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English Language
UTME / JAMB 1997
Concord (Subject-Verb Agreement)
Fill each gap with the most appropriate option from the list following the gap.
All the cattle on Lamidi's farm ...... ?
A
is tick-free
B
are tick-free
C
is ticks-free
D
are ticks-free
medium Difficulty
Verified Correct Answer: Option B
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #10891)
English Language
UTME / JAMB 1997
Lexis, Structure & Register (Cloze & Vocabulary)
Fill each gap with the most appropriate option from the list following the gap.
He saw the play and so ....... ?
A
was she
B
had she
C
should she
D
did she
medium Difficulty
Verified Correct Answer: Option D
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #10892)
English Language
UTME / JAMB 1997
Lexis, Structure & Register (Cloze & Vocabulary)
Fill each gap with the most appropriate option from the list following the gap.
The ..... of what she was cooking filled the whole compound?
A
fragrance
B
scent
C
aroma
D
smell
medium Difficulty
Verified Correct Answer: Option C
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #10894)
English Language
UTME / JAMB 1997
Question Tags, Modals & Pronouns
Fill each gap with the most appropriate option from the list following the gap.
I hope i have not ...... too much on your time?
A
invaded
B
encroached
C
intruded
D
trespassed
medium Difficulty
Verified Correct Answer: Option B
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #10896)
English Language
UTME / JAMB 1997
Lexis, Structure & Register (Cloze & Vocabulary)
Fill each gap with the most appropriate option from the list following the gap.
The exercise presented us with a lot of problems but later it was all ...... sailing?
A
plain
B
smooth
C
rough
D
tough
medium Difficulty
Verified Correct Answer: Option B
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #10897)
Physics
WAEC / WASSCE 1997
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
An object of mass 0.40 kg attached to the end of a string is whirled around in a horizontal circle of radius 2.0m with a constant speed of 8\(ms^{-1}\). Calculate the angular velocity of the object
A
0.8rad\(s^{-1}\)
B
2 rad\(s^{-1}\)
C
4 rad\(s^{-1}\)
D
8 rad\(s^{-1}\)
E
16 rad\(s^{-1}\)
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
V=rw, 8=2w, w=8/2= 4rad/s
Source: Myschool Past Questions Archive (Record #26288)
Physics
WAEC / WASSCE 1997
Linear Motion, Projectiles & Kinematics
Solution
An object falls freely from a height of 25m onto the roof a building 5m high. Calculate the velocity with which the object strikes the roof (g=10\(ms^{-2}\)
A
17.3\(ms^{-2}\)
B
20\(ms^{-2}\)
C
24.5\(ms^{-2}\)
D
125\(ms^{-2}\)
E
200\(ms^{-2}\)
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(v^2 = u^2 +2aS = 0 +2\times(25-5)\)
\(v^2 =0+ 20\times 20 = 400\);
v =\(\sqrt{400}= 20(ms^{-2}\)
Source: Myschool Past Questions Archive (Record #26289)
Physics
WAEC / WASSCE 1997
Current Electricity & Electric Circuits
Solution
A ball of mass 0.1kg approaching a tennis player with a velocity of 10ms\(^{-1}\),is hit back in the opposite direction with a velocity of 15ms\(^{-1}\). If the time of impact between the racket and the ball is 0.01s, calculate the magnitude of the force with which the ball is hit
A
5000N
B
500N
C
250N
D
50N
E
25N
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
M =0.1kg; F=\(m\left(\frac{v-u}{t}\right) = 0.1\left(\frac{15-(-10)}{0.01}\right)\) F=250N
Source: Myschool Past Questions Archive (Record #26290)
Physics
WAEC / WASSCE 1997
Current Electricity & Electric Circuits
Two forces 3N and 4N act on a body in directions due north and due east respectively. Calculate their equilibrant
A
5N 53° east of North
B
5N 53° west of the south
C
5N 37° north of east
D
7N 37° west of North
E
7N 37° south of west
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #26292)
Physics
WAEC / WASSCE 1997
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
A missile weighing 400N on the earth surface is shot into the atmosphere to an altitude of 6.4 x \(10^{-6}\)m. Taking the earth as a sphere of radius 6.4 x \(10^{-6}\)m and assuming the inverse-square law of universal gravitation, what would be the weight of the missile at that altitude?
