Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 19261–19275 of 29821 verified questions
Sort by:
Chemistry
UTME / JAMB 2000
Acids, Bases, pH & Salts
Solution
The pOH of a solution of 0.25 mol dm\(^{-3}\) of hydrochloric acid is
A
12.40
B
13.40
C
14.40
D
14.60
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
pH = - log [0.25]
= - log[ \(\frac{25}{100}\) ]
= - (log 25 - log 100)
= - ( 1.397 - 2)
= - ( - 0.60)
pH = 0.60
N.B : You can use your mathematical table, to check for log 25, if you don't have log on your calculator. Already with our knowledge of lorithm, log 100 = 2.
Thus we were asked to find pOH not pH. However, there is relationship between the two as:
pH + pOH = 14
0.60 + pOH = 14
pOH = 14 - 0.60
pOH = 13.40
Source: Myschool Past Questions Archive (Record #1550)
Chemistry
UTME / JAMB 2000
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
MnO\(_{4(aq)}^{-1}\) + 8H\(^+ _{(aq)}\) + Y → Mn\(^{2+} _{(aq)}\) + 4H\(_2\)O\(_{(l)}\)
Y in the equation above represents
A
2e-
B
3e-
C
5e-
D
7e-
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
We want the number of charges on both sides of the equation to be the same.
i.e. number of charges on the reactant side = the number of charges on the product side.
-1 + 8 = 2
7 = 2
difference in number of charges = 5, hence Y = 5.
Source: Myschool Past Questions Archive (Record #1551)
Chemistry
UTME / JAMB 2000
Periodic Table & Periodicity
Solution
The noble gas, argon,is used for
A
electric arc welding
B
welding brass
C
underwater welding
D
steel welding
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Argon is an inert gas that's non-flammable, non-toxic, and has low reactivity with metals.Argon produces a stable, quiet, and smooth arc. It's also versatile and can be used on a variety of metals, including mild steel, stainless steel, and aluminum. As a result, it is the most common noble gas used for electric arc welding.
Source: Myschool Past Questions Archive (Record #1495)
Chemistry
UTME / JAMB 2000
Water, Solutions & Solubility
Solution
A side effect of soft water is that
A
it gives offensive taste
B
excess calcium is precipitated
C
it attacks lead contained in pipes
D
it encourages the growth of bacteria
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Water is a solvent, and soft water is more aggressive at leaching metals from pipes. Soft water has little or no minerals, so it pulls minerals from the pipes it travels through. Thus, Soft water can dissolve lead from pipes because it's more reactive and lacks minerals.
Source: Myschool Past Questions Archive (Record #1496)
Chemistry
UTME / JAMB 2000
Metals, Transition Elements & Extraction
Solution
Water molecule can be ligands especially when they are bonded to
A
alkaline earth metals
B
alkali metals
C
transition metals
D
group VII elements
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Ligands are molecules or ions that bond to a central metal atom or ion. Water molecules can act as ligands when bonded to transition metals. When a water molecule acts as a ligand, it's called an aqua ligand.
Source: Myschool Past Questions Archive (Record #1497)
Chemistry
UTME / JAMB 2000
Air & Environmental Chemistry
Solution
The air pollutant unknown in nature is
A
NO
B
CO
C
HCHO
D
DDT
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
DDT is not found naturally in the environment as it is a synthetic chemical compound that was created for use as an insecticide. On the other hand, NO (nitric oxide), CO (carbon monoxide), and HCHO (formaldehyde) can all be found in nature to some extent, either as byproducts of natural processes or produced by living organisms.DDT (Dichlorodiphenyltrichloroethane) is an air pollutant that is not found in nature
Source: Myschool Past Questions Archive (Record #1498)
Chemistry
UTME / JAMB 2000
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
1.0 dm3 of distilled water was used to wash 2.0g of a precipitate of AgCl. If the solubility product of AgCl is 2.0 x 10\({^-10}\)moldm-6, what quantity of silver was lost in the process?
A
2.029 * 10-3mol dm-3
B
1.414 * 10-3mol dm-3
C
2.029 * 10-5mol dm-3
D
1.414 * 10-5mol dm-3
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
In order to calculate this, it suffices to calculate the solubility of Ag, so as to know the amount lost.
\(K_{sp} = [Ag^{+}][Cl^{-}]\)
Let the solubilty of Ag and Cl = d
\(2 \times 10^{-10} = d \times d= d^{2}\)
\(d = \sqrt{2\times10^{-10}}\)
= \(1.414 \times 10^{-5}moldm^{-3}\)
Source: Myschool Past Questions Archive (Record #1499)
Chemistry
UTME / JAMB 2000
Electrolysis & Electrochemical Cells
Solution
\(\frac{1}{2}\)Zn\(^{2+}\)(aq) + e\(^-\) → \(\frac{1}{2}\) Zn(s)
In the reaction above, calculate the quantity of electricity required to discharge zinc.
