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Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Which of the following quantities has the same unit as the watt?
A
Force x time
B
Force x distance
C
Force x acceleration
D
Force x velocity
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #27945)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Solution
The external and internal diameter of a tube are measured as (32 \pm 2)mm and (21 \pm 1)mm respectively. Determine the percentage error in the thickness of the tube.
A
27%
B
14%
C
9%
D
3%
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
The thickness of the tube is given by:
thickness = (external diameter − internal diameter) / 2
= (32 − 21) / 2
= 11 / 2
= 5.5 mm
Let t = thickness = \(\frac{(D − d)}{2}\), where D = external diameter and d = internal diameter.
The absolute error in thickness is found using the rules for propagation of errors (for subtraction and division by a constant):
\Deltat = \(\frac{(\DeltaD + \Deltad)}{2}\)
= \(\frac{(2 + 1)}{2}\) = \(\frac{3}{2}\)
=1.5 mm.
The percentage error in thickness is:
Percentage error = \(\frac{\Deltat }{\text{t}}\) \times 100%
= (\(\frac{1.5}{ 5.5}\)) \times 100%
= (\(\frac{15}{ 55}\)) \times 100%
= (\(\frac{3}{11}\)) \times 100% ≈ 27.27%
Source: Myschool Past Questions Archive (Record #27952)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Solution
Two forces of magnitudes 7N and 3N act at right angles to each other. The angle \(\theta\) between the resultant and the 7N force is given by
A
cos\(\theta\) = \(\frac{3}{7}\)
B
sin\(\theta\) = \(\frac{3}{7}\)
C
tan\(\theta\) = \(\frac{3}{7}\)
D
cot\(\theta\) = \(\frac{3}{7}\)
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
\(\theta\) = tan-1\(\frac{3}{7}\)
Source: Myschool Past Questions Archive (Record #27956)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Solution
A rocket burns fuel at the rate of 10kgs-1 and ejects it with velocity of 5 x 103ms-1. The thrust exerted by the gas on the rock is
A
2.5 x 107N
B
5.0 x 104N
C
5.0 x 102N
D
2.0 x 10-3N
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Thrust = \(\frac{\text{mass x velocity}}{time}\)
= 10 x 5 x 103
= 5.0 x 104N
Source: Myschool Past Questions Archive (Record #27957)
Physics
UTME / JAMB 1993
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
The force experienced by an object of mass 60.0kg in the moon's gravitational field is 1.002 x 102N. What is the intensity of the gravitational field?
A
0.60Nkg-1
B
1.67Nkg-1
C
6.12 x 102Nkg-1
D
9.81ms-2
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Intensity = \(\frac{1.002 \times 102}{60}\)
= 1.67Nkg-1
Source: Myschool Past Questions Archive (Record #27961)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Which of the following correctly describes the energy changes in the generation of light by a hydroelectric power station?
A
Electrical \(\to\) mechanical \(\to\) potential
B
potential \(\to\)mechanical \(\to\)electrical \(\to\) light
C
mechanical \(\to\) sound \(\to\) electrical \(\to\) light
D
kinetic \(\to\) mechanical \(\to\) electrical \(\to\)light
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #27964)
Physics
UTME / JAMB 1993
Work, Energy, Power & Simple Machines
Solution
A plane inclined at angle \(\theta\) has a velocity ratio of 10 : 1. The inclination of the plane to the horizontal is given by
A
tan\(\theta\) = \(\frac{1}{10}\)
B
cot\(\theta\) = \(\frac{1}{10}\)
C
cos\(\theta\) = \(\frac{1}{10}\)
D
sin\(\theta\) = \(\frac{1}{10}\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
V.R = \(\frac{1}{sin\theta}\)
= 10
sin = \(\frac{1}{10}\)
Source: Myschool Past Questions Archive (Record #27968)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Solution
A weightless vessel of dimensions 4m x 3m x 2m is filled with a liquid of density 1000kgm\(^{-3}\) and sealed. What is the maximum pressure this container can exert on a flat surface? [g = 10ms\(^{-2}\)]
A
9 x 104Nm-2
B
4 x 104Nm-2
C
3 x 104Nm-2
D
2 x 104Nm-2
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Pressure = density x acceleration due to gravity x height.
