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Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Solution
A body is projected from the earth's surface with the intention of letting it escape from the earth's gravitational field. What is the minimum escape velocity of the body? [Earth's radius = 6.4 x 103km, g = 10ms-2]
A
14 kms-1
B
13 kms-1
C
12 kms-1
D
11 kms-1
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Velocity = \(\sqrt2gR\)
= 2 x 6400 x 100 x 10
= 11 km-1
Source: Myschool Past Questions Archive (Record #27760)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
A uniform rod PQ of length 1m and mass 2kg is pivoted at the end p. If load of 14N is placed at the center of the rod, find the force that should be applied vertically upwards at Q to maintain the rod at equilibrium horizontally [g = 10ms-2]
A
68N
B
28N
C
17N
D
7N
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #27766)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Solution
A vehicle of mass m is driven by an engine of power P from rest. Find the minimum time it will take to acquire a speed
A
\(\frac{mv^2}{2p}\)
B
\(\frac{mv^2}{p}\)
C
\(\frac{mv}{p}\)
D
\(\frac{mv}{2p}\)
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
To find the minimum time \( t \) it takes for a vehicle of mass \( m \) to acquire a speed \( v \) when driven by an engine of power \( P \), we use the work-energy principle.
The relationship is given by:
\(t = \frac{m v^2}{2P}\)
Thus, the minimum time \( t \) to acquire speed \( v \) is:
\(t = \frac{m v^2}{2P}\).
Source: Myschool Past Questions Archive (Record #27768)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Which of the following statements are TRUE about frictional force? i. it is always a disadvantage ii. it is sometimes a disadvantage iii. it always exist where there is a relative motion of two bodies that are in contact iv. it is sometimes very useful
A
i, iii only
B
i, iv only
C
ii, iii only
D
iii, iv only
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #27772)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Solution
The energy contained in a wire when it extended by 0.02m by a force 500 N is
A
5J
B
10J
C
103J
D
104
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Energy = \(\frac{1}{2}\)Fe
= \(\frac{1}{2}\) x 500 x 0.02
E = 5J
Source: Myschool Past Questions Archive (Record #27774)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Solution
A hydraulic press has a large circular piston of radius 0.8m and a circular plunger of radius 0.2m. A force of 500N is exerted by the plunger. Find the force exerted on the piston
A
8000N
B
4000N
C
2000N
D
31N
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Pressure on piston = pressure on the plunger
\(\frac{500}{\pi\ \times\ 0.2 \times\ 0.2}\) = \(\frac{F}{\pi\ \times\ 0.8 \times\ 0.8}\)
F = 8000N
Source: Myschool Past Questions Archive (Record #27776)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Solution
The equation PxVyTz = constant in charles' law when
A
x = 1, y = -1, z = 1
B
x = 0, y = 1, z = -1
C
x = 1, y = 0, z = -1
D
x = 0, y = 1, z = 1
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
According to Charles' law, the volume of a given mass of gas is directly proportional to its absolute temperature at constant pressure.
Source: Myschool Past Questions Archive (Record #27807)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Solution
An electric kettle with negligible heat capacity is rated at 2000W. If 2.0kg of water is put in it, how long will it take the temperature of water to rise from 20OC to 100OC? [specific heat capacity of water = 4200Jkg-1k-1]
A
420S
B
336S
C
168S
D
48S
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Heat energy = Elect. energy
mc\(\theta\) = power x time
2 x 4200 x (100 - 20) = 2000 x t
t = 336s
Source: Myschool Past Questions Archive (Record #27810)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Which of the following statements give the TRUE difference between evaporation and boiling? i. Evaporation occurs at all temperatures while boiling occurs at a fixed temperature for a given pressure. ii. Evaporation is a surface phenomenon while boiling is an interior phenomenon. iii. Evaporation is affected by surface area while boiling is not.
A
i and ii only
B
i and iii only
C
ii and iii only
D
i, ii, iii.
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #27827)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Solution
At different locations on the earth's surface, the earth's magnetic field is
A
the same in magnitude and direction
B
the same in magnitude but different in direction
C
different in both magnitude and direction
D
different in magnitude but different in direction
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
The magnetic field around the earth is like that around the bar magnet.
The magnetic lines of force emerge from the geographic south pole and enter the north pole forming closed loops. Hence the magnetic field changes in both magnitude and direction at different locations on the earth's surface.
Source: Myschool Past Questions Archive (Record #27845)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Solution
An electric current of 2 amperes flows in a heating coil of resistance 50 ohms for 3 minutes 20 seconds. Determine the heat produced
A
0.5kJ
B
8.0kJ
C
20.0kJ
D
40.0kJ
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Heat energy = Elect. energy
heat energy= I2RT
= 2 X 2 X 50 X 200
= 40000J
to convert to kJ, divide J by 1000
hence, \(\frac{40000}{1000}\) = 40kJ
Source: Myschool Past Questions Archive (Record #27853)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Solution
If the maximum voltage across a 100ohms resistor is 20V, then the maximum power it can dissipate is
A
5.00W
B
4.00W
C
2.00W
D
25W
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
P = \(\frac{V^2}{R}\)
= \(\frac{20 \times 20}{100}\)
= 4W
Source: Myschool Past Questions Archive (Record #27854)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Solution
A light of energy 5eV falls on a metal and the electrons with a maximum kinetic energy of 2eV are ejected. The work function of the metal is
A
0.4eV
B
2.5eV
C
3.0eV
D
7.0eV
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Work function = 5 - 2
= 3eV
Source: Myschool Past Questions Archive (Record #27857)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Diagram
Solution
The value of T in the figure above is
Attached Figure / Diagram
A
10.0N
B
11.8N
C
20.0N
D
40.0N
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
The total upward vertical force must balance the downward weight of 20 N.
There are two vertical components:
2 \times (T \times sin(30^\circ)) = 20 N
Sin(30^\circ) = \(\frac{1}{2}\) = 0.5
So:
2 \times T \times 0.5 = 20
T = 20
Source: Myschool Past Questions Archive (Record #41728)
Physics
UTME / JAMB 1995
Mechanics and Properties of Matter
Diagram
Solution
The acceleration of the system show above is
Attached Figure / Diagram
A
2ms-2
B
4ms-2
C
6ms-2
D
8ms-2
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
M\(_2\)g - M\(_2\)a = M\(_1\)a + M\(_1\)g Sin\(\theta\)
(30 x 10) - 30a = 20a + 20 x 10 x Sin 30
300 - 30a = 20a + 100
- 30a - 20a = 100 - 300
- 50a = - 200
a = \(\frac{-200}{-50}\) = 4m/s\(^2\)
Source: Myschool Past Questions Archive (Record #41729)