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Physics
UTME / JAMB 1995
Current Electricity & Electric Circuits
Solution
When a ball rolls on a smooth level ground, the motion of its center is
A
translational
B
oscillatory
C
random
D
rotational
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
A ball rolling along a smooth surface observes translational motion at the center while the rest of the body rotates round the center.
Source: Myschool Past Questions Archive (Record #27753)
Physics
UTME / JAMB 1995
Current Electricity & Electric Circuits
Solution
What is the acceleration due to gravity 'g' on the moon, if g is 10-2 on the earth?
A
0. 10 ms-2
B
0.74ms-2
C
1.6ms-2
D
10.00ms-2
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
s = 10-2 on earth
g = 6 ms-2 on earth
Earth on moon = \(\frac{10}{6}\)
= 1.6ms-2
Source: Myschool Past Questions Archive (Record #27758)
Physics
UTME / JAMB 1995
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
A body is projected from the earth's surface with the intention of letting it escape from the earth's gravitational field. What is the minimum escape velocity of the body? [Earth's radius = 6.4 x 103km, g = 10ms-2]
A
14 kms-1
B
13 kms-1
C
12 kms-1
D
11 kms-1
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Velocity = \(\sqrt2gR\)
= 2 x 6400 x 100 x 10
= 11 km-1
Source: Myschool Past Questions Archive (Record #27760)
Physics
UTME / JAMB 1995
Equilibrium of Forces, Moments & Flotation
A uniform rod PQ of length 1m and mass 2kg is pivoted at the end p. If load of 14N is placed at the center of the rod, find the force that should be applied vertically upwards at Q to maintain the rod at equilibrium horizontally [g = 10ms-2]
A
68N
B
28N
C
17N
D
7N
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #27766)
Physics
UTME / JAMB 1995
Current Electricity & Electric Circuits
Solution
A vehicle of mass m is driven by an engine of power P from rest. Find the minimum time it will take to acquire a speed
A
\(\frac{mv^2}{2p}\)
B
\(\frac{mv^2}{p}\)
C
\(\frac{mv}{p}\)
D
\(\frac{mv}{2p}\)
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
To find the minimum time \( t \) it takes for a vehicle of mass \( m \) to acquire a speed \( v \) when driven by an engine of power \( P \), we use the work-energy principle.
The relationship is given by:
\(t = \frac{m v^2}{2P}\)
Thus, the minimum time \( t \) to acquire speed \( v \) is:
\(t = \frac{m v^2}{2P}\).
Source: Myschool Past Questions Archive (Record #27768)
Physics
UTME / JAMB 1995
Scalars, Vectors & Relative Motion
Which of the following statements are TRUE about frictional force? i. it is always a disadvantage ii. it is sometimes a disadvantage iii. it always exist where there is a relative motion of two bodies that are in contact iv. it is sometimes very useful
A
i, iii only
B
i, iv only
C
ii, iii only
D
iii, iv only
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #27772)
Physics
UTME / JAMB 1995
Current Electricity & Electric Circuits
Solution
The energy contained in a wire when it extended by 0.02m by a force 500 N is
A
5J
B
10J
C
103J
D
104
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Energy = \(\frac{1}{2}\)Fe
= \(\frac{1}{2}\) x 500 x 0.02
E = 5J
Source: Myschool Past Questions Archive (Record #27774)
Physics
UTME / JAMB 1995
Work, Energy, Power & Simple Machines
Solution
A hydraulic press has a large circular piston of radius 0.8m and a circular plunger of radius 0.2m. A force of 500N is exerted by the plunger. Find the force exerted on the piston
A
8000N
B
4000N
C
2000N
D
31N
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Pressure on piston = pressure on the plunger
\(\frac{500}{\pi\ \times\ 0.2 \times\ 0.2}\) = \(\frac{F}{\pi\ \times\ 0.8 \times\ 0.8}\)
F = 8000N
Source: Myschool Past Questions Archive (Record #27776)
Physics
UTME / JAMB 1995
Equilibrium of Forces, Moments & Flotation
The volume of an air bubble increases from the bottom to the top of a lake at constant temperature because
A
atmospheric pressure acts on the surface of the lake
B
pressure increases with depth
C
density remains constant with pressure
D
the bubble experiences an upthrust
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #27780)
Physics
UTME / JAMB 1995
Work, Energy, Power & Simple Machines
Temperature is the measure of the
A
quantity of heat transferred into the molecules of an object
B
mean kinetic energy of the molecules of the object
C
kinetic energy of any individual molecule of the substance
D
amount of work done by the molecules of the object
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #27784)
Physics
UTME / JAMB 1995
Current Electricity & Electric Circuits
Solution
A rectangular metal block of volume 10\(^{-6}\)m\(^3\) at 273k is heated to 573k. If its coefficient of linear expansion is 1.2 x 10\(^{-5}\)k\(^{-1}\), the percentage change of it volume is
A
1.5%
B
1.1%
C
0.4%
D
0.1%
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Y = \(\frac{\Delta V}{V \times \Delta \theta}\)
3 x 10-5 x 1.2 = \(\frac{\Delta\ V}{10^{-6}\times\ (573 - 273)}\)
\(\Delta\)V = 1.080 x 10\(^{-7}\)m\(^3\)
%\(\Delta\)V = \(\frac{1.080 \times\ 10^{-7}}{10^{-6}}\) x 100
= 1.08%
\(\approx\) = 1.1%
Source: Myschool Past Questions Archive (Record #27793)
Physics
UTME / JAMB 1995
Equilibrium of Forces, Moments & Flotation
A piece of wood floats inside water at room temperature with a fraction of it above the liquid surface. As the temperature of the water is raised, the part of the wood above the liquid will
A
decrease because the density of water decreases with temperature
B
increase because the density of water decreases with temperature
C
decreases because the density of water increases with water temperature
D
increase because the density of water increases with temperature
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #27804)
Physics
UTME / JAMB 1995
Gas Laws & Heat Transfer
Solution
The equation PxVyTz = constant in charles' law when
A
x = 1, y = -1, z = 1
B
x = 0, y = 1, z = -1
C
x = 1, y = 0, z = -1
D
x = 0, y = 1, z = 1
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
According to Charles' law, the volume of a given mass of gas is directly proportional to its absolute temperature at constant pressure.
Source: Myschool Past Questions Archive (Record #27807)
Physics
UTME / JAMB 1995
Calorimetry, Latent Heat & Change of State
Solution
An electric kettle with negligible heat capacity is rated at 2000W. If 2.0kg of water is put in it, how long will it take the temperature of water to rise from 20OC to 100OC? [specific heat capacity of water = 4200Jkg-1k-1]
A
420S
B
336S
C
168S
D
48S
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Heat energy = Elect. energy
mc\(\theta\) = power x time
2 x 4200 x (100 - 20) = 2000 x t
t = 336s
Source: Myschool Past Questions Archive (Record #27810)
Physics
UTME / JAMB 1995
Temperature, Thermometry & Thermal Expansion
Solution
A temperature scale has a lower fixed point of 40mm and a upper fixed point of 200mm. What is the reading on this scale when a thermometer reads 60oC?
A
33.3mm
B
36.0mm
C
96.0mm
D
136.0mm
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
200mm ..... 100oC
Xmm ..... 60oC
400mm ..... 0oC
\(\frac{x - 40}{200 - 40}\) = \(\frac{60 - 0}{100 - 0}\)
X = 136mm
Source: Myschool Past Questions Archive (Record #27815)