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Chemistry
WAEC / WASSCE 2017
Matter & Separation Techniques
Solution
The use of diamond in abrasives is due to its
A
high melting point
B
hardness
C
octahedral shape
D
durability
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Diamonds are very hard, they are often used as an abrasive.
Source: Myschool Past Questions Archive (Record #49254)
Chemistry
WAEC / WASSCE 2017
Kinetics, Energetics and Equilibrium
Solution
Which of the following statements about endothermic reaction is correct?
A
Activation energy is high
B
A catalyst is required
C
It occurs reversibly
D
Heat energy is absorbed
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Endothermic reactions are those reactions which absorb energy from the surroundings and result in a net decrease in temperature.
Source: Myschool Past Questions Archive (Record #49255)
Chemistry
WAEC / WASSCE 2017
Matter & Separation Techniques
Solution
A 0.1\(moldm^{-3}\) solution of sodium hydroxide was diluted with distilled water to 0.001\(moldm^{-3}\). What is the dilution factor?
A
1000.00
B
100.00
C
10.00
D
0.01
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
The formula to calculate the dilution factor when using concentrations is DF = \(\frac{C_1}{C_2}\), where C\(_1\) is the initial concentration of the stock solution and C\(_2\) is the final concentration of the diluted solution.
Dilution factor= \(\frac{0.1}{0.001}\) = 100
Source: Myschool Past Questions Archive (Record #49260)
Chemistry
WAEC / WASSCE 2017
Acids, Bases, and Salts
Solution
Graphite and Diamond are similar in that they
A
have octahedral shape
B
have same density
C
form carbon(IV) oxide on combustion
D
conduct electricity
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
A diamond is pure carbon. Graphite is pure carbon. Both will burn to form carbon dioxide.
Source: Myschool Past Questions Archive (Record #49267)
Chemistry
WAEC / WASSCE 2017
Matter & Separation Techniques
Solution
In a saturated solution at a given temperature, the undissolved solutes are in equilibrium with
A
the solvent
B
dissolved solute particles
C
the saturated solution
D
insoluble solute particles
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
In a saturated solution dissolved solute and undissolved solute are in equilibrium with each other. Is different from A saturated solution is said to be in equilibrium with undissolved solute when the rate of dissolution of the solute equals the rate of crystallization. This means that the amount of solute being dissolved is the same as the amount of solute coming out of solution, resulting in no net change in the concentration of the solution.
Source: Myschool Past Questions Archive (Record #49271)
Chemistry
WAEC / WASSCE 2017
Stoichiometry & Mole Concept
Solution
The number of atoms present in 2.5moles of a triatomic gas is equivalent to [1mole = \(6.02\times 10^{23}\)]
A
\(2.5\times 10^{23}\)
B
\(1.5\times 10^{23}\)
C
\(1.5\times 10^{24}\)
D
\(2.5\times 10^{24}\)
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
1 mole = \(6.02 \times 10^{23}\)
2.5 moles = \(6.02 \times 10^{23} \times 2.5\)
= \(15.05 \times 10^{23} = 1.505 \times 10^{24}\)
\(\approxeq 1.5 \times 10^{24}\)
Source: Myschool Past Questions Archive (Record #49274)
Chemistry
WAEC / WASSCE 2017
Kinetics, Energetics and Equilibrium
Solution
When Magnesium reacts with oxygen, heat is
A
absorbed and the reaction is endothermic
B
evolved and the reaction is endothermic
C
evolved and the reaction is exothermic
D
absorbed and the reaction is exothermic
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The Magnesium actually reacts with oxygen in the air, is burnt and produces a bright light. The bright light emits a lot of heat so the reaction is exothermic.
Source: Myschool Past Questions Archive (Record #49275)
Chemistry
WAEC / WASSCE 2017
Acids, Bases, and Salts
Solution
Which of the following gases is not acidic?
A
\(SO_{3}\)
B
\(NO_{2}\)
C
\(Co_{2}\)
D
CO
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
The compound CO is treated as a neutral oxide, though in truth, it is slightly acidic. Regardless of this, within the options supplied, CO is the best option available.
