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Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Diagram
Solution
A body of mass 40kg is being dragged along the floor by a rope inclined at 60 degrees to the horizontal. The frictional force between the box and the floor is 100N and the tension on the rope is 300N. How much work is done by dragging the box for a distance of 4m
Attached Figure / Diagram
A
680J
B
400J
C
200J
D
100J
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Force required to move the object forward = Fcos 60 = 300 x 0.5 = 150N
Frictional Force = 100N
Total force acting on the object = 150 - 100 = 50N
Work Done = Total force x distance = 50 x 4 = 200J.
Source: Myschool Past Questions Archive (Record #41730)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Diagram
Solution
The fig above shows two similar bulbs X and Y connected to suitable power supply with F as an appropriate fuse rating, if the filament of X breaks then the
Attached Figure / Diagram
A
Brightness Of Y will reduce
B
Brightness Of Y will remain constant
C
Brightness Of Y will increase
D
fuse F will blow
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Diagram above shows a Parallel circuit
If one of the parallel path is broken, current will continue to flow in other parts.
Voltage is the same across each component of the parallel circuit.
The brightness of a light bulb is given by its power. P = I\(^2\)R,
and so brightness depends on current and resistance.
Hence; the brightness of Y will not be affected except for a variation in resistance property.
Source: Myschool Past Questions Archive (Record #41731)
Physics
WAEC / WASSCE 1995
Mechanics and Properties of Matter
Solution
(a) Explain what is meant by acceleration of free fall due to gravity, g.
(b) State two reasons why g varies on the surface of the earth
(c) A stone is projected upwards at an angle of 30^\circ to the horizontal from the top of a tower of height 100 m and it hits the ground at a point Q. If the initial velocity of projection is 100ms\(^{-1}\), calculate the
(i) maximum height of the stone above the ground;
(ii) time it takes to reach this height;
(iii) time of flight
(iv) horizontal distance from the foot of the tower to the point Q. (Neglect air resistance and take g as 10m\(^{-2}\))
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) This is the force of attraction of the Earth on a mass
It is a vector quantity and is measured in ms\(^{-2}\)
It pulls the acceleration when a body is in vacuum or without resistance. OR/F = g
(all symbols explained) where F = force of gravity, M = mass of the object
(b) — (Shape of the earth). The earth is not a perfect sphere (1) or the shape of the earth is elliptical - Rotation of the Earth about its polar axis.
(c)(i) Let H = height of tower and h = vertical difference covered by the stone from the point of projection.
(i) V\(_2\) = (Usin\(\theta\))\(^2\) - 2gh
\(\theta\) = 100 x 100 x (\(\frac{1}{2}\))\(^2\) - 20h
h = \(\frac{2500}{20}\)
= 125m
height above the ground
(i) S = H + 125 S = 100 + 125 S = 225m
(ii) V = U sin \(\theta\) – gt
0 = 100 sin 30^\circ – 10t
t = \(\frac{100 \times 0.5}{10}\)
t = 5s
(iii) Using S = ut + 1/2 gt\(^2\)
225 = 0 + 1/2 x 10t\(^2\)
t = \(\sqrt{45}\) = 6.71
Time of flight, T= 5 + 6.
T = 11.71s
(iv) Range R = UTcos\(\theta\)
Or S = ut – 1/2 gt\(^2\)
g = 0
=100 x 0.8660 x 11.71
= 1014.08 (C14)
Range \(\frac{U^2 sin20}{ g}\)
= 1013.22m
Source: Myschool Past Questions Archive (Record #54769)
Physics
WAEC / WASSCE 1995
Mechanics and Properties of Matter
Solution
(a) State Faraday's law of electromagnetic induction.
(b) Draw a labelled diagram of an induction coil and explain how it works.
(c) How is the effect of eddy currents minimized in the coil?
(d) State two reasons why a capacitor should be included in the primary circuit of the coil.
(e) State three uses of an induction coil.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Whenever there is a change in the magnetic flux linked with a circuit, an electromotive force is induced, (1\(\frac{1}{2}\)) the strength of which is proportional to the rate of change of the flux linked with the circuit (1\(\frac{1}{2}\)).
E \(\alpha\) \(\frac{d \theta}{dt} or E = \frac{Nd \theta}{dt}\)
Where E = induced e.m.f.
\(\theta\) = magnetic flux.
