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Physics
WAEC / WASSCE 1996
Reflection, Refraction & Dispersion of Light
Solution
A boy walks away from a plane mirror at a speed of 3 ms-1 in a direction normal to the surface of the mirror. At what speed is his image approaching him?
A
8 9.0ms-1
B
6.0ms-1
C
4.5ms-1
D
1.5ms-1
E
0.0ms-1
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Velocity of image w.r.t boy = velocity of object - velocity of image
velocity w.r.t to boy = v - (-v)
=3.0 - (-3.0)
The image velocity is 6 m/s towards the boy.
Source: Myschool Past Questions Archive (Record #25224)
Physics
WAEC / WASSCE 1996
Lenses & Optical Instruments
Solution
A converging lens of focal length 5cm forms a virtual image which is 10cm from the lens. How far from the lens is the object?
A
2.0cm
B
3.3cm
C
5.0cm
D
10.0cm
E
15.0cm
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(f = \frac{uv}{u+v}\)
\(5 = \frac{-10u}{-10+u}\)
\(50 + 5u = -10u\)
\(50 = -10u - 5u\)
\(u = \frac{50}{-15}\)
u= -3.3cm
Source: Myschool Past Questions Archive (Record #25230)
Physics
WAEC / WASSCE 1996
Current Electricity & Electric Circuits
Which of the following instruments produces sound by the vibration of air column?
A
Piano
B
Guitar
C
Flute
D
Hand bell
E
Talking drum
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25231)
Physics
WAEC / WASSCE 1996
Waves, Sound & Vibrations
The walls and ceilings of many standard auditoria are covered with perforated pads to
A
increase the intensity of sound waves
B
increase the loudness of sound waves
C
reduce the effect of reverberations of sound waves
D
increase the interference effect of sound waves
E
decrease the frequency of sound waves.
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25232)
Physics
WAEC / WASSCE 1996
Current Electricity & Electric Circuits
A string of length 1.0 m vibrates in 10 loops. If the total mass of the string is 1.0 x 10-3 kg and the tension in it is 10N, calculate the frequency of the vibration.
A
50Hz
B
100Hz
C
250Hz
D
400Hz
E
500Hz
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #25233)
Physics
WAEC / WASSCE 1996
Current Electricity & Electric Circuits
The distance between two successive crests of a water is 1m. lf a particle on the surface of the water makes two complete vertical oscillations in 1 second, calculate the speed of the wave
A
0.5 ms-1
B
1.0 ms-1
C
2.0ms-1
D
3.0ms-1
E
4.0ms-1
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25234)
Physics
WAEC / WASSCE 1996
Reflection, Refraction & Dispersion of Light
Diagram
The graph above shows the relationship between sin i and sin r for a ray of light in air incident on a liquid surface. If i and r are respectively angles of incidence and refraction, deduce the refractive index of the liquid from the graph
Attached Figure / Diagram
A
1.63
B
1.50
C
1.33
D
1.25
E
0.08
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #25225)
Physics
WAEC / WASSCE 1996
Reflection, Refraction & Dispersion of Light
When a ray of light is incident normally on an air- glass interface, its angle of refraction is
A
0o
B
42o
C
45o
D
60o
E
90o
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #25226)
Physics
WAEC / WASSCE 1996
Reflection, Refraction & Dispersion of Light
Diagram
Solution
A ray of light is incident on a glass block as shown in the diagram above. If the reflected and the retracted rays are perpendicular to each other, what is the refractive index of the glass relative to air.?
Attached Figure / Diagram
A
1.60
B
1.58
C
1.52
D
1.50
E
1.48
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Given: Angle of incidence i = 58º
Reflected and refracted rays are perpendicular.
Since the angle between the reflected ray and the normal is also 58º
\(r + 58^\circ = 90^\circ\)
\(r = 32^\circ\)
Using Snell's law:
\(n=\frac{\sin i}{\sin r}\)
n= \(\frac{\sin58^\circ}{\sin32^\circ}\)
n \(\approx \frac{0.848}{0.530}\) = 1.6
So, the refractive index of the glass relative to air is 1.6.
