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Chemistry
UTME / JAMB 1994
Reaction Rates & Chemical Equilibrium
Diagram
In the diagram above the activation energy is represented by
Attached Figure / Diagram
A
y - x
B
x
C
x - z
D
y
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #31487)
Chemistry
UTME / JAMB 1994
Stoichiometry, Mole Concept & Volumetric Analysis
Diagram
The IUPAC name of the compound above is
Attached Figure / Diagram
A
2,2-dimethyl but -1-yne
B
2,2-dmethyl but -1-ene
C
3,3-dimethyl but -1-ene
D
3,3-dimethyl but-1-yne
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #31517)
Chemistry
UTME / JAMB 1994
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Diagram
Solution
Use the diagram above to answer this question. The reaction taking place in flask G is known as?
Attached Figure / Diagram
A
hydrolysis
B
double decomposition
C
dehydration
D
pyrolysis
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The reaction of conc. \(H_2SO_4\) with ethyl ethanol is a dehydration reaction. a process used in producing ethene from alcohol.
Source: Myschool Past Questions Archive (Record #31518)
Chemistry
UTME / JAMB 1994
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
From the above diagram, the caustic soda in the conical flask serves to
A
dry ethene gas
B
remove carbon (iv) oxides from ethene
C
remove carbon (ii) oxide from ethene
D
remove sulphur (iv) oxide from ethene
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Caustic soda, \(NaOH\) , serves to remove gaseous impurities from the gas evolved during the laboratory preparation of ethene. Basically, the major impurities are Sulphur (IV) oxide and Carbon (IV) oxide.
Source: Official Exam / Past Question Archive
Chemistry
WAEC / WASSCE 1994
Nature of Matter & Separation Techniques
The components of universal indicator solution can best be separated by
A
chromatography
B
filtration
C
evaporation
D
crystallization
E
fractional distillation
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #36321)
Chemistry
WAEC / WASSCE 1994
Acids, Bases, pH & Salts
The number of replaceable hydrogen atoms in one acid indicates its
A
basicity
B
acidity
C
alkalinity
D
reactivity
E
pH value
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #36322)
Chemistry
WAEC / WASSCE 1994
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
Catalytic hydrogenation of alkenes produces compounds with the general formula
A
CnH2n+1 OH
B
CnH2n+1
C
CnH2n+2
D
CnH2n-2
E
Cx(H2O)y
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
.In a hydrogenation reaction, two hydrogen atoms are added across the double bond of an alkene, resulting in a saturated alkane.
Source: Myschool Past Questions Archive (Record #36324)
Chemistry
WAEC / WASSCE 1994
Chemical Energetics & Thermochemistry
A measure of the degree of disorder in a chemical system is known as the
A
enthalpy
B
free energy
C
activation energy
D
entrophy
E
equilibrium
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #36329)
Chemistry
WAEC / WASSCE 1994
Particulate Nature of Matter, Laws & Formulae
In any chemical reaction, the total mass of the products is always equal to that of the reactants. This is statement of the law of
A
definite proportion
B
conservation of matter
C
multiple proportions
D
reciprocal proportions
E
constant composition
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #36330)
Chemistry
WAEC / WASSCE 1994
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
Which of the following is not a property of magnesium oxide?
A
High melting point
B
Dissolution in polar solvents
C
Presence of ionic bonds
D
Possession of crystal lattice
E
Low binding energy
medium Difficulty
Verified Correct Answer: Option E
Chemical Principles & Mechanism
Magnesium oxide (MgO) is an ionic compound that exhibits the following properties:
A. High melting point: MgO has a high melting point (2800^\circC) due to the strong ionic bonds between magnesium and oxygen ions.
B. Dissolution in polar solvents: MgO is soluble in polar solvents like water, which is due to the ability of water molecules to interact with the ions.
C. Presence of ionic bonds: MgO is an ionic compound, meaning it is held together by ionic bonds between magnesium cations (Mg²⁺) and oxygen anions (O²⁻).
D. Possession of crystal lattice: MgO has a crystal lattice structure, which is typical of ionic compounds.
E. Low binding energy: MgO has a high binding energy due to the strong ionic bonds between the magnesium and oxygen ions. This high binding energy is responsible for its high melting point. Hence, option E is the correct answer because MgO does not have a low binding energy.
Source: Myschool Past Questions Archive (Record #36331)
Chemistry
WAEC / WASSCE 1994
Reaction Rates & Chemical Equilibrium
Which of the following would increase the rate of reaction of chips of a metal M as shown in the equation below? M(s) + 2HCI(aq) → MCI2(aq) + H2(g)
A
Diluting the hydrochloric acid
B
Adding some distilled water
C
Decreasing the temperature
D
Grinding the metal into powder
E
Increasing the pressure
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #36332)
Chemistry
WAEC / WASSCE 1994
Oxidation, Reduction & Redox Reactions
Solution
The oxidation number of phosphorus in \(PO_4^{3-}\) is
A
+ 1
B
+2
C
+3
D
+4
E
+5
medium Difficulty
Verified Correct Answer: Option E
Chemical Principles & Mechanism
The oxidation number of phosphorus in \(PO_4^{3-}\) is calculated as follow;
\(PO_4\) = -3
but oxidation number of oxygen = -2
P + (-2 x 4) = - 3
P - 8 = -3
P = -3 + 8 = +5
\(\therefore\) the oxidation number of phosphorus in \(PO_4^{3-}\) = + 5.
Source: Myschool Past Questions Archive (Record #36333)
Chemistry
WAEC / WASSCE 1994
Atomic Structure, Orbitals & Nuclear Chemistry
The number of atoms in 1.2g of carbon - 12 isotope is
A
1.00 x 10 22
B
6.02 x 1022
C
1.20 x 10 23
D
1.00 x 1023
E
6.02 x 1024
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #36337)
Chemistry
WAEC / WASSCE 1994
Acids, Bases, pH & Salts
Tetraoxosulphate (lV) acid is described as strong acid because it is highly
A
corrosive
B
concentrated
C
reactive
D
soluble in water
E
ionized in water
medium Difficulty
Verified Correct Answer: Option E
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option E.
Source: Myschool Past Questions Archive (Record #36338)
Chemistry
WAEC / WASSCE 1994
Oxidation, Reduction & Redox Reactions
The following will decolourize acidified potassium tetraoxomanganate (VII) solution except
A
sulphur (lV) oxide
B
but-3-ene
C
pentane
D
hydrogen sulphide
E
propyne
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #36339)