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Chemistry
WAEC / WASSCE 1992
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
All your burette readings (initial and final), as well as the size of your pipette, must be recorded but on no account of experimental procedure is required. All calculations must be done in your answer book.
F is a solution, O a dibasic acid H\(_2\)X. G is a solution containing 1.00g of sodium hydroxide in 250cm\(^3\) of solution.
(a) Put F in the burette and titrate with 20cm\(^3\) or 25cm\(^3\) portion of G using methyl orange as indicator. Record the volume of your pipette. Tabulate your burette readings and calculate the average volume of F used
(b) From your results and the information provided, calculate the;
(i) concentration of G in mol. dm\(^3\)
(ii) concentration of F in mol. dm\(^{-3}\)
(iii) molar mass of the acid H\(_2\)X, given that 100cm\(^3\) of solution F contained 0.4850 the acid.
The equation for the reaction is H\(_2\)X\(_{(aq)}\) + 2NaOH\(_{(aq)}\) \(\to\) Na\(_2\)X\(_{(aq)}\) + 2H\(_2\)O [H = 1; O = 16; Na = 23]
A
Electrons are present in metals but not in salt solutions
B
Metals are conductors while salts are electrolytes
C
Electricity is carried by mobile elrctrons in metals but by ions is aqueous salt solution
D
salts ionize in aqueous solutions while metals do not
E
Metals are reducing agents while salts are not
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Volume of pipette (G) = 25.00cm\(^3\)
(a) The average volume of F used = 24.80cm\(^3\)
(b)(i) Molar mass of NaOH = 40g/mol
Given that solution G contains 1.00g of NaOH in 250cm\(^3\) of solution = 4.00g in 1000cm\(^3\) of solution
molar concentration of G \(\frac{4}{40}\) = 0.100 mol. dm\(^{-3}\)
(ii) The equation of the reaction is H\(_2\)CX\(_{(aq)}\) + 2NaOH\(_{(aq)}\) + 2H\(_2\)O
\(\frac{\text{concentration of F x volume of F}}{\text{concentration of G x volume of G}}\) = mole ratio of \(\frac{F}{G}\)
\(\frac{C_1 \times 24.80}{0.100 \times 25.00}\) = \(\frac{1}{2}\)
C\(_1\) = \(\frac{0.100 \times 25.00}{24.80 \times 2}\)
C\(_1\) = 0.0504m
concentration of F = 0.504 mol dm\(^{-3}\)
(iii) Molar mass of H\(_2\)X\(_3\)
Given that 1000cm\(^3\) 1000 cm\(^3\) of solution of F \(\to\) 0.485 of acid
1000cm\(^3\) of sol. of F \(\to\) 485 x \(\frac{100}{10}\) = 4.85g/dm\(^3\)
Molar mass of H\(_2\)X = \(\frac{\text{mass concentration}}{molarity}\)
\(\frac{4.85 g/dm^3}{0.050mol/dm^{-3}}\) = 96 gmol\(^{-1}\)
Source: Official Exam / Past Question Archive
Chemistry
UTME / JAMB 1992
Stoichiometry, Mole Concept & Volumetric Analysis
A given mass of gas occupies 2 dm2 at 300k. At what temperature will its volume be doubled keeping the pressure constant?
A
400k
B
480k
C
550k
D
600k
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #44444)
Chemistry
UTME / JAMB 1992
Atomic Structure, Orbitals & Nuclear Chemistry
The nucleus of the isotopes tritium,contains
A
two neutrons with no protons
B
one neutron and one proton
C
two neutrons and one proton
D
two neutrons, one proton and one electron
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #44446)
Chemistry
WAEC / WASSCE 1992
Non-Metals & Their Compounds
Solution
(a) State the method of collecting gases which are denser than air.
(b) Name two gases that can be used to perform the fountain experiment in the laboratory. State the physical property which makes it suitable for the experiment.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) Gasses denser than air can be collected by upward displacement of air or downward delivery.
(b) Hydrogen chloride and ammonia are restively used to person the fountain experiment because of their high solubility in water
Source: Myschool Past Questions Archive (Record #54455)
Chemistry
WAEC / WASSCE 1992
Metals, Transition Elements & Extraction
Solution
(a) State the main ore of tin.
(b) Write an equation for the reaction involved in the smelting of purified tin ore
(c) List two alloys of tin
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) The main ore of tin is cassiterite or tin stone, (SnO\(_2\))
(b) SnO\(_{(s)}\) + 2C\(_{(s)}\) \(\to\) Sn\(_{(l)}\) + 2CO\(_{(g)}\)
(c) Bronze (Cu and Sn); Soldier (Pb and Sn)
Source: Myschool Past Questions Archive (Record #54456)
Chemistry
WAEC / WASSCE 1992
Non-Metals & Their Compounds
Solution
(a) Name the crystalline allotrope of sulphur that is stable at room temperature.
