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Physics
WAEC / WASSCE 1993
Atomic, Quantum, Nuclear Physics & Electronics
Solution
Which of the following is used a nuclear reactor to slow down fast moving neutrons?
A
Carbondioxide gas
B
Liquid sodium metal
C
Concrete shield
D
Graphite rods
E
Boron rods
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The uses of graphite:
Used in making a pencil.
Used as a dry lubricant.
For making electrodes.
For polishing iron articles.
As a moderator in the nuclear furnace.
The moderator of a nuclear reactor is a substance that slows neutrons down.
Source: WAEC / JAMB / NECO Classroom Archive (Record #25048)
Physics
UTME / JAMB 1993
Lenses & Optical Instruments
Solution
The property of the eye known as its power of accommodation is controlled by the
A
pupil
B
virteous humour
C
iris
D
ciliary muscles
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The ciliary body produces the fluid in the eye called aqueous humor.
It also contains the ciliary muscle, which changes the shape of the lens when your eyes focus on a near object.
This process is called accommodation.
Source: WAEC / JAMB / NECO Classroom Archive (Record #28008)
Chemistry
UTME / JAMB 1993
Nature of Matter & Separation Techniques
Solution
Which of the following substances is a mixture?
A
Sulphur powder
B
Bronze
C
Distilled water
D
Ethanol
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Bronze is a mixture of copper and tin. Water is a compound of the elements hydrogen and oxygen.
Source: WAEC / JAMB / NECO Classroom Archive (Record #13302)
Chemistry
UTME / JAMB 1993
Oxidation, Reduction & Redox Reactions
Solution
NH\(_3\) + H\(_3\)O\(^+\) → NH\(_4\)\(^+\) + H\(_2\)O. It may be deduced from the reaction above that?
A
a redox reaction has occurred
B
H3O+ acts as an oxidizing agent
C
H3O+ acts as an acid
D
water acts as an acid
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
In the reaction NH\(_3\) + H\(_3\)O\(^+\), H\(_3\)O\(^+\) acts as an acid, donating a proton (H\(^+\)) to NH\(_3\), which then becomes NH\(_4\)\(^+\).
According to Brønsted-Lowry Acid-Base Theory, an acid is a substance that donates a proton (H\(^+\)), while a base is a substance that accepts a proton.
H\(_3\)O\(^+\) (Hydronium Ion) is formed when a proton (H\(^+\)) is added to a water molecule (H\(_2\)O.).
In the reaction NH\(_3\) + H\(_3\)O\(^+\) → NH\(_4\)\(^+\) + H\(_2\)O, H\(_3\)O\(^+\) donates a proton (H\(^+\)) to NH\(_3\), forming NH\(_4\)\(^+\) and H\(_2\)O.
Source: WAEC / JAMB / NECO Classroom Archive (Record #13337)
Chemistry
WAEC / WASSCE 1993
Non-Metals & Their Compounds
Solution
Carbon is often deposited in the exhaust-pipe of cars because of the?
A
presence of carbon in petrol
B
dehydrogenation of petrol
C
incomplete combustion of petrol
D
presence of additives in petrol
E
contamination of petrol with diesel
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The incomplete combustion process that occurs in an engine; result to the emission of carbon monoxide (CO) as a waste product from the exhaust system of vehicles.
Environmental carbon monoxide is produced by incomplete combustion process from any carbon containing fuel.
Source: WAEC / JAMB / NECO Classroom Archive (Record #36259)
Mathematics
WAEC / WASSCE 1993
Sets, Logic & Venn Diagrams
Solution
S = {1, 2, 3, 4, 5, 6}, T = {2,4,5,7} and R = {1,4, 5}, and (S∩T) ∪ R
A
{1, 4, 5}
B
{2, 4, 5}
C
{1, 2, 4, 5}
D
{2, 3, 4, 5}
E
{1, 2, 3, 4, 5}
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
S = {1, 2, 3, 4, 5, 6}; T = {2, 4, 5, 7}; R = {1, 4, 5}
(S∩T) ∪ R = {2, 4, 5} ∪ {1, 4, 5}
= {1, 2, 4, 5}
Source: Myschool Past Questions Archive (Record #23187)
Mathematics
WAEC / WASSCE 1993
Plane Geometry, Polygons & Circle Theorems
Solution
Simplify: \(\frac{3}{4} \div 1\frac{1}{4} \times (1\frac{1}{2} - \frac{2}{3})\)
A
7/30
B
7/24
C
9/25
D
1/2
E
18/25
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\(\frac{3}{4} \div 1\frac{1}{4} \times (1\frac{1}{2} - \frac{2}{3})\)
\(\frac{3}{4} \div \frac{5}{4} \times (\frac{9 - 4}{6})\)
= \(\frac{3}{4} \times \frac{4}{5} \times \frac{5}{6}\)
= \(\frac{1}{2}\)
Source: Myschool Past Questions Archive (Record #23188)
Mathematics
WAEC / WASSCE 1993
Inequalities & Linear Programming
Solution
Solve the inequality: 3m + 3 > 9
A
m > 2
B
m > 3
C
m>4
D
m>6
E
m>12
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
3m + 3 > 9
3m > 9 - 3
3m > 6
m > 2
Source: Myschool Past Questions Archive (Record #23189)
Mathematics
WAEC / WASSCE 1993
Number Bases & Modular Arithmetic
Solution
Convert 89\(_{10}\) to a number in base two.