[F = 96 500 C mol\(^{-1}\)]
A
0.965 x 104C
B
4.820 x 104C
C
9.650 x 104C
D
48.200 x 104C
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
1 mol → 96500 x 2
0.5 mol → X
X = 0.5 x 96500 x 2
= 9.650 x 10\(^4\)C
Source: Myschool Past Questions Archive (Record #1552)
Chemistry
UTME / JAMB 2000
Electrolysis & Electrochemical Cells
Solution
Given that M is the mass of substance deposited in an electrolysis and Q the quantity of electricity consumed, then Faraday's law can be written as
A
M = Z/Q
B
M = Q/Z
C
M = Z/2Q
D
M = QZ
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Faraday’s First Law of Electrolysis states that the mass of a substance deposited at any electrode is directly proportional to the amount of charge passed.
Mathematically it can be expressed as follows – m ∝ Q
Removing the proportionality sign m=ZQ. Therefore, option D is the correct answer
Source: Myschool Past Questions Archive (Record #1553)
Chemistry
UTME / JAMB 2000
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
0.46g of ethanol when burned raised the temperature of 50g of water by 14.3K. Calculate the heat of combustion of ethanol.
[C = 12, O = 16, H = 1, Specific heat capacity of water = 4.2 jg-1K-1]
A
+3000 KJ mol-1
B
+300 KJ mol-1
C
-300 KJ mol-1
D
-3000 KJ mol-1
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Heat absorbed by water = (mC\Deltat) = (50 x 4.2 x 14.3) = 3003.0J = 3.003kJ
no of moles of ethanol = \(\frac{mass}{molar mass}\) = \(\frac{0.46}{46}\) = 0.01 mol.
Therefore, heat of combustion of ethanol = \(\frac{heat absorbed by water}{no of mole of ethanol}\) = \(\frac{-3.003}{0.01}\) = - 300.3kj/mol
Source: Myschool Past Questions Archive (Record #1554)
Chemistry
UTME / JAMB 2000
Reaction Rates & Chemical Equilibrium
Solution
Powdered marble reacts faster with hydrochloric acid solution than the granular form because the powdered form has
A
more molecules
B
more atoms
C
larger surface area
D
relatively large mass
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
A powdered substance typically reacts faster than the granular or solid form of the same substance because of its larger surface area. This is because more particles are exposed to the other reactant, which increases the likelihood of collisions and the rate of reaction.
Source: Myschool Past Questions Archive (Record #1555)
Chemistry
UTME / JAMB 2000
Chemical Energetics & Thermochemistry
Solution
N2(g) + O2(g) ↔ 2NO(g); \DeltaH = + 180.6 kJ mol-1
In the reaction above, increase in temperature will
A
increase the quantity of N2
B
increase in the yield of NO
C
decrease the yield of NO
D
decrease the quantity of O2
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
In a chemical system in equilibrium, an increase in temperature for an endothermic reaction (\DeltaH = + 180.6 kJmol-1) will cause the equilibrium position to shift to the right, thereby favouring an increase in the yield of the product i.e NO. On the other hand, a decrease in temperature will cause the equilibrium position to shift to the left, favouring an increase in the yield of the reactants on the LHS. The reverse is the case when it is an exothermic reaction (\DeltaH = -ve). The correct answer is option B
Source: Myschool Past Questions Archive (Record #1556)
Chemistry
UTME / JAMB 2000
Reaction Rates & Chemical Equilibrium
Solution
For a reaction in equilibrium, the species involved in the equilibrium constant expression are
A
gaseous and solid species
B
liquid and solid species
C
solid and dissolved species
D
gaseous and dissolved species
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Solid species are not shown in equilibrium constant expressions because their concentrations do not change significantly during a reaction. The activity of pure liquids and solids is 1 and the activity of a solution can be estimated using its concentration. So, pure liquids and solids actually are involved, but since their activities are equal to 1, they don't change the equilibrium constant and so are often left out. The equilibrium constant expression only contains those species whose concentrations could change significantly during the reaction - gaseous and dissolved species. Option D is the correct answer.
Source: Myschool Past Questions Archive (Record #1557)
Chemistry
UTME / JAMB 2000
Non-Metals & Their Compounds
Solution
A phenomenon where an element exist in different forms in the same physical state is known as
A
isomerism
B
amorphism
C
allotropy
D
isotopy
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Allotropy is the existence of two or more different physical forms of an element. For instance, Carbon exhibit allotropy as it exists in about three different forms, physically such as Diamond, Graphite and amorphous Carbon.
Source: Myschool Past Questions Archive (Record #1558)
Chemistry
UTME / JAMB 2000
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
The substance often used for vulcanization of rubber is
A
chlorine
B
hydrogen peroxide
C
sulphur
D
tetraoxosulphate (IV) acid
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Vulcanization is a process that involves heating rubber with sulphur to improve its strength and elasticity. The process is carried out by mixing latex with sulphur and heating it. Other vulcanizing agents, like selenium and tellurium, are sometimes used, but sulphur is the most common.
Source: Myschool Past Questions Archive (Record #1559)