P = 4 x 1000 x 10
= 4 x 10\(^4\)Nm\(^{-2}\)( since max. pressure is required)
Source: Myschool Past Questions Archive (Record #27971)
Physics
UTME / JAMB 1993
Equilibrium of Forces, Moments & Flotation
Solution
An object of mass 400g and density 600kgm-3 is suspended with a sting so that half of it is immersed in paraffin of density 900kgm-3. The tension in the string is
A
1.0N
B
3.0N
C
4.0N
D
5.0N
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
volume of object = \(\frac{400 \times 10^{-2}}{600}\)
= 0.00067m3
volume of paraffin displaced = \(\frac{1}{2}\) x 0.00067
= 0.00034m3
mass of paraffin = 900 x 34 x 10-5
= 0.3kg
weight of paraffin = 0.3 x 10
= 3N = upthrust = tension in the string
Source: Myschool Past Questions Archive (Record #27973)
Physics
UTME / JAMB 1993
Temperature, Thermometry & Thermal Expansion
The thermometric properties of the thermocouple is that is
A
e.m.f. changes with temperature
B
resistance changes with temperature
C
volume changes with temperature
D
pressure changes with resistance
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #27974)
Physics
UTME / JAMB 1993
Temperature, Thermometry & Thermal Expansion
Solution
A metal rod 800mm long is heated from 10oC to 95oC. If it expands by 1.36mm, the linear expansivity of the metal is
A
2.0 x 102K-1
B
2.0 x 102K-1
C
5.0 x 10-3K-1
D
2.0 x 10-5K-1
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
a = \(\frac{1.36}{800 \times (95 - 10)}\)
= 2.0 x 10-5K-1
Source: Myschool Past Questions Archive (Record #27978)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Solution
When the volume of a given mass of gas is halved and its temperature doubled, the pressure
A
remains constant
B
increases by a factor of 4
C
increases by a factor of 3
D
decreases by a factor of 4
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(\frac{P_1V_1}{T_1}\) = \(\frac{P_2V_2}{T_2}\)
V1 = 2V2 and T2 = 2T1
\(\frac{P_1\times 2V_2}{T_1}\) = \(\frac{P_2\times V_2}{2T_1}\)
P2 = 4P1
Source: Myschool Past Questions Archive (Record #27983)
Physics
UTME / JAMB 1993
Current Electricity & Electric Circuits
Solution
200g of water at 90^\circC is mixed with 100g of water at 30^\circC. What is the final temperature?
A
50oC
B
60oC
C
70oC
D
80oC
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Heat lost = heat gained
200 x c x (90 - \(\theta\))= 100\(\times\) c \(\times\) (\(\theta - 30\))
Dividing through by 100c, we have
2(\(90 - \theta\)) = (\(\theta - 30\))
simplifying, we have
\(\theta\) = 70^\circ
Source: Myschool Past Questions Archive (Record #27988)
Physics
UTME / JAMB 1993
Waves, Sound & Vibrations
Solution
The relationship between L and the wavelength I of the stationary wave is
A
2L = \(\lambda\)
B
L = \(\lambda\)
C
L = \(\frac {\lambda}{3}\)
D
4L = 3 \(\lambda\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
L = - \(\lambda\) \(\Rightarrow\)4L = 3 \(\lambda\)
Source: Myschool Past Questions Archive (Record #27992)
Physics
UTME / JAMB 1993
Waves, Sound & Vibrations
Solution
Determine the distance between the consecutive antinodes XX if the wavelength is 60cm
A
15cm
B
30cm
C
60cm
D
120cm
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Distance XX = \(\frac{1}{2}\)\(\lambda\)
= \(\frac{1}{2}\) x \(\frac{60}{1}\)
= 30cm
Source: Myschool Past Questions Archive (Record #27995)