(b)
Workability: All except key and capacitor. When the platinum contacts touch ar,d the key k is closed, current passes through the primary coil and the core is magnetised. The soft iron armature is then attracted so the, the platinum contacts separate and the circuit is broken. When this happens, the core loses its magnetism and the armature is pulled back by the spring so that contact is re-established. As the contact is repeatedly made and broken in the primary circuit, changes of magnetic flux take place and induces an e.m.f. in the secondary coil. Because of the much larger number of turns in the secondary compared with the primary, a very high e.m.f is induced in the secondary coil which is sufficient to cause a spark to jump across the spark gap.
(c) The core of the coil is made of bundle of soft-iron wires OR that are of the coil is laminated. Or use of particle of iron dust. Or lamination of iron sheet or iron core not metallic sheet
(d) – To control sparking at the platinum contacts (which otherwise wears off the contact points)
-- It promotes a rapid decay of the magnetic flux at the break of the primary circuit and this helps to increase the secondary e.m.f.
(e) It is used in the
– coil
– ignition system of motor cars
– inveitigation of high voltages
– study of electric discharge through gases
– operation of x-ray tubes
– merse radio transmitter.
Source: Myschool Past Questions Archive (Record #54770)
Physics
WAEC / WASSCE 1995
Mechanics and Properties of Matter
Solution
(a) What is surface tension? Explain the phenomenon in terms of intermolecular forces
(b) Describe a simple experiment to demonstrate the surface tension of a liquid
(c) State three examples to illustrate the effects of surface tension
(d) Why does water wet a clean glass surface whereas mercury does not?
(e) State two methods by which the surface tension of a liquid may reduced.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Surface tension is the property of a liquid which makes its surface behave as though covered with an elastic sink. Or it is the tangential force on the surface of a liquid. Surface tension is force per unit length on the surface of a liquid
Consider two molecules A and B as shown above. The molecule A will be attracted uniformly in all directions trot pulled in any one particular. direction. On the other hand, B is attracted more by molecules within the body of the liquid and it therefore experiences a resultant inward force at right angles to the surface. There will therefore be a tendency for the surface of the liquid to contact and have as little an area as possible. The surface is thus in a tension.
Diagram or description link
NB: Water and needle shown but not labelled
A beaker is filled to the brim with water as shown above. A dry needle is placed on a small piece of filter paper, which is then gently placed on the water surface. It would be observed that the filter paper sinks to the bottom of the beaker while the needle is left floating. The surface thereby acts like an elastic skin covering the liquid which is able to support the weight of the needle
(c) – When water is allowed to drip slowly from a water tap, the shape of each small drop is spherical.
- When mercury spills on a glass sheet, it forms spherical droplets.
- Soap bubbles are spherical in shape. - Insects (water - skaker) area able to walk across a water surface etc.
- Toy duck on liquid
- A flowing or floating needle on water.
(d) The adhesion of water molecules to glass molecules is stronger than the cohesion between water molecules. Hence, when water spills on a clean glass surface it spreads and wets the glass. On the other hand, the cohesion between mercury molecules is greater than the adhesion between mercury and glass molecules. Therefore when mercury spills on glass it forms small spherical droplets on larger flattened drops
(e) By adding
- detergent/soap
- alcohol
- oil
- By heating the liquid/increasing the temperature of the liquid
- adding camphor.
Source: Myschool Past Questions Archive (Record #54771)
Physics
WAEC / WASSCE 1995
Mechanics and Properties of Matter
Solution
(a) Define the boiling it of a liquid.
(b) Describe with the a d. labelled diagram, an experiment to determire the boiling point of a small quantity of a liquid.
(c) factors that may affect the boiling point of a liquid
(d) Using the kinetic theory of matter, explain why pure water changes to steam at S.T.P. without any change in temperature, although heat is being supplied to the water.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
a) The boiling pointer of a liquid is the temperature at which its s.v.p. is equal to the external atmospheric pressure OR The temperature at which a (pure) liquid boils when the atmospheric pressure on it is 760 mm Hg. OR The temperature at which the liquid changes from the liquid to the gaseous state without change in temperature when the atmospheric pressure is normal (760mm Hg).
Method: Some mercury is introduced into J - tube and the entrapped air removed. Some liquid is introduced into the shorter length of the J - tube above the mercury. The beaker and its contents are heated and the water stirred continuously. At a stage when the levels of mercury in the two limbs of the J-tube are the same the temperature is read. At this temperature the s.v.p of the liquid is equal to the atmospheric pressure, and this temperature is the boiling point of the liquid. The process is repeated with the beaker and its contents cooling. The temperature at which the levels of mercury in the two limbs are equal is read and the mean of the two taken.
(c) Pressure on the liquid, impurities in the liquid.
(d) The extra heat supplied during boiling is used in breaking the intermolecular attractions and in mabling the steam expand or enabling the molecules move further apart against the atmospheric pressure. Hence, there is no change in temperature during the change of state.
