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Physics
WAEC / WASSCE 1999
Mechanics and Properties of Matter
Solution
(a) State the conditions for the equilibrium of a rigid body acted upon by parallel forces
(b)(i) Describe an experiment, using the principle of moments, to determine the mass of a metre rule
(ii) State two precautions necessary to ensure accurate results.
(c) A bullet of mass 120g is fired horizontally into a fixed wooden block with a speed of 20ms\(^{-1}\). The bullet is brought to rest in the block in 0.1s by a constant resistance. Calculate the:
(i) magnitude of the resistance;
(ii) distance moved by the bullet in the wood.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) - Sum of forces in one direction is equal to the sum of forces in opposite direction. - Sum of anti-clockwise moments about a point is equal to the sum of clockwise moment about the same point.
(b) Diagram:
Method: Suspend the metre rule on a knife edge. Adjust its position until it balances horizontally. Note the balance point G. Then suspend a mass M on one side of the rule. Adjust the rule until it balances horizontally again. Read and record X and Y as in the diagram above. According to the principle of moment:
Mgx = Mgy
m = \(\frac{Mgy}{gx} = \frac{My}{x}\)
m = mass of rule
Precautions
- Avoid drought
- Avoid parallax in reading the metre rile
(c)(i) Deceleration a = \(\frac{u - v}{t} = \frac{20 - 0}{0.1}\) = 200ms
Resistance = ma = 0.12 x 200 = 24N
(ii) Distance, s \(\frac{u^2 - v^2}{2a} = \frac{20^2 - O^2}{2 \times 200} = \frac{400}{400}\)
= 1.0m
Source: Myschool Past Questions Archive (Record #54670)
Physics
WAEC / WASSCE 1999
Mechanics and Properties of Matter
Solution
(a) Explain (i) work: (ii) power
(b) Show that the efficiency E, the force ratio M.A. and the velocity ratio V.R. of a machine are related by the equation: E = M.A. x 100% V.R.
(c) An inclined plane of angle 15^\circ is used raise a load of 4500N through a height of 2m. If the plane is 75% efficient calculate:
(i) velocity ratio of the plane;
(ii) work done on the load
(d) Explain Charles' law using the Kinetic theory of matter.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)(i) Work is the product of force and distance moved in the direction of the force
(ii) Power is the time rate of doing work. Unit of power is watts or J / sec.
(b) E = \(\frac{\text{Work output}}{\text{work input}}\) x 100% work input
E = \(\frac{\text{load x distance moved by load}}{\text{effort x distance moved by effort}}\)
But Ma = \(\frac{Load}{effort}\) and V.R = \(\frac{\text{distance moved by effort}}{\text{Effort distance moved by load}}\)
E = \(\frac{MA}{1} \times \frac{1}{VR}\) x 100%
E = \(\frac{MA}{V.R}\) x 100%
(c)(i) VR = \(\frac{1}{sin \theta}\) = \(\frac{1}{sin 45^o} = \frac{1}{0.2588}\) = 3.86
75% = \(\frac{9000}{Win}\) x 100%
Win = \(\frac{9000 \times 100}{75}\) = 12,000J
work input = 12000 J.
(d) At constant pressure, the number of collision per unit time is constant. An increase in temperature causes average Kinetic energy increases. The molecules then move faster. The volume therefore increases so as to maintain the number of collision per unit time.
Source: Myschool Past Questions Archive (Record #54672)
Physics
WAEC / WASSCE 1999
Mechanics and Properties of Matter
Solution
(a) Sketch the magnetic flux pattern around a long; straight, current-carrying wire
(b) State two methods by which the sensitivity of a moving-coil galvanometer can be increased.
(c) A series RLC circuit comprises a 100-\(\Omega\) resistor, a 3-H inductor and a 4-\(\mu\)f capacitor. The a.c source of tile circuit has an e.m.f of 100V and a frequency of 160 Hz.
(i) Draw the circuit diagram of the arrangement. Calculate the:
(ii) capacitive reactance;
(iii) inductive reactance:
(iv) impedance of the circuit;
(v) current in the circuit;
(vi) average power dissipated in the circuit.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)
(b) The sensitivity is increased by a weak spring and increasing the strength of the magnet C
(c)(i)
(ii) X = \(\frac{1}{2 \pi FC} = \frac{1}{2 \pi \frac{160}{\pi} \times 4}\) = 781\(\Omega\)
(iii) X\(_L\) = 2\(\pi\)fL = 2\(pi\) x \(\frac{160}{\pi}\) x 3 = 960\(\Omega\)
(iv) Z = \(\sqrt{R^2 + (X_L - X_c)^2} = \sqrt{100^2 + (960 - 781)^2}\) = 205\(\Omega\)
(v) I = \(\frac{v}{z} = \frac{100}{205} = 0.49A\)
(vi) P = I\(^2R\) = (0.49)\(^{2}\) x 100
= 23.795 W = 24W
Source: Myschool Past Questions Archive (Record #54674)
Physics
WAEC / WASSCE 1999
Mechanics and Properties of Matter
Solution
(a) Explain: (i) Fusion. (ii) Fission.