A
1101001
B
1011001
C
1001101
D
101101
E
11001
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
\(89_{10}\)
2
89
2
44 r 1
2
22 r 0
2
11 r 0
2
5 r 1
2
2 r 1
2
1 r 0
0 r 1
\(89_{10} = 1011001_{2}\)
Source: Myschool Past Questions Archive (Record #23190)
Mathematics
WAEC / WASSCE 1993
Fractions, Decimals, Percentages & Approximations
Solution
A stick of length 1.75m was measured by a boy as 1.80m. Find the percentage error in his measurement
A
27/9%
B
26/7%
C
5%
D
277/9%
E
284/7%.
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
% error = \(\frac{error value}{true value}\) x 100%
% error = \(\frac{1.80 - 1.75}{1.75}\) x 100% = \(\frac{0.05}{1.75}\) x 100% = \(\frac{20}{7}\)% = 2\(\frac{6}{7}\)%
Source: Myschool Past Questions Archive (Record #23191)
Mathematics
WAEC / WASSCE 1993
Indices, Logarithms & Surds
Solution
Simplify: \(\frac{4^{-\frac{1}{2}} \times 16^{\frac{3}{4}}}{4^{\frac{1}{2}}}\)
A
1/4
B
0
C
1
D
2
E
4
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\(\frac{4^{-\frac{1}{2}} \times 16^{\frac{3}{4}}}{4^{\frac{1}{2}}}\)
= \(\frac{16^{\frac{3}{4}}}{4^{\frac{1}{2}} \times 4^{\frac{1}{2}}}\)
= \(\frac{(2^4)^{\frac{3}{4}}}{4^{\frac{1}{2}} \times 4^{\frac{1}{2}}}\)
= \(\frac{2^3}{4}\)
= 2
Source: Myschool Past Questions Archive (Record #23193)
Mathematics
WAEC / WASSCE 1993
Indices, Logarithms & Surds
Solution
Simplify: \(\frac{\log \sqrt{27}}{\log {81}}\)
A
1/6
B
3/8
C
1/2
D
3/4
E
6
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
\(\frac{\log \sqrt{27}}{\log 81}\)
= \(\frac{\log \sqrt{3^3}}{\log 3^4}\)
= \(\frac{\log 3^{\frac{3}{2}}}{\log 3^4}\)
= \(\frac{\frac{3}{2} \log 3}{4 \log 3}\)
= \(\frac{\frac{3}{2}}{4}\)
= \(\frac{3}{8}\)
Source: Myschool Past Questions Archive (Record #23194)
Mathematics
WAEC / WASSCE 1993
Algebraic Expressions, Polynomials & Factorisation
Solution
Factorize the expression 2s\(^2\) - 3st - 2t\(^2\).
A
(2s - t)(s + 2t)
B
(2s + t)(s - 2t)
C
(s + t)(2s - 1)
D
(2s + t)(s -t)
E
(2s + t)(s + 2t)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
2s\(^2\) - 3st - 2t\(^2\)
= 2s\(^2\) - 4st + st - 2t\(^2\)
= 2s(s - 2t) + t(s - 2t)
= (2s + t)(s - 2t)
Source: Myschool Past Questions Archive (Record #23195)
Mathematics
WAEC / WASSCE 1993
Linear, Simultaneous & Quadratic Equations
Solution
Solve the equation x\(^2\) - 2x - 3 = 0
A
(-3, 1)
B
(-1, -3)
C
(3,1)
D
(43, 0)
E
(-1, 3).
medium Difficulty
Verified Correct Answer: Option E
Step-by-Step Mathematical Solution
x\(^2\) - 2x - 3 = 0
x\(^2\) - 3x + x - 3 = 0
x(x - 3) + 1(x - 3) = 0
(x + 1)(x - 3) = 0
x = (-1, 3)
Source: Myschool Past Questions Archive (Record #23196)
Mathematics
WAEC / WASSCE 1993
Plane Geometry, Polygons & Circle Theorems
Solution
Write as a single fraction: \(\frac{5}{6r} - \frac{3}{4r}\)
A
r/12
B
12/r
C
1/6r
D
r/6
E
1/12r
medium Difficulty
Verified Correct Answer: Option E
Step-by-Step Mathematical Solution
\(\frac{5}{6r} - \frac{3}{4r}\)
= \(\frac{10 - 9}{12r}\)
= \(\frac{1}{12r}\)
Source: Myschool Past Questions Archive (Record #23197)