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For a regular polygon of n sides n = \(\frac{360}{\text{Exterior angle}}\) Exterior < = 180^\circ - 140^\circ = 40^\circ n = \(\frac{360}{40}\) = 9 sides

The required locus is angle bisector of the two lines

Mean of 10 numbers = 16 The total sum of numbers = 16 x 10 = 160 Mean of 11 numbers = 18 Total sum of numbers = 11 x 18 = 198 The 11th no. = 198 - 160 = 38

Given that 4, 16, 30, 20, 10, 14 and 26 Adding up = 120 nos \(\geq\) 16 are 16 + 30 + 20 + 26 = 92 The requires sum of angles = \(\frac{92}{120}\) x \(\frac{360^o}{1}\) = 276o

Total pairs: C(4,2) = 6. Favorable (even sum): both odd (1 way: {1,3}) or both even (1 way: {2,4}) → 2 ways. P = \(\frac{2}{6}\) = \(\frac{1}{3}\).

Given from 41 to 56 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56 The nos multiple of 9 are: 45, 54 P(multiple of 9) = \(\frac{2}{16}\) = \(\frac{1}{8}\)

real-life examples of convection: Breeze. The formation of sea and land breeze form the classic examples of convection. Boiling Water. Blood Circulation in Warm-Blooded Mammals. Air-Conditioner. Radiator. Refrigerator. The vacuum between the two walls prevents heat being transferred from the inside to the outside by conduction and convection.

speed = \(\frac{90 \times 10^3}{3600}\) = 25ms\(^{-1}\) Acceleration = \(\frac{\text{velocity change}}{\text{time}}\) = \(\frac{25}{10}\) : Acceleration = 2.5 Using S = Ut + \(\frac{1}{2}\) at\(^2\) S = \(\frac{1}{2}\) X 2.5 X 10\(^2\) = 125m

No expanded working has been attached for this question yet. The verified answer is Option C.

Given Data: Frequency (F) = \(\frac{500}{\pi}\) , Inductance (L) = 0.9H, Capacitance (C) = \(2 \times 10^{-6}\) Total circuit reactance = Inductive reactance ( X\(_L\) ) - Capacitive reactance ( X\(_C\) ) when ( X\(_L\) ) > ( X\(_C\) ) Inductive reactance ( X\(_L\) ) = 2\piFL = 2 \(\times\) \pi \(\times\) \(\frac{500}{\pi}\) \(\times\) 0.9 = 900\Omega Capacitive reactance ( X\(_C\) ) = \(\frac{1}{2\piFC}\) = \(\frac{1}{2 \times \pi \times 500/\pi \times 2 \times 10^{-6}}\) = \(\frac{1}{2 \times 10^{-3}}\) = \(\frac{1}{0.002}\) = 500\Omega Total circuit reactance = ( X\(_L\) ) - ( X\(_C\) ) = (900 - 500)\Omega =400\Omega

No expanded working has been attached for this question yet. The verified answer is Option A.

125\(^{\frac{-1}{3}}\) x 49\(^{\frac{-1}{2}}\) x 10\(^0\) = 5\(^{-1}\) x 7\(^{-1}\) x 1 = \(\frac{1}{35}\)

3\(^{2x}\) = 27 3\(^{2x}\) = 3\(^3\) 2x = 3 x = 1.5

0.00562 = 5.62 x 10\(^{-3}\)

1/3log10P = 1 log10P1/3 = log1010 P1/3 = 10 P = 1000