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Physics
UTME / JAMB 2017
Heat Energy & Temperature
Which of the following is not true of an electrical charge?
A
Negative charge means deficit electrons
B
Negative charge means excess of electrons
C
electric current means movement of electrons
D
All of the above
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Official Exam / Past Question Archive
Physics
WAEC / WASSCE 2017
Heat Energy & Temperature
Solution
You are provided with cells, a potentiometer, an ammeter, a voltmeter, a bulb, a key, a jockey, and other necessary materials.
i. Measure and record the e.m.f E of the battery.
ii. Set up a circuit as shown in the diagram above.
iii. Close the key K and use the jockey to make a firm.
iii. Contact at J on the potentiometer wire such that PJ = x= 10cm.
iv. Take and record the voltmeter reading V and the () Corresponding ammeter reading.
v. Evalute log V and log I.
vi. Repeat the procedure for five other values of x = 20 cm, 30 cm, 40 cm, 50 cm, and 60 cm.
vii. Tabulate your readings.
viii. Plot a graph with log I on the vertical axis and log V on the horizontal axis.
ix. Determine the slope s, of the graph.
x. Determine the intercept, c, on the vertical axis.
xi. State two precautions taken to ensure accurate results.
(b)i. How is the brightness of the bulb affected as x increases?
ii. List two electrical devices whose actions do not obey Ohm's law.
A
Visible, ultraviolet, X-ray
B
X-ray, visible, ultraviolet
C
Ultraviolet, visible, X-ray
D
X-ray, ultraviolet, visible
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
S/N
I/A
V/V
LogV/V
LogI/A
1.0
0.10
0.30
-0.552
-1.000
2.0
0.15
0.50
-0.301
-0.823
3.0
0.20
0.70
-0.154
-0.698
4.0
0.25
0.80
-0.096
0.602
5.0
0.30
0.90
-0.045
0.522[
Slopes S = \(\frac{\bigtriangleup \text{logI}}{\bigtriangleup \text{logV}}\) = \(\frac{\text{logl}_{2}} {\text{logV}_{2}}\) - \(\frac{\text{logl}_{1}}{\text{logV}_{2}}\)
S = \(\frac{-1.00 - (-0.70)}{-0.15 - (0.50)}\) = \(\frac{0.30}{0.10}\)
S= 3
PRECUATIONS
1. avoided parallax error when reading ammeter and voltmeter
2. opened the key when readings are not being taken to ensure that the cells do not run down.
3. ensured that the jockey is not dragged along the potentiometer wire.
(b)i. As x increases, the brightness of the bulb increases. As x increases, voltage and current through the bulb also increases, hence brightness increases
ii. Electrical devices whose action does not obey ohm's law. They are: Diode, Capacitor, Transistor, Thermistor and Thyristor.
SEE GRAPH ABOVE
Source: Official Exam / Past Question Archive
Physics
WAEC / WASSCE 2017
Mechanics and Properties of Matter
Diagram
Solution
You are provided with two retort stands, two-metre rules, pieces of thread, and other necessary apparatus. ( see illustration above)
i. Set up the apparatus as illustrated above ensuring the strings are permanently 10cm from either end of the rule.
ii. Measure and record the length L = 80 cm of the two strings.
iii. Hold both ends of the rule and displace the rule slightly, then release so that it oscillates about a vertical axis through its centre.
iv. Determine and record the time t for 10 complete oscillations.
v. Determine the period T of oscillations.
vi. Evaluate log T and L.
vii. Repeat the procedure for four other values of L= 70 cm, 60 cm, 50 cm, and 40 cm
viii. Tabulate your readings.
ix. Plot a graph with log T on the vertical axis and log L on the horizontal axis.
x. Determine the slope, s, and the intercept, c on the vertical axis.
xi. State two precautions taken to ensure accurate results.
(b)i. Define simple harmonic motion.
ii. Determine the value of L corresponding to t= 12 s from the graph in 1.
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
S/N
L/CM
t/s
T=t/o/S
LogT/S
LogL/cm
1
80.0
17.90
1.79
0.252
1.903
2
70.0
17.30
1.73
0.238
1.845
3
60.0
15.34
1.53
0.185
1.775
4
50.0
13.90
1.39
0.145
1.698
5
40.0
13.06
1.31
0.155
1.602
Slope (s) = \(\frac{\bigtriangleup \text{logT}_{2}}{\bigtriangleup\text{logL}_{2}}\) - \(\frac{\bigtriangleup \text{logT}_{1}}{\bigtriangleup\text{logL}_{1}}\)
= \(\frac{0.15 - 0.05}{0.164 - 0.148}\)
= \(\frac{0.100}{0.016}\) = 6.25
PRECAUTIONS
1. avoided zero error in the reciding of the stop watch
2. avoided Parallax in reading the metre rule and the stop watch
3. ensured that the support of the bifilar pendulum is rigid
4. ensured smooth and regular oscillations in a horizontal plane.
