Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 1141–1155 of 1709 verified questions
Sort by:
Physics
UTME / JAMB 1999
Mechanics and Properties of Matter
Solution
If a sound wave goes from a cold air region to a hot air region, its wavelength will
A
increase
B
decrease
C
decrease then increase
D
remain constant
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
When a sound wave moves from a region of cold air to a region of hot air, its wavelength will increase. This occurs because sound travels more quickly in warmer air due to the heightened energy of the air molecules, which allows for a longer wavelength while the frequency remains unchanged.
Source: Myschool Past Questions Archive (Record #559)
Physics
UTME / JAMB 1999
Mechanics and Properties of Matter
Solution
Gamma rays are produced when
A
high velocity electrons are abruptly stopped in metals
B
energy changes occur within the nucleus of atoms
C
energy changes occur within the electronic structure of atoms
D
electrons are deflected in very strong magnetic fields
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Gamma rays are electromagnetic radiation of nuclear origin; they are produced from energy changes which occur within the nucleus of atoms
Source: Myschool Past Questions Archive (Record #630)
Physics
UTME / JAMB 1999
Mechanics and Properties of Matter
Solution
What is the speed of a particle of mass 10-27kg whose wavelength is 10-8m.
[h = 6.63 x 10-34Js]
A
6.63ms-1
B
66.30ms-1
C
663.00ms-1
D
6630.00ms-1
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Energy of a particle is given by
E = hf = hV/λ (since V = fxλ)
But in terms of mass M, E = ∆MV2
∴ ∆MV2 = hV/λ
∆MV = h/λ
∴ V = h/λ∆M
V = 6.63 x 10-34/(10-27 x 10-8)
V = 6.63 x 10-34/10-35
V = 6.63 x 10-34+35
V = 6.63 x 10
V = 66.3ms-1
Source: Myschool Past Questions Archive (Record #644)
Physics
UTME / JAMB 1999
Mechanics and Properties of Matter
if ∆x is the uncertainty in the measurement of the position of a particle along the x-axis and ∆Px is the uncertainty in the measurement of the linear momentum along the x-axis, then the uncertainty principle relation is given as
A
∆x ∆Px ≥ h
B
∆x ∆Px = 0
C
∆x ∆Px < h
D
∆x ∆Px = ∞
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #664)
Physics
UTME / JAMB 1999
Mechanics and Properties of Matter
Diagram
Solution
The diagram above shows the velocity-time graph of a vehicle. Its acceleration and retardation respectively are
Attached Figure / Diagram
A
8.0 ms-2, 4,0 ms-2
B
4.0 ms-2, 8.0 ms-2
C
4.0 ms-2, 2.0 ms-2
D
2.0 ms-2, 4.0 ms-2
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Acceleration = slope = AE/OE = 80/20 = 4m/s2
∴ acceleration and retardation = 4m/s2; 2m/s2
Source: Myschool Past Questions Archive (Record #11133)
Physics
UTME / JAMB 1999
Mechanics and Properties of Matter
Diagram
Solution
In the circuit above, The potential across each capacitor is 100V. The total energy stored in the two capacitors is
Attached Figure / Diagram
A
3.0 x 104J
B
3.0 x 102J
C
2.5 x 10-2J
D
6.0 x 10-3J
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Energy stored in a capacitor is given by
E = \(\frac{1}{2}\)CV\(^2\)
But the effective capacitance for the parallel arrangement is given by
C = C\(_1\) + C\(_2\)
= 2 + 3
= 5\muF = 5 x 10\(^{-6}\) x (100)\(^2\)
∴E = \(\frac{1}{2}\)CV\(^2\)
= \(\frac{1}{2}\) x 5 x 10\(^{-6}\) x 10\(^4\)
2.9 x 10\(^{-2}\)J
Source: Myschool Past Questions Archive (Record #11272)
Physics
UTME / JAMB 1999
Mechanics and Properties of Matter
Diagram
Solution
In the diagram above, if the internal resistance of the cell is zero, the ration of the powers P1 and P2 dissipated by R1 and R2
Attached Figure / Diagram
A
R2/R1
B
R1/R2
C
R1+R2/R1
D
R1+R2/R2
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Power = IV = I2R = V2/R
In terms of e.m.f E, of a cell we have