(b) State three advantages of fusion over fission in the generation of power
(c) Calculate in joules, the binding energy for
\(\frac{59}{27}\) Co
(Atomic mass of \(^{59}_{2} Co\) = 58.9332 u)
(Mass of proton = 1.00783u)
(Mass of neutron = 1.00867 u)
(Unified atomic mass unit, U = 931 MeV)
(1 eV = 1.6 x 10\(^{-19}\) J)
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)(i) Fusion is the coming together of two light nuclei to form a heavier nucleus with the release of large amount of energy
\(^2_1H + ^3_1H \to ^4_2He\) + energy
(ii) Fission is the breaking up of heavy nucleus into two nuclei of comparable masses when bombarded with neutrons releasing energy and neutrons in the process.
\(^{235}_{92}U + ^1_0n \to ^{90}_{36}kr + ^{144}_{56}Ba + 2^1_0H + energy)\)
(b) - Binding materials are cheap and easy to come by
- it produces less dangerous products.
- There is no e mass of hydrogen that can be obtained
(c) Bonding energy = Mass of (Protons + neutron) - atomis mass = 27(1.00783u) + 32(1.00867u) - 58.93332 u
= 27.21121u + 32.27744u - 58.9332 u
= 59.48865 u - 58.9332 u
= 0.55545 u
= 0.55545 x 931 MeV = 517.12 x 10\(^6\) eV
= 517.12 x 10\(^6\) x 1.6 x 10\(^{19}\) J
= 8.27 x 10\(^{-11}\)J.
Source: Myschool Past Questions Archive (Record #54680)
Physics
WAEC / WASSCE 1999
Mechanics and Properties of Matter
Solution
In the diagram, a thread AC, fixed at pulley A passes over pulley C on a force board and carries an unknown mass \(m_o\). Retain this mass \(m_o\) throughout the experiment. Draw a line along the direction of AC on the paper held behind the thread. Locate the mid-point B of AC and mark its position on this line. Draw BP at right angles to AC. By means of a loop of thread, suspend a mass M 50 g from AC and adjust the position of the loop so that the line of action of the weight of M lies along with BP. Ensure that M and \(m_o\), hang off the force board. Measure BO = y and AO. Evaluate y / AO. Repeat the experiment for M = 70,90,110 and 130g respectively. In each case, determine the corresponding values of y, AO, and y / AO. Tabulate your readings. Plot a graph of Y/AO on the vertical axis and M on the horizontal axis. Determine the slopes s of the graph. State two precautions taken to ensure accurate results. Attach your traces to your answer script.
(b)i. Distinguish between the resultant and the equilibrant of forces.
ii. State two conditions necessary for the equilibrium of three non-parallel coplanar forces.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Table of values/observation
S/N
M(g)
y(cm)
Ao(cm)
\(\frac{y}{AO}\)
1
50.00
2.30
8.00
0.288
2
70.00
2.45
8.20
0.378
3
90.00
3.65
8.40
0.417
4
110.00
4.10
8.60
0.465
5
130.00
5.00
9.10
0.549
Slope (s) = \(\frac{\bigtriangleup {(\frac{y}{AO})}}{\bigtriangleup {m(g)}} = \frac{0.55-0.15}{130-6} = \frac{0.4}{124}\)
0.003226g\(^{-1}\)
Precautions:
- Force board must be firmly fixed.
- Avoid parallax errors when reading the metre rule.
(b)i. The resultant and the equilibrant of forces have the same magnitude but opposite directions.
ii. The conditions for the equilibrium of three non-parallel co-planar forces are:
The lines of action of the forces must meet at a point.
All the three forces must be concurrent (i.e, meet at a point).
The algebraic sum of their moment about a point must be zero.
The algebraic sum of the forces at a point must be equal to zero.
Source: Myschool Past Questions Archive (Record #60137)
Physics
UTME / JAMB 1998
Mechanics and Properties of Matter
Solution
A bullet fired at a wooden block of thickness 0.15m manages to penetrate the block. If the mass of the bullet is 0.025kg and the average resisting force of the wood is 7.5 x 103N, calculate the speed of the bullet just before it hits the wooden block.
