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Mathematics
UTME / JAMB 1998
Algebraic Expressions, Polynomials & Factorisation
Solution
When the expression pm\(^2\) + qm + 1 is divided by (m - 1), it has a remainder is 2, and when divided by (m + 1), the remainder is 4. Find p and q respectively
A
2, -1
B
-1, 2
C
3, -2
D
-2, 3
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
pm\(^2\) + qm + 1 = (m - 1) Q(x) + 2, where Q(x) = remainder.
p(1)\(^2\) + q(1) + 1 = 2
p + q + 1 = 2
p + q = 1.....(i)
pm\(^2\) + qm + 1 = (m - 1)Q(x) + 4
p(-1)\(^2\) + q(-1) + 1 = 4
p - q + 1 = 4
p - q = 3....(ii)
p + q = 1, p - q = 3
Using elimination method, add eqn i and ii
2p = 4, p = 2
from eqn ii
p - q = 3
2 - q = 3
-q = 3 - 2 = 1
q = - 1
Therefore, p = 2 and q = -1
q = 2
Source: WAEC / JAMB / NECO Classroom Archive (Record #30667)
Mathematics
WAEC / WASSCE 1998
Mensuration (Areas, Perimeters & Volumes)
Diagram
Solution
In the diagram O is the center of circle PRQ. The radius is 3.5cm and ∠POQ = 50o. Use the diagram to answer question below. (take π = 3.142)
Calculate, correct to three significant figures, the area of sector OPQ
Attached Figure / Diagram
A
3.403cm2
B
5.350cm2
C
10.99cm2
D
157.1cm2
E
175.0cm2
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
Area of a sector = \(\frac{\theta}{360}\) x \(\pi\)r\(^2\)
Area of a sector = \(\frac{50}{360}\) x 3.142 x 3.5 x 3.5
= \(\frac{50 \times 3.142\times 3.5 \times 3.5}{360}\)
= \(\frac{1924.475}{360}\) ≈ 5.346cm\(^2\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #26359)
Mathematics
WAEC / WASSCE 1998
Mensuration (Areas, Perimeters & Volumes)
Diagram
Solution
Calculate the perimeter of the trapezium PQRS
Attached Figure / Diagram
A
24cm
B
36cm
C
48cm
D
72cm
E
520cm
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
Using Pythagora's rule for △PSM
Hyp\(^2\) = Opp\(^2\) + Adj\(^2\)
5\(^2\) = Opp\(^2\) + 4\(^2\)
→ Opp\(^2\) = 25 - 16
→ Opp = \sqrt9 = 3
base SR = 18 + 3 = 21
base PQ = 18
side PS = 5
side QR = 4
perimeter of the trapezium PQRS = 21 + 18 + 5 + 4 = 48cm
Source: WAEC / JAMB / NECO Classroom Archive (Record #26360)
Mathematics
WAEC / WASSCE 1998
Mensuration (Areas, Perimeters & Volumes)
Solution
The diagonal and one side of a square are x and y units respectively. Find an expression for y in terms of x
A
\(y=\frac{x}{2}\)
B
\(y\frac{x}{\sqrt{2}}\)
C
\(y=\sqrt{x}\)
D
\(y=\sqrt{\frac{x}{2}}\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
diagonal of a square(x) = y\sqrt2
y in terms of x →
y = \(\frac{x}{\sqrt2}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #26368)
Mathematics
UTME / JAMB 1998
Mensuration (Areas, Perimeters & Volumes)
Solution
a cylindrical drum of diameter 56 cm contains 123.2 litres of oil when full. Find the height of the drum in centimeters
A
12.5
B
25.0
C
45.0
D
50.00
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
V = \(\pi r^2 h\)
= 123.2 x 1000
= \(\frac{22}{7}\) x 28 x 28 x h
= 123200 = 88 x 28h
= 2464h
∴ h = \(\frac{123200}{2464}\)
= 50cm
N.B: 1 litre = 1 dm3
= 1000cm3
Source: WAEC / JAMB / NECO Classroom Archive (Record #30721)
Mathematics
WAEC / WASSCE 1998
Trigonometry, Elevation & Bearings
Solution
A ladder 5cm long long rest against a wall such that its foot makes an angle 30o with the horizontal. How far is the foot of the ladder from the wall?