(b)(i) Give one example of a fuel that contains significant amount of sulphur as an impurity.
(ii) State one environmental disadvantage of using a fuel that has high sulphur content
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) The Rhombic (Octahedral) Sulphur is the stable allotrope at room temperature.
(b)(i) Petroleum crude oil
(ii) Air pollution.
Source: Myschool Past Questions Archive (Record #54457)
Chemistry
WAEC / WASSCE 1992
Electrolysis & Electrochemical Cells
Solution
(a) Give the electrolyte of a named secondary electrochemical cell.
(b) Consider the cell represented as shown below: \(Cu_{(s)}Cu^{2+}_{(aq)}/Zn^{2+}_{(aq)}/Zn{(s)}\)
(i) What does the vertical double stroke represent?
(ii) Which of the metals forms the cathode?
(iii) Name the electrode to which each half-cell should be coupled if the oxidation potential of the half-cells are to be determined.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) Dilute tetraoxosulphate (VI) acid i.e H\(_2\)SO\(_4\);
(b)(i) Salt bridge
(ii) Copper metal is the cathode in the Zinc - Zn\(^{2+}\) voltaic cell.
(iii) Specially prepared platinum electrode over which hydrogen gas is bubbled
Source: Myschool Past Questions Archive (Record #54458)
Chemistry
WAEC / WASSCE 1992
Reaction Rates & Chemical Equilibrium
Solution
Magnesium ribbon reacts with dilute hydrochloric acid at room temperature.
(a) State three ways by which the reaction can be made to proceed faster
(b) Write an equation for the reaction.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) Grind the magnesium ribbon into powder to increase its surface area which increases the rate of reaction Increase in the concentration of the copper will increase the rate of reaction. At lower than room temperature at catalyst can be applied to increase the rate of reaction.
(b) Mg\(_{(s)}\) + 2HCI\(_{(aq)}\) --> MgCl\(_{2(aq)}\) + H\(_{2(g)}\)
.
Source: Myschool Past Questions Archive (Record #54459)
Chemistry
WAEC / WASSCE 1992
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
(a) Give one example of naturally-occurring acids
(b) If 0.5 mole of a mono-alkanoic acid weighs 44g, determine the molecular formula and the name of the acid. (H = 1, C = 12, O = 16)
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) An example of naturally occurring acid is the ethanoic acid (CH\(_3\)COOH)
(b) If 0.5 mole of the mono-alkanoic acid weighs 44g
1 mole of the acid will weigh 2 x 44 = 88g.
i.e. (CH\(_2\)) x + 45 = 88
(CH\(_2\)) X = 88 - 45 = 43;
(14) x = 43
x = \(\frac{43}{14}\) = 3
3(CH\(_2\)) = \(C_3H_{6 +1}COOH = C_3H_7COOH\)
The monoalkanoic acid is butanoic acid.
Source: Myschool Past Questions Archive (Record #54460)
Chemistry
WAEC / WASSCE 1992
Periodic Table & Periodicity
Solution
(a) Three elements A, B and C have atomic numbers 8, 11 and 12 respectively.
(i) Write the formula of the compound formed by the chemical combination of A and B.
(ii) State which of the three elements belong(s) to the s-block of the Periodic Table. Give reason for your answer:
(b) List the component elements of bleaching powder.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) B\(_2\)A
(ii) B and C are the elemems belonging to S-block of the Periodic Table because their outermost I electrons are just filled in S-sub energy level.
(b) Calcium, Oxygen, Chlorine
Source: Myschool Past Questions Archive (Record #54461)
Chemistry
WAEC / WASSCE 1992
Metals, Transition Elements & Extraction
Solution
(a) Name one metal in each case Which:
(i) exists as a liquid at room temperature,
(ii) can be found in nature in the uncombined state
(b) X and Y are 0.5 mol. dm\(^{-3}\) freshly prepared aqueous solutions of two salts of iron
(II) With excess sodium hydroxide solution, X gave a dirty green precipitate which was not obtained in the case of Y.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
a)(i) Caesium(Cs)
(ii) Gold (Au)
(b) Solution Y has been oxidized to iron (III) salts and it will give a reddish brown precipitate with excess sodium hydroxide.
Source: Myschool Past Questions Archive (Record #54462)
Chemistry
WAEC / WASSCE 1992
Acids, Bases, pH & Salts
Solution
(a) What is meant by the term acid salt? Give one example.