b. i. Simple harmonic motion is defined as the motion of an object whose acceleration is proportional to the distance from a fixed point and is always directed towards that point
see graph above
Source: Myschool Past Questions Archive (Record #59906)
Physics
WAEC / WASSCE 2017
Mechanics and Properties of Matter
Solution
You are provided with a beaker, a thermometer, a stirrer Stopwatch/clock, measuring cylinder, table salt, water, and other necessary materials.
i. You Measure 200cm\(^{3}\) of water into the beaker.
ii. Heat the water until it boils steadily for about 2 minutes.
iii. Read and record the boiling point \(b_0\).
iv. Add table salt of mass M = 10.0 g to the boiling water and stir continuously until another boiling point \(b_1\) is attained.
v. Read and record \(b_i\).
vi. Evaluate \(\theta_{i}\) = (\(b_i\) - \(b_0\))
vii. Using the same mixture, repeat the procedure four more times by adding 10.0 g of salt each time to give the cumulative mass \(M_i\) of salt as 20 g, 30g, 40g, and 50g.
viii. In each case allow the mixture to boil steadily for at least 2 minutes then read and record the boiling point b.
ix. Tabulate your readings.
x. Plot a graph with \(M_i\) on the vertical axis and \(\theta_{1}\) on the horizontal axis.
xi. Determine the slope, s, of the graph.
xii. State two precautions taken to ensure accurate results.
(b) i. Define the boiling point of a liquid.
ii. What effects do impurities have on the boiling point of a liquid?
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
bo = 102^\circc
S/N
M/g
bi/ ^\circc
\(\theta_{1}\)=(bi-bo)/^\circ
1.0
10.0
104.00
104 - 102 = 2.00
2.0
20.0
106.00
106 - 102 = 4.00
3.0
30.0
108.00
108 - 102 = 6.00
4.0
40.0
110.00
110 - 102 = 8.00
5.0
50.0
112.00
112 - 102 = 10.00
Slope, s = \(\frac{\bigtriangleup M_{2} - \bigtriangleup M_{1}}{\bigtriangleup\theta_{2} - \bigtriangleup\theta_{1}}\)
= \(\frac{40}{8} - \frac{10}{2} = \frac{30}{6}\)
S = 5
PRECAUTIONS
1. stirred the water gently to ensure uniform temperature.
2. avoided splashing of the water
3. avoided error due to parallax in reading the thermometer and the stop clock.
(b) i. Boiling point is defined as the point when liquid changes to vapour when the saturation vapour pressure is equal to the atmospheric pressure.
ii. Impurities affect the boiling of a liquid because their presence inicreases the boiling rboint of the liquidelcom- pared to the boiling point of a pure solvent.
Source: Myschool Past Questions Archive (Record #59919)
Physics
WAEC / WASSCE 2017
Electricity and Magnetism
Diagram
Solution
You are provided with cells, a potentiometer, an ammeter, a voltmeter, a bulb, a key, a jockey, and other necessary materials.
i. Measure and record the e.m.f E of the battery.
ii. Set up a circuit as shown in the diagram above.
iii. Close the key K and use the jockey to make a firm.
iii. Contact at J on the potentiometer wire such that PJ = x= 10cm.
iv. Take and record the voltmeter reading V and the () Corresponding ammeter reading.
v. Evalute log V and log I.
vi. Repeat the procedure for five other values of x = 20 cm, 30 cm, 40 cm, 50 cm, and 60 cm.
vii. Tabulate your readings.
viii. Plot a graph with log I on the vertical axis and log V on the horizontal axis.
ix. Determine the slope s, of the graph.
x. Determine the intercept, c, on the vertical axis.
xi. State two precautions taken to ensure accurate results.
(b)i. How is the brightness of the bulb affected as x increases?
ii. List two electrical devices whose actions do not obey Ohm's law.
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
S/N
I/A
V/V
LogV/V
LogI/A
1.0
0.10
0.30
-0.552
-1.000
2.0
0.15
0.50
-0.301
-0.823
3.0
0.20
0.70
-0.154
-0.698
4.0
0.25
0.80
-0.096
0.602
5.0
0.30
0.90
-0.045
0.522[
Slopes S = \(\frac{\bigtriangleup \text{logI}}{\bigtriangleup \text{logV}}\) = \(\frac{\text{logl}_{2}} {\text{logV}_{2}}\) - \(\frac{\text{logl}_{1}}{\text{logV}_{2}}\)
S = \(\frac{-1.00 - (-0.70)}{-0.15 - (0.50)}\) = \(\frac{0.30}{0.10}\)
S= 3
PRECUATIONS
1. avoided parallax error when reading ammeter and voltmeter
2. opened the key when readings are not being taken to ensure that the cells do not run down.