A
\(\frac{5\sqrt{2}}{3}m\)
B
\(2\frac{1}{2}m\)
C
\(\frac{5\sqrt{3}}{2}m\)
D
\(\frac{10\sqrt{3}}{3}m\)
E
\(10\sqrt{3}m\)
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
cos 30 = \(\frac{adj}{hyp}\)
cross multiply:
adj = cos 30 X 5
= 5 \(\frac{\sqrt3}{2}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #26352)
Mathematics
WAEC / WASSCE 1998
Statistics (Data Representation, Central Tendency & Dispersion)
Diagram
Solution
The pie chart above show the distribution of how students travelled to a certain school on a particular day. Use this information to answer the question below
If a hundred students travelled by bus, find the total number of students in the school
Attached Figure / Diagram
A
300
B
400
C
500
D
600
E
750
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
If X represent the total number of students
where the bus holds a right angle; 90º
\(\frac{90}{360}\times X=100\)(students traveling by bus)
\(X=\frac{100\times 360}{90}=400\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #26362)
Physics
WAEC / WASSCE 1998
Calorimetry, Latent Heat & Change of State
Solution
A waterfall is 1260m high. Calculate the change in temperature of a quantity of water that falls from the top to the bottom of the waterfall. (Neglect heat losses to the surroundings, take g as 10m-2 and specific heat capacity of water as 4200Jkg-1K-1)
A
0.3oC
B
3.0oC
C
33.3oC
D
42.0oC
E
100.0oC
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(\Delta t = \frac{gh}{c} = \frac{1260 \times 10}{4200}\)
= 3.0o
Source: WAEC / JAMB / NECO Classroom Archive (Record #33586)
Physics
UTME / JAMB 1998
Equilibrium of Forces, Moments & Flotation
Solution
A uniform meter rule weighing 0.5N is to be pivoted on a knife-edge at the 30cm-mark. where will a force of 2N be placed from the pivot to balance the meter rule?
A
95cm
B
25cm
C
20cm
D
5cm
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Taking moment about P,
2 x d = 0.5 x (50 - 30)
2x = 10
x = 5 cm
Source: WAEC / JAMB / NECO Classroom Archive (Record #27602)
Physics
UTME / JAMB 1998
Scalars, Vectors & Relative Motion
Diagram
Solution
A body on the ground is acted on by a force of 10N at a point P as shown in the fig above. What force is needed to stop the body from moving eastwards?
Attached Figure / Diagram
A
5N in the direction of east
B
5N in the diretion of west
C
5V3N in the direction of west
D
10N in the southwest direction
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The horizontal (eastward) component of the 10N force is = 10 cos60
→ 10 x 0.5 = 5N.
The equilibrant force needed to stop the body moving eastward must act in exactly the
opposite direction.
Therefore, the needed force is 5N in the direction of West
Source: WAEC / JAMB / NECO Classroom Archive (Record #41743)
Physics
WAEC / WASSCE 1998
Temperature, Thermometry & Thermal Expansion
Solution
An object is heated from 30ºC to 57ºC. The increases in its temperature on the Kelvin scale is
A
17k
B
27k
C
81k
D
246k
E
300k
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
30^\circC + 273 = 303K
57^\circC + 273 = 330K
∆T = 330K - 303K
→ 27K
Source: WAEC / JAMB / NECO Classroom Archive (Record #33544)
Physics
UTME / JAMB 1998
Reflection, Refraction & Dispersion of Light
Solution
The most suitable type of mirror used for the construction of the search light is the?
A
concave mirror
B
convex mirror
C
spherical mirror
D
parabolic mirror
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
In optics, parabolic mirrors are used to gather light in reflecting telescopes and solar furnaces, and project a beam of light in flashlights, searchlights, stage spotlights, and car headlights.
Source: WAEC / JAMB / NECO Classroom Archive (Record #27651)
Chemistry
UTME / JAMB 1998
Particulate Nature of Matter, Laws & Formulae
Solution
A solid begins to melt when?
A
constituent particles acquires a greater kinetic energy
B
energy of vibration of particles of the solid is less than the intermolecular forces
C
constituent particles acquires energy above the average kinetic energy
D
energy of vibration of particles of the solid equals the intermolecular forces
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
When a solid is heated, the particles are given more energy and start to vibrate faster.
At a certain temperature, the particles vibrate so much that their ordered structure breaks down.
At this point the solid melts into liquid.
Source: WAEC / JAMB / NECO Classroom Archive (Record #13871)
Chemistry
UTME / JAMB 1998
Electrolysis & Electrochemical Cells
Solution
The oxide that remains unchanged when heated in hydrogen is?
A
CuO
B
Fe2O3
C
PbO2
D
ZnO
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Zinc oxide doesn't react to hydrogen gas because the reaction is not spontaneous.
Source: WAEC / JAMB / NECO Classroom Archive (Record #13921)
Chemistry
WAEC / WASSCE 1998
Electrolysis & Electrochemical Cells
Solution
How many electrons are removed from Cr2- when it is oxidized to CrO42-?
A
o
B
2
C
4
D
8
E
10
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
from Cr2- to CrO42- involves 8 electrons to give oxidation state of Cr is +6
Source: WAEC / JAMB / NECO Classroom Archive (Record #36617)