IE = I2R = E2/R
∴P1 = E2/R; P2 = E2/R2/E2/R2
= E2/R1 x R2/E2 = R2/R1
∴P1/P2 = R2/R1
Source: Myschool Past Questions Archive (Record #11273)
Physics
UTME / JAMB 1999
Mechanics and Properties of Matter
Diagram
Solution
The diagram above shows a solid figure with base PQ and center of gravity G on a inclined plane. Which of the following statements is correct
Attached Figure / Diagram
A
The solid will fall over if the vertical line through G lies outside the base
B
The solid will fall over if the vertical line through lies inside the base
C
The solid will not fall over if the vertical line through G lies outside the base
D
The solid can never fall over
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
The solid will fall over if when the vertical line through G lies outside the base, when slightly tilted
Source: Myschool Past Questions Archive (Record #11143)
Physics
UTME / JAMB 1999
Mechanics and Properties of Matter
Diagram
Solution
In the J-tube above, Y and X are on the same horizontal level and 30cm3 of air is trapped above Y when the atmospheric pressure is 75cm Hg, calculate the volume of air trapped above Y when 15cm Hg is now poured into the limb above X
Attached Figure / Diagram
A
15 cm3
B
25 cm3
C
35 cm3
D
45 cm3
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Since the temperature of the air is to remain constant, => P\(_1\)V\(_1\) = P\(_2\)V\(_2\)
∴ 75 x 30 = (75 + 15) x V\(_2\)
75 x 30 = 90 x V\(_2\)
V\(_2\) = \(\frac{75 \times 30}{90}\)
\(\frac{2250}{90}\) = 25cm\(^2\)
Source: Myschool Past Questions Archive (Record #11174)
Physics
UTME / JAMB 1999
Mechanics and Properties of Matter
If ∆x is the uncertainty in the measurement of the position of a particle along the x-axis and ∆Pa is the uncertainty in the measurement of the linear momentum along the x-axis, then the uncertainty principle relation is given as
A
∆x ∆Px ≥ h
B
∆x ∆Px = 0
C
∆x ∆Px < h
D
∆x ∆Px = ∞
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #1432)
Physics
WAEC / WASSCE 1999
Mechanics and Properties of Matter
The force between molecules of the same substance is termed
A
elastic force
B
repulsive force
C
cohesive force
D
adhesive force
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25467)
Physics
WAEC / WASSCE 1999
Mechanics and Properties of Matter
A net force of magnitude 0.6N acts on a body of mass 40g, initially at rest. Calculate the magnitude of tire resulting acceleration.
A
90ms-2
B
60ms-2
C
30ms-2
D
15ms-2.
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #25468)
Physics
WAEC / WASSCE 1999
Mechanics and Properties of Matter
Solution
A body weighing 100N moves with a speed of 5ms-1 in a horizontal circular path of radius 5m. Calculate the . magnitude of the centripetal force acting on the body. (g = 10ms-2)
A
10N
B
50N
C
75N
D
100N
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
W = 100N, r = 5m, v = 5m/s and g = 10m/s2
BUT \(F_c\) = \(\frac{M \times V^2}{r}\)
W = mg = m = 100/10 = 10kg
\(F_c\) = \(\frac{10\times 5^2}{5}\) = 50N
Source: Myschool Past Questions Archive (Record #25470)
Physics
WAEC / WASSCE 1999
Mechanics and Properties of Matter
The heat capacity of a substance is the energy
A
required to raise the temperature of a unit mass of the substance by one degree.
B
required to raise the temperature of the substance by one degree
C
absorbed by the substance at constant temperature
D
lost by a unit mass of the substance.
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #25481)
Physics
WAEC / WASSCE 1999
Mechanics and Properties of Matter
The temperature of a piece of metal of mass 9 g is raised from 10oC to 110oC when it absorbs 108J of heat energy. Determine the specific heat capacity of the metal in J kg-1K-1
A
1.2
B
12.0
C
120.0
D
1200.0
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25482)