3. ensured that the jockey is not dragged along the potentiometer wire.
(b)i. As x increases, the brightness of the bulb increases. As x increases, voltage and current through the bulb also increases, hence brightness increases
ii. Electrical devices whose action does not obey ohm's law. They are: Diode, Capacitor, Transistor, Thermistor and Thyristor.
SEE GRAPH ABOVE
Source: Myschool Past Questions Archive (Record #59926)
Physics
UTME / JAMB 2016
Motion Force Circular Motion
Solution
A satellite revolving around the earth is kept on its orbit by?
A
Centripetal forces only
B
Centripetal and frictional forces
C
Centrifugal forces only
D
Centripetal and centrifugal forces
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
The concept of centrifugal force can be applied in rotating devices, such as centrifuges, centrifugal pumps, centrifugal governors, and centrifugal clutches, and in centrifugal railways, planetary orbits and banked curves, when they are analyzed in a rotating coordinate system.
Source: WAEC / JAMB / NECO Classroom Archive (Record #44729)
Physics
WAEC / WASSCE 2016
Semi Conductor
Solution
In a p-type semiconductor, the?
A
number of holes are equal to the number of electrons
B
electrical resistivity increases
C
electrons are the majority charge carriers
D
holes are the majority charge carriers
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Properties of p type semiconductor
This type of semiconductors form due to the doping trivalent atoms in a pure semiconductor crystal.
The majority carriers in p-type semiconductors are holes which have positive charges.
Minority carriers of this type semiconductors are free electrons.
Source: WAEC / JAMB / NECO Classroom Archive (Record #45692)
Physics
UTME / JAMB 2016
Waves and Optics
Solution
Myopic defects in the human eye can be corrected through the use of a
A
Concave Mirror
B
Concave lens
C
Prism
D
Convex lens
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
In myopia, distant objects appear blurry because light focuses in front of the retina. A concave lens diverges the light rays, shifting the focus point back onto the retina.
Source: Myschool Past Questions Archive (Record #44659)
Physics
UTME / JAMB 2016
Electricity and Magnetism
A charged particle is moving in a uniform magnetic field. if the direction of motion of the charged particle is parallel to the magnetic field, the path of the charge will
A
Be a straight line
B
Curve inwards
C
Be a parabola
D
Curve outwards
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #44661)
Physics
UTME / JAMB 2016
Heat Energy & Temperature
What happens to a water pool on a day when the humidity of the air is very low?
A
Temperature decreases
B
Slow evaporation
C
Temperature increases
D
Rapid evaporation
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #44662)
Physics
UTME / JAMB 2016
Mechanics and Properties of Matter
Solution
A satellite moves in a circular orbit of radius 4R round the earth. The acceleration of the satellite in terms of g is
A
\(\frac{g}{16}\)
B
\(\frac{g}{4}\)
C
\(\frac{4}{g}\)
D
\(\frac{16}{g}\)
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
\(\frac{g}{R^2}\) = \(\frac{g}{4^2}\) = \(\frac{g}{16}\)
Source: Myschool Past Questions Archive (Record #44663)
Physics
UTME / JAMB 2016
Mechanics and Properties of Matter
I.Chemical II.Sound III.Electricity
Which of the above forms of energy can directly be converted to light energy?
A
I and II only
B
II and III only
C
I, II and III
D
I and III only
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #44664)
Physics
UTME / JAMB 2016
Heat Energy & Temperature
If the distance between the object and the pinhole of a pinhole camera is reduced by half the size of the image of the object
A
Is quadrupled
B
Is halved
C
Remains the same
D
Is double
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #44665)
Physics
UTME / JAMB 2016
Waves and Optics
Solution
An object is placed 15cm in front of a plane mirror. If the mirror is moved further 5cm away from the object and the image is
A
80cm
B
40cm
C
50cm
D
70cm
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
An object is placed 15 cm in front of a plane mirror.
Initial Image Position: The image is 15 cm behind the mirror.
Mirror Movement: The mirror is moved 5 cm further away from the object, making the distance to the mirror 20 cm.
New Image Position: The new image is now also 20cm behind the mirror.
Conclusion
The total distance from the object to the image is 20 cm + 20 cm = 40 cm.
Source: Myschool Past Questions Archive (Record #44666)
Physics
UTME / JAMB 2016
Heat Energy & Temperature
Which of the following statements is correct about a machine?
A
Efficiency of a machine is always greater than I
B
Efficiency decreases with an increase in friction
C
Velocity ratio depends on friction
D
Mechanical advantage increases with an increase in friction
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #44667)