(b) State the reason why an all-glass apparatus must be used for the laboratory preparation of concentrated trioxonitrate (V) acid.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a) Acid salt is the salt which contains acidic hydrogen e.g. Sodium hydrogen trioxocarbonate (IV) (NaHCO\(_3\))
(b) Glass is not attacked by the concentrated trioxonitrate (V) acid
Source: Myschool Past Questions Archive (Record #54463)
Chemistry
WAEC / WASSCE 1992
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
(a) Name: (i) one structural isomer of glucose.
(ii) the process by which starch is converted to glucose.
(b) The open-chain structure of glucose is shown below.
(a) State the functional groups present in the structure.
(ii) Which of the functional groups would react with warm Fehling's solution?
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) Fructose
(ii) Starch is converted to glucose by enzymatic hydrolysis of the starch.
(b)(i) Carbonyl group and the alkanol functional group
(ii) It is the alkanol group that reacts with warm Fehling's solution.
Source: Myschool Past Questions Archive (Record #54464)
Chemistry
WAEC / WASSCE 1992
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
(a)(i) State three differences between electrovalent compound and covalent compound.
(ii) Name the type of chemical bonding involved in the formation of ammonium ion from ammonia.
(b)(i) Name the quantum numbers which define an electron within an atom.
(ii) State the orbital in which the fifth electron of an atom is most likely to be found. Sketch the shape of the orbital.
(iii) State the period and the group to which the element boron belongs in the Periodic Table.
(c)(i) What is meant by the entropy of a chemical system?
(ii) Calculate the free energy change for a given reaction at 300 K using the following data obtained for the reaction: \(\Delta\) = -710KJ mol\(^{-1}\); \(\Delta\)S = 0.15 KJ mol\(^{-1}\)K\(^{-1}\)
(iii) From your evaluation in (c)(i) above, state whether the reaction is spontaneous or not at the given temperature. Give reason for your answer.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i)
Electrovalent compounds
Convalent convounds
The compound is made up of an aggregate of ions of opposite charges.
Can conduct electricity as electrolyte.
Can dissolve in water.
Made up of molecules
Cannot conduct electricity
Can only dissolve in organic solvents such as ether.
(ii) Coordinate or the active bond.
(b)(i) The principal quantum number, angular momentum quantum number, Magnetic Orbital quantum number and magnetic spin quantum number.
(ii) The 2 p-orbital group 3A and period two
(c)(i) The measure of the degree of disorderliness or randomness of a chemical system.
(ii) \(\Delta\) G = \(\Delta\) H - T\(\Delta\) S = -710 - 300(0.15) = -710 - 45 = -755 KJ/mol
(iii) The reaction is spontaneou because \(\Delta\) G is negative.
Source: Myschool Past Questions Archive (Record #54465)
Chemistry
WAEC / WASSCE 1992
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
(a) Give the products of the following reactions:
(i) hydrolysis of simple proteins.
(ii) alkaline hydrolysis of fats and oils.
(b) A combustion tube was packed with small pieces of broken clay pot and the tube maintained at a temperature of 750K. When the vapour of decane was passed into the tube, the main products included a gaseous hydrocarbon X.
(i) Name the process involved in the reaction. Give its industrial application.
(ii) State the function of the pieces of broken pot in the experiment.
(iii) Give one chemical test to distinguish between X and methane.
(iv) Draw a labelled diagram for the laboratory preparation of X.
(c)(i) State what would be observed if a piece of sodium was added to 10cm\(^3\) of propanol in a beaker. Write an equation for the reaction.
(ii) Give the main product formed when excess acidified potassium heptaoxodichromate (VI) reacts with each of the following: propan-1- ol: propan - 2 -of; State the type of process involved in the reactions.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) Amino acids
(ii) Soap + glycerol
(b)(i) Cracking process. Conversion of the less demanded fractions to the more demanded in oil industry.
(ii) The pieces of broken pot is to avoid local heating and therefore create medium of uniform heating.
(iii) X is an alkene and will decolourize the reddish-brown colour of bromine vapour which methane cannot do.
(v) Laboratory preparation of ethene.
(c)(i) Effervescence occurs and hydrogen gas is evolved. 2CH\(_3\)CH\(_2\)CH\(_2\)OH + 2Na\(_{(S)}\) \(\to\) H\(_{2(s)}\) + 2CH\(_3\)CH\(_2\)CH\(_2\)ONa
(ii) Propan-1-ol and propan-2-one respectively. The process involved in the reaction is oxidation of alkanols.
Source: Myschool Past Questions Archive (Record #54466)