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Physics
WAEC / WASSCE 1993
Current Electricity & Electric Circuits
Solution
A body moves along a circular path with uniform angular speed of 0.6 rad s-1 and at a constant speed of 3.0ms-1. Calculate the acceleration of the body towards the centre of the circle.
A
25.0ms-2
B
5.4 ms-2
C
5.0ms-2
D
1.8 ms-2
E
0.2ms-2
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
A = wv = 0.6 x 3.0 = 1.8m-2
Source: Myschool Past Questions Archive (Record #24994)
Physics
WAEC / WASSCE 1993
Units, Measurements & Dimensional Analysis
Which of the following is a derived unit?
A
Ampere
B
Kilogramme
C
Second
D
Ohm
E
Kelvin
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #24995)
Physics
WAEC / WASSCE 1993
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
A body timed 20 oscillations of a certain pendulum three times and obtained 44.3s, 45.5s and 45.7s respectively. Calculate the mean period of oscillation of the pendulum
A
0.13s
B
2.22s
C
2.26s
D
44.30s
E
45.17s
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
\(\text{Given times: } 44.3 \, \text{s}, \, 45.5 \, \text{s}, \, 45.7 \, \text{s}\)
Sum the total times:
\(\text{Total time} = 44.3 + 45.5 + 45.7 = 135.5 \, \text{s}\)
Calculate the mean time for 20 oscillations:
\(\text{Mean time} = \frac{135.5 \, \text{s}}{3} = 45.17 \, \text{s}\)
Find the mean period of oscillation (for one oscillation):
\(\text{Mean period} = \frac{45.17 \, \text{s}}{20} = 2.2585 \, \text{s}\)
Thus, the mean period of oscillation of the pendulum is approximately 2.26 seconds.
Source: Myschool Past Questions Archive (Record #24996)
Physics
WAEC / WASSCE 1993
Newton's Laws, Momentum & Collisions
Solution
A body of mass M1 moving with a velocity U collides with a stationary body of mass M2 and both move with a common velocity V lf linear momentum is conserved, which of the following expressions correctly represents V?
A
M1 U/M1 + M2
B
M2 U/M1 + M2
C
M1 + M2/M1 U
D
M1 - M2/M1 U
E
M1 U/M1 - M2
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
M1U + M2 x 0 = (M1 + M2)v
V = M1 U/M1 + M2
Source: Myschool Past Questions Archive (Record #24997)
Physics
WAEC / WASSCE 1993
Current Electricity & Electric Circuits
Diagram
Solution
A body of mass m = 0.5 kg is suspended by a string and pulled by a horizontal force of 12N as shown in the diagram. Calculate the tension T in the String if the body is in equilibrium. [Take g as 10ms\(^{-1}\)]
Attached Figure / Diagram
A
7.0
B
10.9
C
12.5
D
13.0
E
17.0
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Mg = 5N
T\(_2\) = 5\(^2\) + 12\(^2\) = 13N
Source: Myschool Past Questions Archive (Record #24998)
Physics
WAEC / WASSCE 1993
Linear Motion, Projectiles & Kinematics
Solution
A particle starts from rest and moves with a constant acceleration of 0.5 ms-2? Calculate the time taken by the particle to cover a distance of 25m.
A
25s
B
7.1s
C
10.0s
D
50.0s
E
100.0s.
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
S = ut + 1/2at2
25 = 0 + 1/2 x 0.5t2
T = 10s
Source: Myschool Past Questions Archive (Record #24999)
Physics
WAEC / WASSCE 1993
Units, Measurements & Dimensional Analysis
Solution
A block of material of volume 2 X 10\(^{-5}\)m\(^3\) and density 2.5 x 10\(^3\) kgm\(^{-3}\) is suspended from a spring balance with half volume of the block immersed in water. What is the reading of the spring balance? (Density of water =1.0x10\(^3\) kg m\(^{-3}\) g = 10 ms\(^{-2}\)).
