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The primary role of the Senate is to enact (create or pass) laws, making this the best answer over “create” or “compose,” which are less formal in this legislative context.

"Power" is the clearest term to use in the context of governmental authority. The Senate has no authority (or power) to direct the president’s actions.

The president has executive powers. This power is what allows him to enforce and carry out the law.

Regulated is the best option because it means controlling or supervising according to rules. It means that the President's powers might be subject to oversight.

The most formal way to adjust presidential powers in law is through an act of the National Assembly.

Tan30º = \(\frac{T_1}{100}\) T\(_1\) = 100 Tan30º

When an iron rod is moved from the Earth to the Moon, the following properties are affected: > Mass: The mass of the rod remains unchanged regardless of its location. Mass is a measure of the amount of matter in an object and does not vary with location. > Weight: The weight of the rod will change because weight is the force due to gravity acting on the mass of the rod. Since the gravitational force on the Moon is weaker than that on Earth (about 1/6th of Earth's gravity), the weight of the rod will decrease. > Relative Density: Relative density (or specific gravity) is the ratio of the density of a substance to the density of a reference substance (usually water). Since the composition of the iron rod does not change, its relative density remains the same regardless of the location. So the properties that remain unchanged are: < Mass (i) < Relative Density (iii)

Density of liquid = \(\frac{M}{V}\) = \(\frac{20}{13.5}\) = 1.48g/cm\(^3\) Volume = area x length = 0.54 x 25 = 13.5cm\(^3\) = volume of cylinder = volume of liquid. weight of liquid displaced = weight of object = mass of liquid = 20g volume of liquid = 13.5cm\(^3\) Relative density of liquid = \(\frac{\text{ density of liquid}}{\text{density of water}}\) R. d = \(\frac{1.481}{1}\) = 1.48g/cm\(^3\)

Apparent weight = 32N Real weight = 96N Density of water = 1000\(kgm^{-3}\) acceleration (g) = 10\(ms^{-2}\) Upthrust = Real weight - Apparent weight ⇒ 96N - 32N = 64N ρ be the density of liquid and 'V ' be the volume of the body and we know that upthrust force F = ρVg V = \(\frac{F}{ρg}\) = \(\frac{64}{1000 \times10}\) = 6.4 x 10\(^{-3}m^3\)

Limiting frictional force is proportional to normal reaction. but R = normal reaction = mg mass = 1.6kg F\(_{\text{lim}}\) = 8N g = 10m/s\(^2\) R = 1.6 x 10 = 16N coefficient of Friction = \(\frac{\text{F}}{\text{R}}\) = \(\frac{8}{16}\) = 0.5.

Its acceleration decreases before terminal velocity is attained: When the ball bearing is released, it accelerates due to gravity. As it falls, the viscous drag force exerted by the fluid increases. This drag force opposes the weight of the ball bearing, resulting in a decrease in acceleration until terminal velocity is reached.

Let V\(_t\) = velocity of truck, = 20m/s V\(_c\) = velocity of car = 40m/s \(_cV_t\) = V\(_t\) - V\(_c\) = 40 -(-20) = 40 + 20 = 60m/s

given: u = 15m/s, a = 4m/s\(^2\), t = 10secs, S = ? Using: S = ut + \(\frac{1}{2}\)at\(^2\) S = 15 x 10 + 0.5 x 4 x 100 S = 350m.

Taking moment about the 40cm mark Total clockwise moments = total anti-clockwise moment m x 30 = 90 x 10 + 72 x 30 30m = 900 + 2160 = 3060 m = \(\frac{3060}{30}\) = 102g.

period = 0.25 x 4 = 1.0sec, time taken to make one complete circle.