Source: Myschool Past Questions Archive (Record #49276)
Chemistry
WAEC / WASSCE 2017
Stoichiometry & Mole Concept
Solution
A hydrocarbon contained 14.3% hydrogen. The empirical formula for the hydrocarbon is [H= 1.0, C= 12.0]
A
\(CH\)
B
\(CH_{2}\)
C
\(CH_{3}\)
D
\(CH_{4}\)
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
The percentage of Carbon in the compound is (100 - 14.3)% = 85.7%
C : H
\(\frac{85.7}{12.0} : \frac{14.3}{1.0}\)
\( 7.14 : 14.3\)
\(\frac{7.14}{7.14} : \frac{14.3}{7.14}\)
\(\approxeq 1 : 2\)
Therefore, the empirical formula is \(CH_{2}\).
Source: Myschool Past Questions Archive (Record #49291)
Chemistry
WAEC / WASSCE 2017
Acids, Bases, and Salts
Solution
Which of the following statements is NOT a chemical property of an acid?
A
Evolution of ammonia when heated with ammonium salts
B
Evolution of carbon dioxide gas when added to a trioxocarbonate (IV) salt
C
Formation of salt and water with alkalis
D
Formation of salt and hydrogen gas with reactive metals
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Ammonium salts react with bases to release ammonia and not with acids.
Source: Myschool Past Questions Archive (Record #49295)
Chemistry
WAEC / WASSCE 2017
Acids, Bases, and Salts
Solution
Halogens generally react with metals to form
A
alkalis
B
acids
C
bases
D
salts
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
The word "halogen" is a Greek word meaning salt former, because they form salts when they react with metals eg NaCl.
Source: Myschool Past Questions Archive (Record #49302)
Chemistry
WAEC / WASSCE 2017
Atomic Structure and Periodic Table
Solution
Potassium Chloride solid does not conduct electricity because
A
it is a covalent compound
B
strong cohesive forces make its ions immobile
C
strong cohesive force makes its molecule immobile
D
each of potassium and chlorine structures contain noble gas structure
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
For a substance to conduct electricity, it must have charge particles like electrons and ions within it that are able to move freely throughout it. In its solid state, potassium chloride (like many other ionic compounds) have fixed ions, hence, they are immobile and can't conduct electricity.
Source: Myschool Past Questions Archive (Record #49305)
Chemistry
WAEC / WASSCE 2017
Acids, Bases, and Salts
Solution
When water was added to a white anhydrous substance X, the colour changed to blue. X is
A
\(CuSO_{4}\)
B
\(FeSO_{4}\)
C
\(Na_{2}SO_{4}\)
D
\(PbSO_{4}\)
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
When water is added to white coloured anhydrous copper sulphate, its colour changes to blue, indicating that the blue coloured copper sulphate pentahydrate is regenerated.
Source: Myschool Past Questions Archive (Record #49311)
Chemistry
WAEC / WASSCE 2017
Matter & Separation Techniques
Solubility curve can be used in the determination of the
A
amount of crystals formed
B
amount of solvent that can be recovered
C
amount of solid drugs in a given solution
D
temperature of the solution
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #49312)
Chemistry
WAEC / WASSCE 2017
Stoichiometry & Mole Concept
Solution
If 0.2g of a salt is required to saturate 200\(cm^{3}\) of water at room temperature, what is the solubility of the salt?
A
0.2\(gdm^{-3}\)
B
1.0\(gdm^{-3}\)
C
2.0\(gdm^{-3}\)
D
5.0\(gdm^{-3}\)
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Solubility in \(gdm^{-3}\) = \(\frac{mass of salt in gram}{volume of liquid in dm^{3}}\)
200\(cm^{3}\) = \(\frac{200}{1000} dm^{3} = 0.2dm^{3}\)
Solubility = \(\frac{0.2g}{0.2dm^{3}}\)
= 1.0\(gdm^{-3}\)
Source: Myschool Past Questions Archive (Record #49313)