A
100N
B
200N
C
400N
D
800N
E
1600N
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
To find the weight of the missile at an altitude using the inverse-square law of gravitation, we can use the formula for gravitational force:
\(F = \frac{G \cdot m_1 \cdot m_2}{r^2}\)
where:
- \( F \) is the gravitational force (weight),
- \( G \) is the gravitational constant,
- \( m_1 \) is the mass of the Earth,
- \( m_2 \) is the mass of the missile,
- \( r \) is the distance from the center of the Earth to the missile.
Step 1: Determine the radius at altitude
1. The radius of the Earth is \( R = 6.4 \times 10^6 \, \text{m} \).
2. The altitude \( h = 6.4 \times 10^6 \, \text{m} \).
Thus, the distance from the center of the Earth to the missile at that altitude is:
\(r = R + h = 6.4 \times 10^6 \, \text{m} + 6.4 \times 10^6 \, \text{m} = 12.8 \times 10^6 \, \text{m}\)
Step 2: Calculate the weight at the altitude
The weight of the missile at the surface is given as \( W_0 = 400 \, \text{N} \). The weight at altitude can be calculated using the ratio of the squares of the distances:
\(W = W_0 \cdot \left( \frac{R}{r} \right)^2\)
Substituting the values:
\(W = 400 \cdot \left( \frac{6.4 \times 10^6}{12.8 \times 10^6} \right)^2\)
Calculating this:
\(W = 400 \cdot \left( \frac{1}{2} \right)^2 = 400 \cdot \frac{1}{4} = 100 \, \text{N}\)
The weight of the missile at an altitude of \( 6.4 \times 10^6 \, \text{m} \) is \( 100 \, \text{N} \).
Source: Myschool Past Questions Archive (Record #26293)
Physics
WAEC / WASSCE 1997
Equilibrium of Forces, Moments & Flotation
Solution
A solid plastic cube of side 0.2m is submerged in a liquid density of 0.8kg\(m^{-3}\). Calculate the upthrust of the liquid on the cube (g=10\(ms^{-2}\)
A
0.064N
B
0.025N
C
0.016N
D
0.008N
E
0.003N
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Upthrust = Volume of fluid displaced =vpg =0.2 x 0.2 x 0.2 x0.8 x 10= 0.064N
Source: Myschool Past Questions Archive (Record #26294)
Physics
WAEC / WASSCE 1997
Calorimetry, Latent Heat & Change of State
Solution
A piece of copper of mass 30g loses 60J of heat energy. If the specific heat capacity of copper is 400J\(kg^{-1}K^{-1}\), Calculate the change in the temperature of the copper
A
0.2K
B
0.8K
C
2K
D
4.5K
E
5K
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
H=\(mc\Delta\theta \Rightarrow 60=0.03\times400\times\Delta\theta\\60= 12\Delta\theta therefore \Delta\theta=60/12 =5K\)
Source: Myschool Past Questions Archive (Record #26295)
Physics
WAEC / WASSCE 1997
Calorimetry, Latent Heat & Change of State
Which of the following explains why a thick glass cup cracks when boiling water is poured into it?
A
Unequal expansion of the exterior and interior walls of the cup
B
Anomalous expansion of the water
C
Greater specific latent capacity of water compared with that of glass
D
Large increase in the heat capacity of the cup
E
High density of the water
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #26297)
Physics
WAEC / WASSCE 1997
Waves, Sound & Vibrations
Solution
When white light is incident on a glass prism the spectrum produced on a screen placed beyond the prism is due to?
A
Diffraction
B
Reflection
C
Refraction
D
Polarisation
E
Interference
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
White light splits into a spectrum when it passes through a glass prism due to refraction, as different wavelengths bend by varying amounts, causing dispersion.
Source: Myschool Past Questions Archive (Record #26298)
Physics
WAEC / WASSCE 1997
Lenses & Optical Instruments
Solution
At what distance from a simple microscope must an object be placed so that the image 5 times the size of the object is produced 20cm from the lens?
A
2cm
B
3.3cm
C
4cm
D
5cm
E
15cm
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
M=\(\frac {v}{u}\) = 5
v = 5u
But, v = 20,
V = 5u = 20
u = \(\frac{20}{5}\) = 4 cm.
Source: Myschool Past Questions Archive (Record #26299)