Source: Myschool Past Questions Archive (Record #25227)
Physics
WAEC / WASSCE 1996
Reflection, Refraction & Dispersion of Light
The refractive index of a medium relative to air is 1.8. Calculate the critical angle for the medium to the nearest degree.
A
18o
B
34o
C
45o
D
68o
E
90o.
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #25229)
Physics
WAEC / WASSCE 1996
Current Electricity & Electric Circuits
The main function of the mouth of a telephone is to convert sound energy into
A
heat energy
B
light energy
C
chemical energy
D
electrical energy
E
mechanical energy
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #25240)
Physics
WAEC / WASSCE 1996
Current Electricity & Electric Circuits
Which of the following is not a component of a d.c. electric motor?
A
Commutator
B
Field magnets
C
Slip rings
D
Armature
E
Carbon brushes
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25241)
Physics
WAEC / WASSCE 1996
Current Electricity & Electric Circuits
Diagram
The diagram above illustrates the conversion of a galvanometer of resistance 29 to an ammeter. The galvanometer gives a full-scale deflection for a current of 10mA. Calculate the value of R.
Attached Figure / Diagram
A
2.0 x 103 Ω
B
2.0 x 102 Ω
C
2.0 x 10-1 Ω
D
2.0 x 10-2 Ω
E
2.0 x 10-3 Ω
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option E.
Source: Myschool Past Questions Archive (Record #25242)
Physics
WAEC / WASSCE 1996
Current Electricity & Electric Circuits
Solution
A wire of length 100cm and cross-sectional area of 2.0 x 10-3cm2 has a resistance of 0.10 \Omega. Calculate its electrical conductivity.
A
5.0 x 107Ω-1cm-1
B
5.0 x 106Ω-1cm-1
C
2.0 x 106Ω-1cm-1
D
5.0 x 105Ω-1cm-1
E
2.0 x 106Ω-1cm-1
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Given: Length of the wire, \( L = 100 \, \text{cm} = 1.0 \, \text{m} \), Cross-sectional area, \( A = 2.0 \times 10^{-3} \, \text{cm}^2 = 2.0 \times 10^{-7} \, \text{m}^2 \)
Resistance, \( R = 0.10 \, \Omega \)
The formula for resistivity \( \rho \) is given by:
\(\rho = R \cdot \frac{A}{L}\)
Substituting the values:
\(\rho = 0.10 \, \Omega \cdot \frac{2.0 \times 10^{-7} \, \text{m}^2}{1.0 \, \text{m}} = 2.0 \times 10^{-8} \, \Omega \cdot \text{m}\)
Now, we can find the conductivity \( \sigma \):
\(\sigma = \frac{1}{\rho} = \frac{1}{2.0 \times 10^{-8} \, \Omega \cdot \text{m}} = 5.0 \times 10^{7} \, \Omega^{-1} \cdot \text{m}^{-1}\)
To convert to \( \text{cm}^{-1} \):
\(\sigma = 5.0 \times 10^{7} \, \Omega^{-1} \cdot \text{m}^{-1} \times \left( \frac{1}{100 \, \text{cm}} \right) = 5.0 \times 10^{5} \, \Omega^{-1} \cdot \text{cm}^{-1}\)
Thus, the electrical conductivity is:
\(\sigma = 5.0 \times 10^{5} \, \Omega^{-1} \cdot \text{cm}^{-1}\).
Source: Myschool Past Questions Archive (Record #25243)
Physics
WAEC / WASSCE 1996
Magnetism, Electromagnetism & AC Circuits
Lenz's law of electromagnetic induction states that
A
e.m.f. is induced in a circuit whenever there is a change in the magnetic flux linked with the circuit.
B
the induced current in a conductor is in such a direction as to oppose the change producing it
C
the magnitude of the induced e.m.f. in a circuit is proportional to the rate of change of the number of lines of force linking the circuit
D
a force is exerted on a current-carrying conductor in a magnetic Held
E
the induced charge is constant for a fixed change of flux.
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #25244)