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Physics
UTME / JAMB 1993
Waves, Sound & Vibrations
Which of the following waves can propagate through a vacuum?
A
High velocity sound waves
B
Ultrasonic waves
C
Acoustic waves
D
Infra-red waves
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #27996)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Solution
Radio waves emitted from an antenna are picked up by a radar after reflection from an aircraft in 4 x 10\(^{-3}\)S. How far is the aircraft from the antenna? [c = 3 x 10\(^8\)ms\(^{-1}\) ]
A
6.0 x 10\(^2\)km
B
1.2 x 103km
C
3.0 x 103km
D
6.0 x 10 5km
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
\(\text{Total time (to aircraft and back)} = 4 \times 10^{-3} \, \text{s} \)
\(\text{Speed of radio waves} = 3 \times 10^8 \, \text{m/s}\)
\(\text{Round-trip distance} = 3 \times 10^8 \times 4 \times 10^{-3}\) = 1.2 \(\times 10^6 \, \text{m}\)
\(\text{Actual distance to aircraft} = \frac{1.2 \times 10^6}{2}\)
= 600,000m = 600km.
Source: Myschool Past Questions Archive (Record #27999)
Physics
UTME / JAMB 1993
Reflection, Refraction & Dispersion of Light
Solution
Which of the following expressions gives the linear magnification produced by a concave mirror of radius of curvature r, if U and V are the object and image distances respectively?
A
\(\frac{V}{r}\) - 1
B
\(\frac{2V}{r}\) - 1
C
\(\frac{U}{r}\) - 1
D
\(\frac{2U}{r}\) - 1
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
F = \(\frac{r}{2}\) and v = mu
F = \(\frac{UV}{U + V}\)
\(\frac{r}{2}\) = \(\frac{U \times mu}{U + mu}\)
\(\frac{r}{2}\) = \(\frac{mu^2}{u(1 + m)}\)
\(\frac{r}{2} = \frac{mu}{1+m}\)
\(\frac{r}{2} = \frac{v}{1+m}\)
\(\frac{2v}{r} = 1+m\)
\(m = \frac{2v}{r} - 1\)
Source: Myschool Past Questions Archive (Record #28003)
Physics
UTME / JAMB 1993
Lenses & Optical Instruments
Solution
If the focal length of a camera lens is 20cm, the distance from the film at which the lens must be set to produce a sharp image of an object 100cm away is
A
17cm
B
20cm
C
25cm
D
100cm
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
F = \(\frac{uv}{u + v}\)
20 = \(\frac{100 \times v}{100 + v}\)
v = 25cm
Source: Myschool Past Questions Archive (Record #28005)
Physics
UTME / JAMB 1993
Reflection, Refraction & Dispersion of Light
Which of the following may be used to explain a mirage? i. layers of air near the road surface have varying refractive indices in hot weather. ii. road surfaces sometimes become good reflectors in hot weathers. iii. light from the sky can be reflected upwards after coming close to the road surface.
A
ii only
B
ii and iii only
C
i and iii only
D
i, ii, and iii only
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #28006)
Physics
UTME / JAMB 1993
Reflection, Refraction & Dispersion of Light
Solution
A beam of light is incident from air to water at an angle of 30oC. Find the angle of refraction if the refractive index of water is \(\frac{4}{3}\)
A
15oC
B
18oC
C
22oC
D
24oC
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
\(\frac{4}{3}\) = \(\frac{sin30}{sinr}\)
r = 22oC
Source: Myschool Past Questions Archive (Record #28007)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Which of the following correctly explain(s) why a green leaf appears green in bright day light? i. it absorbs only the green component of sunlight. ii. it absorbs all colour of sunlight except green. iii. it reflects only the green component of sunlight.
A
i only
B
ii only
C
i and iii only
D
ii and iii only
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #28009)
Physics
UTME / JAMB 1993
Magnetism, Electromagnetism & AC Circuits
Solution
Which of the following correctly explains why soft iron is proffered to steel in electromagnets? i. soft iron is more readily magnetized than steel. ii. soft iron is more readily demagnetized than steel. iii. soft iron retains magnetism more than steel.
A
i only
B
ii and iii only
C
i and ii only
D
i, ii, and iii.
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Soft iron is more readily magnetized than steel (i): Soft iron can become magnetized more easily and reaches saturation quicker than steel.
Soft iron is more readily demagnetized than steel (ii): Soft iron loses its magnetism more quickly when the magnetic field is removed, which is desirable in applications like electromagnets that need to be turned on and off.
Soft iron retains magnetism more than steel (iii): Soft iron does not retain magnetism as well as steel; that is one of the reasons it is used in electromagnets.
Therefore, i and ii are correct.
Source: Myschool Past Questions Archive (Record #28010)
Physics
UTME / JAMB 1993
Magnetism, Electromagnetism & AC Circuits
A current carrying conductor experiences a force when placed in a magnetic field because the
A
conductor is magnetized
B
magnetic field of the current interacts with external magnetic field
C
force is due to the motor principle
D
electric field of the current interacts with the external magnetic field
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #28011)
Physics
UTME / JAMB 1993
Waves, Sound & Vibrations
A simple cell with mercury-amalgamated zinc electrode prevents
A
local actions
B
polarization
C
buckling
D
degradation
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #28012)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Solution
The terminal voltage of a battery is 4.0V when supplying a current of 2.0A, and 2.0V when supplying a current of 3.0A. The internal resistance of the battery is
A
0.5 \(\Omega\)
B
1.0\(\Omega\)
C
2.0\(\Omega\)
D
4.0\(\Omega\)
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
E = 4 + 2r and E = 2 + 3r
therefore, r = 2\(\Omega\)
Source: Myschool Past Questions Archive (Record #28013)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Solution
A current of 100mA passes through a conductor for 2 minutes. The quantity of electricity transported is
A
200C
B
50C
C
12C
D
0.002C
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Q = it
= 100 x 10-3 x 2 x 60
= 12C
Source: Myschool Past Questions Archive (Record #28014)
Physics
UTME / JAMB 1993
Electrostatics & Capacitors
Solution
A parallel plate capacitor of area 10cm2 in vacuum has a capacitance of 10-2\(\mu\)F. What is the distance between the plates?(e = 9 x 10-12fm)
A
9 x 10-13m
B
9 x 10-7m
C
9 x 10-3m
D
9 x 107m
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
C = \(\frac {\varepsilon_o\ A}{d}\)
10-2 x 10-6 = \(\frac {9 \times 10 ^{-12}}{d}\) x 10-4
= 9 x 10-7m
Source: Myschool Past Questions Archive (Record #28015)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Solution
A 40-W instrument has a resistance of 90\(\Omega\). On what voltage should it be operated normally?
A
60V
B
150V
C
225V
D
3600V
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
P = \(\frac{V}{R}\)
V = \(\sqrt{PR}\)
V = \(\sqrt{40 \times 90}\)
= 60V
Source: Myschool Past Questions Archive (Record #28016)
Physics
UTME / JAMB 1993
Magnetism, Electromagnetism & AC Circuits
Solution
Which of the following devices may be used to step up the voltage in a d.c. circuit?
A
a step-up transformer
B
a d.c. generator
C
a wattmeter
D
an induction coil
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
An induction coil is a transformer for producing high-voltage alternating current from a low-voltage direct current, consisting essentially of two concentric coils with a common soft-iron core, a primary coil with relatively few windings of heavy wire, and a secondary coil with many turns of fine wire. Excitation of the primary coil by rapidly interrupted or variable current induces high voltage in the secondary coil.
Source: Myschool Past Questions Archive (Record #28017)