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English Language
WAEC / WASSCE 1997
Lexis, Structure & Register (Cloze & Vocabulary)
In question numbered 96 above, choose the best option from letters A - E that best completes the gap.
A
fire
B
heater
C
lantern
D
lamp
E
stove
medium Difficulty
Verified Correct Answer: Option E
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option E.
Source: Myschool Past Questions Archive (Record #24494)
English Language
WAEC / WASSCE 1997
Lexis, Structure & Register (Cloze & Vocabulary)
In question numbered 97 above, choose the best option from letters A - E that best completes the gap.
A
plate
B
kettle
C
saucepan
D
frying-pan
E
warmer
medium Difficulty
Verified Correct Answer: Option B
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #24495)
English Language
WAEC / WASSCE 1997
Lexis, Structure & Register (Cloze & Vocabulary)
In question numbered 98 above, choose the best option from letters A - E that best completes the gap.
A
banana
B
corn
C
lettuce
D
yam
E
cabbage
medium Difficulty
Verified Correct Answer: Option D
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #24496)
English Language
WAEC / WASSCE 1997
Lexis, Structure & Register (Cloze & Vocabulary)
In question numbered 99 above, choose the best option from letters A - E that best completes the gap.
A
slices
B
cubes
C
morsels
D
portions
E
fragments
medium Difficulty
Verified Correct Answer: Option A
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #24497)
English Language
WAEC / WASSCE 1997
Lexis, Structure & Register (Cloze & Vocabulary)
In question numbered 100 above, choose the best option from letters A - E that best completes the gap.
A
coconuts
B
tomatoes
C
eggs
D
onions
E
palm nuts
medium Difficulty
Verified Correct Answer: Option C
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #24498)
Chemistry
UTME / JAMB 1997
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
35 cm3 of hydrogen was sparked with 12 cm3 of oxygen at 110^\circC and 760mm Hg to produce steam. What percentage of the total volume of gas left after the reaction is hydrogen?
A
11%
B
31%
C
35%
D
69%
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Reaction for the equation:
\(2H_{2} + O_{2} \to 2H_{2} O\)
\(2 vol : 1 vol : 2 vol\)
Hence, 2 volumes of Hydrogen is needed for the reaction with Oxygen to produce steam (water).
\(\therefore 12cm^{3} O_{2} \to 2 \times 12cm^{3} = 24cm^{3} H_{2}\)
\(\text{Excess of Hydrogen} : 35 cm^{3} - 24 cm^{3} = 11 cm^{3}\)
\(\text{% Hydrogen left after the reaction} = \frac{11}{35} \times 100% = \frac{220}{7} = 31.48% \)
\(\approxeq 31% \)
Source: Myschool Past Questions Archive (Record #13720)
Chemistry
UTME / JAMB 1997
Particulate Nature of Matter, Laws & Formulae
2.85g of an oxide of copper gave 2.52g of copper on reduction and 1.90g of another oxide gave 1.52g of copper on reduction. The data above illustrates the law of?
A
constant composition
B
conservation of mass
C
reciprocal proportions
D
multiple proportions
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #13723)
Chemistry
UTME / JAMB 1997
Particulate Nature of Matter, Laws & Formulae
Solution
An element, X, forms a volatile hydride XH3 with a vapour density of 17.0. The relative atomic mass of X is?
(H = 1)
A
34.0
B
31.0
C
20.0
D
14.0
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Molecular Mass = Vapour density x 2 = 17.0 x 2 = 34.0
∴ Relative Atomic Mass of X in XH3 = 34 - 3
= 31.0 ∴ x = 31.0
Source: Myschool Past Questions Archive (Record #13730)
Chemistry
UTME / JAMB 1997
Kinetic Theory of Matter & Gas Laws
Solution
A mixture of 0.20 mole of Ar, 0.20 mole of N2 and 0.30 mole of He exerts a total pressure of 2.1 atm. The partial pressure of He in the mixture is?
A
0.90 atm
B
0.80 atm
C
0.70 atm
D
0.60 atm
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Total no mole = 0.2 + 0.2 + 0.3 = 0.7
Partial pressure of He = (0.3)/(0.7) x 2.1 =0.90
Source: Myschool Past Questions Archive (Record #13734)
Chemistry
UTME / JAMB 1997
Stoichiometry, Mole Concept & Volumetric Analysis
The temperature of a body decreases when drops of liquid placed on it evaporate because?
A
the atmospheric vapour pressure has a cooling effect on the body
B
a temperature gradient exists between the drops of liquid and the body causing the latter to vaporate
C
the heat of vapourization is drawn from the body causing it to cool
D
the random motion of the liquid molecules causes a cooling effect on the body
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #13735)
Chemistry
UTME / JAMB 1997
Atomic Structure, Orbitals & Nuclear Chemistry
The electron configuration of two elements with similar chemical properties are represented by?
A
1s22s22p5 and 1s22s22p4
B
1s22s22p4 and 1s22s22p63s1
C
1s22s22p63s1 and 1s22s1
D
1s22s22p4 and 1s22s1
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #13742)
Chemistry
UTME / JAMB 1997
Periodic Table & Periodicity
In the periodic table, what is the property that decreases along the periodic and increases down the group?
A
Atomic number
B
Electron affinity
C
Ionization potential
D
Atomic radius
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #13743)
Chemistry
UTME / JAMB 1997
Stoichiometry, Mole Concept & Volumetric Analysis
Two elements, P and Q with atomic numbers 11 and 8 respectively , combine chemically to form the compound PxQY. The respective values of x and y are?
A
1 and 1
B
1 and 2
C
2 and 1
D
3 and 1
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #13745)
Chemistry
UTME / JAMB 1997
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
Oxygen is a mixture of two isotopes 16-O and 18-O with relative abundances of 90% and 10% respectively. The relative atomic mass of oxygen is?
A
16.0
B
16.2
C
17.0
D
18.0
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
816O, 818O
90% 10%
R.A.M = (90)/(100) x 16 + (10)/(100) x 18 = 14.4 + 1.8 = 16.2
Source: Myschool Past Questions Archive (Record #13754)
Chemistry
UTME / JAMB 1997
Kinetic Theory of Matter & Gas Laws
Solution
If 30cm\(^3\) of oxygen diffuses through porous plug in 7s, how long will it take 60 cm\(^3\) of chlorine to diffuse through the same plug?
A
12s
B
14s
C
21s
D
30s
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Given:
t\(_c\) = ? V\(_c\) = 60cm\(^3\) , M\(_c\) = 35.5 x 2 = 71
t\(_o\) = 7s; V\(_o\) = 30cm\(^3\) , M\(_o\) = 16 x 2 = 32
According to Graham's law of diffusion, R ∝ 1/\sqrtM
\(\frac{R_o}{R_c}\) = \(\sqrt{\frac{M_c}{M_o}}\)
Also, Rate of diffusion = \(\frac{Volume}{time}\)
\(\frac{R_o}{R_c}\) = \(\frac{V_o}{t_o}\) \div \(\frac{V_c}{t_c}\) = \(\frac{V_o}{t_o}\) X \(\frac{t_c}{V_c}\)
Therefore, \(\frac{V_o}{t_o}\) X \(\frac{t_c}{V_c}\) = \(\sqrt{\frac{M_c}{M_o}}\)
\(\frac{{30}\times{t_o}}{{7}{60}}\) = \(\sqrt{\frac{71}{32}}\)
\(\frac{t_c}{14}\) = 1.489
t\(_c\) = 14 x 1.489
t\(_c\) = 20.846
t\(_c\) = 21s
Source: Myschool Past Questions Archive (Record #13779)