Source: Myschool Past Questions Archive (Record #54772)
Physics
WAEC / WASSCE 1994
Mechanics and Properties of Matter
Solution
A gas occupies a certain volume at 27°C. At what temperature will its volume be three times the original volume assuming that its pressure remains constant?
A
81°C
B
162°C
C
354°C
D
627°C
E
900°C
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
\(\frac{V_{1}}{T_{1}}\) = \(\frac{V_{2}}{T_{2}}\) x \(\frac{V_{1}}{27+273}\) = \(\frac{3V_{1}}{T_{2}}\) , \(T_{2}\)= 900K; T=627°C
Source: Myschool Past Questions Archive (Record #26246)
Physics
WAEC / WASSCE 1994
Mechanics and Properties of Matter
The instrument used in the measurement of atmospheric pressure is?
A
Hydrometer
B
Ratemeter
C
Barometer
D
Photometer
E
Manometer
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #26248)
Physics
WAEC / WASSCE 1994
Mechanics and Properties of Matter
The electrical energy supplied by a Leclanche cell is obtained from the
A
Nuclear energy
B
Magnetic energy
C
Solar energy
D
Chemical energy
E
Mechanical energy
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #26257)
Physics
WAEC / WASSCE 1994
Mechanics and Properties of Matter
A particle of charge q and mass m moving with a velocity v enters a uniform magnetic field of strength B in the direction of the field. The force on the particle is
A
qvB
B
mqvB
C
qvB/m
D
mvB/q
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #26264)
Physics
WAEC / WASSCE 1994
Mechanics and Properties of Matter
Solution
A lamp marked 100W, 250V is lit for 10 hours. If it operates normally and 1KWh of electrical energy costs 2k, what is the cost of lighting the lamp?
A
1k
B
2k
C
5k
D
10k
E
20k
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
100W X 10h = 1000Wh = 1KWh thus cost is 2k
Source: Myschool Past Questions Archive (Record #26265)
Physics
WAEC / WASSCE 1994
Mechanics and Properties of Matter
Solution
A note of frequency of 2000Hz has a velocity of \(400ms^{-1}\). What is the wavelength of the note?
A
800m
B
200m
C
5m
D
2m
E
0.2m
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
\(\lambda = \frac{v}{f} = \frac{400}{2000} = 0.2\)m
Source: Myschool Past Questions Archive (Record #26275)
Physics
WAEC / WASSCE 1994
Mechanics and Properties of Matter
Solution
A ball is dropped from a height of 45m above the ground. Calculate the velocity of the ball just before it strikes the ground. (Neglect air resistance and take g as \(10ms^{-2}\)
A
21.2\(ms^{-1}\)
B
30\(ms^{-1}\)
C
300\(ms^{-1}\)
D
450\(ms^{-1}\)
E
900\(ms^{-1}\)
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(v^2 = u^2+2as=0^2 + 2\times 10\times 45 \Rightarrow
v^2 = 900m^2s^{-2} \Rightarrow \\
v = \sqrt{900m^2s^{-2}} \Rightarrow
v = 30ms^{-1}\)
Source: Myschool Past Questions Archive (Record #26277)
Physics
WAEC / WASSCE 1994
Mechanics and Properties of Matter
Solution
A body accelerates uniformly from rest at \(2ms^{-2}\). Calculate the velocity after traveling 9m
A
36\(ms^{-1}\)
B
18\(ms^{-1}\)
C
6\(ms^{-1}\)
D
4.5\(ms^{-1}\)
E
4.24\(ms^{-1}\)
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
\(V^2= U^2+2as\) =\(0+ 2\times 2ms^{-2}\times 9 =36ms^{-1}\) thus
V=\(\sqrt{36m^2s^{-2}}\) = \(6ms^{-1}\)
Source: Myschool Past Questions Archive (Record #26278)
Physics
WAEC / WASSCE 1994
Mechanics and Properties of Matter
Solution
\(500cm^{-3}\) of a gas is collected at 0°C and at a pressure of 72cm of mercury. What is the volume of the the gas at the same temperature and at a pressure of 76cm of the same mercury?
A
\(\frac{76\times500}{72}cm^3\)
B
\(\frac{72\times500}{76}cm^3\)
C
\(\frac{72\times76}{500}cm^3\)
D
\(\frac{76}{72\times500}cm^3\)
E
\(\frac{72}{76\times500}cm^3\)
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(P_1V_1=P_2V_2, V_2= \frac{72\times500}{76}cm^3\)
Source: Myschool Past Questions Archive (Record #26282)