits
Solution
A battery of emf 24V and internal resistance 4Ω is connected to a resistor of 32Ω. What is the terminal p.d of the battery?
A
24.0V
B
21.3V
C
16.0V
D
2.7V
E
2.0V
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
E = V + Ir
V = E- Ir
V = 24 - {(24/36) x 4}
V = 21.3V
Source: Myschool Past Questions Archive (Record #21256)
Physics
WAEC / WASSCE 1988
Current Electricity & Electric Circuits
Two parallel conductors carry equal currents in the same direction. Which of the following statement is not a correct observation?
A
Each of teh conductors will experience a force
B
Each of the conductors can move
C
The forces on the conductors will be equal
D
There are concentric lines of force around each conductor
E
The two conductors will repel each other
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option E.
Source: Myschool Past Questions Archive (Record #21257)
Physics
WAEC / WASSCE 1988
Current Electricity & Electric Circuits
Solution
It takes 4 minutes to boil a quantity of water electrically. How long will it take to boil same quantity of water using the same heating coil but with the current doubled? (neglecting any external heat loss).
A
64 minutes
B
32 minutes
C
8 minutes
D
2 minutes
E
1 minute
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
D ∝ l2
E will increase 4 times when current is doubled.
Therefore time will decrease by a factor of 4, which is 1 minute.
Source: Myschool Past Questions Archive (Record #21258)
Physics
WAEC / WASSCE 1988
Current Electricity & Electric Circuits
Solution
A lamp is marked 220V 60 W. Calculate the energy it would consume when connected to a 220V source for 1 hour.
A
216000J
B
13200J
C
3600J
D
864J
E
220J
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
E = pt
=> 60 x 1 x 60 x 60 = 216000J
Source: Myschool Past Questions Archive (Record #21264)
Mathematics
WAEC / WASSCE 1988
Plane Geometry, Polygons & Circle Theorems
Diagram
Solution
In the diagram above, O is the centre of the circle through points L, M and N, if ∠MLN = 74o and ∠MNL = 39o, calculate ∠LON.
Attached Figure / Diagram
A
67o
B
100o
C
113o
D
126o
E
134o
medium Difficulty
Verified Correct Answer: Option E
Step-by-Step Mathematical Solution
From the diagram, < LMN = 180^\circ - (74^\circ + 39^\circ) (sum of angle in a triangle)
= 67^\circ
< LON = 2 x 67^\circ (angle subtended at the centre is twice the angle at the circumference)
= 134^\circ
Source: WAEC / JAMB / NECO Classroom Archive (Record #22196)
Mathematics
UTME / JAMB 1988
Trigonometry, Elevation & Bearings
Solution
If \(\cos^2 \theta + \frac{1}{8} = \sin^2 \theta\), find \(\tan \theta\).
A
3
B
\(\frac{3\sqrt{7}}{7}\)
C
3\(\sqrt{7}\)
D
\(\sqrt{7}\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
\(\cos^2 \theta + \frac{1}{8} = \sin^2 \theta\)..........(i)
from trigometric ratios for an acute angle, where \(cos^{2} \theta + \sin^2 \theta = 1\) ........(ii)
Substitute for equation (i) in (i) = \(\cos^2 \theta + \frac{1}{8} = 1 - \cos^2 \theta \)
= \(\cos^2 \theta + \cos^2 \theta = 1 - \frac{1}{8}\)
\(2\cos^2 \theta = \frac{7}{8}\)
\(\cos^2 \theta = \frac{7}{2 \times 8}\)
\(\frac{7}{16} = \cos \theta\)
\(\sqrt{\frac{7}{16}}\) = \(\frac{\sqrt{7}}{4}\)
but cos \(\theta\) = \(\frac{\text{adj}}{\text{hyp}}\)
\(opp^2 = hyp^2 - adj^2\)
\(opp^2 = 4^2 - (\sqrt{7})^{2}\)
= 16 - 7
opp = \(\sqrt{9}\) = 3
\(\tan \theta = \frac{\text{opp}}{\text{adj}}\)
= \(\frac{3}{\sqrt{7}}\)
\(\frac{3}{\sqrt{7}}\) x \(\frac{\sqrt{7}}{\sqrt{7}}\) = \(\frac{3\sqrt{7}}{7}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #31745)
Mathematics
UTME / JAMB 1988
Fractions, Decimals, Percentages & Approximations
Solution
The thickness of an 800 pages of book is 18mm. Calculate the thickness of one leaf of the book giving your answer in meters and in standard form
A
2.25 x 10-4m
B
50 x 10-4m
C
2.25 x 10-5m
D
4.50 x 10-5m
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
Thickness of an 800 pages book = 18mm to meter
18 x 103m = 1.8 x 10-2m
One leaf = \(\frac{1.8 \times 10^{-2}}{800}\)
= \(\frac{1.8 \times 10^{-2}}{8 \times 10^{2}}\)
= \(\frac{-1.8}{8}\) x 10-4
= 0.225 x 10-4
= 2.25 x 10-5m
one leaf contains 2 pages
: 2 * 2.25 x 10\(^{-5}\)m
= 4.5 * 10\(^{-5}\)m
Source: WAEC / JAMB / NECO Classroom Archive (Record #31708)
Mathematics
UTME / JAMB 1988
Fractions, Decimals, Percentages & Approximations
Solution
Simplify \(\frac{4a^2 - 49b^2}{2a^2 - 5ab - 7b^2}\)
A
\(\frac{a - b}{2a + b}\)
B
\(\frac{2a + 7b}{a - b}\)
C
\(\frac{2a - 7b}{a + b}\)
D
\(\frac{2a + 7b}{a + b}\)
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\(\frac{4a^2 - 49b^2}{2a^2 - 5ab - 7b^2}\) = \(\frac{(2a)^2 - (7b)^2}{(a + b)(2a - 7b)}\)
= \(\frac{(2a + 7b)(2a - 7b)}{(a + b)(2a - 7b)}\)
= \(\frac{2a + 7b}{a + b}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #31733)
Mathematics
WAEC / WASSCE 1988
Statistics (Data Representation, Central Tendency & Dispersion)
Diagram
Solution
The histogram below shows the number of candidates, in thousands, obtaining given ranges of marks in a State examination. Find the total number of candidates that sat for the examination
Attached Figure / Diagram
A
80,000
B
120,000
C
250,000
D
260,000
E
270,000
medium Difficulty
Verified Correct Answer: Option E
Step-by-Step Mathematical Solution
No of candidates = { 5 + 10 + 60 + 80 + 50 + 30 + 5 + 5 + 5}thousand = 270 x 1000 = 270000
Source: WAEC / JAMB / NECO Classroom Archive (Record #22228)
Physics
UTME / JAMB 1988
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
A particle starts from rest and moves with a constant acceleration of 0.5ms\(^{-2}\). The distance covered by the particle in 10s is?
A
2.5m
B
5.0m
C
25.0m
D
50.0m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
X = ut + \(\frac{1}{2}\)at
= (0 x 10) + (\(\frac{1}{2}\) x 0.5 x 10 x 10)
= 25m
Source: WAEC / JAMB / NECO Classroom Archive (Record #28369)