A
0.10N
B
0.25N
C
0.30N
D
0.40N
E
0.50N
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Weight of object = mg
= \(\rho vg\) = 2.5 x 10\(^3\) x 2 x 10\(^{-5}\) x 10 = 0.5N;
Upthrust = weight of displaced fluid = \(\rho_{water} vg\)
= \(\frac{1.0 \times 10^3 \times 2 \times 10^{-5} \times 10}{2}\) = 0.1N
∴Reading = 0.5 – 0.1 = 0.4N
Source: Myschool Past Questions Archive (Record #25000)
Physics
WAEC / WASSCE 1993
Linear Motion, Projectiles & Kinematics
Solution
An object is projected with a velocity of 100 ms\(^{-1}\) from the ground level at an angle \(\theta\) to the vertical. If the total time of flight of the projectile is 10 s, calculate \theta. (g = 10 ms\(^{-2}\)).
A
0o
B
30o
C
45o
D
60o
E
90o
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
T = \(\frac{2u sin \theta}{g}\)
sin \theta = \(\frac{Tg}{2u}\)
sin \theta = \(\frac{10 \times 10}{2 \times 100}\) = 0.5
\theta = sin\(^{- 0.5}\) = 30º
\(\theta\)\(_{horizontal}\) = 30º
But \(\theta\)\(_{vertical}\) = 90º - 30º = 60º
Source: Myschool Past Questions Archive (Record #25001)
Physics
WAEC / WASSCE 1993
Linear Motion, Projectiles & Kinematics
Solution
How far will a body move in 4 seconds if uniformly accelerated from rest at the rate of 2 ms-2?
A
32m
B
24m
C
16m
D
1.2m
E
5m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
S = ut + \(\frac{1}{2}\) at\(^2\) = 0 + \(\frac{1}{2}\) x 2 x 4\(^2\) = 16m
Source: Myschool Past Questions Archive (Record #25002)
Physics
WAEC / WASSCE 1993
Current Electricity & Electric Circuits
If the temperature of water is gradually increased from 0o to 4oC, the density of the water within this range
A
increases for a while and then decreases
B
decreases for a while and then increases
C
increases gradually
D
decreases gradually
E
remains the same
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25003)
Physics
WAEC / WASSCE 1993
Current Electricity & Electric Circuits
The expansion of solids can be considered a disadvantage in the
A
fire alarm system
B
thermostat
C
riveting of steel plates
D
balance wheel of a watch
E
fitting of wheels on rims.
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #25004)
Physics
WAEC / WASSCE 1993
Temperature, Thermometry & Thermal Expansion
Solution
A solid metal cube of side 10 cm is heated from
10oC to 60oC. lf the linear expansivity of the metal is 1.2 x 105K-1, calculate the increase in its volume.
A
0.6cm3
B
1.2 cm3
C
1.8 cm3
D
3.6 cm3
E
6.0cm3.
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Δv = 3αvΔθ = 3 x 1.2 x 10-5 x 1000
X(60 – 10) = 1.8cm
Source: Myschool Past Questions Archive (Record #25005)
Physics
WAEC / WASSCE 1993
Current Electricity & Electric Circuits
Solution
A gas has a volume of 546 cm3 at OºC. What is the volume of the gas at -100ºC if its pressure remains constant?
A
346cm3
B
446cm3
C
546cm3
D
646cm3
E
746 cm3.
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
\(\frac{V_1}{T_1} = \frac{V_2}{ T_2}\)
\(T_1\) = 0 + 273 = 273K, \(T_2\) = -100+273 = 173K
\(\frac{546}{273} = \frac{V_2}{ 173}\)
\(V_2 = 346cm^3\)
Source: Myschool Past Questions Archive (Record #25006)
Physics
WAEC / WASSCE 1993
Waves, Sound & Vibrations
Which of the following are correct of plane- polarized light? I. Plane polarization of light is the formation of hydrogen bubbles on the particles of light. II. Plane polarization of light is the splitting of light into its spectral components III. Plane-polarized light vibrates in one plane only. IV. Polarization is characteristic of transverse waves.
A
I and II only
B
I and IV only
C
II and III only
D
III and IV only
E
I and III only
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #25007)
Physics
WAEC / WASSCE 1993
Waves, Sound & Vibrations
Longitudinal waves cannot be
A
diffracted
B
retracted
C
polarized
D
reflected
E
superposed
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25008)