A
450ms-1
B
400ms-1
C
300ms-1
D
250ms-1
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
F = ma
Therefore, a = \(\frac{F}{m}\)
a = \(\frac{7.5 \times 10^{3}}{0.025}\)
a = 3 x 105m/s2
using V2 = U2 + 2ax;
V2 = 02 + (2 x 3 x 105 x 0.15)
Therefore V = 300 m/s
Source: Myschool Past Questions Archive (Record #27576)
Physics
UTME / JAMB 1998
Mechanics and Properties of Matter
Solution
The velocity of a sound wave at 27oC is 360ms-1. Its velocity at 127oC is
A
120√3 ms-1
B
240 ms-1
C
240√3 ms-1
D
720√3 ms-1
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Velocity \(\alpha \sqrt{temperature}\)
\(\frac{V_1}{V_2} = \sqrt{\frac{T_1}{T_2}}\)
therefore, \(\frac{360}{V_2} = \sqrt{\frac{27 + 273}{127 + 273}}\)
\(V_2 = 240\sqrt{3}\)m/s
Source: Myschool Past Questions Archive (Record #27580)
Physics
UTME / JAMB 1998
Mechanics and Properties of Matter
Solution
A ball is moving at 18ms\(^{-1}\) in a direction inclined at 60º to the horizontal. The horizontal component to its velocity is
A
9√3ms-1 ·
B
6√3ms-1 ·
C
8√3ms-1 ·
D
9ms-1 ·
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Since the angle is inclined to the horizontal,
The horizontal component of the velocity V\(_x\) = V x cos \(\theta\) = 18 x cos 60º = 9m/s
(NOTE: Cos 60º = 0.5)
Source: Myschool Past Questions Archive (Record #27584)
Physics
UTME / JAMB 1998
Mechanics and Properties of Matter
Solution
A ball of mass 0.15kg is kicked against a rigid vertical wall with a horizontal velocity of 50ms-1. If it rebounced with a horizontal velocity of 30ms-1, Calculate the impulse of the ball on the ball · ·
A
3.0Ns
B
4.5Ns
C
7.5Ns
D
12.0Ns
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Impulse = m(v-u)
= 0.15(50--30)
= 0.15 X 80
= 12N/s
Source: Myschool Past Questions Archive (Record #27589)
Physics
UTME / JAMB 1998
Mechanics and Properties of Matter
Solution
The force of attraction between two point masses is 10-4N when the distance between them is 0.18m. If the distance is reduced to 0.06m, calculate the force.
A
1.1 x 10-5N
B
3.3 x 10-5N
C
3.0 x 10-4N
D
9.0 x 10-4N
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
F \(\alpha \frac{1}{r^2}\)
therefore, \(\frac{F_1}{F_2}\) = \(\frac{r_1}{(r_2)^2}\)
\(\frac{10^{-4}}{F_2}\) = \(\frac{(0.06)^2}{(0.18)^2}\)
F = 9 x 10-4N
Source: Myschool Past Questions Archive (Record #27601)
Physics
UTME / JAMB 1998
Mechanics and Properties of Matter
Solution
A man whose mass is 80kg climbs a staircase in 20s and expends power of 120W. Find the height of the staircase.[g = 10ms-2]
A
1.8m
B
2.0m
C
2.5m
D
3.0m
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Power x time = mgh
120 x 20 = 80 x 10 x h
2400 = 800h
making h the subject of formula,divide both side by 800
\(\frac{2400}{800}\) = h
h = 3m
Source: Myschool Past Questions Archive (Record #27603)
Physics
UTME / JAMB 1998
Mechanics and Properties of Matter
A parachute attains a terminal velocity when
A
its density is equal to the density of air
B
the viscous force of the air and the upthrust completely counteract its weight
C
it expands as a result of reduced external pressure
D
the viscous force of the air is equal to the sum of the weight and upthrust
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #27604)
Physics
UTME / JAMB 1998
Mechanics and Properties of Matter
Solution
In a wheel and axle mechanism the diameters of the wheel and axle are 40cm and 8cm respectively. Given that the machine is 80% efficient, what effort is required to lift a load of 100N?
A
20N
B
25N
C
50N
D
80N
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Efficiency = \(\frac{\text{work done by hand}}{\text{work done by effort}}\)
80 = \(\frac{100{\times 8}}{E {\times} 40}\) x \(\frac{100}{1}\)
E = 25N
Source: Myschool Past Questions Archive (Record #27605)
Physics
UTME / JAMB 1998
Mechanics and Properties of Matter
Solution
The tendon in a man's leg is 0.01m long. If a force of 5N stretches the tendon by 2.0 x 10-5m, calculate the strain on the muscle.
A
5 x 106
B
5 x 102
C
2 x 10-3
D
2 x 10-7
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Strain = \(\frac{extension}{\text{original length}}\)
\(\frac{2 {\times} 10^{-5}}{0.01}\)
= 2 x 10-3
Source: Myschool Past Questions Archive (Record #27606)
Physics
UTME / JAMB 1998
Mechanics and Properties of Matter
Solution
Which of these statements are correct for the pressures in liquids? i. pressure in a liquid at a point acts equally in all directions. ii. pressure increases with depth. iii. pressure at a depth depends on the shape of the container. iv. pressure at the same depth in different liquids are proportional to the density at different liquids.
A
i, ii, iii only
B
i, ii, iv only
C
i, iii, iv only
D
ii, iii, iv only
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
(i) Pressure in a liquid at a point acts equally in all directions. Pressure increases with depth and pressure at the same depth in different liquids is proportional to the density at different liquids are correct for the pressure in liquid
Source: Myschool Past Questions Archive (Record #27608)